Answer:
the coach will have a combination of 2 players since there are initially 4 players on ground and he's picking two from them.
My computer can download a movie in 5 hours. If I install an extra processor it can download the movie in 4 hours. How long, working alone, would it have taken the new extra processor to download the movie?
Pls try to help within 10-20 min I really need it!!!!!!
=======================================================
Explanation:
We have two workers, more or less. Worker A gets the job done in 5 hours. Worker B comes along to help. If A and B work together, they get the job done in 4 hours. This assumes neither worker hinders the other.
Worker A's rate is 1/5 of a job per hour. In other words, after 1 hour, 1/5 of the job is done.
The combined rate is 1/4 for similar reasoning
Worker B's rate is 1/x where x represents how long it takes worker B to get the job done on its own.
The equation to solve is
1/5 + 1/x = 1/4
Note how 1/5 and 1/x represents the sum of the individual rates to get the combined rate 1/4
To solve this equation, it helps to clear out the fractions. Multiply every term by the LCD 20x
20x(1/5 + 1/x) = 20x(1/4)
20x(1/5) + 20x(1/x) = 20x(1/4)
4x + 20 = 5x
From here you can probably see solving this is relatively easy
4x+20 = 5x
20 = 5x-4x
20 = x
x = 20
Therefore, it will take 20 hours for worker B to get the job done on its own.
Going back to the processing context, it takes 20 hours for the new processor to download the movie. This is where the new processor is working alone without help from the original processor.
----------------
Side note: downloading a movie really depends on internet speed rather than processor speed.
Simplify 4 + (−3 − 8)
Answer:
-7
Step-by-step explanation:
4 + (−3 − 8)
PEMDAS
Parentheses first
4 + (-11)
Add and subtract next
-7
Answer:
first I'm using BODMAS
4+(-11)
= -7
hope it helps
Researchers want to determine whether or not there is a difference in systolic blood pressure based on how many hours a person exercises per week. They divide a sample of 72 people into 3 groups based on how many hours they exercise per week. Group 1 exercises less than 2 hours per week, Group 2 exercises between 2 and 5 hours per week, and Group 3 exercises more than 5 hours per week. Researchers measure and record the systolic blood pressure for each participant. They choose α = 0.05 level to test their results. For your convenience, I have prepared an excel file with the data titled: data_homework10_BP groups. Use this data to run a One-way Anova.
1. What is the between groups degrees of freedom for this study?
a. 2
b. 3
c. 72
d. 69
2. This finding is statistically significant.
a. True
b. False
3. Based on this information, the researcher should make the decision to ___________.
a. reject the null hypothesis
b. fail to reject the null hypothesis
Answer:
(1) The between groups degrees of freedom is 2.
(2) TRUE.
(3) The correct option is (a).
Step-by-step explanation:
(1)
The between groups degrees of freedom for the study is:
[tex]\text{df}_{B}=k-1\\=3-1\\=2[/tex]
Thus, the between groups degrees of freedom is 2.
(2)
The hypothesis for he one-way ANOVA is:
H₀: All the means are equal.
Hₐ: At least one of the mean is not equal.
The output of the ANOVA test is attached below.
The p-value of the test is 0.00005.
p-value = 0.00005 < α = 0.05
Thus, the result is statistically significant.
The statement is TRUE.
(3)
As the p-value of the test is less than the significance level, the researcher should make the decision to reject the null hypothesis.
The correct option is (a).
The length of time it takes students to complete a statistics examination is uniformly distributed and varies between 40 and 60 minutes. What is the probability density function for the length of time to complete the exam?
