How many moles are in 9.20x10^20 molecules of water (H2O)?
Please and thank you :)!!!

Answer:

First write the balanced equation for the reaction of HCl with Zn (NOTE: the previous answer did NOT do this and thus obtained an incorrect answer)

Zn + 2HCl ==> ZnCl2 + H2(g)

moles of H2 desired:  PV = nRT

n = PV/RT = (1 atm)(10L)/(0.0821 Latm/Kmol)(298K)

n = 0.409 mole H2 desired

moles Zn needed:

0.409 moles H2 x 1 mole Zn/2 moles HCl = 0.204 moles Zn needed

mass Zn needed = 0.204 moles Zn x 65.4 g/mol = 13.4 g Zn needed (to 3 sig. figs.)

Explanation:people always get this wrong but i got you

Answer:

[tex]T_f=72.5\°C[/tex]

Explanation:

Hello!

In this case, since this a problem in which the cold water is heated by the hot water, we can write:

[tex]Q_{hot}+Q_{cold}=0[/tex]

Thus, by plugging in the mass, specific heat and temperatures, we obtain:

[tex]m_{hot}C_{hot}(T_f-T_{hot})+m_{cold}C_{cold}(T_f-T_{cold})=0[/tex]

Now, we can also write:

[tex]m_{hot}(T_f-T_{hot})+m_{cold}(T_f-T_{cold})=0[/tex]

Then, after applying some algebra, it is possible to obtain:

[tex]T_f=\frac{m_{hot}T_{hot}+m_{cold}T_{cold}}{m_{hot}+m_{cold}}[/tex]

If we plug in, we obtain:

[tex]T_f=\frac{350.0g*95.0\°C+150.0g*20.0\°C}{350.0g+150.0g}[/tex]

[tex]T_f=72.5\°C[/tex]

Best regards!

Answer:

[tex]F=1.92x10^5N[/tex]

Explanation:

Hello!

In this case, since the force exerted by an object with a certain mass an acceleration is:

[tex]F=m*a[/tex]

We can plug in the given mass of 12,000 kg and acceleration of 16 m/s^2 to obtain:

[tex]F=12,000kg*16m/s^2\\\\F=192,000kg*m/s^2\\\\F=1.92x10^5N[/tex]

Best regards!

Answer:

because they react with other gases of atmosphere and pollute the environment

Answer:

I'm pretty sure this is a question about your opinion so there is no wrong answer! Just think about the question and if you were in those shoes. There is no right or wrong answer! :)

Explanation:

Answer:

I think its C I'm sorry if I'm wrong good luck guys!

Explanation:

Answer:

6.25gm

half life is 66hrs 11 days is 24*11 then take that and divide by 66 to find out how many time it will have halved and half 50 by that many times

Explanation:

If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.

Molybdenum-99 follows first-order decay.

First-order decay means that for a population of atoms (e.g. radioactive), molecules, or anything else, a constant fraction/unit time is converted to something else.

The half-life (th) of Mo-99 is 66 h.

We will find its rate constant (k) using the following expression.

k = ln2 / th = ln2 / 66 h = 0.011 h⁻¹

Next, we will convert 11 days to hours, knowing that 1 day = 24 h.

11 d × 24 h/1 d = 264 h

If we start with 50 g of Mo-99, we can calculate the remaining mass after 264 h using the following expression.

[tex][Mo] = [Mo]_0 \times e ^{-k \times t} }\\\\[Mo] = 50g \times e ^{-0.011 h^{-1} \times 264 h} } = 2.7 g[/tex]

where,

If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.

Learn more about first-order decay here: https://brainly.com/question/14478152

Answer:

Answer:

C4H4

Explanation:

92.31% of 52.0 g/mol is 48.0012 g/mol

7.69% of 52.0 g/mol is is 3.9988 g/mol

Carbon has a gram-formula mass of about 12, which goes into 48.0012 about 4 times, so there should be 4 atoms of Carbon

Hydrogen has a gram-formula mass of about 1, which goes into 3.9988 about 4 times, so there should also be 4 atoms of hydrogen

Answer:

speed = distance ÷ times

Answer:

speed is distance divided by time, hope this helps

Have a wonderful day :) thanks for the points

Answer:

When Carbohydrates are burned (decomposed ) they break down into carbon and water.

Explanation:

The formula for glucose sugar is C6H12O6 If the compound is broken down it results in

6C+6H2O six carbon atoms and six water molecules.

An experiment that illustrates this well is to pour concentrated sulfuric acid about 1/3 deep into the volume of graduated sucrose sugar in a beaker about 1/4 full

The sulfuric acid is hydrophilic it will break the sucrose sugar molecule apart. The water will rise as steam above the beaker.

The sugar will turn brown and the a black carbon cone will rise out of the sugar sulfuric acid solution. The carbon cone will rise about the top of the beaker.

This experiment shows that the carbohydrate sugar is made of only Carbon and Water.

Answer:

please refer to the attachment above;)

Answer:

Because it contains Na+ and Cl- ions, Which are conductors of electricity

Explanation:

Answer:

C.Iodine ion

Explanation:

BECAUSE HIS LACK OF IODINE THAT'S WHY HE HAS GOITER

Answer:

Cells are the smallest living unit of an organism

Answer:

all living things living things have blood cells

Explanation:

this is because robert hooke did not make this apart of the theory

Answer:

AN ELECTRON HAS THE SMALLEST MASS!

