How much Oxygen would be required to react with 101 g of Methane?
A.101 g
B.202 g
C.303 g
D.404 g

Answer:

Is the answer eight atoms

Answer:

because they contains clues about what the earth was like in the past. different rocks from under only certain conditions and even the dullest gray lump of rock.

C. picking a tray in the cafeteria line

Answer:

I think it would double it's self

Answer:

potential energy

Explanation:

Answer:

fire > rocks > air

Answer:

[tex]\boxed {\boxed {\sf 5.2 *10^{22} \ molecules \ NaCl}}[/tex]

Explanation:

1. Convert grams to moles

First, convert grams to moles using the molar mass. This can be found on the Periodic Table.

Sodium (Na) has an oxidation state of +1 and chlorine (Cl) has an oxidation state of -1, so they combine in a 1:1 ratio for a formula of NaCl. We can simply add their moles masses.

Use this as a ratio.

[tex]\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Multiply by the given number of grams.

[tex]5.0 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Flip the fraction so the grams of sodium chloride cancel.

[tex]5.0 \ g \ NaCl *\frac {1 \ mol \ NaCl}{ 58.4397693 \ g \ NaCl}[/tex]

[tex]5.0 *\frac {1 \ mol \ NaCl}{ 58.4397693 }=\frac {5.0 \ mol \ NaCl} { 58.4397693 } = 0.0855581749 \ mol \ NaCl[/tex]

2. Convert moles to molecules

We must use Avogadro's Number. This tells us the amount of particles (molecules, atoms, etc.) in 1 mole of a substance. In this case, it is molecules of sodium chloride.

[tex]\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

Multiply by the number of moles we calculated.

[tex]0.0855581749 \ mol \ NaCl*\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

The moles of sodium chloride cancel.

[tex]0.0855581749 *\frac{6.022*10^{23} \ molecules \ NaCl}{1}=5.15231329*10^{22} \ molecules \ NaCl[/tex]

The original measurement of grams has 2 (2 and 0) significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 5 in the hundredth place tells us to round the 1 to a 2.

[tex]5.2 *10^{22} \ molecules \ NaCl[/tex]

Answer:

FALSE!

Explanation:

Gymnosperms do use seeds but are exposed like the pine cones of pines. Angiosperms still have seeds, however, they flower or fruit.

Answer:

False

Explanation:

Answer:

[tex]V_2=2.5m^3[/tex]

Explanation:

Hello!

In this case, according to the Charles' law as a directly proportional relationship between volume and temperature:

[tex]\frac{V_2}{T_2}=\frac{V_1}{T_1}[/tex]

Thus, in order to compute the final volume, V2, we obtain the following expression:

[tex]V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5m^3*300K}{600K}\\\\V_2=2.5m^3[/tex]

Best regards!

Answer:

Shared (bonding) electrons : 8

Unshared (lone, non-bonding) electrons : 16

Explanation:

The Lewis dot stricture of the molecule attached to this answer shows us all the valence electrons present in the molecule.

Altogether, we have a total number of 24 valence electrons in SO3.

There are eight electrons shared between atoms of elements, these are the bonding electrons.

There are sixteen electrons that are not shared between atoms of elements, These are the lone or non-bonding electrons.

Hence, there are four shared pairs of electrons and eight pairs of unshared electrons.

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

[tex]NH_3+H_2O\rightleftharpoons NH_4^++OH^-[/tex]

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

[tex]Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}[/tex]

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

[tex]1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M[/tex]

Which is also:

[tex][OH^-]=1.643x10^{-3}M[/tex]

Thereafter we can compute the pOH first:

[tex]pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784[/tex]

Finally, the pH turns out:

[tex]pH=14-2.784\\\\pH=11.216[/tex]

Regards!

Answer:

Pb(NO₃)₂ is the limiting reactant.

The equation is: Pb(NO₃)₂ (aq) + 2KCl (aq) →  PbCl₂ (s) ↓  + 2KNO₃ (aq)

Explanation:

We identify our reactants:

Pb(NO₃)₂ → Lead (II) nitrate

KCl → Potassium chloride

Our reaction is:

Pb(NO₃)₂ (aq)  +  2KCl (aq) →  PbCl₂ (s) ↓  + 2KNO₃ (aq)

1 mol of Lead (II) nitrate reacts to 2 moles of KCl, in order to produce 2 moles of potassium nitrate and 1 mol of slid Lead (II) chloride.

We determine the moles of the reactants:

6.06 g . 1mol /331.2 g = 0.0183 moles of Lead (II) nitrate

6.58 g . 1mol / 74.55g = 0.0882 moles of KCl

2 moles of KCl react to 1 mol of Pb(NO₃)₂

Then, 0.0882 moles of KCl may react to (0.0882 . 1) /2 = 0.0441 moles

We have 0.0183 moles of Pb(NO₃)₂ and we need 0.441 moles. Then, the

Pb(NO₃)₂ is our limiting reactant.

Answer:

[tex][OH^-]=2.455x10^{-3}M[/tex]

Explanation:

Hello there!

In this case, since a strong base produce OH ions in solution, it possible to first compute the pOH as shown below:

[tex]pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-11.39\\\\pOH=2.61[/tex]

Thus, via the definition of the pOH we can compute the concentration of the strong base as follows:

[tex]pOH=-log([OH^-])[/tex]

Thus, solving for the concentration we obtain:

[tex][OH^-]=10^{-pOH}=10^{-2.61}[/tex]

[tex][OH^-]=2.455x10^{-3}M[/tex]

Best regards!