Answer:
[tex]X \sim Unif (a=40, b=60)[/tex]
And for this case we want to find the probability density function and we know that is given by:
[tex] f(x) =\frac{1}{b-a}=\frac{1}{60-40}= \frac{1}{20}, 40\leq X\leq 60[/tex]
Step-by-step explanation:
Let X the random variable who represent the length of time it takes students to complete a statistics examination. And the distribution for x is given by:
[tex]X \sim Unif (a=40, b=60)[/tex]
And for this case we want to find the probability density function and we know that is given by:
[tex] f(x) =\frac{1}{b-a}=\frac{1}{60-40}= \frac{1}{20}, 40\leq X\leq 60[/tex]
Mexican currency is the peso. One Mexican peso is currently equal to 0.055 U.S. dollars. If a traveler exchanges $400 for Mexican pesos, how many pesos will he receive? Round to the nearest peso.
Answer:
7,273 Pesos
Step-by-step explanation:
1 Peso = $0.055
The formula below converts pesos to dollars:
1 Peso x 0.055 = $1
The formula below converts dollars to pesos:
$1/0.055= 1 Pesos
We use the second formula because we are coverting
from dollars to pesos.
$400/0.055=7,273 Pesos
Answer:
22
Step-by-step explanation:
If one Mexican peso is .055 U.S dollars that means it has a greater value than the dollar so we can make the following ratio 1:.055. But if the .055 is a 400 1:400 we just multiply to get 22.
evaluate the algebraic expression for the given values 6+5(x-6)³ for X=8
Find the sum. Please
Answer:
[tex]\dfrac{2y^2 +12y -8}{y^3-3y+2}[/tex]
Step-by-step explanation:
It usually works to factor the denominators, so you can determine the least common denominator.
[tex]\dfrac{2y}{y^2-2y+1}+\dfrac{8}{y^2+y-2}=\dfrac{2y}{(y-1)^2}+\dfrac{8}{(y-1)(y+2)}\\\\=\dfrac{2y(y+2)}{(y-1)^2(y+2)}+\dfrac{8(y-1)}{(y-1)^2(y+2)}=\dfrac{2y^2+4y+8y-8}{(y-1)^2(y+2)}\\\\=\boxed{\dfrac{2y^2 +12y -8}{y^3-3y+2}}[/tex]
Simplify the expression. 641/3
Answer:213.7
Step-by-step explanation:
Which one of the following groups of numbers includins all prime numbers? a)2,3,5 b)7,17,63,67 c)3,11,63,67 d)1,3,11,23
Answer:
a) 2, 3, 5
Step-by-step explanation:
2, 3, 5
All numbers are prime.
7, 17, 63, 67
63 is not a prime number.
3, 11, 63, 67
63 is not a prime number.
1, 3, 11, 23
1 is not a prime number.
Based on data from the Greater New York Blood Program, when blood donors are randomly selected the probability of the having Group O blood is 0.45. Knowing that information, find the probability that AT LEAST ONE of the 5 donors has Group O blood type.
Answer:
The probability that at least one of the 5 donors has Group O blood type is 0.9497.
Step-by-step explanation:
We can model this as a binomial random variable, with n=5 (the sample size) and p=0.45.
The probability that exactly k donors have Group O blood type in the sample can be written as:
[tex]P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{5}{k} 0.45^{k} 0.55^{5-k}\\\\\\[/tex]
We have to calculate the probability P(x≥1). In this case it easy to substract from 1 the probabitity that x is exactly 0:
[tex]P(X\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{5}{0} p^{0}(1-p)^{5}=0.55^5=0.0503\\\\\\P(x\geq1)=1-0.0503=0.9497[/tex]
PLSSSSSSS HELP WILL MARK BRAINLIEST Doug owns a lawn mowing and landscaping business. The income from the business is given by the function f(x) = 2x + 54, where f(x) is the income in dollars and x is the area in square meters of lawn mowed. If he has earned {204, 344, 450, 482} dollars in the last four months, what are the corresponding areas of lawn he mowed?
Answer:
i think this person answered but idrk perseusharrison79
Step-by-step explanation:
For 2 parallelograms, the corresponding side lengths are 1 inch and x inches, and 2 inches and 6 inches.
