Answer:
In a vacuum, light travels at 670,616,629 mph (1,079,252,849 km/h). To find the distance of a light-year, you multiply this speed by the number of hours in a year (8,766). The result: One light-year equals 5,878,625,370,000 miles (9.5 trillion km).7. (a) At a distance of d/5 from a positive charge, by what factor is the electric potential changed: (1) 1/5, (2) 5, (3) 1/25 or (4) 25? Why? (b) How far from a +2.0 uC charge is a point with an electric potential value of 15KV? (c) How much of a change in potential would occur if the point were moved to three times the distance?
Answer:
it would change and the points would be off because of the change
A 80 N force is needed to slide a 50.0 kg box across a flat surface at a constant velocity. What is the coefficient of kinetic friction between the box and the floor
Answer:
0.16
Explanation:
Given data
Force F= 80N
Mass m= 50kg
Reaction R= Weight= mg= 50*9.81= 490.5N
We know that
F=UR
Substitute and solve of U
U=F/R
U= 80/490.5
U=0.16
Hence the coefficient of friction is 0.16
g A boat is anchored 2000 ft from shore anddirects its searchlight towards an automobile travelingdown the straight road. At the particular moment whenthe distance rfrom the searchlight to the automobile is3000 ft, the automobile has speed 80 ft/s and increasesits speed at a rate of 15 ft/s2 down the road.Find the required angular velocity and angularacceleration of the boat's searchlight to track the automobile at this instant.(Answers: 0.018 rad/s CCW, 0.004 rad/s2 CCW)
Answer:
Explanation:
The distance of searchlight will act as radius R and velocity of car may be supposed to be tangential velocity v . We are required to calculate angular velocity ω .
v = 80 ft /s
R = 3000 ft
ω = v / R
= 80 / 3000 = .027 rad / s
For angular acceleration the formula is
angular acceleration α = a / R
a is linear acceleration = 15 ft / s²
α = 15 / 3000 = .005 rad / s².
Given that the frequency of an EM wave is 4THz,what is the wavelength?
a) 75,000um
b) 75,000nm
c) 75,000pm
d) 75,000A
Answer:
B. 75,000nm
Explanation:
The wavelength of a wave can be calculated thus;
λ = v/f
Where;
λ = wavelength (m)
v = velocity of light = 3 × 10^8m/s
f = frequency (Hz)
According to this question, the EM wave has a frequency of 4THz i.e. 4 Terahertz = 4 × 10^12Hz
λ = 3 × 10^8 ÷ 4 × 10^12
λ = 3/4 × 10^(8-12)
λ = 0.75 × 10^-4
λ = 0.000075m
Based on the options given, this value is equivalent to 75,000nm, which means 75000 × 10^-9m.
What recreational drug does an alcopop contain?
An "alcopop" is a term used to describe a flavored alcoholic beverage that typically resembles a soft drink or a fruit juice in appearance and taste. It is also referred to as a "ready-to-drink" (RTD) beverage.
Alcopops are often targeted toward younger consumers and are known for their sweet and fruity flavors, which can mask the taste of alcohol.
The specific recreational drug that an alcopop contains is alcohol itself. Alcohol, or ethanol, is a psychoactive substance that can have intoxicating effects when consumed.
It is considered a recreational drug because of its ability to alter consciousness, impair judgment and coordination, and produce pleasurable or mood-altering effects.
The alcohol content in alcopops can vary, but it is typically lower than in pure spirits or liquors. This is often achieved through dilution with other ingredients, such as carbonated water or fruit juices, to create a milder alcoholic beverage.
Alcopops may also contain additional flavorings, sweeteners, and additives to enhance their taste and appeal.
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is found in wood or straw?*
2.