Answer:

A) electron

good luck, i hope this helps :)

3 ..............................

Answer:

[tex]T_2 =388.50K[/tex]

Explanation:

Given

[tex]p_1 = ??[/tex] -- Initial vapour pressure

[tex]p_2 = 6.50p_1[/tex] --- Final vapour pressure

[tex]T_1 = 355K[/tex] ---- Initial temperature

[tex]T_2 = ??[/tex] --- Final temperature

[tex]\triangle _{vap}H = 64.08kJmol[/tex] --- Enthalpy of vaporization

Required

Calculate T2

To do this, we make use of Clausius-Clapeyron equation.

Which states that:

[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex]

Where:

[tex]R = 8.314 J.K^{-1}mol^{-1}[/tex] --- Universal Gas constant

[tex]\triangle _{vap}H = 64.08kJmol[/tex]

[tex]\triangle _{vap}H = 64080\ kJmol[/tex]

[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex] becomes

[tex]ln(\frac{6.50p_1}{p_1}) = \frac{64080}{8.314}(\frac{1}{355} - \frac{1}{T_2})[/tex]

[tex]ln(\frac{6.50p_1}{p_1}) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]

[tex]ln(6.50) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]

[tex]1.872 = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]

Take LCM

[tex]1.872 = 7707.48(\frac{T_2 - 355}{355T_2})[/tex]

[tex]1.872 = 7707.48*\frac{T_2 - 355}{355T_2}[/tex]

[tex]1.872 = \frac{7707.48*(T_2 - 355)}{355T_2}[/tex]

Cross Multiply

[tex]355T_2*1.872 = 7707.48*(T_2 - 355)[/tex]

[tex]664.56T_2 = 7707.48T_2 - 2736155.4[/tex]

Collect Like Terms

[tex]664.56T_2 - 7707.48T_2 =- 2736155.4[/tex]

[tex]-7042.92T_2 =- 2736155.4[/tex]

Make T2 the subject

[tex]T_2 =\frac{- 2736155.4}{-7042.92}[/tex]

[tex]T_2 =388.497299416[/tex]

[tex]T_2 =388.50K[/tex]

The final temperature is 388.50K

The temperature at which the vapor pressure will be 6.50 times higher than it was at 355K is 389 K

The Clausius-Clapeyron Equation is widely used for the determination of the vapor pressure of another temperature, provided we know the vapor pressure at a certain temperature as well as the heat of vaporization.

Given that:

By using the Clausius-Clayperon Equation:

[tex]\mathbf{In \Big( \dfrac{P_2}{P_1} \Big) = \dfrac{\Delta H_{vap}}{R} \Big (\dfrac{1}{T_1} - \dfrac{1}{T_2} \Big) }[/tex]

[tex]\mathbf{In \Big( \dfrac{6.5P_1}{P_1} \Big) = \dfrac{64.08 \times 10^3 }{8.314} \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]

[tex]\mathbf{In(6.5)=7707.48 \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]

[tex]\mathbf{1.872 =21.71 - \dfrac{7707.48}{T_2} }[/tex]

[tex]\mathbf{\dfrac{7707.48}{T_2} = 21.71- 1.872 }[/tex]

[tex]\mathbf{\dfrac{7707.48}{T_2} = 19.838 }[/tex]

[tex]\mathbf{T_2= \dfrac{7707.48}{19.838} }[/tex]

[tex]\mathbf{{T_2}=388.521 \ K }[/tex]

T₂ ≅ 389 K

Learn more about Clausius-Clayperon equation here:

https://brainly.com/question/1077674?referrer=searchResults

Answer:

8.34

Explanation:

1) how much moles of NH₃ are in the reaction;

2) how much moles of H₂ are in the reaction;

3)  the required mass of the H₂.

all the details are in the attachment; the answer is marked with red colour.

Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.

Note2: the suggested solution is not the shortest one.

Answer:

A spectator ion is an ion that does not take part in the chemical reaction and is found in solution both before and after the reaction. In the above reaction, the sodium ion and the nitrate ion are both spectator ions. The equation can now be written without the spectator ions.

Explanation:

Answer:

have thick fur on feet protecting them from the hot ground; have large, bat-like ears radiate body heat and help keep them cool; have long, thick hair that insulates them during cold nights and protects them from the hot sun during the day; have light coloured fur to reflect sunlight and keep their bodies cools.

Explanation:

I hope this helps!

Answer: Simpe its 1

Explanation:I took that quiz before hope this helps :)

Answer:

101 years

Explanation:

Use the half life equation, where t1/2 is the half life, and k is the rate constant:

t1/2 = 0.693/k

t1/2 = 0.693/0.00683 yr -1

t1/2 = 101 years

Answer:

PV=nRT

STP is 100kPa and 273.15K

PV/RT=n

n=17.3moles

Explanation:

Answer:

Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.

Explanation:

:)

Answer:

Chlorine Ion

Explanation:

The chlorine ion is adding 1 valence electron in order to complete its outer most shell. It has a charge of 1- meaning it is adding an electron.

Answer:

I believe it's D!

Explanation:

B is what is being saved, C is a potential creation of, A is a method.

Answer:

B

B

A

C

Explanation:

3

B. Vanillin as a phenoxide ion (conjugate base)

4

B. Protonation of acetic anhydride

5

A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride

6

C. 1 mmol of vanillin and 10.6 mmol acetic anhydride