How many moles of "02" are in a 192g sample of O2? *
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Answer:

the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L  

Explanation:

Given that;

Tank volume v = 3250 liters

wastewater flows into the tank Q = 200 L/min

TCE concentration Co= 25 mg/L

reactor decays TCE at a reaction rate K = 0.20 min-1

mass balance

we know that;

Accumulation = inflow - outflow ± generation

⇒dc/dt = QCo - Qc ± rc.V

now at a steady state; dc/dt = 0

so

0 = QCo - Qc + rcV

where rc = -kc

0 = QCo - Qc - kcV

Qc + kcV = QCo

c(Q + kV) = QCo  

c = QCo / (Q + kV)

so we substitute

c = (200 × 25) / (200 + (0.2×3250))

c = 5000 / 850

c = 5.88 mg/L      

Therefore,  the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L  

Answer:

ruthless, my style as a juvenile

ran with a gang, slanged in the meanwhile

Explanation:

Answer:

relation (but not a function)

Explanation:

c on edge

Answer:

If your asking what golds natural state of matter is it's solid.

Explanation:

Answer:

the answer is soild

Explanation:

i did it on edge :)

Answer:

[tex]V=3.50x10^{-22}L[/tex]

Explanation:

Hello there!

In this case, given the dimensions of the box, we first compute the volume by multiplying each side:

[tex]V=4nm*8.75nm*10nm=350nm^3[/tex]

Next, we apply the following conversion factor in order to obtain the corresponding liters:

[tex]V=350nm^3*(\frac{1m}{10^9nm} )^3*\frac{1000L}{1m^3} \\\\V=350nm^3*\frac{1m^3}{10^{27}nm^3} *\frac{1000L}{1m^3}\\\\V=3.50x10^{-22}L[/tex]

Best regards!

Answer:

C)

Explanation:

Answer:

22 g

Explanation:

Step 1: Write the balanced equation

N₂(g) + 3 H₂(g) ⇒ 2 NH₃(g)

Step 2: Calculate the moles of NH₃ produced from 2.0 moles of H₂

The molar ratio of H₂ to NH₃ is 3:2.

2.0 mol H₂ × 2 mol NH₃/3 mol H₂ = 1.3 mol NH₃

Step 3: Calculate the mass corresponding to 1.3 moles of NH₃

The molar mass of NH₃ is 17.03 g/mol.

1.3 mol × 17.03 g/mol = 22 g

Answer:

its b

Explanation:

just did the test on A P E X

If the isotope models are accurate, One shows 8 neutrons, and one shows 9. Therefore, the correct option is option B.

A chemical element's isotope is one of more than one species of atoms that share the same atomic number, spot on the periodic table, and almost identical chemical activity, but differ in atomic mass and physical characteristics. There are a number of isotopes for each chemical element.

The first step in identifying and labelling an atom is to count the protons within its nucleus. Usually, this nuclear number is denoted by the letter Z. The fact that all atoms possessing the same number of electrons have essentially equal chemical characteristics lends the atomic number its enormous significance. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

Therefore, the correct option is option B. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

To know more about isotope, here:

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Answer:

The representative particle of an ionic compound is the formula unit. A formula unit uses a formula to calculate the basic whole number ratio of the ions in an ionic compound.

Explanation:

HAHAH I'm not sure

Answer:

C₂H₄O

Explanation:

In a compound that contains Cabon, hydrogen and oxygen, the combustion produce CO₂ from the carbon, and H₂O from the hydrogens. Using the mass of the products we can solve the moles of Carbon and hydrogen. The empirical formula is the simplest whole-number of atoms present in a molecule.

