The statement "one-eighth the age, a" can be expressed algebraically as ?

0

1

2

3

4

5

take x 1 so 1-1

2-1..........

Answer:

750 is the answer. Hope it helps!

Answer:

numbers dont do into math please move this to englash

Step-by-step explanation:

it posted Wong

Answer:

[tex]P(X > 11) = 0.368[/tex]

[tex]P(X > 22) = 0.135[/tex]

[tex]P(X > 33) = 0.050[/tex]

[tex]x = 33[/tex]

Step-by-step explanation:

Given

[tex]E(x) = 11[/tex] --- Mean

Required (Missing from  the question)

[tex](a)\ P(X>11)[/tex]

[tex](b)\ P(X>22)[/tex]

[tex](c)\ P(X>33)[/tex]

(d) x such that [tex]P(X <x)=0.95[/tex]

In an exponential distribution:

[tex]f(x) = \lambda e^{-\lambda x}, x \ge 0[/tex] --- the pdf

[tex]F(x) = 1 - e^{-\lambda x}, x \ge 0[/tex] --- the cdf

[tex]P(X > x) = 1 - F(x)[/tex]

In the above equations:

[tex]\lambda = \frac{1}{E(x)}[/tex]

Substitute 11 for E(x)

[tex]\lambda = \frac{1}{11}[/tex]

Now, we solve (a) to (d) as follows:

Solving (a): P(X>11)

[tex]P(X > 11) = 1 - F(11)[/tex]

Substitute 11 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{1}{11}* 11})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-\frac{11}{11}})[/tex]

[tex]P(X > 11) = 1 - (1 - e^{-1})[/tex]

Remove bracket

[tex]P(X > 11) = 1 - 1 + e^{-1}[/tex]

[tex]P(X > 11) = e^{-1}[/tex]

[tex]P(X > 11) = 0.368[/tex]

Solving (b): P(X>22)

[tex]P(X > 22) = 1 - F(22)[/tex]

Substitute 22 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{1}{11}* 22})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-\frac{22}{11}})[/tex]

[tex]P(X > 22) = 1 - (1 - e^{-2})[/tex]

Remove bracket

[tex]P(X > 22) = 1 - 1 + e^{-2}[/tex]

[tex]P(X > 22) = e^{-2}[/tex]

[tex]P(X > 22) = 0.135[/tex]

Solving (c): P(X>33)

[tex]P(X > 33) = 1 - F(33)[/tex]

Substitute 33 for x in [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{1}{11}* 33})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-\frac{33}{11}})[/tex]

[tex]P(X > 33) = 1 - (1 - e^{-3})[/tex]

Remove bracket

[tex]P(X > 33) = 1 - 1 + e^{-3}[/tex]

[tex]P(X > 33) = e^{-3}[/tex]

[tex]P(X > 33) = 0.050[/tex]

Solving (d): x when [tex]P(X <x)=0.95[/tex]

Here, we make use of:

[tex]P(X<x) = F(x)[/tex]

Substitute [tex]F(x) = 1 - e^{-\lambda x}[/tex]

[tex]P(X<x) = 1 - e^{-\lambda x}[/tex]

So, we have:

[tex]0.95 = 1 - e^{-\lambda x}[/tex]

Subtract 1 from both sides

[tex]0.95 -1= 1-1 - e^{-\lambda x}[/tex]

[tex]-0.05=- e^{-\lambda x}[/tex]

Reorder the equation

[tex]e^{-\lambda x} = 0.05[/tex]

Substitute 1/11 for [tex]\lambda[/tex]

[tex]e^{-\frac{1}{11} x} = 0.05[/tex]

Solve for x:

[tex]x = -\frac{1}{1/11}\ ln(0.05)[/tex]

[tex]x = -11\ ln(0.05)[/tex]

[tex]x = 32.9530550091[/tex]

[tex]x = 33[/tex] --- approximated

Answer:

Here,

150+10=180

162-180=18

Answer is 18°

Step-by-step explanation:

So the round of nearest tenth is 18°

Hope it will help have a great day at school. ^_^

Answer:

the answer is 3 miles

Step-by-step explanation:

1 +2 = 3 so 3

Answer:

Length of the person = 1.9 m

Step-by-step explanation:

Actual length of the lorry = 9.5 m

Length of the lorry as per scale = 10 cm

Scale factor used to get the actual length of the lorry = [tex]\frac{\text{Actual length}}{\text{Length on scale}}[/tex]

                                                                                         = [tex]\frac{9.5}{10}[/tex]

                                                                                         = 0.95 : 1

Let the actual length of the person = x meters

Length of the person as per scale = 2 cm

Scale factor used to get the length of person is same.

Therefore, relation between the actual length of the person and scale length will be,

[tex]\frac{x}{2}= \frac{0.95}{1}[/tex]

x = 2 × 0.95

x = 1.9 meters

Answer:

(f o h)(-5)=-33

Step-by-step explanation:

Let f(x) = 4x - 1, h(x) = - X-3.

(f o h)=4(-x-3)-1

(f o h)=-4x-12-1

(f o h)=-4x-13

(f o h)(-5)=-4(-(-5))-13

(f o h)(-5)=-20-13

(f o h)(-5)=-33

Answer:

=[tex](x-1)(x+6)[/tex]

Step-by-step explanation:

Answer:

[tex]x^{2} +5x-6=(x-1)(x+6)[/tex]

Step-by-step explanation:

Answer

i think this is what you mean

Step-by-step explanation:

x          y

2         0

1          2

0         4

-1         6

-2        8

Answer:

no

Step-by-step explanation:

64/16 = 4

60/14 = 4.28...

Answer:

d

Step-by-step explanation:

Answer:

more than a number = addition

so it is D because the end result has to be 33.

Step-by-step explanation:

Hope this helped!

Answer:

300 sqft

Step-by-step explanation:

30 times ten is 300 and the measure is feet squared

Answer:

9000 ft 3

Step-by-step explanation:

Answer:

56

Step-by-step explanation: Use the values of a, b, and c to find the discriminant.

Answer:

[tex]\Delta =56[/tex]

Step-by-step explanation:

We are given:

[tex]y = x^2 - 8x + 2[/tex][tex]y=x^2-8x+2[/tex]

So, a = 1, b = -8, and c = 2.

The discriminant (symbolized by Δ) is given by:

[tex]\Delta =b^2-4ac[/tex]

So, our discriminant in this case will be:

[tex]\Delta=(-8)^2-4(1)(2)=64-8=56[/tex]

Since our discriminant is a positive value, our equation has two real roots.

Given:

The statement is " a is the fourth root of 16".

To find:

The true statement for the given statement.

Solution:

The given statement is

a is the fourth root of 16.

Mathematically, it can be written as

[tex]a=\sqrt[4]{16}[/tex]

Taking power 4 on both sides.

[tex]a^4=(\sqrt[4]{16})^4[/tex]

[tex]a\times a\times a\times a=16[/tex]

Therefore, the correct option is A.

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

Important Information :

'a' is the fourth root of 16 can be written as

[tex]a=\sqrt[4]{16}[/tex]

To remove fourth root, we take exponent 4 on both sides

[tex]a=\sqrt[4]{16}\\(a)^4=(\sqrt[4]{16})^4[/tex]

Exponent 4  and fourth root will get cancelled

[tex]a^4=16\\a \cdot a\cdot a \cdot a=16[/tex]

a x a x a x a = 16

A true statement ,  if a is the fourth root of 16 is

a x a x a x a = 16

learn more about the radicals here:

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Answer:

D

Step-by-step explanation:

Answer:

m= - 4/13

Step-by-step explanation:

Answer:

-4/13

Step-by-step explanation:

Hopefully this helps :)

Answer:

Table C

Step-by-step explanation:

Given

Table A to D

Required

Which shows a proportional relationship

To do this, we make use of:

[tex]k = \frac{y}{x}[/tex]

Where k is the constant of proportionality.

In table (A)

x = 2, y = 4

[tex]k = \frac{y}{x}[/tex]

[tex]k = \frac{4}{2}[/tex]

[tex]k = 2[/tex]

x = 4, y = 9

[tex]k = \frac{y}{x}[/tex]

[tex]k = \frac{9}{4}[/tex]

[tex]k = 2.25[/tex]

Both values of k are different. Hence, no proportional relationship

In table (B)

x = 3, y = 4

[tex]k = \frac{y}{x}[/tex]

[tex]k = \frac{4}{3}[/tex]

[tex]k = 1.33[/tex]

x = 9, y = 16

[tex]k = \frac{y}{x}[/tex]

[tex]k = \frac{16}{9}[/tex]

[tex]k = 1.78[/tex]

Both values of k are different. Hence, no proportional relationship

In table (C):

x = 4, y = 12

[tex]k = \frac{y}{x}[/tex]

[tex]k = \frac{12}{4}[/tex]

[tex]k = 3[/tex]

x = 5, y = 15

[tex]k = \frac{y}{x}[/tex]

[tex]k = \frac{15}{5}[/tex]

[tex]k = 3[/tex]

x = 6, y = 18

[tex]k = \frac{y}{x}[/tex]

[tex]k = \frac{18}{6}[/tex]

[tex]k = 3[/tex]

This shows a proportional relationship because all values of k are the same for this table

Answer:

B

Step-by-step explanation:

If you look at 3 on the X-axis and go down 4 then you will get point B as your answer.

Answer:

E is the correct answer because A is (-4,-3), B is (-4,3), C is (5,1), D is (4,-3), E is (3,-4), and F is (-2,-4)

Answer:

Step-by-step explanation:

-7 which set of number belongs, betwen

Natural

Whole

Intergers

Rational

Irrational

Real

The number of bananas that Ron sold is 315.

Division is one of the operation in mathematics where number is divided  into equal parts as that of a definite number.

Given that,

Cost for a banana = $0.60

Also given, he made $150.00, after taking off $39.00 for his banana stand rental.

Total amount of money that Ron made by selling the bananas = $150 + $39 = $189

Number of bananas sold = 189 / 0.6

                                          = 315

Hence Ron sold 315 bananas.

Learn more about Division here :

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After plotting the above equation on the coordinate plane, we can see the graph of the function.

A parametric equation in mathematics specifies a set of numbers as functions of one or more independent variables known as parameters.

We have two parametric equations:

x = 1 – t² and

y = 2t

t = y/2  and

0 ≤ t² ≤ 5

1 ≤ 1 - t²≤ 4

1 ≤ x≤ 4

Plug the above value in x = 1 – t²

x = 1- (y/2)²

x = 1 - y²/4

4x = 4 - y²

y² = 4(1 - x)

Thus, after plotting the above equation on the coordinate plane, we can see the graph of the function.

Learn more about the parametric function here:

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Answer:

$56.10

Step-by-step explanation:

Answer:

$8.50

Step-by-step explanation:

Answer:

[tex]V= 4\pi (9h^2 -12h + 4)[/tex]

Step-by-step explanation:

Given

Shape: Cylinder

[tex]Radius = 3h - 2[/tex]

[tex]Height = h[/tex]

[tex]Base\ Area = \pi (3h - 2)^2[/tex]

Required

Simplify the volume

The volume is calculated as:

[tex]Volume = Base\ Area * Height[/tex]

Substitute values for Base Area and Height

[tex]V= \pi(3h-2)^2*h[/tex]

Expand the bracket

[tex]V= \pi(3h-2)(3h-2)*h[/tex]

Open brackets

[tex]V= \pi (9h^2 -6h - 6h + 4) *h[/tex]

[tex]V= \pi (9h^2 -12h + 4) *h[/tex]

[tex]V= 4\pi (9h^2 -12h + 4)[/tex]