Answer: true

Explanation:

Answer: A. True

Explanation:

Answer:

25°C

Explanation:

Combined Gas Law (P₁V₁)/T₁ = (P₂V₂)/T₂

(0.947 atm)(150 mL)/25°C = (0.987 atm)(144mL)/T₂

5.682 = 142.128/T₂

T₂ = 142.128/5.682

T₂ = 25.0137272756°C = 25°C

Answer:

To calculate the concentration of the acid solution, use three steps.

1. Use the volume of base used at the endpoint and the known concentration of the base solution to find the moles of base used.

2. Use the stoichiometry to find the moles of acid from the moles of base.

3. Divide the moles of acid by the volume of acid used in the titration to find the concentration of acid.

Explanation:

Titration is the process used in volumetric analysis to determine the amount of a substance present in a given sample.

In any titration, a solution of known concentration known as the standard solution is used to react with a solution of of unknown concentration. The reacting volumes of the solutions are then used to calculate the unknown  concentration of the second solution.

In acid-base neutralization reactions, an equivalence point/endpoint of the neutralization titration is obtained and is the point at which the moles of H+ is equal to the moles of OH- . An indicator is used to indicate the equivalence point during a titration by a color change observed in the indicator.

In order to calculate the concentration of an acid, we need to know accurately, use three steps:

1. Use the volume of base used at the endpoint and the known concentration of the base solution to find the moles of base used.

2. Use the stoichiometry of the reaction to find the moles of acid from the moles of base.

3. Divide the moles of acid by the volume of acid used in the titration to find the concentration of acid.

In order to calculate the concentration of a base, use three steps:

1. Use the volume of acid used at the endpoint and the known concentration of the acid solution to find the moles of acids used.

2. Use the stoichiometry of the reaction to find the moles of base from the moles of acid.

3. Divide the moles of base by the volume of base used in the titration to find the concentration of base.

Answer:

1.25 grams of chlorine.

Explanation:

Hello there!

In this case, since it is possible to define the parts per million of chlorine as the milligrams of chlorine per liters of water, in order to obtain the mass of chlorine in 2500 L, we proceed as follows:

[tex]ppm=\frac{mg}{L}\\\\mg=ppm*L[/tex]

In such a way, we plug in the given 0.500 ppm and 2500 L to obtain (in grams):

[tex]mg=0.500mg/L*2500L\\\\g=1250mg*\frac{1g}{1000mg}\\\\ g=1.25g[/tex]

Best regards!

Answer:

2.28bar

Explanation: Boyle's law P1V1=P2V2 manipulate formula in favor of V2 the new formula should beP1V1/V2

0.895*318/125=2.2768 but to same sigfig it is 2.28

Explanation:

for example, one gene will code for the protein insulin, which is important role in helping your body to control the amount of sugar in your blood. Genes are the basic unit of genetics. Human beings have 20,000 to 25,000 genes.

Answer:

420.7 degrees C

Explanation:

Use the formula V1/T1 = V2/T2 (Charles' Law) to find T2. Make sure to convert  your temperatures to Kelvin by adding 273 to the Celsius temperature.

V1 = 4.50 L

V2 = 10 L

T1 = 39.2 C = 312.2 K

Solve V1/T1 = V2/T2 for T2 and you get T2 = V2T1/V1

T2 = (10 L)(312.2 K) / (4.50 L) = 693.8 K

You can subtract 273 to get the temperature back to Celsius.

T2 = 693.8 - 273 = 420.7 degrees C

Answer:

Cold front

Explanation:

Answer:

metal

Explanation:

it's a soft silvery metal

Answer:

0.25 mole of CO₂

Explanation:

We'll begin by calculating the mass of oxygen in 1 mole of carbon dioxide (CO₂). This is illustrated below:

Molecular formula of carbon dioxide

=> CO₂

Mass of oxygen in CO₂ = 2O

= 2 × 16

= 32 g

Thus, 1 mole of CO₂ contains 32 g of oxygen.

Finally, we shall determine the number of mole of CO₂ that contains 8 g of oxygen. This can be obtained as follow:

1 mole of CO₂ contains 32 g of oxygen.

Therefore, Xmol of CO₂ will contains 8 g of oxygen i.e

Xmol of CO₂ = 8/32

Xmol of CO₂ = 0.25 mole

Thus, 0.25 mole of CO₂ contains 8 g of oxygen.

oxygen  is needed as a reactant for cellular respiration

Cellular respiration can be defined as the process  which occurs in every cells mainly mitochondria of plants and animals, it involve in the break down of sugars in the presence of oxygen and releases energy in the form of ATP.

The waste product of this process are carbon dioxide and water during exhalation process done  by lungs,  breathing and cellular respiration are related to each other.

At every step of cellular respiration energy is used in the form of ATP and carry out the normal function. It can aerobic and anaerobic respiration on the basis of use of oxygen.

For more details regarding cellular respiration, visit

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Answer:

just downloud smart

Explanation:

thank me later

Answer:

carbon

Explanation:

The properties of carbon forms the basis for all life. Explanation: The atoms of carbon are found in the molecules of all living species.

Answer:

Al4C3 +12 H2O → 4Al(OH)3 + 3CH4

4NH3 + 5O2 → 4NO + 6H2O

Answer:

Mouthing is the answer to your question