Balance these equations

Answer:

The volume of the gas is 89.60

Explanation:

When converting from moles to volume, you would multiply by 22.4 because 1 mole equals 22.4 liters at STP.

So...

4.0 moles * 22.4 liters =

89.60 liters

Answer:

[tex]\boxed {\boxed {\sf 89.6 \ liters}}[/tex]

Explanation:

At STP (standard temperature and pressure), all gases have a volume of 22.4 liters per mole.

[tex]\frac {22.4 \ L }{1 \ mol }[/tex]

Multiply by the given number of moles, 4.0

[tex]4.0 \ mol *\frac {22.4 \ L }{1 \ mol }[/tex]

The moles will cancel out. The 1 in the denominator can be ignored, so this becomes a simple multiplication problem.

[tex]4.0 * {22.4 \ L }=89.6 \ L[/tex]

4.0 moles of a gas at STP have a volume of 89.6 liters.

Answer:

Fractional Distillation could be used to:

Fractional Distillation is used to obtain one substance from a mixture. It depends on the boiling points of the substances.

Answer:

Examples of complex compound include potassium ferrocyanide K4[Fe(CN)6] and potassium ferricyanide K3[Fe(CN)6]. Other examples include pentaamine chloro cobalt(III) chloride [Co(NH)5Cl]Cl2 and dichlorobis platinum(IV) nitrate [Pt(en)2Cl2](NO3)2.

Answer:

yer

Explanation:

Answer:

glucose

Explanation:

plants use sunlight water and the gases in the air to make glucose which is aform of sugar

Answer:631 g

Explanation: bc i did the math

630.581 grams of soda ash would be needed to produce 1,000 g of sodium bicarbonate.

Moles can be related to the mass or weight of any substance as follow:

n = W/M, where

W = given mass

M = molar mass

Given balanced chemical equation for the formation of sodium bicarbonate is:

Na₂CO₃ + CO₂ + H₂O → 2NaHCO₃

From the stoichiometry of the reaction, it is clear that:

1 mole of Na₂CO₃ is required = to form 2 moles of NaHCO₃

Or 1/2 mole of Na₂CO₃ is required = to form 1 moles of NaHCO₃

Moles of NaHCO₃ be calculated by using the above formula as:

n = 1,000g (given) / 84.007g/mole = 11.90 moles

So, moles of Na₂CO₃ required to form 11.90 moles of NaHCO₃ = 11.90×1/2 = 5.95 moles

Now we convert the mole of Na₂CO₃ to grams by using the mole formula:

W = 5.95mole × 105.98g/mole = 630.581 grams.

Hence, 630.581 grams of soda ash would be needed.

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Answer:

W and X

Explanation:

isotopes : are masses of atoms with the same number of proton and electron but different neutron .

W and X have the same number of protons and different number of neutrons.

Answer:

when the pH increases suddenly in the flask

Explanation:

I think it's right. :)

When the pH increases suddenly in the flask at that point is a base no longer added during a titration.

Titration is a typical quantitative chemical analysis procedure used in laboratories to quantify the concentration of a specified analyte. The titrant or titrator is a reagent that is produced as a standard solution with a known concentration as well as volume.

The pH scale, which originally stood for "potential of hydrogen," is used to describe the acidity as well as basicity of aqueous solutions. The pH of acidic solutions is lower than that of basic as well as alkaline solutions.

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Answer:

The given reaction in your problem is the ionic equation for an acid (carbonic acid) reacting with a base (sodium hydroxide). All components of the reaction are then written in ionic form except for reactant weak electrolytes and the driving force product compound of the reaction (H2O). See following explanation.

Explanation:

Metathesis Rxn: molecular equation of rxn      

H₂CO₃(aq) + 2NaOH(aq) => Na₂CO₃(aq) + 2H₂O(l)

Ionic Equation: shows all components of the reaction

H₂CO₃(aq) + 2Na⁺(aq) + 2OH⁻(aq) => 2Na⁺(aq) + CO₃²⁻(aq) + 2H₂O(l)

H₂CO₃(aq)  wk. electrolyte and H₂O(l) driving force compound are not shown ionized in ionic equation. Only strong electrolytes that ionize 100%; i.e., salts and strong acids and bases.

Net Ionic Equation: shows only the reactive components without the spectator ions (nonreactive components), in this case, the Na⁺(aq) ions.

H₂CO₃(aq) + 2OH⁻(aq) =>  CO₃²⁻(aq)  + 2H₂O(l)

Answer:

hope this helps

Explanation:

1M NaCl solution is 58.5 g/1000 ml , where molecular wt of NaCl being 58.5 grams , so 29.2 g of NaCl in 1000 ml of water will be equal to : 29.2g /58.5g = 0.499145299 M , so 29.2 g NaCl dissolved in 100 ml would correspond to , 0.499145299 M X 1000 ml/100 ml = 4.99145 M or about 4.99 M

Answer:

..... yep

Explanation:

tep no yep no hyshshshss

motion results in the kinetic energy of an object

Answer:

a

Explanation:

its a lol

I am currently learning this and I would say Suspensions!

