How much force is needed to accelerate an object of mass 90 kg at a rate of 1.2 m/s²

Answers

Answer 1

Answer:

108 N

Explanation:

Use Newton's second law.

F = ma

F = (90 kg) (1.2 m/s²)

F = 108 N


Related Questions

Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows. Then, she knocked down the pyramid causing the marshmallows to fall. If the marshmallows represent the atoms in the substance, which change of state is Freida modeling?

Answers

Answer:melting 2020 edge

Explanation:

:)

Answer:

Melting

Explanation:

find the mass of an object with a density of 1.5 g/cm^3 and had a volume of 8cm^3

Answers

Answer:

12 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 1.5 × 8

We have the final answer as

12 g

Hope this helps you

During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the trebuchet launches the stones with a velocity of +48.5" m"/s at an angle of 42.0°, how long does it take the stone to hit the ground? For those settings, what is the maximum range? How high will the stones go? Show all your work

Answers

Answer:

a) t = 6.62 s

b) x = 238.6 m

c) H = 53.7 m

Explanation:

a) We can find the time of flight as follows:

[tex] y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} [/tex]

Where:

[tex]y_{f}[/tex] is the final height = 0

[tex]y_{0}[/tex] is the initial height = 0

[tex]v_{0_{y}}[/tex] is the initial vertical velocity of the stone

t: is the time

g: is the gravity = 9.81 m/s²

[tex] v_{0}sin(42)t - \frac{1}{2}gt^{2} = 0 [/tex]      

[tex] 48.5 m/s*sin(42)*t - \frac{1}{2}9.81 m/s^{2}*t^{2} = 0 [/tex]  

By solving the above quadratic equation we have:  

t = 6.62 s

b) The maximum range is:

[tex] x = v_{0_{x}}t = 48.5 m/s*cos(42)*6.62 s = 238.6 m [/tex]

c) The maximum height (H) can be found knowing that at this height the final vertical velocity of the stone is zero:

[tex] v_{f_{y}}^{2} = v_{0_{y}}^{2} - 2gH [/tex]  

[tex] H = \frac{v_{0_{y}}^{2} - v_{f_{y}}^{2}}{2g} = \frac{(48.5 m/s*sin(42))^{2} - 0}{2*9.81 m/s^{2}} = 53.7 m [/tex]

I hope it helps you!

Please select the word from the list that best fits the definition The skeletons of tiny ocean animals grow together to form ______, structures that are found only in warm, clear ocean water.

Answers

Answer:

coral reef

Explanation:

A person picking apples stand on a ladder 3.0 m above the ground. He throws them into
a basket 2.0 m away. How fast must the person throw the apple in order for it to land in
the basket?

Answers

Answer:

The speed the apple must be thrown in order for it to land in the basket is  2.554 m/s.

Explanation:

Given;

height above the ground, h = 3.0 m

horizontal distance, X = 2.0 m

The time to drop from the given height;

h = ¹/₂gt²

[tex]t = \sqrt{\frac{2h}{g} }\\\\t = \sqrt{\frac{2*3}{9.8} }\\\\t = 0.783 \ s[/tex]

The horizontal speed traveled by the apple is given by;

vₓ = X / t

vₓ = 2 / 0.783

vₓ = 2.554 m/s

Therefore, the speed the apple must be thrown in order for it to land in the basket is  2.554 m/s.

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