How does the comet's energy change as it moves from point B to point C?
A. KE increases, GPE increases
B. KE increases, GPE decreases
C. KE decreases, GPE increases
D. KE decreases, GPE decreases


Need it asap please help me thanks in advance just trying to pass my senior year :)

Answer:

The first layer is the crust a very thin layer compared to any other

the second layer is the mantal there is 2 parts to the matal there is a solid mental and a hard mental

the last part is the core the most dense part of earth

Explanation:

Answer:

plane on edge

Explanation:

Answer: Infrastructure is the general term for the basic physical systems of a business, region, or nation. and it involves the production of public goods

Explanation:

Answer:

a constant speed of 2 m/s followed by speed of zero

Explanation:

I got it right on the test.

☁️ Answer ☁️

The main disadvantage of convex mirrors is that they show a distorted picture of what is behind you. Distances are seen not as they are in reality and things appear closer than they really are. They are showing cars approximately twice as far away as they actually are.

Hope it helps.

Have a nice day hyung!~ ￣▽￣❤️

Answer:

disadvantage is that convex mirror is that they make it appear like those objects are at a more noteworthy distance than they actually are. It always gives a virtual, erect and a diminished image.

Answer:

answer: no

Explanation:

Answer:

a. 6.04 m/s^2 (3 sig. fig.) b.  T = 30.2 N

Explanation:

a) Assume that the acceleration due to gravity is 9.81 m/s^2 downwards

8x9.81 = (5+8)a

a = 6.04 m/s^2 (3 sig. fig.)

b) Using the results from (a)

   T = 5(6.04)

   T = 30.2 N

Answer:

Peregrine Falcon/hawk

Explanation:

i really dunno if you are talking about brids that can't fly or not.

Answer:

Decreases to half.

Explanation:

From the question given above, the following data were obtained:

Initial mass (m₁) = m

Initial force (F₁) = F

Initial acceleration (a₁) =?

Final mass (m₂) = ½m

Final force (F₂) = ¼F

Final acceleration (a₂) =?

Next, we shall determine a₁. This can be obtained as follow:

F₁ = m₁a₁

F = ma₁

Divide both side by m

a₁ = F / m

Next, we shall determine a₂.

F₂ = m₂a₂

¼F = ½ma₂

2F = 4ma₂

Divide both side by 4m

a₂ = 2F / 4m

a₂ = F / 2m

Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:

a₁ = F / m

a₂ = F / 2m

a₂ : a₁ = a₂ / a₁

a₂ / a₁ = F/2m ÷ F/m

a₂ / a₁ = F/2m × m/F

a₂ / a₁ = ½

Cross multiply

a₂ = ½a₁

From the illustrations made above, the acceleration of the car will decrease to half the original acceleration

Answer:

yes? what is the quseten

Explanation:

v is the max speed it can go   if you droped a egg and a watermelon off a roof 20ft high thay would hit the ground at the same time becuse gravaty will effect them qualy. if you drop them from a jet liner 20,000 ft up thay will hit max.v. wich depends on mass so thay will hit at differnt times.  

C. Teaching the parents tp persistetly support the teen's unstable self-image

Explanation:

Therapeutic boarding schools doesn't help parents cope with their teens by: c. teaching the parents to persistently support the teen's unstable self-image.

In Psychology, there are different types of personality disorder and these include the following:

Basically, a therapeutic boarding school is an institution that is established to help parents positively cope with offspring who have borderline personality disorder.

However, therapeutic boarding schools doesn't teach parents to persistently support any teen's unstable self-image.

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Answer:

[tex]\boxed {\boxed {\sf 3.5 \ Newtons}}[/tex]

Explanation:

Force is the product of mass (in kilograms) and acceleration (in meters per square second).

[tex]F=ma[/tex]

The mass of the ball is 140 grams and the acceleration is 25 m/s². Convert grams to kilograms.

Substitute the values into the formula.

[tex]F= 0.14 \ kg * 25 \ m/s^2[/tex]

Multiply.

[tex]F= 3.5 \ kg*m/s^2[/tex]

[tex]F= 3.5 \ N[/tex]

3.5 Newtons of force are required.

Answer:

A ruler.

Explanation:

Just measure height, length and width and multiply each.

Answer:

B

Explanation:

.....................

Answer:

B. Rapid Physical Growths

E = sigma/2 * epselon naught

E = 300 * 10^-9/(2 * 8.854 * 10^-12)

E = 1.7 * 10^4 N/C

Assuming that the electric field is uniform all across the surface:

Then, Electric flux = E * A

Electrix flux = 1.7 * 10^4 * 15 = 2.5 x 10^5 Nm^2/C

It should be b)

The electric flux through the given area of the conductor is

2.26 x 10³ Nm²/C.

