how many moles of Ag are in 43.1 grams of Ag2O






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Answer:

they are all right

Explanation:

Answer:

(B. Plants and meat)

Explanation:

Answer:

owa owa

Explanation:

owa owa owa owa owa ow

Answer:

Mount Etna I believe

Explanation:

2900 g Au

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 14.7 mol Au

[Solve] g Au

Step 2: Identify Conversion

[PT] Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

2895.46 g Au ≈ 2900 g Au

Answer:

The final temperature of the gas would need to be approximately 158.4 K

Explanation:

The details of the sample of nitrogen gas are;

The initial temperature of the nitrogen gas, T₁ = 22.7°C = 295.85 K

The initial volume occupied by the gas, V₁ = 12.2 L

The initial pressure of the gas, P₁ = 150.4 kPa

The final volume of the gas, V₂ = 9.7 L

The final pressure of the gas, P₂ = 101.3 kPa

Let 'T₂', represent the final temperature of the gas, by the ideal gas equation, we have;

[tex]\dfrac{P_1 \times V_1}{T_1} = \dfrac{P_2 \times V_2}{T_2}[/tex]

[tex]\therefore \ T_2 = \dfrac{P_2 \times V_2 \times T_1 }{P_1 \times V_1}[/tex]

Plugging in the values gives;

[tex]\therefore \ T_2 = \dfrac{101.3 \, kPa \times 9.7 \ L \times 295.85 K}{150.4 \ kPa \times 12.2 \ L} \approx 158.4327959 \ K[/tex]

The final temperature of the gas, T₂ ≈ 158.4 K

Answer:

vuvbuvivovoivuighhghgig

Answer:

Increases, decreases

Explanation:

Answer:

1 in. =2.54 cm

3*(10^-4)*2.54=7.62*10^-4

Explanation:

Answer:

A) actual yield

Explanation:

Theoretical yield is the amount of product expected based on the stoichiomety.

Percent yield is the actual yield over the theoretical yield.

Answer: 12.1 ml of ethanol is needed

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} CO_2=\frac{18.2g}{44g/mol}=0.414moles[/tex]  

[tex]C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)[/tex]  

According to stoichiometry :

2 moles of [tex]CO_2[/tex] is produced by = 1 mole of [tex]C_2H_5OH[/tex]

Thus 0.414 moles of [tex]CO_2[/tex] is produced by=[tex]\frac{1}{2}\times 0.414=0.207moles[/tex]  of [tex]C_2H_5OH[/tex]

 Mass of [tex]C_2H_5OH=moles\times {\text {Molar mass}}=0.207moles\times 46.07g/mol=9.54g[/tex]

Volume of ethanol = [tex]\frac{\text {Mass of ethanol}}{\text {density of ethanol}}=\frac{9.54g}{0.789g/ml}=12.1ml[/tex]

12.1 ml of ethanol is needed to produce 18.2 g of [tex]CO_2[/tex]

Answer:

Chemistry is the scientific discipline involved with elements and compounds composed of atoms, molecules and ions their composition, structure, properties, behavior and the changes they undergo during a reaction with other substances.

Explanation:

hope thats helps

Answer: 2 copper, 2 Sulfur, 1 Magnesium, 2 Chlorine.

Explanation:

Wasn't sure if this was what you were looking for, but thought if you got the left side that was all you needed?

Answer: The equilibrium constant, [tex]K_c[/tex], for the reaction is 0.061.

Explanation:

Initial concentration of [tex]PCl_5[/tex]  = [tex]\frac{\text {given mass}}{\text {Molar mass}\times Volume in L}}=\frac{12.3g}{208.2g/mol\times 1.50L}=0.039M[/tex]  

Equilibrium concentration of [tex]PCl_5[/tex] = [tex]\frac{31.8}{100}\times 0.039=0.012M[/tex]  

The given balanced equilibrium reaction is,

                            [tex]PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)[/tex]

Initial conc.              0.039 M                0 M        0 M

At eqm. conc.     (0.039-x) M              (x) M   (x) M

Given : (0.039-x) = 0.012

x = 0.027

The expression for equilibrium constant for this reaction will be,

[tex]K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}[/tex]

Now put all the given values in this expression, we get :

[tex]K_c=\frac{0.027\times 0.027}{0.012}=0.061[/tex]

The equilibrium constant, [tex]K_c[/tex], for the reaction is 0.061.

Answer:

NaO2

Explanation:

Solutions are mixtures that are homogenous and comprise solutes and solvents. Methyl alcohol will react with solid sodium chloride to form a solution. Thus, option D is correct.

The solutions are the mixtures of the solute and the solvent. The solute and the solvent are capable of forming a solution only if they both are either polar or nonpolar.

Here, chlorine is a gas, and sodium superoxide is a solid that cannot react with solid sodium chloride to make a solution and hence is eliminated. As sodium chloride is polar it cannot react with nonpolar carbon tetrachloride.

Methyl alcohol is polar and so is sodium chloride. They will react together as,

CH₃OH + NaCl → CH₃Cl + NaOH

Therefore, option D. CH₃OH will react to form a solution.

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Answer:

22.414 dm3

Explanation:

this is the answer

Answer:

i think the answer is A....

Explanation:

Igneous rocks (from the Latin word for fire) form when hot, molten rock crystallizes and solidifies. The melt originates deep within the Earth near active plate boundaries or hot spots, then rises toward the surface.

Answer:

Can you send an image of the question, please?