Moles CO₂ = Moles C:

11.8g CO₂ * (1mol / 44g) = 0.268 moles CO₂ = 0.268 moles C * (12g/mol) =

3.216g C

Moles H₂O = 1/2 moles H:

4.83g H₂O * (1mol / 18g) = 0.268 moles H₂O * (2 mol H / 1 mol H₂O) =

0.537 mol H * (1g/mol) = 0.537g H

Mass O to find moles O:

5.90g Sample - 3.216g C - 0.537g H = 2.147g O * (1mol / 16g) = 0.134 moles O

Ratio of atoms -Dividing in 0.134 moles-:

C = 0.268mol C / 0.134 mol O = 2

H = 0.537mol H / 0.134 mol O = 4

O = 0.134mol O / 0.134 mol O = 1

Empirical formula is:

Answer:

B should be the answer, and ur low-key valid lol

Explanation:

Answer:

[tex]Y=34.3\%[/tex]

Explanation:

Hello there!

In this case, according to the balanced chemical reaction:

[tex]2Al + Cr_2O_3 \rightarrow Al_2O_3 + 2Cr[/tex]

We notice there is a 1:1 mole ratio between Al2O3 and Cr2O3; thus, the following stoichiometric setup is used to compute the theoretical yield first:

[tex]m_{Al_2O_3 }=23.3gCr_2O_3*\frac{1molCr_2O_3}{151.99gCr_2O_3} *\frac{1molAl_2O_3}{1molCr_2O_3} *\frac{101.96gAl_2O_3}{1molAl_2O_3} \\\\m_{Al_2O_3}=15.6gAl_2O_3[/tex]

Thus, the percent yield turns out:

[tex]Y=\frac{5.35g}{15.6g} *100\%\\\\Y=34.3\%[/tex]

Best regards!

The law of conservation of mass states that, for any isolated system, the mass can neither be created nor be destroyed  

learn more about conservation of mass and energy:

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Answer:

Calcium is more reactive than magnesium because calcium atom is larger than magnesium atom and it has one more energy level. ... Thus Ca is more reactive than Mg.

Answer: Thus 24.0 g of [tex]SO_2[/tex] would be needed.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]      

[tex]\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles[/tex]

[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(l)[/tex]  

According to stoichiometry :

1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]

Thus 0.1875 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.1875=0.375moles[/tex]  of [tex]SO_2[/tex]  

Mass of [tex]SO_2=moles\times {\text {Molar mass}}=0.375moles\times 64g/mol=24.0g[/tex]

Thus 24.0 g of [tex]SO_2[/tex] would be needed to completely react with 6.00 g of [tex]O_2[/tex] such that all reactants could be consumed.

Answer:

NH₃

M = n/V(L)

0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Explanation:

Step 1: Given and required data

Step 2: Calculate the moles (n) of ammonia (solute)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V(L)

n = M × V(L)

n = 2.25 mol/L × 0.375 L = 0.844 mol (Both numbers have 3 significant figures so the result has 3 significant figures as well)

Answer:The rock forms large crystals

Explanation:

Answer:

20000 Mg

Explanation:

Answer:

[tex]V=5.2 mL=0.052L[/tex]

Explanation:

Hello!

In this case, since the chemical reaction between silver nitrate and sodium chloride is:

[tex]AgNO_3(aq)+NaCl(aq)\rightarrow AgCl(s)+NaNO_3(aq)[/tex]

We can see there is a 1:1 mole ratio between each solution; thus, we first compute the moles of each reactant considering their molar masses:

[tex]n_{AgNO_3}=14.77g*\frac{1mol}{169.87g}=0.087molAgNO_3\\\\ n_{NaCl}=0.2631g*\frac{1mol}{58.44}=0.0045molNaCl[/tex]

Now, since the concentration of the silver chloride solution is 0.087 M, we may assume that the concentration of the NaCl solution is the same, so we can compute the volume as shown below:

[tex]V=\frac{n_{NaCl}}{M}=\frac{0.0045mol}{0.087mol/L}\\\\V=0.052L[/tex]

Or:

[tex]V=5.2 mL[/tex]

Best regards!

The volume of solution needed to react with 0.2631 g of NaCl  is 0.052 L.