Not drawn to scale
StartFraction 1 over x EndFraction = StartFraction 2 over 6 EndFraction
StartFraction 1 over x EndFraction = StartFraction 6 over 2 EndFraction
StartFraction 1 over 6 EndFraction = StartFraction 2 over x EndFraction
One-half = StartFraction 6 over x EndFraction
Step-by-step explanation:
6th grade math , please help
Answer: 4 to 10 then it’s 6 to 20 then it’s 8 to 25 Then it’s 10 to 30 then it’s 12 to 35 I hope this is the answer
Step-by-step explanation:
Step-by-step explanation:
Ava is walking at a constant rate of 5 feet each 2s so :
5 ft ⇒ 2 sWe should keep adding 2s in the time and 5 feet in the distance
Let's complete the chart:
0⇒02⇒54⇒106⇒158⇒2010⇒25Write the numbers in scientific notation.
8. 5,100,000
9. .00000698
10. 3.000052
Write the numbers in standard form.
11. 6.548 x 10-3
12. 5.854 x 10' 58.54
13. 2.25 x 106
Answer:
8)5.1*10⁶
9)6.98*10 to the power of -6
10) 3.000052*10⁰
11)0.006548
A property is listed for $580,000. The listing agreement promises to
pay a 7% commission. A buyer makes an offer of $547,000 on May 4th
and gives a $2,000 deposit. The offer is accepted with no change on
May 8th and a closing date is set for June 5th. The day of closing goes
to the buyer. Taxes for the property are $5309 and are paid in arrears.
The buyer will pay for the inspection at closing $280.00 and the seller
will pay for a home warranty in the amount of $360.00. The mortgage
remaining is $480,000. Using the 365 day method, what will the seller
net?
$506,095
$544,386
$26,096
$26,085.00
Answer:
$26,096
Step-by-step explanation:
property taxes = 31 January + 28 February + 31 March + 30 April + 31 May + 4 June = 155 days
property taxes = (155 days/365 days) x $5,309 = $2,254
agent's commission = 7% x $547,000 = $38,290
seller's net = $547,000 - $480,000 (mortgage) - $38,290 (agent's commission) - $360 (home warranty) - $2,254 (property taxes) = $26,096
Answer:
26,096
Step-by-step explanation:
Proration using 365-day method:
Buyer days are June - December 210 days (June 30 + July 31 + August 31 + September 30 + October 31 + November 30 + December 31 - June 4 days)
Seller days are January - June 155 days (January 31 + February 28 + March 31 + April 30 + May 31 + June 30 - June 26 days)
Formula with closing day to buyer: 210/365 x $5,309 = $3,054.49 --> $5,309 - $3,054.49 = $2,254.51 property taxes
Commission:
$547,000 sale price x .07 commission fee = $38,290 commission
Seller Net:
$547,000 sale price - $480,000 mortgage = $67,000 - $38,290 commission = $28,710 - $360.00 home warranty = $28,350 - $2,254.51 = $26,096
Chang knows one side of a triangle is 13 cm. Which set of two sides is possible for the lengths of the other two side
bf this triangle?
O 5 cm and 8 cm
O 6 cm and 7 cm
O 7 cm and 2 cm
8 cm and 9 cm
Answer:
It's (D) 8 cm and 9 cm. Hope this helps you!
Step-by-step explanation:
The other 2 sides added have to be greater than 13.
Answer:
8 and 9
Step-by-step explanation:
The triangle inequality states that the sum of the two shortest sides must be greater than the longest side.
Let's check the first one. 5 + 8 > 13 → 13 > 13 which is false.
6 + 7 > 13 → 13 > 13 which is false.
7 + 2 > 13 → 9 > 13 which is false.
8 + 9 > 13 → 17 > 13 which is true.
