Answer:
47.8 moles of H₂O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2H₂ + O₂ —> 2H₂O
From the balanced equation above,
1 mole of O₂ reacted to produce 2 moles of H₂O
Finally, we shall determine the number of mole of water, H₂O, produced by the reaction of 23.9 moles of O₂. This can be obtained as follow:
From the balanced equation above,
1 mole of O₂ reacted to produce 2 moles of H₂O.
Therefore, 23.9 moles of O₂ will react to produce = 23.9 × 2 = 47.8 moles of H₂O.
Thus, 47.8 moles of H₂O were obtained from the reaction.
Which statement correctly describes a difference between aesexual and sexual reproduction?
Answer:
(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.
Explanation:
This is variation is caused as a result of both gamete production and fertilisation.
why it is necessary to rinse the pipette after washing with water
Answer:Because When you're cleaning your glassware, you use water to rinse it off. If the burette is not completely dry by the time you use it, the remaining traces of water on the inside will make your titrant more dilute and thereby change its concentration.Before a burette is used, it needs to be cleaned. During the cleaning process, usually, water is introduced into the burette. Be the water clean or not, if the burette is then used without rinsing it with the solution that it is going to be filled with, the result of that analytical exercise will not be precise and accurate. The reason is that water residue in the burette would dillute the solution when it's filled in the burette which would make it impossible to determine the exact concentration of the solution moved by the burette. By rinsing and re-rinsing the burette several times with the solution it is going to be filled with, residue water from the cleaning process would be successfully removed from the burette as are other leftover substances from the cleaning process.
hope this helps have a nice night ❤️❤️❤️
Explanation:
How do you name ethers in chemistry?
Answer:
Common names of ethers simply give the names of the two alkyl groups bonded to oxygen and add the word ether. The current practice is to list the alkyl groups in alphabetical order (t-butyl methyl ether), but older names often list the alkyl groups in increasing order of size (methyl t-butyl ether).
Explanation:
Hope it is helpful.......
5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure
water?
Answer:
2.8 m
Explanation:
From the question given above, the following data were obtained:
Number of mole KBr = 0.210 mole
Mass of water = 0.075 kg
Molality of KBr =?
Molality is simply defined as the mole of solute per unit kg of water. Mathematically, it can be expressed as follow:
Molality = mole of solute / Kg of water.
With the above formula, we can obtain the molality of the KBr solution. This can be obtained as follow:
Number of mole KBr = 0.210 mole
Mass of water = 0.075 kg
Molality of KBr =?
Molality = mole of solute / Kg of water.
Molality = 0.210 / 0.075
Molality = 2.8 m
Therefore, the molality of the KBr solution is 2.8 m.
Some advocates of anabolic steroid use report that testicular atrophy associated with use of trenbolone can be alleviated if users also inject themselves with human chorionic gonadotropin, a hormone similar in structure and function to LH and FSH. Please explain how this treatment might work.
Answer:
Human chorionic gonadotropin (HCG) injections are much safer to use with some mild side effects to treat issues of testicular atrophy. Human chorionic gonadotropin (HCG) injections would increase blood flow and enable the testes' produce testosterone, reduce the shrinkage of the testicles and it also aids in the production of sperm cells which has been initially impaired due to testicular atrophy.
Explanation:
Anabolic steroid is a drug that plays the role of testosterone.
Testicular atrophy is the shrinkage of the testicles caused by old age or infections. Once it occurs, it lowers the production of testosterone and sperm cells.
Trenbolone increases muscle building, aids lean fat deposition, reduces the production of testosterone, and could also lead to testicular atrophy.
Which of the following is a true statement?
Often, fossil remains of a large complex animal are complete.
Often, fossil remains of a small simple animal are complete.
Often, fossil remains of a large complex animal are incomplete.
Often, fossil remains of a small simple animal are incomplete.
Answer:
i think its C
Explanation:
what do liquid methane and liquid water have in common
Answer:
methane on the other hand is made of one carbon atom and 4 hydrogen atoms. like water, the bonds are covalent.
Liquid methane and Liquid water are both covalent compounds, thus, they both have covalent bonds in common.
What is methane?Methane is a covalent compound which exists as a gas at room temperature.
Methane is composed of four hydrogen atoms and a carbon atom linked together by covalent bonds.
What is water?Water is a covalent compound which exists as a liquid at room temperature.
Water is composed of two atoms of hydrogen and one atom of oxygen linked together by covalent bonds.
What do liquid methane and Liquid water have in common?Since both liquid water and liquid methane are covalent compounds, they both have covalent bonds in common.
Therefore, liquid methane and liquid water have covalent bonds in common.
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PLEASE HELP! Will mark Brainly if correct!
