Answer:
One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.
Al+hcl=alcl3+H balance
Answer:
Explanation:
Kindly answer the way I have written.
what are the roles of the mucous select two options PLEASE HELP
Answer:
The answer is A and C
Calculate the mass (in g) of solute needed to prepare a solution with the given concentration and volume.
Sea water has a concentration of approximately 0.60 M sodium chloride. How much
sodium chloride is dissolved in 1.00 L of solution?
Coke has a concentration of 0.342 M. What mass of sugar (in g) is dissolved in a 2-L
bottle of coke?
What volume of concentrated nitric acid (15.8 M) is needed to prepare 4.0 L of a 2.0 M solution?
What volume of 9.0 M copper (II) sulfate stock solution is needed to prepare 3.0 L of a 5.0 M
solution?
Answer:
1. 35g NaCl.
2. 234g sugar.
3. 0.506L of concentrated nitric acid are needed.
4. 1.67L of 9.0M copper (II) sulfate are needed
Explanation:
Molarity is defined as the ratio between moles of solute and the volume of the solution.
1. 1.00L * (0.60mol / L) = 0.60 moles NaCl are dissolved
To convert moles to mass we must use its molar mass:
0.60mol NaCl * (58.44g/mol) =
35g NaCl
2. 2L * (0.342mol / L) = 0.684 moles Sugar = moles sucrose
0.684 mol * (342.30g / mol) = 234g sugar
3. 4L of a 2.0M are:
4L * (2.0mol/L) = 8moles
8mol * (1L / 15.8mol) = 0.506L of concentrated nitric acid are needed
4. 3.0L * (5.0 mol / L) = 15.0 moles copper (II) sulfate.
15.0mol * (1L / 9.0mol) = 1.67L of 9.0M copper (II) sulfate are needed
Why does Play-Doh taste salty?
Pls my science teacher wants an answer so pls answer ASAP i need an explaination
Answer:
It's made of salt
Explanation:
The recipe has salt as an ingredient
Answer:
playdoh is literally made of salt. thats why it tastes salty
Explanation:
12 G of carbon react with 16 G of oxygen how much carbon monoxide is formed
Answer:
28 g CO
Explanation:
First convert grams to moles.
1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)
12 g C • [tex]\frac{1 mol C}{12 g C}[/tex] = 1 mol C
1 mol O = 15.996 g (I'm just going to round to 16)
16 g O • [tex]\frac{1 mol O}{16 g O}[/tex] = 1 mol O
So the unbalanced equation is:
[tex]C + O_{2}[/tex] -> [tex]CO[/tex] (the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)
The balanced equation is:
[tex]2 C + O_2[/tex] -> [tex]2 CO[/tex]
However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation
[tex]C + \frac{1}{2} O_2[/tex] -> [tex]CO[/tex].
1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.
Round the measurement to 3 significant figures. 13.06
Answer: 13.1
Explanation: just round the .06 to 1 creating three sig figs.
In each of the following sets of elements, which one will be least likely to gain or lose electrons?
1. Cesium (Cs), Rubidium (Rb), and Sodium (Na)
2. Barium (Ba), Calcium (Ca), and Beryllium (Be)
3. Fluorine (F), Chlorine (Cl), and Bromine (Br)
4. Tellurium (Te), Oxygen (O), and Sulfur (S)
with 24.1 moles of P4O10 how many moles of H3PO4 could be made
Which is Not part of hydrogen's line-emission spectrum?
Answer: Aufbau series.
Explanation:
The students in Mrs. Jamison's class were conducting a lab experiment to determine the if temperature affected how fast 2 drops of food coloring mixed into water. They used frozen water, refrigerated water, room temperature water, and hot water. Which water allowed the food coloring to mix the fastest?
A) Hot water
B) Frozen water
C) Refrigerated water
D) Room temperature water
Answer:
A
Explanation:
How many grams of Ag are produced if I start the reaction with 5.5 mol Cu?
Equation given:
Cu + 2AgNO3 -> 2Ag + Cu(NO3)2
Answer:
9.34 g Ag
Explanation:
Our bodies use nitrogen
Question 2 options:
directly from the air
after bacteria make N into ammonia molecules
from the plants and other animals we eat
all of the above
it's the 1 and 3 I think it's that hopefully it's right
What is the highest occupied energy level for an atom of copper (Cu)? *
Answer:
third energy level - 18
hope this helps
HELP ASAP!!! please chemistry sucks
If a cell were compared to a school, which part of the school would represent the cell's nucleus?