How many gallons of 20% moonshine and how many gallons of 30% moonshine have to be mixed together to make 100 gallons of 28% moonshine? x = gallons of 20% moonshine y = gallons of 30% moonshine
Answer:
20 and 80
Step-by-step explanation:
x+y= 100
0.2x+0.3y= 0.28*100
0.2x+0.3*(100-x)= 280.2x- 0.3x +30= 280.1x= 2x= 20 ⇒ y= 80
The mean arrival rate of flights at Philadelphia International Airport is 195 flights or less per hour with a historical standard deviation of 13 flights. To increase arrivals, a new air traffic control procedure is implemented. In the next 30 days, the arrival rate per day is given in the data vector below called flights. Air traffic control manager wants to test if there is sufficient evidence that arrival rate has increased.
flights <- c(210, 215, 200, 189, 200, 213, 202, 181, 197, 199,
193, 209, 215, 192, 179, 196, 225, 199, 196, 210,
199, 188, 174, 176, 202, 195, 195, 208, 222, 221)
a) Find sample mean and sample standard deviation of arrival rate using R functions mean() and sd().
b) Is this a left-tailed, right-tailed or two-tailed test? Formulate the null and alternative hypothesis.
c) What is the statistical decision at the significance level α = .01?
Answer:
a) The sample mean is M=200.
The sample standard deviation is s=13.19.
b) Right-tailed. The null and alternative hypothesis are:
[tex]H_0: \mu=195\\\\H_a:\mu> 195[/tex]
c) At a significance level of 0.01, there is notenough evidence to support the claim that the arrival rate is significantly higher than 195.
Step-by-step explanation:
We start by calculating the sample and standard deviation.
The sample size is n=30.
The sample mean is M=200.
The sample standard deviation is s=13.19.
[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{30}(210+215+200+. . .+221)\\\\\\M=\dfrac{6000}{30}\\\\\\M=200\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{29}((210-200)^2+(215-200)^2+(200-200)^2+. . . +(221-200)^2)}\\\\\\s=\sqrt{\dfrac{5048}{29}}\\\\\\s=\sqrt{174.07}=13.19\\\\\\[/tex]
This is a hypothesis test for the population mean.
The claim is that the arrival rate is significantly higher than 195. As we are interested in only the higher tail for a significant effect, this is a right-tailed test.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=195\\\\H_a:\mu> 195[/tex]
The significance level is 0.01.
The standard deviation of the population is known and has a value of σ=13.
We can calculate the standard error as:
[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{13}{\sqrt{30}}=2.373[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{200-195}{2.373}=\dfrac{5}{2.373}=2.107[/tex]
This test is a right-tailed test, so the P-value for this test is calculated as:
[tex]\text{P-value}=P(z>2.107)=0.018[/tex]
As the P-value (0.018) is bigger than the significance level (0.01), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.01, there is notenough evidence to support the claim that the arrival rate is significantly higher than 195.
what value of x is in the solution set of 2(3x–1)>4x–6?
Answer:
x > -2
Step-by-step explanation:
2(3x–1)>4x–6
Divide each side by 2
2/2(3x–1)>4x/2–6/2
3x-1 > 2x-3
Subtract 2x from each side
3x-2x-1 > 2x-3-2x
x-1 > -3
Add 1 to each side
x-1+1 > -3+1
x > -2
solve the inequality:8x+3>2x-15
8x + 3 > 2x - 15
8x - 2x > -15 - 3
6x > -18
x > -3
Answer:
x > -3
Step-by-step explanation:
8x + 3 > 2x - 15
Add -3 and -2x on both sides.
8x - 2x > -15 - 3
6x > -18
Divide 6 into both sides.
x > -18/6
x > -3
Please help me
And explain
Answer: 144
Step-by-step explanation:
ABD plus DBC makes up ABC so when you add the two it will give you a whole (76+68).
A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen, resulting in the accompanying data (from "Engineering Properties of Soil," Soil Science, 1998: 93–102).1.10 5.09 0.97 1.59 4.60 0.32 0.55 1.450.14 4.47 1.20 3.50 5.02 4.67 5.22 2.693.98 3.17 3.03 2.21 0.69 4.47 3.31 1.170.76 1.17 1.57 2.62 1.66 2.05The values of the sample mean, sample standard deviation,and (estimated) standard error of the mean are2.481, 1.616, and .295, respectively. Does this data suggestthat the true average percentage of organic matterin such soil is something other than 3%? Carry out atest of the appropriate hypotheses at significance level.10. Would your conclusion be different if a 5 .05 hadbeen used? [Note: A normal probability plot of the datashows an acceptable pattern in light of the reasonablylarge sample size.]
