Answer: student loan you have to pay back. Scholarships are free money basically
Explanation:
If carpet costs $3.25 a square foot, what would it
cost to replace a 200 square foot room?
Answer:
650$=200 X 3.25
Explanation:
Answer:
$650
Explanation:
$3.25 times 200 equals $650
Wire will always be stranded when it is larger than which of the following?
12 AWG
8 AWG
4 AWG
6 AWG
Answer:
got em blake the red head
Explanation:
Wire will always be stranded when it is larger than 6 AWG. Check more about American Wire Gauge below.
What is AWG rule about?The American Wire Gauge (AWG) is known to be a kind of standardized wire gauge system that are known to be widely used in all parts of the United States. It centers around the diameter of electrical wire.
Conclusively, AWG general rules of thumb states that for every 6 gauge one has to lower the wire diameter and as such, Wire will always be stranded when it is larger than 6 AWG.
Learn more about Wire from
https://brainly.com/question/25922783
Which feature would be used to measure OUTER diameter?
Answer:
Calipers
Explanation:
Calipers can also be used to measure holes of different shapes: square, rectangular, cylindrical or hexagonal. The lower set of jaws on the caliper is used to measure the outer diameter of a cylinder. It will also give you the total length or width of an object.
What is the purpose of a set of curly braces { } in pseudocode?
Answer:
Braces are used to signify a block of code. We look at the curly braces as a guide to where code starts and when it ends.
Explanation:
cos square there + cos square theta multiply cot square theta = cot square theta
Explanation:
We need to prove that : [tex]\cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta=\cot^2\theta[/tex]
Taking LHS : [tex]\cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta[/tex]
Taking [tex]\cos^2\theta[/tex] common as follows :
[tex]\cos^2\theta(1+ \cot^2\theta)[/tex] ...(1)
We know that :
[tex]cosec^2\theta-\cot^2\theta=1\\\\cosec^2\theta=1+\cos^2\theta[/tex] ....(2)
Use equation (2) in equation (1) as follows :
[tex]\cos^2\theta{\cdot} cosec^2\theta[/tex]
We know that : [tex]cosec\theta=\dfrac{1}{\sin\theta}[/tex]
So,
[tex]\cos^2\theta{\cdot} \dfrac{1}{\sin^2\theta}\\\\=\cot^2\theta[/tex]
=RHS
Hence, LHS = RHS