Solve for the x.
Assume the segments that appear to be tangent are tangent.
4.5 i think im really not sure check with someone else before answering
What should be true in order for a scatter plot to show that a linear fit may be appropriate for a data set?
O The points should form an upward curve.
O The points should be scattered randomly.
O The points should appear to lie generally along a line.
O The points should form one line above the x-axis and another below it.
On a scatter plot, the points are randomly placed around the graph. The correct option is B.
What is a scatter plot?A scatter plot is a type of plot or mathematical diagram using Cartesian coordinates to display values for typically two variables for a set of data. If the points are coded, one additional variable can be displayed.
A scatter (XY) plot is a vertical data visualization method for displaying the relationship between two sets of data. It is a graphical display of data that consists of a collection of points plotted in a two- or three-dimensional plane.
The locations of the points in a scatter plot are chosen at random. The best choice is B.
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Please someone answer this!
Andrew has $90 in a savings account. The interest rate is 10% per year and is not compounded. How much interest will he earn in 2 years?
Answer: 108$
Step-by-step explanation:
PLEASE HELP ASAPPPPPP!!!!!!!!!!!!
Answer:
324
Step-by-step explanation:
divide 752 by 2 to get 376
then subtract 52 from 376 to get 324
tell whether the slope is positive or negative. then find the slope.
Answer:
slope is negative
m=-1
Step-by-step explanation:
the slope of a line is positive if it passes through Quadrants III and I. The slope is negative if it passes through II and IV.
yes, this line passes through Quadrant I alongside II and IV, but it doesn't pass through Quadrant III (it has to pass through Quadrant III to be positive)
that means that the slope of this line must be negative
We can calculate the slope (m) with this formula:
(y2-y1)/(x2-x1)
we can pick two points- for example, (1,3) and (2,2)
label the points:
x1=1
y1=3
x2=2
y2=2
now substitute into the equation
m=(2-3)/(2-1)
m=-1/1
m=-1
the slope is -1
Hope this helps! :)
1) How many fourths are in one whole?
2) How many eighths are in one whole?
3) How many thirds are in one whole?
PLEASE HELP ASAP
Answer:
4 fourths are in one whole
8 eighths are in one whole
and 3 thirds are in one whole
Step-by-step explanation:
The circumference of a tree trunk is 50 ft
Answer:
So the length will be the same as the length of the torso
The size of the coyote population at a national park increases at the rate of 4.3% per year. If the size
of the current population is 183, find how many coyotes there should be in 6 years. Use
y = yoe^0.043t and round to the nearest whole number.
A) 235
B) 241
C) 239
D) 237
Answer:
B
Step-by-step explanation:
The estimated number of coyotes after six years, rounded to the closest whole number, is 237.
Therefore, option D) 237 is the appropriate response.
Given that in a national park the population of coyote is increasing by 4.3% per year.
The current population is 183.
We need to find the size of the population after 6 years.
To calculate the number of coyotes in 6 years using the given growth rate, we can use the formula:
[tex]y = y_oe^{0.043t[/tex]
Where:
y = final population after t years
y₀ = initial population
r = growth rate
t = time in years
In this case, the initial population (y₀) is 183, the growth rate (r) is 4.3% or 0.043, and we want to find the final population (y) after 6 years (t = 6).
Plugging in the values:
[tex]y = 183 \times e^{(0.043 \times 6)[/tex]
Calculating this expression:
[tex]y \approx 183 \times e^{(0.258)[/tex]
Using a calculator:
[tex]y \approx 183 \times 1.294[/tex]
[tex]y \approx 236.502[/tex]
Rounding to the nearest whole number, the estimated number of coyotes after 6 years is 237.
Therefore, the correct answer is option D) 237.
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50 points and Ill give brainiest - please help ASAP with WORK FOR IT please and thank you!! :)
2 pages with work
Answer:
1) (x + 12)²+(y+6)²= 28
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√28
h=-12
k=-6
;.centre=(-12,-6)
radius =√28 units
2) x²+(y+7)²=15
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√15
h=0
k=-7
;.centre=(0,-7)
radius=√15 units
3) (x + 4)²+(y - 1)² = 4
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√4=2units
h=-4
k=1
;.centre=(-4,1)
radius=√2units
4) (x+3)²+(y-1)²= 8
comparing above equation with(x-h)²+(y-k)²=r²
we get
r=√8=2√2units
h=-3
k=1
;.centre=(-3,1)
radius=2√2units