Answer:
We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.
We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.
Step-by-step explanation:
We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;
1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.
Let [tex]\mu[/tex] = true average percentage of organic matter
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 3% {means that the true average percentage of organic matter in such soil is 3%}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu \neq[/tex] 3% {means that the true average percentage of organic matter in such soil is something other than 3%}
The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean percentage of organic matter = 2.481%
s = sample standard deviation = 1.616%
n = sample of soil specimens = 30
So, the test statistics = [tex]\frac{2.481-3}{\frac{1.616}{\sqrt{30} } }[/tex] ~ [tex]t_2_9[/tex]
= -1.76
The value of t-test statistics is -1.76.
(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.
Since the value of our test statistics doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.
(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.
Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.
Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.
1. For some constant c, the random variable X has probability density function
cx", 0
0, otherwise.
What is the value of c?
a) 1/n;
b) na ;
c)n + 1;
d) n;
e) n–1.
Answer:
Answer is (D) n
Step-by-step explanation:
Probability density function defines the likelihood of an outcome for a discrete random variable or a continuous random variable whose integral gives the probability that the value of the variable lies in the same interval.
The constant here is C
CX" implies CX prime prime (meaning that X has been differentiated twice).
The value of C is n, which is the number of values of X.
HELP!! Im not sure what i did wrong!!
I'm not sure what exactly you did wrong, but I agree with you that the sample size is too small, so the correct answer will probably be the fourth options. Hope that this gives you some confidence, and 'm sorry not to be able to help you any further...
1- if angle A = 30, then its complementary is -- and its supplementary is
2- If a triangle has an area of 360, and its base = 10, what is its height?
3- if two triangles have the same angle measures, then the triangles are
4. What is the definition of similar triangles?
5- One of triangle congruence tests is SSS, what are 3 other congruent tests
6- What is a regular polygon?
7- If a rectangle has an area of 240 and a length of 24, what is the width?
8- Colinear points lie on the same
9- 3 non-colinear points determine a
10- The sum of 2 supplementary angles add up to -------
1 - complementary = 90- 30 = 60
suplementary = 180- 30 = 150
2 - area = hb/2 = 360 = hb/2 = h = 72
3 - similar
4- see number 3
5 - asa, ssa, sas
6 - polygon that had all equal angle measures and sides (equiangular and equilateral)
7 - length x width = area so
240 / 24 = 10
8 - line
9 - triangle
10 - 180, as see in question 1
vote me brainliest ):>
CAN SOMEONE PLEASE HELP ME THIS IS DUE SOON!!
Answer:
95 ft²
Step-by-step explanation:
Given:
regular pyramid with,
Square base of side length (s) = 5 ft
Slant height (l) = 7 ft
Required:
Surface area
Solution:
Surface area of a regular pyramid = ½*P*l + B
Where,
P = perimeter of the square base = 4(s) = 4(5) = 20 ft
l = slant height = 7 ft
B = area of base = s² = 5² = 25 ft²
Surface area = ½*20*7 + 25
= 10*7 + 25
= 70 + 25
Surface area of regular pyramid = 95 ft²
Which expression is equivalent to [tex]4^7*4^{-5}[/tex]? A. [tex]4^{12}[/tex] B. [tex]4^2[/tex] C. [tex]4^{-2}[/tex] D. [tex]4^{-35}[/tex]
Answer:
B. [tex]4^2[/tex]
Step-by-step explanation:
[tex]4^7 \times 4^{-5}[/tex]
Apply rule (if bases are same) : [tex]a^b \times a^c = a^{b + c}[/tex]
[tex]4^{7 + -5}[/tex]
Add exponents.