Volume of the solution will be calculated by using the below formula:

M = n/V, where

M = concentration in terms of molarity

n = no. of moles

V = volume

Given chemical reaction is:

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

First we calculate the moles of given reactants by using the formula:

n = W/M , where

W = given mass

M = molar mass

Moles of AgNO₃ = 14.77g / 169.87g/mole = 0.087 mole

Moles of NaCl = 0.2631g / 58.44g/mole = 0.0045 mole

Concentration of AgNO₃ = 0.087 mole / 1L = 0.087M

From the stoichiometry of the reaction it is clear that mole ration of AgNO₃ & NaCl is 1:1. So, we take the concentration of NaCl is equal to the concentration of AgNO₃ and calculate the volume by using the above formula as:

Volume of NaCl = 0.0045mole / 0.087M = 0.052 L

Hence, 0.052 L is the required volume of NaCl.

To know more about moles, visit the below link:

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Answer:

[tex]m_{Hg}=829.4gHg[/tex]

Explanation:

Hello there!

In this case, considering the Avogadro's number, which helps us to realize that 1 mole of mercury atoms contains 6.022x10²³ atoms and at the same time 1 mole of mercury weights 200.59 g, we obtain:

[tex]m_{Hg}=2.49x10^{24}atoms*\frac{1mol}{6.022x10^{23}atoms} *\frac{200.59g}{1molHg}\\\\m_{Hg}=829.4gHg[/tex]

Best regards!

Answer:

Which infection may have fixes created because of their comprehension of construction and capacity of protein?

Answer:

ions are deflected and the lighter the ions the more the deflection.

Placing magnetic field in the path of the ions cause them to move in a curved path.

Explanation:

This question is all about the way in which mass spectroscopy works. Mass spectroscopy Is one of the techniques in spectroscopy which is used in the identification of chemical compounds.

Mass spectroscopy works based on the principle of ionization. For a mass spectroscopy to start ionization must first occur that is to say this is the first step in the identification of compound in mass spectroscopy.

The following steps are involve in mass spectroscopy;

=> Ionization: the molecules of the sample are first ionized. The ions formed here are positive ions.

=> Acceleration: the ions in step one are accelerated.

=> Deflection: the smaller ions get deflected more than the bigger ions. The magnetic field is used in the deflection of this ions.

=> Detection: the ions are then detected.

Therefore, to answer the question, the ions are deflected and the lighter the ions the more the deflection.

Placing magnetic field in the path of the ions cause them to move in a curved path.

Answer:

Coron, Palawan, El Nido, Palawan, Cebu, Boracay, Siargao.

Explanation:

I hope this helps.

coron,palawan,El nidu, Cebu and boracay are 5 island in Philippines.....

Answer:

The correct answer is - the number of moles of solute per liter of solution.

Explanation:

The molar concentration is also known as molarity which is the amount of concentration of a solute is in a chemical solution is the number of moles of solute per unit volume of solution. It is represented as M and can be calculated by:

M = n/v

Where n is the number of moles of the solute and,

v is the volume of solution (in liters normally)

It is worldwide used measurment for the concentration.

Answer:

Germanium monoxide

hope this helps :)

Answer:

biosphere and lithosphere

Explanation:

The biosphere is described as the zone of life on Earth. It is a sum of all ecosystems. The biosphere is composed of living organisms and non-living factors.

The lithosphere is the outer part of the Earth such that this part is rocky. The lithosphere is made up of the brittle crust.

In general, chemicals enter Ecosystems through the biosphere and lithosphere.

Answer:

The missing information or their role in the discovery of the cell is as follows:

Robert Hooke: He was the first scientist to called cells to tiny box-like cavities he saw in cork and illustrated as cells.

A. Leeuwenhoek: he was a microscopist and microbiologist who used microscopes and observed many other living cells. He called animalcules to these single-cell living organisms later used to prove that cells are the fundamental unit of life.

Schwann and Schleiden:  They presented the theory that suggested that the cells are basic building blocks of all living things.

Virchow: He observed that the cell dividing and come from pre-existing cells.

A (they are experimentally determined exponents)