Surface charge density of the conductor, σ = 300 x 10⁻⁹ C/m²

Area of the conductor, A = 15 m²

The equation for surface charge density is,

σ = q/A    where q is the charge in the conductor.

So,

Charge, q = σ A

q =  300 x 10⁻⁹/15

q = 2 x 10⁻⁸C

Therefore,

Electric flux through the conductor, Φ = q/ε₀

Φ = 2 x 10⁻⁸/8.85 x 10⁻¹²

Φ = 2.26 x 10³ Nm²/C

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Explanation:(2.5kg) (7.5) m/s +70 kg(0) =(2.5kg +70 kg (v3) 18. 75 =72.5 =v3

Answer:

λ = 6.802 10⁻⁷ m,  wavelength corresponds to orange almost red

Explanation:

The expression for constructive interference is

          d sin θ = m λ

let's use trigonometry

          tan θ = y / L

          tan θ = sin θ / cos θ

interference experiments angles are very small

         tan θ = sin  θ = y / L

substituting

          [tex]d \ \frac{y}{L}[/tex] = m λ

in this case they indicate the separation of the slits d = 7.16 10-5 m, the order of the interference is m = 4, the distance y = 3.8 10-2 m and the separation to the screen L = 1 m

A) they ask us for the wavelength

         λ = [tex]\frac{d y}{ m L}[/tex]

let's calculate

         λ = 7.16 10⁻⁵  3.8 10⁻² /(4 1)

         λ = 6.802 10⁻⁷ m

B) Let's reduce the wavelength to nm

          λ = 6.802 10⁻⁷ m (109 nm / 1m)

          λ = 680.2 nm

this wavelength corresponds to orange almost red

Answer:

F. 20 cm m. The stretching force is the weight. (W = mg) of the 4 -kg mass: F = (4 kg)(9.8 m/s2) = 39.2 N.

Either the oscillating mass or the spring constant can be modified to alter the oscillator's natural resonant frequency.

Consider a spring with an unstretched length l, a spring constant of k, and a mass M hanging from it. The oscillation frequency would be k/M if the spring's mass were ignored. According to the rule that was cited, the effect of the spring mass would be to change M in the equation for to M + m/3.

The oscillating system's frequency would rise if the spring was firmer. The resonance frequency of the system would be lowered by adding mass to it.The spring mass would have the effect of changing M in the equation for to M + m/3 in accordance with the cited rule.

Therefore, F. 20 cm m. The weight (W = mg) of the 4 kg mass is the stretching force: F = (4 kg)(9.8 m/s2) = 39.2 N.

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Answer:

true

Explanation:

Answer:

False

Explanation:

includess lighting and powerful winds over 50Mph,creates hail and causes flash flooding and also tornadoes

Answer:

Reena has more power.....

Hope it helps!!!

Answer:

K.E = 4800 Joules.

Explanation:

Given the following data;

Mass = 600 kg

Velocity = 4 m/s

To find the kinetic energy;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

[tex] K.E = \frac{1}{2}*600*4^{2}[/tex]

[tex] K.E = 300 * 16 [/tex]

K.E = 4800 Joules.

Answer:

426

Explanation:

I think the answer is 426 or 120 but we. can get 120 when we add

Answer:

h = 3.26 m

Explanation:

Given that,

Mass of the soccerball, m = 250 g

Speed of the ball, v = 8 m/s

We need to find the height upto which the soccerball is raised. Let the height be h. Using the conservation of energy i.e.

[tex]mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{8^2}{2\times 9.8}\\\\h=3.26\ m[/tex]

So, it will raised up to a height of 3.26 m.

Answer:

9.66E4 J

Explanation:

We have that  the energy required to raise the temperature of the radiator-water system by

1°K

E=116.85KJ

From the question we are told  

A radiator made out of iron of specific heat capacity 450 J/kgk has a mass of 45.0 kg  and is filled with 23.0 kg of water of specific heat capacity 4200 J/kgK.

Determine the energy required to raise the temperature of the radiator-water system by  1°K

Generally the equation for the Energy  is mathematically given as

[tex]E=((mc)_i+mc_w)dt\\\\Therefore\\\\E=(45* 450 +4200*23)1\\\\E=116850J\\\\E=116.85KJ\\\\[/tex]

Therefore

the energy required to raise the temperature of the radiator-water system by

1°K

E=116.85KJ

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Answer:

no electric field line don't song closed loop.

Answer:

F = 1.0178 × 10^(-2) dyne

Explanation:

From stokes law, the viscous force also known as drag force on rain drop is given by the formula;

F = 6πηrv

Where;

η is viscosity

r is radius

v is velocity

We are given;

η = 18 × 10^(-5) poise

r = 0.3 mm = 0.03 cm

v = 1 m/s = 100 cm/s

Thus;

F = 6π × 18 × 10^(-5) × 0.03 × 100

F = 1.0178 × 10^(-2) dyne