[tex]=4^2[/tex]
Answer:
[tex] {4}^{2} [/tex]Step by step explanation
[tex] {4}^{7} \times {4}^{ - 5} [/tex]
Use product law of indices
i.e
[tex] {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
( powers are added in multiplication of same base)
[tex] = {4}^{7 + ( - 5)} [/tex]
[tex] = {4}^{7 - 5} [/tex]
[tex] = {4}^{2} [/tex]
Hope this helps...
Best regards!
Which function models the geometric sequence in the table?
Hope you understand :)
7 + x - 15 = -2.67 solve for x
Answer:
5.33
Step-by-step explanation:
Move your numbers so that they're separate from the variables. You should now have x = -2.67 + 8; x = 5.33
Answer:
x=5.33
Step-by-step explanation:
7+x-15=-2.67
7-15+x=-2.67
Add 7 and -15
-8+x=-2.67
Add 8 on both sides
which equal to 5.33
x=5.33
The tens digit in a two digit number is 4 greater than one’s digit. If we interchange the digits in the number, we obtain a new number that, when added to the original number, results in the sum of 88. Find this number
Answer:
The original digit is 62
Step-by-step explanation:
Let the Tens be represented with T
Let the Units be represented with U
Given:
Unknown Two digit number
Required:
Determine the number
Since, it's a two digit number, then the number can be represented as;
[tex]T * 10 + U[/tex]
From the first sentence, we have that;
[tex]T = 4 + U[/tex]
[tex]T = 4+U[/tex]
Interchanging the digit, we have the new digit to be [tex]U * 10 + T[/tex]
So;
[tex](U * 10 + T) + (T * 10+ U) = 88[/tex]
[tex]10U + T + 10T + U= 88[/tex]
Collect Like Terms
[tex]10U + U + T + 10T = 88[/tex]
[tex]11U + 11T = 88[/tex]
Divide through by 11
[tex]U + T = 8[/tex]
Recall that [tex]T = 4+U[/tex]
[tex]U + T = 8[/tex] becomes
[tex]U + 4 + U = 8[/tex]
Collect like terms
[tex]U + U = 8 - 4[/tex]
[tex]2U = 4[/tex]
Divide both sides by 2
[tex]U = 2[/tex]
Substitute 2 for U in [tex]T = 4+U[/tex]
[tex]T = 4 + 2[/tex]
[tex]T = 6[/tex]
Recall that the original digit is [tex]T * 10 + U[/tex]
Substitute 6 for T and 2 for U
[tex]T * 10 + U[/tex]
[tex]6 * 10 + 2[/tex]
[tex]60 + 2[/tex]
[tex]62[/tex]
Hence, the original digit is 62
The number of job applications submitted before landing an interview are normally distributed with a population standard deviation of 4 applications and an unknown population mean. A random sample of 19 job seekers is taken and results in a sample mean of 55 applications. The confidence intervalis (52.87.57.14). What is the margin of error? Round to two decimal places.
Answer:
The margin of error = 2.13
Step-by-step explanation:
Explanation:-
Given random sample size 'n' =19
mean of the sample(x⁻) = 55 applicants
Given standard deviation of the Population(S.D) = 4
Given confidence intervals are
((52.87.57.14)
we know that The Margin of error is determined by
[tex]M.E = Z_{\alpha } \frac{S.D}{\sqrt{n} }[/tex]
The confidence intervals are determined by
(x⁻ - M.E , x⁻+ M.E)
Step(ii):-
Given confidence intervals are
((52.87.57.14)
Now equating
(x⁻ - M.E , x⁻+ M.E) = ((52.87 , 57.14)
Given mean of the sample x⁻ = 55
( 55 - M.E , 55 + M.E) =((52.87.57.14)
Equating
55 - M.E = 52.87
M.E = 55 - 52.87
M.E = 2.13
Final answer:-
The margin of error = 2.13