Answer:
6.591
explanation
mass of weight is 1.092 , and mass of weight boat and sample = 7.683
mass of the solid sample= (mass of weight boat and sample) - (weight of the boat) = (1.092-7683) = 6.591 g
hence, the mass of the solid sample is 6.591 g
a hypothesis is tested by ___.
a. proposing a theory
b. conducting an experiment
c. making further observations
d. talking with other scientists
Answer:
A.
Explanation:
because a theory is like a prediction and a prediction is like a hypothesis.
Help me with this one please!
Answer:
sorry i dont know
Explanation:
A sample of metal has a mass of 16.12 g, and a volume of 4.87 mL. What is the density of this metal?
Answer:
3.31 g/cm³
Explanation:
1000cm³ = 1L
4.87mL = 4.87 × 10^-3 × 1000 = 4.87 cm³
density = mass/volume = 16.12/4.87 = 3.31 g/cm³
Difference between n-propyl and isopropyl radicals.
Answer:
Isopropyl has the specific orientation of being attached to a central carbon atom with two CH3 molecules attached (so in IUPAC naming it can become dimethylethyl), whereas propyl is three carbons all attached in a line branching off the main carbon chain, so it's two CH2 molecules and one CH3 molecule.
Explanation:
n-propane are longer chain hydrocarbon whereas isopropane is branched hydrocarbon. Isopropyl radical is more stable than n-propyl radical.
What are radicals ?Radicals are reaction intermediates containing one unpaired electron. They are highly reactive species . The stability of radicals depends on the structure and reaction condition.
n -propyl radical is CH₃-CH₂-CH₂·
Isopropyl radical is written as CH₃-CH·-CH₃
The isopropyl group contains a branch in the second carbon and its makes the central carbon with secondary structure.
The stability of tertiary radicals is greater than secondary which is greater than primary. Therefore, isopropyl radical is more stable than n -propyl radical.
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Why is solubility critical when fighting a hydrocarbon fire?
Answer:
Unlike other extinguishing agents - water, dry chemical, CO2, etc., a stable aqueous foam can extinguish a flammable or combustible liquid fire by the combined mechanisms of cooling, separating the flame/ignition source from the product surface, suppressing vapors and smothering. It can also secure for extended periods of time against reflash or reignition. Water, if used on a standard hydrocarbon fuel, is heavier than most of those liquids and if applied directly to the fuel surface, will sink to the bottom having little or no effect on extinguishment or vapor suppression. If the liquid fuel heats above 212ºF, the water may boil below the fuel surface throwing the fuel out of the contained area and spreading the fire. For this reason, foam is the primary fire-extinguishing agent for all potential hazards or areas where flammable liquids are transported, processed, stored or used as an energy source.
this is what I found, hope it helps
In contrast to other extinguishing agents such as water, dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling, separating the flame source from the product surface, suppressing vapors, and smothering.
What is solubility ?The term solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.
It can also protect against ref lash or reignition for extended periods of time. Water is heavier than most liquids when used on a standard hydrocarbon fuel and will sink to the bottom if applied directly to the fuel surface, having little or no effect on extinguishment or vapor suppression.
If the liquid fuel heats above 212°F, water may boil beneath the fuel surface, releasing the fuel and spreading the fire.
Thus, dry chemical, CO2, and so on, a stable aqueous foam can extinguish a flammable or combustible liquid fire through a combination of cooling.
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What is a number at the bottom right of an element in a chemical equation called?
Answer:an element in a chemical equation is called a subscript.
Explanation:
it represents the the number of atoms of that element present in the compound. hope this helps have a great day yall
The number at the bottom right of an element in a chemical equation is called a subscript.
Subscripts represent the number of atoms of that particular element in a molecule or formula unit. They indicate the ratio of atoms or ions present in a compound. Subscripts are written in a smaller font size and appear slightly below the element's symbol.
For example:
In the chemical compound water [tex](H_2O)[/tex],the subscript '2' indicates that there are two atoms of hydrogen (H) bonded to one atom of oxygen (O). The subscript specifies the ratio of elements in the compound, indicating that there are two hydrogen atoms for every one oxygen atom in water.
Therefore, the term subscript refers to the number on the right of an element in a chemical equation.
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Which of the following best describe gas particles?
SELECT ALL THAT APPLY
A.) moving randomly
B.) collide with each other
C.) move slow
D.) High kinetic energy
E.) moving orderly
Answer:
A, B and D
Explanation:
Gas particles move randmly at high speed, colliding with each other
polycondensation reaction takes place between 1.2 moles of a dicarboxylic acid, 0.4 moles of glycerol (a triol) and 0.6 moles of ethylene glycol (a diol). A.Calculate the critical extents of reaction for gelation using (i) the statistical theory of Flory and (ii) the Carothers theory.B.Comment on the observation that the measured value of the critical extent of reaction is 0.866.