ОА the classroom walls because they give the structure to the school
B
the cafeteria cooks because they make food for the entire school
С
the principal because he or she controls all the activity in the school
D
the fence because it controls what enters and exits the school
Answer:
C-The principal because he or she controls all the activity in the school
Which of the following do/does not change with the change in temperature?
i. Mole fraction.
ii. Molality.
Select one:
a. only i
b. Only ii
c. Both i & ii
d. Neither of them
(I did D and it was incorrect)
Answer:
c. Both i & ii
Explanation:
Moles do not change with temperature hence Mole fraction does not depends of temperature.
Molality is number of moles of solutes per kilogram of solvent. It has no relationship with temperature.
This means both of them do not change wit the change in temperature.
Correct option;
c. Both i & ii
Which characteristic is true of sexual reproduction but not of asexual reproduction?
Answer:
Sexual Reproduction involves two different parties
Explanation:
Asexual is the opposite, so it uses no one else to reproduce
Answer:
Sexual reproduction produces diverse offspring .
Sexual reprodction produces more variations whereas asexual reproduction usually produces very similar organisms
Explanation:
Helppp 88.0 grams of Boron, how many atoms of Boron (B) are present?
Answer:
There are no atoms becuase atoms are not in elements.
Explanation:
5. If all the particles in a material are made up of
several smaller particles, and every larger particle
is identical, is the material a pure substance or
not? Explain your reasoning.
Answer:
No. Because a pure substance, no matter if an element, compound, it can only contain one kind of particle .
Explanation:
How could the strength of an electromagnet be increased?
by reducing the length of the core (nail) of the electromagnet
by using the rubber material as the core for the electromagnet
by decreasing the amount batteries used for the electromagnet
by increasing the number of coils in the wires of the electromagnet.
I had this question on a test in K12
The answer is By increasing the number of coils in the wires of the electromagnet.
increasing coil wires is correct, like the other person answered.
what is 20+9-10+67=?
Answer:
86
Explanation:
20 plus 9 equals 29 minus 10 equals 19 plus 67 equals 86
Answer:
86
Explanation:
20+9=29
29-10=19
19+67=86
Magnesium bromide is prepared in a laboratory using the reaction below. Typically, the magnesium bromide is recoveted as a solid by heating way the remaining water
Mg(s) + 2 HB-(aq) - MgBrac) + H200)
If 0.940 mole of HBr in solution is added to 16.5 grams of Mgo in a beaker and then is heated until dry, what are the expected contents of the beaker?
Isotope what dose it mean
Answer:
each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.
"some elements have only one stable isotope"
Explanation:
8.
Sulfur trìoxide decomposes to sulfur dioxide and oxygen gas as
shown in the following reaction:
2503 (g) 2502 (g) + O2 (g)
Given a 240.0 g sample of sulfur trioxide (MM = 80.1 g/mol), how many
grams of oxygen (MM = 32.0 g/mol) are produced, assuming the
decomposition goes to completion?
g
Your answer should be rounded to three significant figures. Do not include units in your
answer
Mass of Oxygen : 47.9
Further explanationGiven
2S03 (g)⇒ 2S02 (g) + O2 (g)
240 g SO3
Required
mass of Oxygen
Solution
mol SO3 :
= 240 g : 80.1 g/mol
= 2.996
From the equation, mol O2 :
= 1/2 x mol SO3
= 1/2 x 2.996
= 1.498
mass O2 :
= 1.498 mol x 32 g/mol
= 47.9
Taking into account the reaction stoichiometry, given a 240.0 g sample of sulfur trioxide, 47.95 grams of oxygen are produced, assuming the decomposition goes to completion.
Reaction stoichiometryIn first place, the balanced reaction is:
2 SO₃ → 2 SO₂ + O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
SO₃: 2 molesSO₂: 2 moles O₂: 1 moleThe molar mass of the compounds is:
SO₃: 80.1 g/moleSO₂: 64.1 g/mole O₂: 32 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
SO₃: 2 moles ×80.1 g/mole= 160.2 gramsSO₂: 2 moles ×64.1 g/mole= 128.2 grams O₂: 1 mole ×32 g/mole= 32 gramsMass of oxygen producedThe following rule of three can be applied: if by reaction stoichiometry 160.2 grams of SO₃ form 32 grams of O₂, 240 grams of SO₃ form how much mass of O₂?