Sucrose
2.Xylose
3.Maltose
4.Galactose
The membrane that surrounds a certain type of living cell has a surface area of 4.7 x 10-9 m2 and a thickness of 1.3 x 10-8 m. Assume that the membrane behaves like a parallel plate capacitor and has a dielectric constant of 4.7. (a) The potential on the outer surface of the membrane is 79.5 mV greater than that on the inside surface. How much charge resides on the outer surface
Answer:
Q = 1.2*10⁻¹² C
Explanation:
For any capacitor, by definition the capacitance C is equal to the relationship between the charge on one of the conductors and the potential difference between them, as follows:[tex]C = \frac{Q}{V} (1)[/tex]
For the special case of a parallel plate capacitor, just by application of Gauss' law to a rectangular surface half out of the outer surface, and half inside it, it can be showed that the value of the capacitance C is a parameter defined only by geometric constants, as follows:[tex]C = \frac{\epsilon_{0}*\epsilon _{r} * A}{d} (2)[/tex]
So, due to the left sides in (1) and (2) are equal each other, right sides must be equal too.Replacing ε₀, εr (dielectric constant), A, d and V by their values, we can solve for Q, as follows:[tex]Q =\frac{\epsilon_{0} * \epsilon_{r} *A* V}{d} = \frac{(8.85*(4.7)^{2}*79.5)e-24 (F/m*m2*V)}{1.3e-8m} = 1.2e-12 C = 1.2 pC (3)[/tex]
1. State the law of conservation of energy and what it means for you as a human considering how energy works.
2. Explain how different forms of energy are related.
PLEASE I NEED HELP!! I NEED IT NOW!! AND PLEASE DO IT IN YOUR OWN WORDS!! THANK YOU!
Answer: 1. The law of consevation of energy sates that energy can neither be created nor destroyed. It can only be transformed or transfered from one form to another. The law of conservation of energy is found everywhere for example, Water falls from the sky, converting potential energy to kinetic energy.
2. Different forms of energy are related because energy cannot be created or destroyed. they can all be transformed into from one form to another.
Explanation:
A 0.20 kg mass is oscillating on Planet X at a small angle from a light string of length 0.15 m with a period of
0.75 s.
What is the acceleration of gravity on Planet X?
Round answer to two significant digits.
Answer:
11 m/s^2
Explanation:
We can determine the acceleration of gravity from the pendulum’s period and length.
Let’s use the equation for the period of a pendulum and solve for the acceleration of gravity:
PLEASE HELP ME EXPLAIN THESE QUESTIONS IT'S FOR ANATOMY AND PHYS
Let’s put the information you just learned into practice: perform a respiration check on a partner who is at least 12 years old. You may, as recommended by the sites, “sneak” the respiration check while checking their pulse as long as your partner has consented for you to check their “vital signs.” Telling someone you are checking their pulse, but instead are planning to check their respiratory rate, would be unethical. Based on your experiences, answer the following questions.
1.Pretend you are entering the respiration rate into a medical record. How would you record it?
2.Was the subject’s respiration rate in a health range?
3.What would be different about detecting an abnormal respiration rate if you were checking the respiration rate of a four year old?
4.Do you think you got an accurate respiration rate? Is there any reason to think the subject might have altered their breathing?
5.What exact steps did you take to measure the respiration rate, including any questions you asked or instructions you gave?
6.How long did you measure for?
7. Which parts of the DRABC acronym deal directly with the respiratory system?
8.Some first-aid practitioners also recommend a secondary assessment, which involves a head-to-toe inspection of the patient. Why would this assessment be important?
9.Under which conditions should CPR be performed? What checks or actions should be performed first?
Answer:
I tried
Explanation:
You have to check a 12 year olds respiration rate by Siting them down and trying to relax. It's best to take the respiratory rate while sitting up in a chair or in bed. Measure their breathing rate by counting the number of times their chest or abdomen rises over the course of one minute. Then Record this number. Now you have to answer the first few questions based on that.
Heart rate, blood pressure, respiratory rate and temperature are the big four vital signs.
8. Secondary assessments are used in order to determine the injury, how the injury occurred, how severe the injury is, and to eliminate further injury and that is why it is important.
9. It should only be performed when a person shows no signs of life or when they are unconscious, unresponsive, not breathing or not breathing normally.
In order to perform CPR, you need to check the scene and the person. Make sure the scene is safe, then tap the person on the shoulder and shout "Are you OK?" to ensure that the person needs help. Then pen the airway, Check for breathing, Push hard, push fast, deliver rescue breaths, continue CPR steps.
The normal respiration rate is in the range from 12 to 16 breaths per minute.
How to record respiration rate?The respiration rate is measured when a person is present at rest. For recording the respiration rate, we just count the number of breaths for one minute by counting how many times the chest rises.
The subject’s respiration rate will be considered in a health range if its respiration rate in the range from 12 to 16 breaths per minute.
Exact steps that you take to measure the respiration rate is to count the number of breaths for an entire minute or count for 30 seconds and multiply that number by two. We can measure the respiration rate for about one minute.
DRABC is an abbreviation that stands for Danger, Response, Airway, Breathing and Circulation. Airway, Breathing and Circulation are the parts of DRABC acronym that deal directly with the respiratory system.
A secondary assessment that involves a head-to-toe inspection of the patient is also necessary because it is done to do inspection of the whole body in order to check the physical condition of the patient. CPR should be performed when a person is unconscious, having abnormal breathing and not breathing.
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Explain why objects in water appear to be a different size then the same objects above the water.
Answer:
the answer is the third one since water reflects it
Explanation:
A 20.0 N force is necessary to stretch a spring 0.500 m. What is the spring constant of this spring?
The spring constant : k = 40 N/m
Further explanationGiven
Force = 20 N
The displacement of the spring=x=0.5 m
Required
The spring constant = k
Solution
Hooke's Law
F = k.x
k = F/x
Input the value :
k = 20/0.5
k = 40 N/m
REAL ANSWER OR REPORTED, REAL GETS BRAINLIST
2. What is the weight of:
A 32 kg child
An 82 kg linebacker
A 1000 kg car
3. What is the mass of:
A student who weighs 524 Newtons
A table that weighs 441 Newtons
A hammer that weighs 51 Newtons
4. A 15 kg box sits motionless on the floor.
Draw a force diagram for the box.
Write a vertical Fnet equation for the box.
Determine the weight of the box.
What is the magnitude of the normal force?
Answer:
32kg = 313.6N
82kg = 803.6N
1000kg = 9800N
524N = 53.47kg
441N = 45kg
51N = 5.20kg
for the box diagram the weight of the 15kg box is 147N
the net force will be equal to zero because the box is motionless
Fg goes downward arrow of box 147N
Fnorm goes upward arrow of box 147N
Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Further, the electric potential is taken to be zero at infinity. If the electric potential at a given point in the region is zero, which of the following statements must be true?
A. The electric field is zero at that point.
B. The charges have the same sign and are symmetrically arranged around the given point.
C. The electric potential energy is a minimum at that point.
D. There is no net charge in the region.
E. Some charges in the region are positive, and some are negative.
Answer:
E. Some charges in the region are positive, and some are negative.
Explanation:
Electric potential is given as;
[tex]V = \frac{W}{Q}[/tex]
where;
W is the work done in moving a charge between two points which have a difference in potential
Q is quantity of charge in the given region
If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.
Therefore, the correct statement in the given options is "E"
E. Some charges in the region are positive, and some are negative.
Help on this question ‼️
Answer:
I think the option b
Is the answer
Answer:
C
Explanation:
after a CCW rotation it would become a waning gibbous, so after a Clockwise rotation it would be a waxing gibbous (opposite)
Francine is dragging a heavy toolbox across a rough, cement floor.
What is a contact force that is acting on the box as Francine pulls it.
A.
static electricity
B.
gravity
C.
magnetism
D.
friction
Answer:
D. Friction
Explanation:
Answer:
d. friction
I took it on study island and got it correct thanks to the other guy that has answered
Explanation:
Someone help me with this PE question?
Answer:
Your abdominals
Explanation:
According to the law of conservation of energy, how will the sum of the kinetic
and potential energies compare at the four points?
Can you also answer questions 1-5
Answer:
I think that this ans may help you
A car completes a journey in 2 hours. Its average speed over this journey was 45 mph. Calculate the distance travelled by the car in miles.
What is light? Let's tallk about anything
a body is projected at an angle of 30 degrees to the horizontal with a velocity of 15m/s, calculate the time it takes to reach the greatest height take g=10ms2 and neglect air resistance
Explanation:
The vertical component the velocity of the projectile is 15 m/s x sin 30 = 7.5 m/s.
The body is accelarating downwards at 10 m/s^2.
This means that every second its upward velocity reduces by 10 m/s.
So if the body is travelling upwards at 7.5 m/s then how long does it take for the velocity to become 0?
(7.5 m/s) / (10 m/s^2) = 0.75 s
A 0.11 kg bullet traveling at speed hits a 18.3 kg block of wood and stays in the wood. The block with the bullet imbedded in it moves forward with a velocity of 8.8 m/s. What was the velocity (speed) of the bullet immediately before it hit the block (in m/s)?
Explanation:
The energy of the system before the collision must equal the energy after the collision.
After the collision the bullet and the block have a total mass of 18.41 kg and they move at a speed of 8.8 m/s. The kinetic energy after the collision is
[tex]\frac{18.41 kg (8.8 m/s)^2}{2} = 713 J[/tex]
Before the collision only the bullet has kinetic energy.
So we can now determine the speed of the bullet using
[tex]\frac{0.11kg (v^2)}{2} = 713 J\\v = 114 m/s[/tex]
A ball player catches a ball 3.10 s after throwing it vertically upward. a) with what speed did he throw it? b) what height did it reach?
Answer:
speed=30.41, height=94.27
Explanation:
since the motion is vertical upward means the motion is against gravitational force and the initial velocity of the ball was zero.
Which two options are homogeneous mixtures?
A. Sand
B. A wet sponge
C. Liquid dishwashing soap
O D. Vinegar
Answer:
Liquid dishwashing soap
Vinegar
A blue ball is thrown upward with an initial speed of 24.1 m/s, from a height of 0.5 meters above the ground. 2.9 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 7.2 m/s from a height of 32 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2. Take up as the positive direction.
1. What is the speed of the blue ball when it reaches its maximum height?.
2. How long does it take the blue ball to reach its maximum height?.
3. What is the maximum height the blue ball reaches?.
4. What is the height of the red ball 3.77 seconds after the blue ball is thrown?.
5. How long after the blue ball is thrown are the two balls in the air at the same height?.
Answer:
1. Speed=0
2. 2.46 s
3.30.1 m
4. 22.0 m
5.1.004 s
Explanation:
We are given that
Initial speed of blue ball, u=24.1 m/s
Height of blue ball from ground y_0=0.5 m
Initial speed of red ball , u'=7.2 m/s
Height of red from ground=y'0=32 m
Gravity, g=[tex]9.81ms^{-2}[/tex]
1.When the ball reaches its maximum height then the speed of the blue ball is zero.
2.v=0
[tex]v=u+at[/tex]
Using the formula and substitute the values
[tex]0=24.1-9.81t[/tex]
Where g is negative because motion of ball is against gravity
[tex]24.1=9.81t[/tex]
[tex]t=\frac{24.1}{9.81}=2.46s[/tex]
3.[tex]y=y_0+ut+\frac{1}{2}at^2[/tex]
Using the formula
[tex]y=0.5+24.1(2.46)-\frac{1}{2}(9.81)(2.46)^2[/tex]
[tex]y=30.1 m[/tex]
4.Time of flight for red ball=3.77-2.9=0.87s
[tex]y'=32-7.2(0.87)-\frac{1}{2}(9.81)(0.87)^2[/tex]
[tex]y'=22.0m[/tex]
Hence, the height of red ball 3.77 s after the blue ball is 22.0 m.
5.According to question
[tex]0.5+24.1(t+2.9)-\frac{1}{2}(9.81)(2.9+t)^2=32-7.2t-\frac{1}{2}(9.81)t^2[/tex]
[tex]0.5+24.1t+69.89-4.905(t^2+5.8t+8.41)=32-7.2t-4.905t^2[/tex]
[tex]0.5+24.1t+69.89-4.905t^2-28.449t-41.25105=32-7.2t-4.905t^2[/tex]
[tex]0.5+69.89-41.25105-32=-24.1t+28.449t-7.2t[/tex]
[tex]-2.86105=-2.851t[/tex]
[tex]t=\frac{2.86105}{2.851}=1.004 s[/tex]
Hence, 1.004 s after the blue ball is thrown are the two balls in the air at the same height.
Two positive charges are fixed a distance apart.the sun of their charges is Qt.what charge must each have in order to maximise the electric force between them
Answer:
Both charges must have the same charge, Qt/2.
Explanation:
Let the two charges have charge Q1 and Q2, respectively.
Use Coulombs's Law to find an expression for the force between the two charges.
[tex]F = k_e\frac{Q_1Q_2}{r^2}[/tex], where
Ke is Coulomb's contant and
r is the distance between the charges.
We know from the question that
Q1 + Q2 = Qt
So,
Q2 = Qt - Q1
[tex]F = k_e\frac{Q_1(Q_t - Q_1)}{r^2}[/tex]
Simplify to obtain,
[tex]F = \frac{k_e}{r^2} (Q_tQ_1 - Q_1^2)[/tex]
In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.
Differentiate F with respect to Q1,
[tex]\frac{dF}{dQ_1} = \frac{k_e}{r^2} (Q_t - 2Q_1)[/tex]
Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.
[tex]\frac{k_e}{r^2} (Q_t - 2Q_1) = 0\\Q_t - 2Q_1 = 0\\2Q_1 = Q_t\\Q1 = \frac{Q_t}{2}[/tex]
It follows that
[tex]Q_2 = \frac{Q_t}{2}[/tex].
A crane is used to lower weights into a lake for an underwater construction project. Determine the tension in the cable of the crane due to a concrete sphere with a radius of 2 m when the sphere is lowered into the water. The concrete has a specific gravity of 2.8.
Answer:
Tension in the cable = 591292.8 N or 591.3 kN
Explanation:
Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid
Weight of object in air = mass * acceleration due to gravity, g
Since mass is not given, it is obtained from the formula, mass = density * volume
Volume of the sphere = 4/3πr³ where r, radius = 2 m; π = 22/7
volume = 4/3 * 22/7 * (2m)³
volume of sphere = 33.52 m³
Density of concrete sphere = specific gravity * density of water
where, specific gravity = 2.8, density of water = 1000 kg/m³
density of concrete = 2.8 * 1000 kg/m³
density of concrete = 2800 kg/m³
acceleration due to gravity, g = 9.8 m/s²
Thus, weight of concrete = 2800 kg/m³ * 33.52 m³ * 9.8 m/s² = 919788.8 N
Upthrust = density of water * volume of sphere * g
Upthrust = 1000 kg/m³ * 33.52 m³ * 9.8 m/s² = 328496 N
The tension in the cable is the calculated as below;
Tension in the cable = Weight of object in air - upthrust/bouyancy due to the liquid
Tension in cable = 919788.8 N - 328.496 N = 591292.8 N
Therefore, tension in the cable is 591292.8 N or 591.3 kN
Mae puts on her new winter scarf. Signals are sent to her brain telling her that the scarf is soft. Which sense provides her brain with this information?
Answer:
Touch
Explanation:
While sliding a couch across a floor, Hannah and Andrea exerts forces FH and FA on the couch. Hannah's force is due north with a magnitude of FH = 59 N and Andrea's force is θ = 22° east of north with a magnitude of FA = 155 N. In this problem, use a coordinate system with y directed north and x directed east.
Part (a) Find the net force in the y-direction in Newtons.
Part (b) Find the net force in the x-direction in Newtons.
Part (c) Calculate the angle in degrees north of east of the net force exerted on the couch by Hannah and Andrea, F HAF→HA.
Part (d) Hannah and Andrea's housemates, David and Stephanie disagree with the move and want to prevent its relocation. Their combined force F DSF→DS must be equal and opposite to that of FHAF→HA. What is the magnitude in Newtons of the force F DSF→DS which will prevent the relocation?
Answer:
a) 202.7 N
b) 58.1 N
c) 74.1º N of E.
d) 210.9 N
Explanation:
a)
The net force exerted in the y-direction, will be the sum of FH (which is directed northwards) and the y-component of FA.Since the magnitude of FA is 155 N and the angle of FA with the y-axis, is 22º (E of N), we can find the N-S component of FA, just applying the the definition of cosine, to the triangle defined by FA, the y- axis and a segment parallel to the x- axis between FA and the y-axis, as follows:[tex]F_{Ay} = F_{A} * cos \theta = 155 N* cos 22 = 143.7 N (1)[/tex]
⇒ Fy = FH + FAy = 59 N + 143.7 N = 202.7 N (2)
b)
We can proceed exactly in the same way for the x-axis. Since FH is directed due North, it has no component along the x-axis.So, Fx is directly the component of FA along the x-axis, which can be found applying the definition of sine to the same triangle than in a) as follows:[tex]F_{x} = F_{A} * sin \theta = 155 N* sin 22 = 58.1 N (3)[/tex]
c)
Taking the same triangle than in a) and b), we can apply the definition of tangent, in order to find the angle between F and the x-axis, as follows:[tex]tg \theta = \frac{F_{y}}{F_{x}} = \frac{202.7N}{58.1N} = 3.5 (4)[/tex]
⇒ θ = tg⁻¹ (3.5) = 74.1º N of E. (5)
d)
In order to be equal and opposite to the combined force FH+FA, it must have the same magnitude.This magnitude can be found applying the Pythagorean Theorem to the same triangle that we used in a), b) and c):[tex]F_{DS} = \sqrt{(F_{x} ^{2} +F_{y} ^{2})} = \sqrt{(58.1N)^{2}) + (202.7N)^{2} } = 210.9 N (6)[/tex]
Tara goes kayaking at sunrise. She rows 50 feet in 20 seconds. She transfers
100 joules of energy. What is Tara's power?
5 W 10 W
50 W
2 W