Explanation:

Answer:

2.10 moles of O₂

Explanation:

2 H₂O₂ (l) → 2H₂O(l)  + O₂(g)

In this reaction we say, that 2 moles of hydrogen peroxide can decompose to 2 moles of water and 1 mol of oyxgen.

So ratio is 2:1, according to stoichiometry.

If we apply a rule of three;

2 moles of hydrogen peroxide can decompose to 1 mol of oxygen

Then 4.20 moles of hydrogen peroxide may produced (4.20 . 1)/2 =

2.10 moles of O₂

Answer:

a

Explanation:

the line is going down

To determine the highest angle the pendulum will swing to after the impact, we can apply the principle of conservation of momentum. Initially, the total momentum is zero since the pendulum is at rest.

After the impact, the total momentum remains zero because the block and embedded projectile move together as a single system.First, let's convert the weight units to a common system. The 5-pound rod is approximately 2.27 kg, and the 10-pound wooden block is around 4.54 kg. The projectile's weight is 0.3 oz, which is about 0.0085 kg.The momentum before the impact is zero, so the momentum after the impact must also be zero. This can be expressed as:(2.27 kg + 4.54 kg + 0.0085 kg) * V_final = 0Solving for V_final gives us V_final ≈ 0 ft/s. Since the velocity is zero after the impact, the pendulum will momentarily stop at its highest point.Therefore, the highest angle the pendulum will swing to after the impact is 0 degrees, or it will come to rest at the vertical position.

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Answer:

5.43×10¯³² J

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.66×10⁴ hm

Energy (E) =?

Next, we shall convert 3.66×10⁴ hm to metre (m). This can be obtained as follow:

1 hm = 100 m

Therefore,

3.66×10⁴ hm = 3.66×10⁴ hm × 100 m / 1 hm

3.66×10⁴ hm = 3.66×10⁶ m

Next, we shall determine the frequency of the frequency of the photon. This can be obtained as follow:

Wavelength (λ) = 3.66×10⁶ m

Velocity (v) = 3×10⁸ m/s

Frequency (f) =?

v = λf

3×10⁸ = 3.66×10⁶ × f

Divide both side by 3.66×10⁶

f = 3×10⁸ / 3.66×10⁶

f = 81.97 Hz

Finally, we shall determine the energy of the photon. This can be obtained as follow:

Frequency (f) = 81.97 Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 81.97

E = 5.43×10¯³² J

Therefore, the energy of the photon is 5.43×10¯³² J

Answer:

Explanation:

3.79 liters in one gallon.

75.0 / 3.79 = 19.79 gallons of gasoline

19.8 x 23.7 = 469 miles per tank

Explanation:

1. It is high in sodium

2. Has low percentage of hardness minerals such as magnesium and calcium.

The water molecule is formed by the covalent bonding between oxygen and hydrogen atoms. Therefore, option C is correct.

Covalent bonding is a type of chemical bonding that involves the sharing of electrons between two atoms. In covalent bonding, the two atoms share a pair of electrons to fill their outermost electron shell and form a stable molecule.

This type of bonding usually occurs between non-metal atoms, which have a high electronegativity and tend to attract electrons strongly. In a covalent bond, the shared electrons are attracted to the positively charged nuclei of both atoms, creating a strong bond.

The strength of the bond depends on the number of shared electrons and the distance between the nuclei. Covalent bonds can be either polar or nonpolar, depending on the electronegativity difference between the two atoms.

In water the bond is formed between oxygen atom and two hydrogen atoms. Hence, C is correct.

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0.434 mol F

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 8.25 g F

[Solve] moles F

Step 2: Identify Conversions

[PT] Molar Mass of F - 19.00 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.434211 mol F ≈ 0.434 mol F

Answer:  https://study.com/academy/answer/complete-the-sentence-concerning-the-energy-level-diagram-for-the-hydrogen-atom-the-equation-relating-the-energy-separation-between-levels-in-the-h-atom-to-the-number-of-the-level-n-is-called-the-equation.html#:~:text=Answer%20and%20Explanation%3A,is%20called%20the%20Bohr's%20equation.

Bohr's equation

Explanation:  https://study.com/academy/answer/complete-the-sentence-concerning-the-energy-level-diagram-for-the-hydrogen-atom-the-equation-relating-the-energy-separation-between-levels-in-the-h-atom-to-the-number-of-the-level-n-is-called-the-equation.html

Answer and Explanation: The equation relating the energy separation between levels in the H atom to the number of the level (n) is called the Bohr's equation.

Answer:

Al₂O₃ is the limiting reactant

Explanation:

The limiting reagent or limiting reactant in a chemical reaction is a reactant that is totally used up when the chemical reaction is completed and subsequently, the reaction stops as no more products can be formed from the excess reactant.

Equation of the the reaction reaction is given below:

3 Mg (s) + Al₂O₃ (s) ----> 3 MgO (s) + 2 Al (s)

Mole ratio of reactants from the equation shows that 3 moles of magnesium metal is required to react with 1 mole of aluminum oxide.

Molar mass of magnesium metal, Mg = 24 g/mol

Molar mass of aluminum oxide, Al₂O₃ = (27 * 2 + 16 * 3) = 102 g/mol

from the equation of reaction,  (24 * 3 g) 72 g of Mg reacts with 102 g of Al₂O₃

Given masses of reactants:

144 g of Mg = 144/24 6 moles of Mg

150 g of Al₂O₃ = 1.47 moles of Al₂O₃

Mole ratio of Mg to Al₂O₃ = 6/1.47 = 4.08 : 1

Therefore, magnesium is excess reactant while Al₂O₃ is the limiting reactant