[tex]mass of O_{2} =\frac{240 grams of SO_{3}x 32 grams of O_{2} }{160.2grams of SO_{3}}[/tex]
mass of O₂= 47.94 grams
Given a 240.0 g sample of sulfur trioxide, 47.95 grams of oxygen are produced, assuming the decomposition goes to completion.
Learn more about the reaction stoichiometry:
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A metal crystallizes in the face‑centered cubic (FCC) lattice. The density of the metal is 12020 kg/m3, and the length of a unit cell edge, , is 389.08 pm. Calculate the mass of one metal atom in grams.
Answer:
1.7700×10^-22 g
Explanation:
A face-centered-cubic cell contains 4 atoms, so the volume per atom is ...
(389.80×10^-12 m)³/(4 atoms) ≈ 1.4725×10^-29 m³
Then the mass of 1 atom is ...
(12020 kg/m³)(1.4725×10^-29 m³) ≈ 1.76995×10^-25 kg
≈ 1.7700×10^-22 g
_____
Additional comment
That is the approximate mass of a Palladium atom.
Answer:
1.7700×10^-22 g
Explanation:
A 150 g sample of brass at 90.0 degrees Celsius is placed in a calorimeter cup that contains 230 g of water at 20.0 degrees Celsius. Disregard the absorption of heat by the cup and calculate the final temperature of the brass and water. Specific heat of water = 4.18 J/gC, specific heat of brass=0.380 J/gC.
Answer:
for brass
mass m1 =150g
t1=90°c
specific heat of brass s1=0.380 J/gC.
for water
t2=20°c
mass m2=230g
Specific heat of water s2= 4.18 J/gC,
Explanation:
we have
Q1=Q2
m1s1{t-t1)=m2s2(t2-t)
150×0.380(t-90)=230×4.18(20-t)
57t-5130=961.4×20-961.4t
57t +961.4t=19228+5130
1018.4t=24358
t=24358/1018.4=23.91=24°c is final temperature
Explain how steam causes burns by describing the transfer of heat.
Answer:
It will be : (in simple terms)
Condensation of hot steam or hot vapor on the cooler skin releases the water's latent heat of vaporization, rapidly raising the temperature of the skin which will result in steam burns.
Hope it helped
All the best!!
NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2
What are the reactants and products also add why
MARKING BRAINLIEST
Choose the products that complete the reaction. The chemical equation may not be balanced.
NaHCO3 + HC2H3O2
Answer: NaC2H3O2 + CO2 + H2O
You can increase a step-up transformer's voltage with
A. a power source connected to the primary coil
B. a source connected to the secondary coil.
C. increasing the number of loops in the primary coil.
D. increasing the number of loops in the secondary coil
Answer:
A. a power source connected to the primary coil
Explanation:
What is the percent by mass of calcium in calcium carbonate,
CaCO3?
(Molar mass of CaCO3 = 100.09 g/mol)
%
What is the percent by mass of calcium in calcium carbonate, CaCO3? (Molar mass of CaCO3 = 100.09 g/mol)
Answer: 40.04 percent
The percent by mass of calcium in calcium carbonate ([tex]CaCO_{3}[/tex]) is approximately 40.04%.
To calculate the percent by mass of calcium in calcium carbonate ([tex]CaCO_{3}[/tex]), we need to determine the molar mass of calcium (Ca) and the molar mass of calcium carbonate ([tex]CaCO_{3}[/tex]), and then use the following formula:
Percent by mass of calcium = (Molar mass of calcium / Molar mass of calcium carbonate) x 100
Given:
Molar mass of [tex]CaCO_{3}[/tex] = 100.09 g/mol
Now, let's calculate the molar mass of calcium (Ca):
The molar mass of calcium (Ca) is 40.08 g/mol.
Plugging in the values into the formula, we get:
Percent by mass of calcium = (40.08 g/mol / 100.09 g/mol) x 100
= 0.4004 x 100
= 40.04%
Therefore, the percent by mass of calcium in calcium carbonate ([tex]CaCO_{3}[/tex]) is approximately 40.04%.
Learn more about percent by mass, here:
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