Answer:
(a). (I). 0.816; 0.816
(ii). 0.917.
(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.
Explanation:
So, without mincing words let's get straight into the solution to the question above.
(a). Using the (i) statistical theory of Flory to Determine the critical extent of reaction gelation, one has to make use of the two equations given below;
P(1) = [ v + vb ( n - 2)^-1/2 ------------------(1).
P(2) = v^1/2 [ 1 + b ( n - 2)^-1/2 ----------(2).
The value for v = 1.2 + 1.2/ 1.2 × 2 = 1.
The value of b = (1.2 + 1.2)/ 1.2 = 0.5.
Thus, putting the values into the equation (1) and (2) above gives;
NB: n = 3.
P(1) = [ 1 + 1 × 0.5 ( 3 - 2)^-1/2 = 0.816.
P(2) = 1^1/2 [ 1 + 0.5 ( 3 - 2)^-1/2 = 0.816.
Using the (ii) carother's theory to Determine the critical extent of reaction gelation.
We have the following values for glycerol: k = 0.4, n = 3.
For ethylene glycol; k = 0.6, n = 2.
Therefore, the critical extent of reaction gelation =2/[ (0.6 × 2) + (0.4 × 3) + (1.2 × 2)/ (0.6 + 0.4 + 1.2)] = 2/ 2.18 = 0.917
(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.
How to frick a chicken...
Answer:uhhhhh should I be concerned
Explanation:
Answer:
hmmm o_O Maybe you... shouldnt
As ice cream melts, the particles in it will ____
which causes it to _____ thermal energy.
a. Speed up, lose
b. Speed up, gain
c. Slow down, lose
d. Slow down, gain
Answer:
a. Speed up, lose
Explanation:
#CARRYONLEARNING
Answer:
b. speed up, gain
Explanation:
The Rock Cycle moves in a specific order. True or
False
Answer:
it is false
Explanation:
it goes in different ways not in order
Is CaO binary or polyatomic?
Answer:
It is going to be binary
Explanation:
PLEASE HELP
How should this combustion reaction be balanced?
C5H3 + 02 → CO2 + H20
A. C5Hg + 502 → 5C02 + H20
B. C5Hg + 702 → 5C02 + 4H20
O C. C5H3 + 3.502 → 5C02 + 8H20
D. C5Hg + 302 → CO2 + 4H20
Answer:
B
Explanation:
All elements on both sides of the equation have the same amount of moles
Given a sample of poly[ethylene-stat-(vinyl acetate)] A.Calculate the mean repeat unit molar mass for a sample of poly[ethylene-stat-(vinyl acetate)] that comprises 12.9 wt% vinyl acetate repeat units.B.Given that its number-average molar mass is 39,870 g/mol, calculate the number-average degree of polymerization of the copolymer.
Answer:
a) The mean repeat unit molar mass for PEVA is 30.72 g/mol
b) degree of polymerization of the copolymer is 1300
Explanation:
Given that;
the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.
Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.
now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;
the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively
so
moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate
moles of vinyl acetate = 12.9 g / 86.09 g/mol
moles of vinyl acetate = 0.1498 mol
moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene
moles of Ethylene = 87.1 g / 28.05 d/mol
moles of Ethylene = 3.1052 mol
Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol
Next we calculate the mole percent;
mole percent of vinyl acetate [tex]X_{V}[/tex] = moles of vinyl acetate / total moles
[tex]X_{V}[/tex] = (0.1498 mol / 3.255 mol) × 100
[tex]X_{V}[/tex] = 4.6%
mole percent of Ethylene [tex]X_{E}[/tex] = moles of Ethylene / total moles
[tex]X_{E}[/tex] = (3.1052 mol / 3.255 mol) × 100
[tex]X_{E}[/tex] = 95.397% ≈ 95.4%
we know that, mean repeat unit molar mass for a sample = ∑[tex]X_{i}[/tex][tex]M_{i}[/tex]
where [tex]X_{i}[/tex] is the fraction ratio and [tex]M_{i}[/tex] is the molecular weight
so or the PEVA
mean repeat unit molar mass M = ( [tex]X_{V}[/tex][tex]M_{V}[/tex]) + ( [tex]X_{E}[/tex][tex]M_{E}[/tex])
so we substitute
M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )
M = 3.96014 + 26.7597
M = 30.72 g/mol
Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol
b)
Degree of polymerization
[tex]DP_{n}[/tex] = [tex]\frac{M_{n} }{M}[/tex]
where [tex]M_{n}[/tex] is the number average molecular weight ( 39,870 g/mol )
so we substitute
[tex]DP_{n}[/tex] = 39,870 g/mol / 30.72 g/mol
[tex]DP_{n}[/tex] = 1297.85 ≈ 1300 { 3 significance figure }
Therefore, degree of polymerization of the copolymer is 1300
An astronomer observes an asteroid in the solar system. He notes that the asteroid is three times farther from the Sun than Earth is.
