How many mol of C3H8 are consumed when 3 mol of CO2 are produced ?

Answer:

4.4 g

Explanation:

Step 1: Write the balanced equation

Cu + 4 HNO₃ ⇒ Cu(NO₃)₂ + 2 NO₂ + 2 H₂O

Step 2: Calculate the moles corresponding to 3.2 L of NO₂ at STP

At standard temperature and pressure, 1 mole of NO₂ occupies 22.4 L.

3.2 L × 1 mol/22.4 L = 0.14 mol

Step 3: Calculate the moles of Cu needed to produce 0.14 moles of NO₂

The molar ratio of Cu to NO₂ is 1:2. The moles of Cu needed are 1/2 × 0.14 mol = 0.070 mol.

Step 4: Calculate the mass corresponding to 0.070 moles of Cu

The molar mass of Cu is 63.55 g/mol.

0.070 mol × 63.55 g/mol = 4.4 g

Answer:

7.35 - 7.45

Explanation:

The pH scale ranges from 0 (strongly acidic) to 14 (strongly basic or alkaline). A pH of 7.0, in the middle of this scale, is neutral. Blood is normally slightly basic, with a normal pH range of about 7.35 to 7.45. Usually, the body maintains the pH of blood close to 7.40.

Hope this helps

Answer:

The normal pH range if a base is more than 7

Explanation:

Basideally the pH range goes from 0-14 in which

Acidic range is :0-7

Neutral :7

Base : 7 - 14

Answer:

ions are deflected and the lighter the ions the more the deflection.

Placing magnetic field in the path of the ions cause them to move in a curved path.

Explanation:

This question is all about the way in which mass spectroscopy works. Mass spectroscopy Is one of the techniques in spectroscopy which is used in the identification of chemical compounds.

Mass spectroscopy works based on the principle of ionization. For a mass spectroscopy to start ionization must first occur that is to say this is the first step in the identification of compound in mass spectroscopy.

The following steps are involve in mass spectroscopy;

=> Ionization: the molecules of the sample are first ionized. The ions formed here are positive ions.

=> Acceleration: the ions in step one are accelerated.

=> Deflection: the smaller ions get deflected more than the bigger ions. The magnetic field is used in the deflection of this ions.

=> Detection: the ions are then detected.

Therefore, to answer the question, the ions are deflected and the lighter the ions the more the deflection.

Placing magnetic field in the path of the ions cause them to move in a curved path.

Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

so

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05  d/mol

moles of Ethylene  = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate [tex]X_{V}[/tex] = moles of vinyl acetate / total  moles

[tex]X_{V}[/tex] = (0.1498 mol / 3.255 mol) × 100

[tex]X_{V}[/tex]  = 4.6%

mole percent of Ethylene [tex]X_{E}[/tex] = moles of Ethylene / total  moles

[tex]X_{E}[/tex]  = (3.1052 mol / 3.255 mol) × 100

[tex]X_{E}[/tex]  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑[tex]X_{i}[/tex][tex]M_{i}[/tex]

where [tex]X_{i}[/tex] is the fraction ratio and [tex]M_{i}[/tex] is the molecular  weight

so or the PEVA

mean repeat unit molar mass M = ( [tex]X_{V}[/tex][tex]M_{V}[/tex]) + ( [tex]X_{E}[/tex][tex]M_{E}[/tex])

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

[tex]DP_{n}[/tex] = [tex]\frac{M_{n} }{M}[/tex]

where [tex]M_{n}[/tex] is the number average molecular weight ( 39,870 g/mol )

so we substitute

[tex]DP_{n}[/tex] = 39,870 g/mol / 30.72 g/mol

[tex]DP_{n}[/tex]  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

Answer:

C₂H₄O

Explanation:

In a compound that contains Cabon, hydrogen and oxygen, the combustion produce CO₂ from the carbon, and H₂O from the hydrogens. Using the mass of the products we can solve the moles of Carbon and hydrogen. The empirical formula is the simplest whole-number of atoms present in a molecule.

Moles CO₂ = Moles C:

11.8g CO₂ * (1mol / 44g) = 0.268 moles CO₂ = 0.268 moles C * (12g/mol) =

3.216g C

Moles H₂O = 1/2 moles H:

4.83g H₂O * (1mol / 18g) = 0.268 moles H₂O * (2 mol H / 1 mol H₂O) =

0.537 mol H * (1g/mol) = 0.537g H

Mass O to find moles O:

5.90g Sample - 3.216g C - 0.537g H = 2.147g O * (1mol / 16g) = 0.134 moles O

Ratio of atoms -Dividing in 0.134 moles-:

C = 0.268mol C / 0.134 mol O = 2

H = 0.537mol H / 0.134 mol O = 4

O = 0.134mol O / 0.134 mol O = 1

Empirical formula is:

Answer:The rock forms large crystals

Explanation:

The law of conservation of mass states that, for any isolated system, the mass can neither be created nor be destroyed  

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Answer:

Carbon (C)

Explanation:

The electron configuration of Carbon is 2-4.