Hope this helps :)

Explanation:

The balanced equation of the reaction is given as;

Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)

1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?

From the reaction;

2 mol of HBr produces 1 mol of  MgBr2

Converting to masses using;

Mass = Number of moles * Molar mass

Molar mass of HBr = 80.91 g/mol

Molar mass of MgBr2 = 184.113 g/mol

This means;

(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2

18.3g would produce x

161.82 = 184.113

18.3 = x

x = (184.113 * 18.3 ) / 161.82 = 20.8 g

2. How many moles of H2O will be produced from 18.3 grams of HBr?

Converting the mass to mol;

Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol

From the reaction;

2 mol of HBr produces 2 mol of H2O

0.226 mol would produce x

2 =2

0.226 = x

x = 0.226 * 2 / 2 = 0.226 mol

3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?

From the reaction;

2 mol of HBr reacts with 1 mol of Mg(OH)2

18.3g of HBr =  0.226 mol

2 = 1

0.226 = x

x = 0.226 * 1 /2

x = 0.113 mol

Answer:  3.36 L of ammonia gas

Explanation:

The balanced chemical reaction is:

[tex]N_2(g)+3H_2(g)\rightarrow 2NH_3(g)[/tex]  

According to stoichiometry :

3 moles of [tex]H_2[/tex] produce = 2 moles of [tex]NH_3[/tex]

Thus 0.75 moles of [tex]H_2[/tex] will producee=[tex]\frac{2}{3}\times 0.75=0.50moles[/tex]  of [tex]NH_3[/tex]

But as percent yield is 30 %, amount of ammonia produced = [tex]\frac{30}{100}\times 0.50moles=0.15moles[/tex]

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure  = 1 atm

V = Volume  = ?

n = number of moles = 0.15

R = gas constant =[tex]0.0821Latm/Kmol[/tex]

T =temperature =[tex]273K[/tex]

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{0.15\times 0.0820 L atm/K mol\times 273K}{1atm}=3.36L[/tex]

Thus 3.36 L of ammonia gas is obtained by reacting 0.75 moles of hydrogen with excess nitrogen.

3.36 L of ammonia gas.

The balanced chemical reaction is:

[tex]N_2(g) + 3H_2(g)\rightarrow 2NH_3(g)[/tex]

  According to the above reaction:- :

3 moles of [tex]H_2[/tex] produce = 2 moles of [tex]NH_3[/tex]

Thus 0.75 moles of  [tex]H_2[/tex] will produce[tex]\frac{2}{3} \times0.75=0.50\ mol\ NH_3[/tex]  

But as percent yield is 30 %, amount of ammonia produced = [tex]\frac{30}{100} \times0.50\ moles\\\\=0.15\ moles[/tex]

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure  = 1 atm

V = Volume  = ?

n = number of moles = 0.15

R = gas constant =0.0821 Latm\Kmol

T =temperature =273 K

[tex]V=\frac{nRT}{P} \\\\=\frac{0.15\ times0.0820\ Latm\Kmol\times273\ K}{1\ atm} \\\\=3.36\L[/tex]

Hence,  3.36 L of ammonia gas is obtained by reacting 0.75 moles of hydrogen with excess nitrogen.

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Answer:

4Al + 3O₂ —> 2Al₂O₃

The coefficients are: 4, 3, 2

Explanation:

__ Al + __ O₂ —> __ Al₂O₃

The above equation can be balance as illustrated below:

Al + O₂ —> Al₂O₃

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by writing 3 before O₂ and 2 before Al₂O₃ as shown below:

Al + 3O₂ —> 2Al₂O₃

There are 4 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 4 before Al as shown below:

4Al + 3O₂ —> 2Al₂O₃

Now the equation is balanced.

The coefficients are: 4, 3, 2

The periodic table brings order to information about the chemical elements. The chemical elements are arranged in order of increasing atomic number. The horizontal rows are called periods and the vertical columns are called groups. Elements in the same group have similar chemical properties.

Answer:

group 1 - cations charge +1

group 7 - anions  charge -1

Explanation:

Group 1 has one valence electron and will lose one electron to complete the octet.

Group 7 has 7 valence electrons and will accept an electron to complete the octet.

Group 1 elements form cations while group 7  elements form anions as per their electronic configuration.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

double bond

Explanation:

it contains combinations

Explanation:

Removing B from the system

- Decreases the rate of the reaction. Backward reaction (formation of reactants) is favoured.

Crushing A into a powder

- Increases the rate of reaction. This is because of the increased surface area of A.

Warming the system

- Increases the rate of the reaction. Temperature is proportional to rate of reaction.

Adding more A to the system

- Increases the rate of reaction. Forward reaction (formation of products) is favoured.

Putting the system into an ice bath

- Decreases the rate of reaction. Temperature is proportional to rate of reaction.

Decreasing the pressure of the system

- Decreases the rate of the reaction.

Answer:

Precipitates Form

Explanation:

I apologize if I am wrong

Answer:

C6H12O6

Explanation:

I attached the method for solving above.

Answer:

i think b

Explanation: