How many grams of chlorine are required in order to consume 85g of
sodium?
2 Na +1 C12
+ 2 Naci

Answer: The formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]

Explanation:

Decomposition of hydrated manganese sulphate is given by:

[tex]MnSO_4.xH_2O\rightarrow MnSO_4+xH_2O[/tex]

Molar mass of [tex]MnSO_4[/tex] = 151.0 g/mol

According to stoichiometry:

(151.0+18x) g of [tex]MnSO_4.xH_2O[/tex] decomposes to give 151.0 g of [tex]MnSO_4[/tex]

Thus 45.91 g of [tex]MnSO_4.xH_2O[/tex] decomposes to give= [tex]\frac{ 151.0}{151.0+18x}\times 45.91g[/tex]  of [tex]MnSO_4[/tex]

Also we are given : 37.07 g of  [tex]MnSO_4[/tex] is produced

Thus we can equate the two equations:

[tex]\frac{ 151.0}{151.0+18x}\times 45.91=37.07[/tex]

[tex]x=2[/tex]  

Thus the formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]

Answer:

0.1795 M

Explanation:

From the given information:

The equation is:

[tex]\mathbf{HF_{(aq)}+ KOH_{(aq)} \to KF _{(aq)} + H_2O}[/tex]

From the above equation, the reaction will go to completion due to the strong base:

At the equivalence point, moles of acid (HF) will be equal to moles of base (KOH)

[tex]\text{Number of moles = Volume} \times Molarity[/tex]

Thus. since moles of HF = moles of KOH

Then; 0.020 × 0.393 M = 0.02379 × (x) M

(x) M = [tex]\dfrac{0.02 \times 0.393 \ M}{0.02379}[/tex]

(x) = 0.3304 M

Thus, the molarity of KOH = 0.3304 M

Using the balanced neutralization reaction;

moles of HF = moles of KOH = moles of conjugate base = 0.00786 mol

∴

Volume = 0.020 L + 0.02379 L

Volume = 0.04379 L

Volume of the solution =  0.04379 L

Therefore; Molarity = [tex]\dfrac{moles}{volume}[/tex]

Molarity = [tex]\dfrac{0.00786 \ mol}{0.04379 \ L}[/tex]

Molarity = 0.17949 mol/L

= 0.1795 M

After the initial neutralization, the molarity at the equivalence point will be:

"0.17949 mol/L"

According to the question,

→ HF (aq) + KOH (aq) [tex]\rightarrow[/tex] KF (aq) + H₂O

Since, moles of HF = moles of KOH

We know that,

Number of moles = Volume × Molarity

→ 0.020 × 0.393 = 0.02379 × M

By applying cross-multiplication,

The molarity of KOH be:

M = [tex]\frac{0.02\times 0.393}{0.02379}[/tex]

   = [tex]\frac{0.00786}{0.02379}[/tex]

   = 0.3304 M

By using balanced neutralization reaction,

Volume = 0.020 + 0.02379

             = 0.04379 L

hence,

The molarity will be:

= [tex]\frac{Moles}{Volume}[/tex]

By substituting the values,

= [tex]\frac{0.00786}{0.04379}[/tex]

= 0.17949 mol/L

Thus the response above is correct.

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Answer:

No

Explanation:

AgNO₃ + KCl --> AgCl + KNO₃

This reaction is a precipitation reaction. AgCl is formed as a white solid due to its low solubility in water.

Answer:

b

Explanation:

Answer:

D. Dry

Explanation:

Colorado's combination of high elevation, midlatitude, and continental interior geography results in a cool, dry climate.

Answer:

Answer:

See explanation

Explanation:

The synthesis of asprin involves the;

i) Hydrolysis of Methyl salicylate

ii) Reaction of salicylic acid with acid anhydride

The chemical name of asprin is acetylsalicylic acid.

It is preferable to use an acid anhydride for ester formation with an alcohol rather than a carboxylic acid because we will not produce water which can then cause the hydrolysis of the newly formed ester.

Answer: sodium chloride water solution

Explanation: Eelctrolyte contains cations and anions which can

Transfer charge

Answer:

some energy drinks like powerade or Gatorade, and some juice drinks to.

Answer:

_c+_so2-_cs2+_co= Toxic

The equilibrium concentration of N₂O₄, given that the concentration of NO₂ is 1.78×10⁻² is 5.42×10⁻²

Keq = [Product] / [Reactant]

Keq = [NO₂]² / [N₂O₄]

5.85×10⁻³ = [1.78×10⁻²]² / [N₂O₄]

Cross multiply

5.85×10⁻³ × [N₂O₄] = [1.78×10⁻²]²

Divide both sides by 5.85×10⁻³

[N₂O₄] = [1.78×10⁻²]² / 5.85×10⁻³

[N₂O₄] = 5.42×10⁻²

Learn more about equilibrium constant:

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Answer:

First answer is "The equilibrium lies to the left", and the second one is 5.42 x 10^-2 M.

Explanation:

Hope i helped yall :D

Answer: Hotspot: A hotspot is a physical location where people can access the Internet, typically using Wi-Fi, via a wireless local area network (WLAN) with a router connected to an Internet service provider. ... While many public hotspots offer free wireless access on an open network, others require payment.

A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.

Explanation: MY own word's.

I think it would be d bc water is everywhere

The volume 15.0 g of O₂ has at a certain temperature and pressure is 2.16 L.

Volume is the space occupied by a three-dimensional object.

By the law of dilution

M₁/V₁ = M₂/V₂

Mass 1 is 5.00

Volume 1 is 7.20 L

Mass 2 15.0 g

Volume 2 is to find

Putting the value in the equation

5.00/ 7.20 = 15.0 / V₂

V₂ = 7.20 × 15.00/ 5.00 = 21.6

Thus, the volume will be 21.6 L.

Learn more about volume

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Answer:

Hey mate......

Explanation:

This is ur answer.......

The largest star, and indeed the only star in our solar system, is the sun. The sun is a bit under a million miles across. About 110 Earths put side by side would equal the size of the sun. The sun has 99.8 percent of the mass of our solar system.

Hope it helps!

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Follow me! :)

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Answer:

it should be 7.300 sorry if I am wrong

Answer:

The answer is 115

Explanation:

Teacher walked me through it.

Answer:

I think A is the correct answer

Answer: the answer is B 100%

Answer:

Hello ur answer is

Pyrosulphuric acid formula

Explanation:

thanks

Answer:

Hello There!!

Explanation:

The answer is=>Pyrosulphuric acid formula.

hope this helps,have a great day!!

~Pinky~

Answer:

The total pressure of the gas mixture = 2.76 atm

Note: The question is not complete. The complete question is as follow:

If 43.1 g of O2 and 6.8 g of CO2 are placed in a 13.7 L container at 34 degree Celsius , what is the pressure of the mixture of gases?

Explanation:

Mass of O₂ gas = 43.1 g, molar mass of O₂ gas = 32.0 g/mol

Number of moles of O₂ gas = 43.1/32.0 = 1.347 moles

Mass of CO₂ gas = 6.8 g, molar mass of CO₂ gas = 44.0 g

Number of moles of CO₂ gas = 6.8/44 = 0.155 moles

Total number of moles of gas mixture, n = (1.347 + 0.155) = 1.502 moles

Volume of gas mixture, V = 13.7 L

Temperature of gas mixture, T = 34 °C = (273.15 + 34) K = 307.15 K

Pressure of gas mixture = ?

Molar gas constant, R = 0.0821 liter·atm/mol·K.

Using the ideal gas equation: PV =nRT

P = nRT/V

P = (1.502 × 0.0821 × 307.15) / 13.7

P = 2.76 atm

Therefore, the total pressure of the gas mixture = 2.76 atm

Answer:

B) 1S and 40

hope it helps

Answer:

b is ur answer

Explanation:

1S and 4O

Answer: 1:16

Explanation:

Answer:

6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Replacing:

Q= 4.184 [tex]\frac{J}{g*C}[/tex] *29.352 g* 52 C

Solving you  get:

Q= 6,386.05 J

6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.

Explanation:

a. Write a balanced equation

The balanced equation for the reaction is given as;

Zn + AgNO3 → Ag + ZnNO3  

b. Interpret the equation by  particles and by moles

In this equation, 1mol of Zn reacts with 1 mol of AgNO3 to from 1 mol of Ag and 1 mol of ZnNO3

1 mol = 6.022 * 10^23 particles

c. What is the limiting reactant?

The mol ratio between both reactants is 1 : 1 from the equation.

Converting the masses given to ml;

Number of mol = Mass / Molar mass

Zn;

Number of mol = 6.70 / 65.38 = 0.1025 mol

AgNO3;

Number of mol = 27.5 / 169.87 = 0.1619 mol

The limiting reactant in this reaction is Zn. This is because Zn would get used up before AgNO3 according to the number of moles calculated.

d. What is the theoretical mass of silver that will be produced?

1 mol of Zn produces 1 mol of Ag

0.1025 mol of Zn would also produce 0.1025 mol mol of Ag

Mass = Molar mass * Number of Moles = 107.87  * 0.1025

Mass = 11.05 g

e. If the actual yield of silver was 14.1 g, what is the percent yield of the

reaction?

Percent yield = Actual Yield / Theoretical yield * 100%

Percent yield = 11.05 / 14.1  * 100 = 78.36%

Answer:

Explanation:

No, it is ludicrous and not possible to separate and detach a basic and neutral compound by 1M NaOH in DCM. This is due to the fact that neutral compounds don't respond and react with NaOH, and NaOH itself occurs to be a base. As a result, it can't respond and react with another base to produce salt. Consequently, we simply need a corrosive component i.e an acid

So; In DCM, we can't use 1M NaOH instead of 1M HCI for isolation and separation of neutral and basic compound mixtures.

Answer:

benzoic acid: pka = 4.19

Explanation:

Answer:

Explanation:

The standard molar mass is:

For (S )-1-chloro-4-ethyl-2-methylhexane = 162.5 g/mol

For triphenylphosphine  = 262 g/mol

For  ( S )-1-chloro-4-ethyl-2-methyl triphenylphosphonium = 424.5 g/mol

The mass required for 81% yield = [tex]\dfrac{81}{100} \times Theoretical \ yield = 4.15 g[/tex]

Theoretical yield = [tex]\dfrac{4.15}{0.81}[/tex]

= 5.1235 g

thus, since 424.5 g yield produce from 162.5 g

∴

5.1235 g yield will produce = [tex]\dfrac{162.5}{424.5}\times 5.1235 \ g[/tex]

= 1.9613 g of alkyl halide (-chloro) required.

Also, since 424.5 g yield produce from 262 g phosphine

∴

5.1235 g yield will produce = [tex]\dfrac{262}{424.5}\times 5.1235 \ g[/tex]

= 3.1622 g of triphenylphosphine required.

Answer:

oof this is way to hard sry man

Explanation:

Answer:

Attached below diagram of the eight diastereomers

The Isomer that reacts so slowly is DIASTEREOMER 8

Explanation:

The Isomer that reacts so slowly is DIASTEREOMER 8 in an E2 reaction and this is because no pair of chlorine and hydrogen atoms can assume the anti-periplanar orientation that is preferred in an E2 elimination

attached below is Diagram of the eight diastereomers ( screen shot from my drawing tool )