How far away from the Sun is the asteroid in astronomical units?
1 AU
2 AU
3 AU
4 AU
helpppppppp
Answer:
3 AU
Explanation:
The distance from the Earth to the Sun is known as 1 AU, or 1 Astronomical Unit. If an asteroid is three times this distance, it is 3 AU away.
Refer to the map of "The Major North American Land Biomes" to answer the question.
Animals of the Deciduous Forest Biome may be found:
in Canada
in Texas
in Mexico
east of the Mississippi River
Answer:
all i can help you with is one of them is Canada. If im
wrong i am sorry.
Explanation:Refer to the map of "The Major North American Land Biomes" to answer the question.
Answer:
is Canada and Texas
good luck and hope it helps
write the subshell electron configuration (i.s. 1s2 2s2, ect.) for S16 atom
Answer:
1s22s22p63s23p4.How many mol of C3H8 are consumed when 3 mol of CO2 are produced ?
Answer:
1 mol C₃H₈
Explanation:
Step 1: Write the balanced equation for the combustion of C₃H₈
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₃H₈ to CO₂ is 1:3.
Step 3: Calculate the moles of C₃H₈ consumed when 3 moles of CO₂ are produced
We will use the established molar ratio.
3 mol CO₂ × 1 mol C₃H₈/3 mol CO₂ = 1 mol C₃H₈
What would be the wavelength of light that has a frequency of 3 X
10-4 Hz in a vacuum?
Answer:
[tex]\lambda=10^{12}\ m[/tex]
Explanation:
Given that,
The frequency of the light, [tex]f=3\times 10^{-4}\ Hz[/tex]
We need to find the wavelength of the light.
The relation between frequency, wavelength and the speed of light is given by :
[tex]c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3\times 10^{-4}}\\\\\lambda=10^{12}\ m[/tex]
So, the wavelength of the light is [tex]10^{12}\ m[/tex].
The wavelength of light will be "[tex]10^{12} \ m[/tex]"
Given:
[tex]f = 3\times 10^{-4} \ Hz[/tex][tex]c = 3\times 10^8[/tex]By using the relation,
→ [tex]\lambda = \frac{c}{f}[/tex]
By putting the values, we get
→ [tex]= \frac{3\times 10^8}{3\times 10^{-4}}[/tex]
→ [tex]= 10^{12} \ m[/tex]
Thus the above response is right.
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Which shows a monosaccharide?
Cuz D is cyclo-thingy molecule and its a sugar
(i think A is fatty acid or other molecules and C is hydrocarbon. B dont have oxygen)
Monosaccharides are the group of carbohydrates that are the simplest form of sugar. Option D. galactose is a monosaccharide sugar.
What are monosachharides?Monosaccharides are simple sugars and are the fundamental unit of carbohydrates. The general structural formula for the monosaccharides is [tex]\rm (CH_{2}O)_{n}.[/tex]
The structure of the monosaccharide sugar contains carbon, oxygen, and hydrogen molecules in their structure. Option A. is a fatty acid molecule, and option B. lacks an oxygen molecule, and hence they are not monosaccharides.
Option C. is a hydrocarbon chain that lacks oxygen molecules and option D. is a galactose that is a simple sugar with six carbon atom rings.
Therefore, option D. galactose is the monosaccharide.
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A 5.41 g sample of carbon reacts with hydrogen to form 6.32 g of an organic compound. What is the empirical formula of the organic compound?
Answer:
CH₂
Explanation:
From the question given above, the following data were obtained:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Empirical formula =?
Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:
Mass of Carbon (C) = 5.41 g
Mass of compound = 6.32 g
Mass of Hydrogen (H) =?
Mass of H = mass of compound – mass of C
Mass of H = 6.32 – 5.41
Mass of H = 0.91 g
Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:
Mass of C = 5.41 g
Mass of H = 0.91 g
Divide by their molar mass
C = 5.41 / 12 = 0.451
H = 0.91 / 1 = 0.91
Divide by the smallest
C = 0.451 / 0.451 = 1
H = 0.91 / 0.451 = 2
Thus, the empirical formula for the compound is CH₂
PLEASE HELP ME! THANK YOU IF YOU DO!!! ^^
Answer:
oceanic formation is the right answer.
Explanation:
this os becoz they slide a past each other and do not rub against each other