how is a student load different from a scholarship

Answers

Answer 1

Answer: student loan you have to pay back. Scholarships are free money basically

Explanation:


Related Questions

If carpet costs $3.25 a square foot, what would it
cost to replace a 200 square foot room?

Answers

Answer:

650$=200 X 3.25

Explanation:

Answer:

$650

Explanation:

$3.25 times 200 equals $650

Wire will always be stranded when it is larger than which of the following?

12 AWG

8 AWG

4 AWG

6 AWG

Answers

Answer:

got em blake the red head

Explanation:

Wire will always be stranded when it is larger than 6 AWG. Check more about American Wire Gauge below.

What is AWG rule about?

The American Wire Gauge (AWG) is known to be a kind of standardized wire gauge system that are known to be widely used in all parts of the United States. It centers around the diameter of electrical wire.

Conclusively, AWG general rules of thumb states that for every 6 gauge one has to lower the wire diameter and as such, Wire will always be stranded when it is larger than 6 AWG.

Learn more about Wire from

https://brainly.com/question/25922783

Which feature would be used to measure OUTER diameter?

Answers

Answer:

Calipers

Explanation:

Calipers can also be used to measure holes of different shapes: square, rectangular, cylindrical or hexagonal. The lower set of jaws on the caliper is used to measure the outer diameter of a cylinder. It will also give you the total length or width of an object.

What is the purpose of a set of curly braces { } in pseudocode?

Answers

Answer:

Braces are used to signify a block of code. We look at the curly braces as a guide to where code starts and when it ends.

Explanation:

cos square there + cos square theta multiply cot square theta = cot square theta​

Answers

Explanation:

We need to prove that : [tex]\cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta=\cot^2\theta[/tex]

Taking LHS : [tex]\cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta[/tex]

Taking [tex]\cos^2\theta[/tex] common as follows :

[tex]\cos^2\theta(1+ \cot^2\theta)[/tex] ...(1)

We know that :

[tex]cosec^2\theta-\cot^2\theta=1\\\\cosec^2\theta=1+\cos^2\theta[/tex] ....(2)

Use equation (2) in equation (1) as follows :

[tex]\cos^2\theta{\cdot} cosec^2\theta[/tex]

We know that : [tex]cosec\theta=\dfrac{1}{\sin\theta}[/tex]

So,

[tex]\cos^2\theta{\cdot} \dfrac{1}{\sin^2\theta}\\\\=\cot^2\theta[/tex]

=RHS

Hence, LHS = RHS

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