Answer:
Follows are the code to the given question:
#include <iostream>//header file
using namespace std;
int main() //main method
{
int nums[20];//defining an array
int n,i,k;//defining integer variables
cout<<"Enter total number you want to insert: ";//print message
cin>>n;//input value of n
cout << "Enter array numbers: " << endl;//print message
for (i = 0;i<n;i++) //defining for loop for input values from user-end
{
cin >> nums[i];//input values
}
for (i = 0; i < n;i++) //defining for loop for count array values
{
for (k =i+1;k<n;k++)//defining for loop for arrange value in ascending order
{
if (nums[i] > nums[k])//checking first and second value
{
int t = nums[i];//defining integer variable that hold first element value in t
nums[i] = nums[k];//holding second element value in first element
nums[k] = t;//assign value in t
}
}
}
cout<<"Two smallest number in list are:";//print message
for (i = 0; i <2; ++i)//defining for loop that prints first two smallest value
cout<<nums[i]<<" ";//print value
return 0;
}
Output:
Enter total number you want to insert: 6
Enter array numbers:
5
10
5
3
21
2
Two smallest number in list are:2 3
Explanation:
In this code, an integer array "nums" is defined, and in the next step multiple integer variable is defined, that uses the for loop input value from the user-end, and in the next step, another two for loop is declared, that uses if block to arrange value into the ascending order at which it stores two smallest value in first and second position in the array element, and in the next step, it uses another for loop to print its element value.
Please read this lab exercise thoroughly, before attempting to write the program.
Write a program that reads the pairs of group number and student count from the text file (user must enter name of file) and:
Displays the number of groups in the file (5 %)
Displays the number of even and odd student count (5%)
Displays the sum of the even student count and the sum of the odd student count as well as the sum of all the student count (5%)
Displays the group numbers of the largest student count and the smallest student count (5 %)
Computes the average of the largest and smallest student count (10 %)
Compute the sum of ALL the digits in the largest student count (i.e. 952 – Sum is 9+5+2 = 16) (15 %)
Assume the contents of the file are as follows but that the pairs of data can change later:
1 25
2 123
3 475
4 61
5 77
6 910
7 234
8 138
9 134
10 95
11 674
12 345
13 31
14 211
15 952
16 873
17 22
18 7
19 876
20 347
21 450
The following is a sample output: User input in red
What is name of the input file? integers.dat
The number of groups in the file is 21
There are 12 odd student count and 9 even student count
The sum of the odd student count is 2645
The sum of the even student count is 4390
The sum of all the student count is 7035
The group number of the largest student count is 15
The group number of the smallest student count is 18
The average of 952 and 7 is 479.5
The sum of all the digits in the largest student count is 16
NOTE:
Use two decimal point precision for the average
To check your code, adjust one of the student count in the file, recompile your code and run again (suggest changing the largest or smallest student count )
Even though there are 21 pairs of numbers in the file, the program should NOT presume there will always be 21 pairs of numbers. In other words, you should not solve this problem by declaring 21 pairs of values. If I choose to use another integers.dat file other than the one provided with the assignment, your program should still work correctly with that file as well. All you can assume is that a series of integers will be read in from the file. Therefore, you need to implement a solution that uses the repetition control structures (for, while, do…while) in the reading and processing of these values to produce your output.
Answer:
filename = input("Enter input file? ")
with open(filename, 'r') as data:
num_groups = []
num_counts = []
for line in data:
cols = line.split()
num_groups.append(int(cols[0]))
num_counts.append(int(cols[1]))
print("The number of num_groups in the file is "+str(len(num_groups)))
c_even = 0; c_odd = 0; s_odd = 0; s_even = 0
for i in num_counts:
if i%2 == 0:
c_even=c_even+1
s_even = s_even + i
else:
c_odd=c_odd+1
s_odd = s_odd + i
print("There are "+str(c_odd)+" odd student and "+str(c_even)+" even student")
print("The sum of odd student is "+str(s_odd))
print("The sum of even student is "+str(s_even))
print("The sum of all student is "+str(s_even+s_odd))
max_count = num_groups[num_counts.index(max(num_counts))]
print("The group number of the largest student is "+str(max_count))
min_count = num_groups[num_counts.index(min(num_counts))]
print("The group number of the smallest student is "+str(min_count))
print("The average of "+str(max(num_counts))+" and "+str(min(num_counts))+" is:",end=" ")
print("%.2f" % ((max(num_counts)+min(num_counts))*0.5))
bigkount = str(max(num_counts))
bigsum = 0
for i in range(len(bigkount)):
bigsum += int(bigkount[i])
print("The sum of all the digits in the largest student is: "+str(bigsum))
Explanation:
The program was written in Python.
Because of the length, I added an attachment where I used comments to explain the lines of the code