Answer:
296.01 J
Explanation:
From the question,
Q = cm(t₂-t₁)....................... Equation 1
Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature
Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k
Substitute these values into equation 1
Q = 897×0.01×(55-22)
Q = 897×0.01×33
Q = 296.01 J
Hence 296.01 Joules of heat is required.
If a motor is rated at 5.6KW, work done in 20minutes is equal to:
Answer:
given Power= 5.6×1000=5600watt
t=20min=20×60=1200sec. work done=?
P=w/t
w=pt=5600×1200=672×10^4Joule
The amount of work done by the motor is equal to 6.72 Megajoules.
Given the following data:
Time = 20 minutesPower = 5.6 Kilowatt = 5600 Watts.Conversion:
1 minute = 60 seconds20 minutes = [tex]20 \times 60 = 1200[/tex] seconds.To determine the amount of work done by the motor:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = power \times time[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = 5600 \times 1200[/tex]
Work done = 6,720,000 Joules
Note: 1,000,000 Joules = 1 Megajoules.
Work done = 6.72 Megajoules.
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