Answer:

Which infection may have fixes created because of their comprehension of construction and capacity of protein?

Answer:uhhhhh should I be concerned

Explanation:

Answer:

hmmm o_O Maybe you... shouldnt

Answer:

6.591

explanation

mass of weight is 1.092 , and mass of weight boat and sample = 7.683

mass of the solid sample= (mass of weight boat and sample) - (weight of the boat) = (1.092-7683) = 6.591 g

hence, the mass of the solid sample is 6.591 g

Answer:

[tex]V=5.2 mL=0.052L[/tex]

Explanation:

Hello!

In this case, since the chemical reaction between silver nitrate and sodium chloride is:

[tex]AgNO_3(aq)+NaCl(aq)\rightarrow AgCl(s)+NaNO_3(aq)[/tex]

We can see there is a 1:1 mole ratio between each solution; thus, we first compute the moles of each reactant considering their molar masses:

[tex]n_{AgNO_3}=14.77g*\frac{1mol}{169.87g}=0.087molAgNO_3\\\\ n_{NaCl}=0.2631g*\frac{1mol}{58.44}=0.0045molNaCl[/tex]

Now, since the concentration of the silver chloride solution is 0.087 M, we may assume that the concentration of the NaCl solution is the same, so we can compute the volume as shown below:

[tex]V=\frac{n_{NaCl}}{M}=\frac{0.0045mol}{0.087mol/L}\\\\V=0.052L[/tex]

Or:

[tex]V=5.2 mL[/tex]

Best regards!

The volume of solution needed to react with 0.2631 g of NaCl  is 0.052 L.

Volume of the solution will be calculated by using the below formula:

M = n/V, where

M = concentration in terms of molarity

n = no. of moles

V = volume

Given chemical reaction is:

AgNO₃(aq) + NaCl(aq) → AgCl(s) + NaNO₃(aq)

First we calculate the moles of given reactants by using the formula:

n = W/M , where

W = given mass

M = molar mass

Moles of AgNO₃ = 14.77g / 169.87g/mole = 0.087 mole

Moles of NaCl = 0.2631g / 58.44g/mole = 0.0045 mole

Concentration of AgNO₃ = 0.087 mole / 1L = 0.087M

From the stoichiometry of the reaction it is clear that mole ration of AgNO₃ & NaCl is 1:1. So, we take the concentration of NaCl is equal to the concentration of AgNO₃ and calculate the volume by using the above formula as:

Volume of NaCl = 0.0045mole / 0.087M = 0.052 L

Hence, 0.052 L is the required volume of NaCl.

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Answer:

Coron, Palawan, El Nido, Palawan, Cebu, Boracay, Siargao.

Explanation:

I hope this helps.

coron,palawan,El nidu, Cebu and boracay are 5 island in Philippines.....

According to stoichiometry and mole concept,1×10¹⁰ molecules reacted with excess hydrogen to make 2 x 10¹⁰ molecules of ammonia.

Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.It is important while balancing chemical equations.

In the given example, as 1 molecule of nitrogen produces 2 molecules of ammonia

∴2 x 10¹⁰ molecules of ammonia will be produced when 2 x 10¹⁰×1/2=1×10¹⁰ molecules .

Thus, 1×10¹⁰ molecules reacted with excess hydrogen to make 2 x 10¹⁰ molecules of ammonia.

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Answer:

ruthless, my style as a juvenile

ran with a gang, slanged in the meanwhile

Explanation:

Answer:Because When you're cleaning your glassware, you use water to rinse it off. If the burette is not completely dry by the time you use it, the remaining traces of water on the inside will make your titrant more dilute and thereby change its concentration.Before a burette is used, it needs to be cleaned. During the cleaning process, usually, water is introduced into the burette. Be the water clean or not, if the burette is then used without rinsing it with the solution that it is going to be filled with, the result of that analytical exercise will not be precise and accurate. The reason is that water residue in the burette would dillute the solution when it's filled in the burette which would make it impossible to determine the exact concentration of the solution moved by the burette. By rinsing and re-rinsing the burette several times with the solution it is going to be filled with, residue water from the cleaning process would be successfully removed from the burette as are other leftover substances from the cleaning process.

hope this helps have a nice night ❤️❤️❤️

Explanation:

Answer:

A)  $0.208 per unit

B) $0.220 per unit

C) An inspector should be hired

Explanation:

percentage of defect rate = 2% = 0.02

cost of inspector = $10 per hour

production rate = 48 per hour

cost of not hiring an inspector = $11

A) Determine the inspection cost per unit if an inspector is hired

= cost of inspector / production rate

= 10 / 48 = $0.208 per unit

B) Determine the defective cost per unit if an Inspector is not hired

= cost of not hiring an inspector * percentage of defect rate

= 11 * 0.02

= $0.220 per unit

C)   Inspection cost < defective cost   i.e. $0.208 < $0.220  hence an inspector should be hired

Answer:

its b

Explanation:

just did the test on A P E X

If the isotope models are accurate, One shows 8 neutrons, and one shows 9. Therefore, the correct option is option B.

