Calculate the approximate initial boiling point (in oC) of a solution of 285 g of

magnesium chloride in 2.0 kg of water. The kb of water is (0.52°C/m)

Answers

Answer 1

Answer:

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Answer 2

The approximate initial boiling point of Magnesium chloride solution has been 102.33 degree Celsius.

The pure water has boiling point 100 degree Celsius. With the addition of the solvent, the boiling point has been increased. The change in the boiling point ([tex]\Delta T_b[/tex]) has been given as:

[tex]\Delta T_b=i.K_b.b[/tex]

Where, i has been the van't Hoff factor

[tex]K_b[/tex] has been the ebullioscopic constant

b has been the molality of the sample

The dissolution of magnesium chloride in water has been given as:

[tex]\rm MgCl_2\;(aq)\;\rightarrow\;Mg^2^+\;+\;2\;Cl^-[/tex]

The i has been the amount of molecules that has been formed by the dissociation of 1 molecule. The dissociation of Magnesium chloride has been resulted in the 1 Mg and 2 Cl. Thus, the i for Magnesium chloride has been 3.

The molality (m) of the solution has been given as:

[tex]m = \dfrac{m_s_o_l_u_t_e}{mwt}\;\times\;\dfrac{1000}{m_s_o_l_v_e_n_t}[/tex]

Where, [tex]m_s_o_l_u_t_e=285\;\text {g}\\m_s_o_l_v_e_n_t=2\;\text{kg}\\mwt=95.211\;\text{g/mol}[/tex]

Substituting the values, molality of the Magnesium chloride solution (b) can be given as:

[tex]b=\dfrac{285}{95.211}\;\times\;\dfrac{1}{2}\;\text{m}\\b=1.49\;\text{m}[/tex]

The molality of the solution has been 1.49 m.

Substituting the values for change in temperature:

[tex]\Delta T_b=3\;\times\;0.52\;\times\;1.49\;^\circ \text C\\\Delta T_b=2.33\;^\circ \text C[/tex]

The rise in boiling temperature with the addition of 285 g of Magnesium chloride has been 2.33 [tex]\rm ^\circ C[/tex]. Since, the initial temperature for pure solvent has been 100 degree Celsius.

The initial temperature of Magnesium chloride solution has been the sum of two. Thus:

[tex]\text {Initial temperature}=100^\circ \text C\;+\;2.33\;^\circ \text C\\\rm Initial\;temperature=102.33\;^\circ C[/tex]

The initial temperature of magnesium chloride solution has been 102.33 degree Celsius.

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Related Questions

determine the velocity of a cart traveling at 135cm in 5.5s.

Answers

velocity = distance/time

distance = 135cm
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velocity = 24.546 cm/s

Answer: 0.245 m/s

Explanation:

So velocity = d/t or distance over time in this case m/s or meters per second. But BE CAREFUL you must remember to convert cm to m always so 135 cm= 1.35m and 1.35m/5.5s= 0.245m/s

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A map of the galaxy would be a lot bigger and have a lot more names such as planets, stars, etc. While a city would be more basic than a whole galaxy.

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2 lol

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Because it can identify a person.

DNA Fingerprint

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Which of the following statements best explains the type of chemical reaction represented by Maya's picture?

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It represents a decomposition reaction because two reactants break apart and form two products.

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Answer:

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Answer:

Hey mate....

Explanation:

This is ur answer.....

Solar radiation can be converted either into thermal energy (heat) or into electrical energy.

Hope it helps!

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Electromagnetic, thermal! Solar energy is electromagnetic since it is from the sun, and then it can convert into thermal or electrical :)

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Answer:

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Which statement is true based on the formula?

6CO2 + 6H2O —> C6H12O6
+ 6O2

1. The mass of carbon dioxide plus water is equal to the mass of sugar plus oxygen

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3. The mass of carbon dioxide plus water is greater than the mass of sugar plus oxygen

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Answer:

The answer of this question is 3

3 is the correct answer hope this help

UGRENT! Please help showing all work

Answers

Answer:

a. The limiting reactant is Ca(OH)₂

b. The theoretical yield of CaCl₂ is approximately 621.488 grams

c. The percentage yield of CaCl₂ is approximately 47.06%

Explanation:

a. The given chemical reaction is presented as follows;

Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

Therefore;

One mole of Ca(OH)₂ reacts with two moles of HCl to produce one mole of CaCl₂ and two moles of water H₂O

The mass of HCl in an experiment, m₁ = 229.70 g

The mass of Ca(OH)₂ in an experiment, m₂ = 207.48 g

The molar mass of HCl, MM₁ = 36.458 g/mol

The molar mass of Ca(OH)₂, MM₂ =74.093 g/mol

The number of moles of HCl, present, n₁ = m₁/MM₁

∴ n₁ = m₁/MM₁ = 229.70 g/(36.458 g/mol) ≈ 6.3 moles

The number of moles of Ca(OH)₂, present, n₂ = m₂/MM₂

∴ n₂ = m₂/MM₂ = 207.48 g/(74.093 g/mol) ≈ 2.8 moles

The number of moles of Ca(OH)₂, present, n₂ = 2.8 moles

According the chemical reaction equation the number of moles of HCl the 2.8 moles of Ca(OH)₂ will react with, = 2.8 × 2 moles = 5.6 moles of HCl

Therefore, there is an excess HCl in the reaction and Ca(OH)₂ is the limiting reactant

b. According the chemical reaction equation the number of moles of CaCl₂ produced in he reaction by the 2.8 moles of Ca(OH)₂ = 2.8 × 2 moles = 5.6 moles of CaCl₂

The molar mass of CaCl₂ = 110.98 g/mol

The mass of the 5.6 moles of CaCl₂ = 5.6 moles × 110.98 g/mol ≈ 621.488 grams

The theoretical yield of CaCl₂ ≈ 621.488 grams

c. Given that the actual mass of CaCl₂ produced = 292.5 grams, we have;

The percentage yield of CaCl₂ = The actual yield/(The theoretical yield) × 100

∴ The percentage yield of CaCl₂ = (292.5 g)/(621.488 g) × 100 ≈ 47.0644646397%

The percentage yield of CaCl₂ ≈ 47.06%.

TICLA ruuis SLCLLICU 10115CI.
Question 3 (1 point)
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Answers

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use this conversation units to help you hope it helps

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Answers

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Have a great Day : P

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