A chemical element's isotope is one of more than one species of atoms that share the same atomic number, spot on the periodic table, and almost identical chemical activity, but differ in atomic mass and physical characteristics. There are a number of isotopes for each chemical element.

The first step in identifying and labelling an atom is to count the protons within its nucleus. Usually, this nuclear number is denoted by the letter Z. The fact that all atoms possessing the same number of electrons have essentially equal chemical characteristics lends the atomic number its enormous significance. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

Therefore, the correct option is option B. If the isotope models are accurate, One shows 8 neutrons, and one shows 9.

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Answer:

The missing information or their role in the discovery of the cell is as follows:

Robert Hooke: He was the first scientist to called cells to tiny box-like cavities he saw in cork and illustrated as cells.

A. Leeuwenhoek: he was a microscopist and microbiologist who used microscopes and observed many other living cells. He called animalcules to these single-cell living organisms later used to prove that cells are the fundamental unit of life.

Schwann and Schleiden:  They presented the theory that suggested that the cells are basic building blocks of all living things.

Virchow: He observed that the cell dividing and come from pre-existing cells.

Answer: Thus 24.0 g of [tex]SO_2[/tex] would be needed.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]      

[tex]\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles[/tex]

[tex]2SO_2(g)+O_2(g)\rightarrow 2SO_3(l)[/tex]  

According to stoichiometry :

1 mole of [tex]O_2[/tex] require = 2 moles of [tex]SO_2[/tex]

Thus 0.1875 moles of [tex]O_2[/tex] will require=[tex]\frac{2}{1}\times 0.1875=0.375moles[/tex]  of [tex]SO_2[/tex]  

Mass of [tex]SO_2=moles\times {\text {Molar mass}}=0.375moles\times 64g/mol=24.0g[/tex]

Thus 24.0 g of [tex]SO_2[/tex] would be needed to completely react with 6.00 g of [tex]O_2[/tex] such that all reactants could be consumed.

Answer:

The correct answer is - the number of moles of solute per liter of solution.

Explanation:

The molar concentration is also known as molarity which is the amount of concentration of a solute is in a chemical solution is the number of moles of solute per unit volume of solution. It is represented as M and can be calculated by:

M = n/v

Where n is the number of moles of the solute and,

v is the volume of solution (in liters normally)

It is worldwide used measurment for the concentration.

Answer:

it is false

Explanation:

it goes in different ways not in order

Answer:

B.

Explanation:

Not sure if this is correct if not sorry.

Answer:

A.

Explanation:

because a theory is like a prediction and a prediction is like a hypothesis.

A (they are experimentally determined exponents)

Answer:

Common names of ethers simply give the names of the two alkyl groups bonded to oxygen and add the word ether. The current practice is to list the alkyl groups in alphabetical order (t-butyl methyl ether), but older names often list the alkyl groups in increasing order of size (methyl t-butyl ether).

Explanation:

Hope it is helpful.......

Answer:

the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L  

Explanation:

Given that;

Tank volume v = 3250 liters

wastewater flows into the tank Q = 200 L/min

TCE concentration Co= 25 mg/L

reactor decays TCE at a reaction rate K = 0.20 min-1

mass balance

we know that;

Accumulation = inflow - outflow ± generation

⇒dc/dt = QCo - Qc ± rc.V

now at a steady state; dc/dt = 0

so

0 = QCo - Qc + rcV

where rc = -kc

0 = QCo - Qc - kcV

Qc + kcV = QCo

c(Q + kV) = QCo  

c = QCo / (Q + kV)

so we substitute

c = (200 × 25) / (200 + (0.2×3250))

c = 5000 / 850

c = 5.88 mg/L      

Therefore,  the steady-state concentration of TCE in the treated water leaving the reactor is 5.88 mg/L  

Answer:

(C) SO2.

SO2 is known as sulfur dioxide.

The below information about acid rain and SO2’s involvement is from epa.gov:

“Acid rain results when sulfur dioxide (SO2) and nitrogen oxides (NOX) are emitted into the atmosphere and transported by wind and air currents. The SO2 and NOX react with water, oxygen and other chemicals to form sulfuric and nitric acids. These then mix with water and other materials before falling to the ground.”

Explanation: