Answer:
7.488 × 10^5
Step-by-step explanation:
= 748.8 × 10^3
(engineering notation)
(thousand; prefix kilo- (k))
= 7.488e5
(scientific e notation)
= 7.488 × 105
(scientific notation)
= 748800
Answer:
Its written as
[tex]7.488 \times {10}^{5} [/tex]
Hope this helps you
Please answer this correctly
Answer:
The second question
Step-by-step explanation:
The orca starts at -25 meters. She goes up 25 meters.
up 25 = +25
-25+25=0
Answer:
Option 2
Step-by-step explanation:
The orca swims at the elevation of -25 meters. The orca swims up 25 meters higher than before.
-25 + 25 = 0
Dr. Iske Larkin stated that she had done some work on nutrition in Manatees. One of the questions that she was interested in was what manatees ate. What type of variable would this be?
a. Categorical
b. Quantitative
Answer: Categorical
Step-by-step explanation:
A quantitative variable is represented by a number. An example of a quantitative variable would be how many pounds of food the manatees ate.
Hope it helps <3
Suppose you and your three friends have two dice each. When everyone rolls, what are the chances that there is at least one 6?
...with 6 dice
15,625 / 46,656
33.49 %
31,031 / 46,656
66.51 %
Determine whether the given value is from a discrete or continuous data set. When a car is randomly selected, it is found to have 8 windows. Choose the correct answer below. A. A discrete data set because there are a finite number of possible values. B. A continuous data set because there are infinitely many possible values and those values cannot be counted. C. A continuous data set because there are infinitely many possible values and those values can be counted. D. The data set is neither continuous nor discrete.
Answer:
A discrete data set because there are a finite number of possible values.
Step-by-step explanation:
We are given the following data set below;
When a car is randomly selected, it is found to have 8 windows.
Firstly, as we know that the discrete data is that data that have countable or finite values, and also we can observe at a point value.
On the other hand, the continuous data is that data in which there is a range of values and we can't count or observe each and every value.
So, in our question; as we can observe that we can count all the windows and it is also a finite number which means that the given data set is a discrete data set because there are a finite number of possible values.
Determine if the matrix below is invertible. Use as few calculations as possible. Justify your answer. 3 0 -4 2 0 6 -3 0 8
a. The matrix is invertible. The columns of the given matrix span R^3.
b. The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.
c. The matrix is invertible. The given matrix has 2 pivot positions.
d. The matrix is not invertible. If the given matrix is A, the equation Ax = 0 has only the trivial solution.
Answer:
b. The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.
Step-by-step explanation:
A square matrix is said to be invertible if the product of the matrix and its inverse result into an identity matrix.
3 0 -4
2 0 6
-3 0 8
Since the second column elements are all zero, the determinant of the matrix is zero ad this implies that the inverse of the matrix does not exist(i.e it is not invertible )
A square matrix is said to be invertible if it has an inverse.
The matrix is not invertible. If the given matrix is A, the columns of A do not form a linearly independent set.
The matrix is given as:
[tex]\left[\begin{array}{ccc}3&0&-4\\2&0&6\\-3&0&8\end{array}\right][/tex]
Calculate the determinant
The determinant of the matrix calculate as:
[tex]|A| = 3 \times(0 \times 8- 6 \times 0) - 0(2 \times 8 - 6 \times -3) -4(2 \times 0 - 0 \times -3)[/tex]
[tex]|A| = 3 \times(0) - 0(34) -4(0)[/tex]
[tex]|A| = 0 - 0 -0[/tex]
[tex]|A| = 0[/tex]
When a matrix has its determinant to be 0, then
It is not invertibleIt does not form a linear independent set.Hence, the correct option is (b)
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Graph the solution set for this inequality:
4x - 2y > 8
Answer:
x-intercept: 2 y-intercept= -4
Step-by-step explanation:
First, change the given equation 4x-2y>8 to slope-intercept form, which is y=mx+b. We do this by solving for y.
4x-2y>8. Subtract 4x from each side
-2y> -4x+8. Divide by -2. Don't forget to switch the sign!
y< 2x-4 is our equation in slope-intercept form.
Now, we can graph it. We know the slope (m)= 2 and the y-intercept= -4. Start at -4 and move up two, over one, making points until you can form a line. We can see from the graph that when x=0, (0, -4) y= -4. When y=0, (2, 0), x=2. These are our intercepts of the graph!
Hope this helps!
The graph of inequality 2x - y > 4 is shown in image.
We have to given that,
The inequality is,
⇒ 4x - 2y > 8
Since, A relation by which we can compare two or more mathematical expression is called an inequality.
Now, We can simplify it as,
⇒ 4x - 2y > 8
Take 2 as common,
⇒ 2 (2x - y) > 8
⇒ 2x - y > 4
So, The graph of inequality 2x - y > 4 is shown in image.
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I don't know what to do.
Answer:
104.93 in
Step-by-step explanation:
When we draw out a picture of our triangle, we should see that we need to use sin∅ to solve:
sin23° = 41/x
xsin23° = 41
x = 41/sin23°
x = 104.931
A new landowner has a triangular piece of flat land she wishes to fence. Starting at the first corner, she measures the first side to be 5.7 m long and is directed 0.3 radians north of east. From the second corner, the second side is 9 m long and is directed 0.9 radians west of north. What is the length of the third side of the fence?
Answer:
The length of the third side of fence is 11.4 m
Step-by-step explanation:
Solution:-
- We are to mow a triangular piece of land. We are given the description of motion and the orientation of land-mower while fencing.
- From one corner of the triangular land, the land-mower travels H1 = 5.7 m at θ1 = 0.3 radians north of east. We will use trigonometric ratios to determine the amount traveled ( B1 ) in the east direction.
[tex]cos ( theta_1 ) = \frac{B_1}{H_1}[/tex]
Where,
B1: Is the base length of the right angle triangle
H1: Hypotenuse of the right angle triangle
Therefore,
[tex]B_1 = H_1*cos ( theta_1 )\\\\B_1 = 5.7*cos ( 0.3 )\\\\B_1 = 5.44541 m[/tex]
- Similarly, from the other corner of the triangular land. The land-mower moves a lateral distance of H2 = 9m and directed θ2 = 0.9 radians north of west. We will use trigonometric ratios to determine the amount traveled ( B2 ) in the west direction.
[tex]cos ( theta_2 ) = \frac{B_2}{H_2} \\[/tex]
Where,
B2: Is the base length of the right angle triangle
H2: Hypotenuse of the right angle triangle
Therefore,
[tex]B_2 = H_2*cos ( theta_2 )\\\\B_2 = 9*cos(0.9)\\\\B_2 = 5.59448 m[/tex]
- The total length of the third side of the fence would be the sum of bases of the two right angles formed by the land-mower motion at each corner.
[tex]L = B_1 + B_2\\\\L = 5.44541 + 5.59448\\\\L = 11.4 m[/tex]
Forty-two divided by seven plus the quantity three divided by six 1. Write the numerical expression. 2. Evaluate within parentheses. 3. There are no exponents to evaluate. 4. Multiply and divide from left to right. 5. Add and subtract from left to righ
Answer:
6.5Step-by-step explanation:
Given Forty-two divided by seven plus the quantity three divided by six, the equivalent numerical expression will be;
[tex]\frac{42}{7} + \frac{3}{6}[/tex]
To evaluate the numerical expression, we will find the LCM of the denominator
[tex]\frac{42}{7} + \frac{3}{6} = \frac{6(42)+7(3)}{42}\\ = \frac{252+21}{42}\\= \frac{273}{42}\\= 6.5[/tex]
The value of the expression 6.5
Answer:
Write and simplify this numerical expression.
Forty-two divided by seven plus the quantity three divided by six
1. Write the numerical expression.
✔ 42 ÷ 7 + (3 ÷ 6)
2. Evaluate within parentheses.
✔ 42 ÷ 7 + 0.5
3. There are no exponents to evaluate.
4. Multiply and divide from left to right.
✔ 6 + 0.5
5. Add and subtract from left to right.
✔ 6.5
Step-by-step explanation:
hope this helps! :)
Work out the surface area of this sphere.
Give your answer to 1 decimal place.
Answer:
452.4
Step-by-step equation:
surface area of a sphere formula= 4πr²
plug 6 in for r
4π(6)² =452.389 rounded to 452.4
Arrange the functions for which the result is a non-infinite value and the limit exists in ascending order of their limit values as x tends to infinity. Please see picture attached.
Answer:
see attached
Step-by-step explanation:
The limit as x gets large is the ratio of the highest-degree terms. In most cases, the limit can be found by evaluating that ratio. Where an absolute value is involved, the absolute value of the highest-degree term is used.
If the ratio gives x to a positive power, the limit does not exist. If the ratio gives x to a negative power, the limit is zero.
The arrangement of functions according to the given condition
[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]
[tex]h(x)=\frac{x^{3} -x^{2} +4}{1-3x^{2} }[/tex]
[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]
[tex]i(x)=\frac{x-1}{|1-4x| }[/tex]
[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]
[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]
[tex]f(x)=\frac{x^{2} -1000}{x-5}[/tex]
[tex]j(x)=\frac{x^{2}-1 }{|7x-1|}[/tex]
What is limit?A limit is the value that a function approaches as the input approaches some value.
According to the given question
[tex]l(x)=\frac{5x^{2} -4}{x^{2} +1}[/tex]
⇒[tex]\lim_{nx\to \infty} \frac{5x^{2} -1}{x^{2} +1}[/tex]
⇒[tex]\lim_{x \to \infty} \frac{x^{2} }{x^{2} } \frac{5-\frac{1}{x^{2} } }{1+\frac{1}{x^{2} } }[/tex]
= 5 ([tex]\frac{1}{x^{2} } = 0[/tex] ,as x tends to infinity [tex]\frac{1}{x^{2} }[/tex] tends to 0)
[tex]i(x)=\frac{x-1}{|1-4x|}[/tex]
⇒[tex]\lim_{x \to \infty} \frac{x-1}{|1-4x|}[/tex] = [tex]\lim_{x \to \infty} \frac{x}{x} \frac{1-\frac{1}{x} }{|\frac{-1}{4}+\frac{1}{x} | }[/tex] =[tex]\frac{1}{\frac{1}{4} }[/tex] =[tex]\frac{1}{4}[/tex]
As x tends to infinity 1/x tends to 0, and |[tex]\frac{-1}{4}[/tex]| gives 1/4
[tex]f(x)= \frac{x^{2} -1000}{x--5}[/tex]
⇒[tex]\lim_{x \to \infty} \frac{x^{2} -1000}{x-5}[/tex]= [tex]\lim_{x \to \infty} \frac{x^{2} }{x} \frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex]= [tex]\lim_{x \to \infty} x\frac{1-\frac{1000}{x^{2} } }{1-\frac{5}{x} }[/tex] ⇒ limit doesn't exist.
[tex]m(x)=\frac{4x^{2}-6 }{1-4x^{2} }[/tex]
⇒[tex]\lim_{x\to \infty} \frac{4x^{2} -6}{1-4x^{2} }[/tex]=[tex]\lim_{x\to \infty} \frac{x^{2} }{x^{2} } \frac{4-\frac{6}{x^{2} } }{\frac{1}{x^{2} } -4}[/tex] [tex]= \lim_{n \to \infty} \frac{4}{-4}[/tex] = -1
As x tends to infinity [tex]\frac{1}{x^{2} }[/tex] tends to 0.
[tex]g(x)=\frac{|4x-1|}{x-4}[/tex]
⇒[tex]\lim_{x\to \infty} \frac{|4x-1|}{x-4}[/tex] = [tex]\lim_{x \to \infty} \frac{|x|}{x} \frac{4-\frac{1}{x} }{1 -\frac{4}{x} } }[/tex] = 4
as x tends to infinity 1/x tends to 0
and |x|=x ⇒[tex]\frac{|x|}{x}=1[/tex]
[tex]h(x)=\frac{x^{3}-x^{2} +4 }{1-3x^{3} }[/tex][tex]\lim_{x \to \infty} \frac{x^{3} -x^{2} +4}{1-3x^{3} }[/tex][tex]= \lim_{x \to \infty} \frac{x^{3} }{x^{3} } \frac{1-\frac{1}{x}+\frac{4}{x^{3} } }{\frac{1}{x^{3} -3} }[/tex] = [tex]\frac{1}{-3}[/tex] =[tex]-\frac{1}{3}[/tex]
[tex]k(x)=\frac{5x+1000}{x^{2} }[/tex]
[tex]\lim_{x \to \infty} \frac{5x+1000}{x^{2} }[/tex] = [tex]\lim_{x \to \infty} \frac{x}{x} \frac{5+\frac{1000}{x} }{x}[/tex] =0
As x tends to infinity 1/x tends to 0
[tex]j(x)= \frac{x^{2}-1 }{|7x-1|}[/tex]
[tex]\lim_{x \to \infty} \frac{x^{2}-1 }{|7x-1|}[/tex] = [tex]\lim_{x \to \infty} \frac{x}{|x|}\frac{x-\frac{1}{x} }{|7-\frac{1}{x}| }[/tex] = [tex]\lim_{x \to \infty} 7x[/tex] = limit doesn't exist.
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Find the missing number if the average is 7.
6 and
A) 8
B) 10
C) 12
D) none of the above
Answer:
A) 8
Step-by-step explanation:
The average of two numbers is 7.
6 and x have an average of 7.
sum of terms / number of terms = average
(6 + x)/2 = 7
6+x = 14
x = 8
The number is 8.
Answer: a 8
i forgot how I got that answer
Two vehicles begin traveling at the same time. Vehicle A travels at 45
miles per hour (MPH) for two hours. Vehicle B travels at 80 MPH for
one hour. Which vehicle travels the farthest, and how much farther
does it travel?
Answer:
The answer is A because 45x2= 90 miles and 80×1 = 80 miles and 90-80= 10 so Vehicle A travels 10 miled farther than Vehicle B. Hope that helps!
Vehicle which travels the farthest is vehicle A and the distance it travels farther is 10 miles.
What is Speed?Speed is the unit rate in terms of distance travelled by an object and the time taken to travel the distance.
Speed is a scalar quantity as it only has magnitude and no direction.
Given that,
Speed of vehicle A = 45 miles per hour
Speed of vehicle B = 80 miles per hour
Vehicle A travels for 2 hours.
Total distance travelled = Speed × Time = 45 × 2 = 90 miles
Vehicle B travels for 1 hour.
Distance travelled = 80 miles
Vehicle A travels farthest since the distance is greater for A.
Difference in the distance = 90 - 80 = 10 miles
Hence the vehicle A travels 10 miles farther.
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Simplify (7+1) - (11+39) 4.
ОА17
ов 59
ос -3
D - 13
Answer:
-41
Step-by-step explanation:
(7 + 1) - (11 + 39) =
= 8 - 50
= -41
Answer:
Step-by-step explanation:
Do the work inside parentheses first. We get:
(8) - (50)(4), or
8 - 200 = -192
PLEASE HELP I NEED TO GRADUATE :D
Answer:
b is the answer
Step-by-step explanation:
In January of 2003(group 1), 1188 out of 1500 spots were bare ground (no vegetation). Find the sample proportion of bare ground spots.
Answer:
[tex] n= 1500[/tex] represent the random sample selected
[tex] X= 1188[/tex] represent the number of pots that were bare ground (no vegetation
[tex]\hat p=\frac{X}{n}[/tex]
And replacing we got:
[tex] \hat p=\frac{1188}{1500}= 0.792[/tex]
So then the sample proportion of bare ground spots is 0.792 for this sample
Step-by-step explanation:
We have the following info given from the problem:
[tex] n= 1500[/tex] represent the random sample selected
[tex] X= 1188[/tex] represent the number of pots that were bare ground (no vegetation)
And for this case if we want to find the sample proportion of bare ground spots we can use this formula:
[tex]\hat p=\frac{X}{n}[/tex]
And replacing we got:
[tex] \hat p=\frac{1188}{1500}= 0.792[/tex]
So then the sample proportion of bare ground spots is 0.792 for this sample
there were 48 females and 60 males present at the high school per rally. Find the ratio of the males to the total number of people present. express as simplified ratio
Answer:
5/9
Step-by-step explanation:
total present = males + females = 60 + 48 = 108
The desired ratio is ...
males/total present = 60/108 = 5/9
The ratio of the males to the total number of people present is 5/9
What is Ratio?Ratio is defined as a relationship between two quantities, it is expressed one divided by the other.
Giiven,
No. of males present at rally = 60
No. of females present at rally = 48
Total no. of people present = males + females = 60 + 48 = 108
The ratio of the males to the total number of people present = No. of males /Total present
∴ No. of males/Total present = 60/108 = 5/9
Thus, the ratio of the males to the total number of people present is 5/9
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you are given an 8-gallon jug filled with water and also two empty jugs: one that holds 5 gallons and other that holds 3 gallons. Using these three jugs, how much can you measure exactly 4 gallons of water. Explain
Answer:
Step-by-step explanation:
We will use following steps to measure exactly 4 gallons of water with the help of 5 gallons and 3 gallons empty jugs.
1). Fill 3 gallons jug completely.
2). Pour this 3 gallons of water into 5 gallons jug. Now we have 3 gallons of water in 5 gallons jug and 3 gallons jug empty.
We can add 2 gallons of water in the empty space of 5 gallons jug more.
3). Fill the 3 gallons jug with the water again.
4). Pour this water into 5 gallons jug which can hold 2 gallons of water more.
Now we have 5 gallons of jug filled fully and 1 gallon water remaining in the 3 gallons jug.
5). Empty the 5 gallons jug completely.
6). Pour the remaining 1 gallon of remaining water in 3 gallons jug into 5 gallons jug.
7). Fill the 3 gallons jug completely and pour it into 5 gallon jug.
8). Finally we have 4 gallons of water in the 5 gallons jug.
I don't know what to do.
Answer:
13 Compute using the 2 right angles, we know that m<FIG=90* and
Please answer now question
Answer:
SSS
Step-by-step explanation:
ST is congruent to SQ
QP is congruent to TP
SP is congruent to SP (reflexive property)
3 sides are congruent, SSS
Answer:
SSS Postulate
Step-by-step explanation:
According to side-side-side postulate, the triangles are congruent
Since,
=> TP = PQ
=> ST = SQ
=> SP = SP (Common)
4) Given that
[tex]f(x) = \sqrt{x} [/tex]
g(x) = x - 7. Then (fog)(x)
(a)
[tex] \sqrt{x + 7} [/tex]
(b)
[tex] \sqrt{x - 7} [/tex]
(c)
[tex] \sqrt{x} - 7[/tex]
(d)
[tex] \sqrt{x} + 7[/tex]
(e) none
Answer:
The answer is option B.
Step-by-step explanation:
f(x) = √x
g(x) = x - 7
To find f o g(x) replace every x in f (x) by
g(x)
That's
[tex]f \: o \: g \: (x) = \sqrt{x - 7} [/tex]
Hope this helps you
Find the product of all positive integer values of $c$ such that $3x^2+7x+c=0$ has two real roots. I will award a lot of points
Answer: 24
Step-by-step explanation:
Let's find one solution:
3x² + 7x + c = 0
a=3 b=7 c=c
First, let's find c so that it has REAL ROOTS.
⇒ Discriminant (b² - 4ac) ≥ 0
7² - 4(3)c ≥ 0
49 - 12c ≥ 0
-12c ≥ -49
[tex]c\leq\dfrac{-49}{-12}\quad \rightarrow c\leq \dfrac{49}{12}[/tex]
Since c must be a positive integer, 1 ≤ c ≤ 4
Example: c = 4
3x² + 7x + 4 = 0
(3x + 4)(x + 1) = 0
x = -4/3, x = -1 Real Roots!
You need to use Quadratic Formula to solve for c = {1, 2, 3}
Valid solutions for c are: {1, 2, 3, 4)
Their product is: 1 x 2 x 3 x 4 = 24
Answer:
$3x^2+7x+c=0$
comparing above equation with ax²+bx+c
a=3
b=7
c=1
using quadratic equation formula
[tex]x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{ 2a} [/tex]
x=(-7+-√(7²-4×3×1))/(2×3)
x=(-7+-√13)/6
taking positive
x=(-7+√13)/6=
taking negative
x=(-7-√13)/6=
How does an earthquake of magnitude 7.8 compare in intensity with an earthquake of magnitude 3.7 on the Richter scale? Round to the nearest whole number.
Answer:
1000 * 10th sqrt of 10 or about 12589 times more powerful?
Step-by-step explanation:
Answer:v 31623
Step-by-step explanation:
Here are summary statistics for randomly selected weights of newborn girls: nequals153, x overbarequals31.5 hg, sequals7.1 hg. Construct a confidence interval estimate of the mean. Use a 90% confidence level. Are these results very different from the confidence interval 30.4 hgless thanmuless than32.8 hg with only 15 sample values, x overbarequals31.6 hg, and sequals2.7 hg?
Answer:
yes it is little different from the confidence interval (30.4 ≤μ≤ 32.8) changes statistics
90% confidence interval estimate of the mean is
(30.1048 , 33.0952)
Step-by-step explanation:
Step(I):-
Given sample size 'n' = 153
Given mean of the sample x⁻ = 31.5
Sample standard deviation 'S' = 7.1 h g
90% confidence interval estimate of the mean is determined by
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
Degrees of freedom
ν = n-1 = 153-1 =152
t₀.₀₅ =1.9757
Step(ii)
90% confidence interval estimate of the mean is
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
[tex](31.5 - 1.9757 } \frac{7.1}{\sqrt{153} } , 31.5 + 1.9757 \frac{7.1}{\sqrt{153} } )[/tex]
( 31.5 - 1.1340 , 31.5 + 1.1340)
(30.366 , 32.634)
90% confidence interval estimate of the mean is
(30.4 , 32.6)
b)
Given sample size 'n' = 15
Given mean of the sample x⁻ = 31.6
Sample standard deviation 'S' = 2.7 h g
90% confidence interval estimate of the mean is determined by
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
Degrees of freedom
ν = n-1 = 15-1 =14
t₀.₀₅ =2.1448
90% confidence interval estimate of the mean is
[tex](x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } )[/tex]
[tex](31.6 - 2.1448 } \frac{2.7}{\sqrt{15} } , 31.6 + 2.1448 \frac{2.7}{\sqrt{15} } )[/tex]
( 31.6 - 1.4952 , 31.6 + 1.4952)
(30.1048 , 33.0952)
Conclusion:-
yes it is little different from the confidence interval (30.4 ≤μ≤32.8)
If the 2412 leaves are not a random sample, but the researchers treated the 2412 leaves as a random sample, this most likely made the data more:_____________.1. accurate, but not precise2. precise, but not accurate3. neither4. both accurate and precise
Answer:
2. Precise but not accurate
Step-by-step explanation:
In a high precision, low accuracy case study, the measurements are all close to each other (high agreement between the measurements) but not near/or close to the center of the distribution (how close a measurement is to the correct value for that measurement)
In the North Area Mall, 18 of the 90 stores sell shoes. If that same ratio holds true for the University Mall and 9 stores there sell shoes, how many stores are at University Mall?
Answer:
18/90=9/x and to find x use proportion so first 90*9=18x and 810=18x and x-45
Step-by-step explanation:
Answer:
45 stores are at University Mall
Step-by-step explanation:
The ratio of malls that sell shoes at North Area mall are 18 out of 90, which simplifies to one fifth of stores. Since the same ratio holds for the University Mall, and 9 is half of 18, the amount of stores at University Mall is 45 because 45 is half of 90.
Solve this system of linear equation. Separate the x- and y- values with a coma. -9x+3y=0 12x+4y=24
[tex]-9x+3y = 0\\\\-9x = -3y\\\\3x = y\\\\\\12x+4y =24\\\\3x+y = 6\\\\y+y=6\\\\2y =6\\\\y =3 \\\\3x=y\\\\x = 1\\\\(x,y) = (1,3)[/tex]
Taranique loves to play the floating duck game at the carnival. For $2.00 per try, she gets to choose one duck out of 50 swimming in the water. If taranique is lucky, she will pick one of the 8 winning ducks and go home with a pink teddy bear. What is the expected value of the game for Taranique if the value of the prize is $5.00?
Answer:
$1.20
Step-by-step explanation:
First we need to find the probability of winning the game.
If there are 8 winning ducks among 50 ducks, and we can pick only one, the probability of winning is 8/50 = 0.16, therefore the probability of losing the game is 1 - 0.16 = 0.84.
The player pays $2 to play, so if the player loses, the owner of the game wins $2, and if the player wins, the owner loses $3 (he receives $2 but pays the prize of $5).
Now, to find the expected value of the game, we just need to multiply the price of winning by the corresponding probability and summing with the same product but related to losing the game:
[tex]Expected\ value = p(winning)*v(winning) + p(losing)*v(losing)[/tex]
[tex]Expected\ value = 0.16 * (-3) + 0.84 * (2)[/tex]
[tex]Expected\ value = \$1.20[/tex]
In ANOVA analyses, when the null hypothesis is rejected, we can test for differences between treatment means by ________. Group of answer choices
Answer:
When conducting an analysis of variance analysis on a set of samples and the null hypothesis is rejected, we can test for the difference between treatment can be tested with the aid of a t-test. This is employed when 2 related groups are involved. Independent sample, paired sample or one-sample t-test can be conducted.
Step-by-step explanation:
A t-test is a test statistic used to make inferences that determine the differences that exist statistically between 2 related groups. It tells us if the 2 groups tested are from the same population. There are 3 types of t-test namely independent sample t-test, paired-sample t-test and one-sample t-test
Assume that the profit generated by a product is given by where x is the number of units sold. If the profit keeps changing at a rate of per month, then how fast are the sales changing when the number of units sold is 1900
Answer:
21794.495 units/month
Step-by-step explanation:
Some data are missing which i can assume as per requirement of the Question.
Let us consider that profit generated by a product is given by
p(x) =4√x
Also, consider that the profit keeps changing at a rate of $1000 per month.
Now, Using the chain rule we can write
dp/dx=(dp/dt)÷(dx/dt).
So, we can calculate
dp/dx=2x^(-1/2)=2/√x.
As per question we have to find out dx/dt
Since, dx/dt= (dp/dt)/(dp/dx),
so plugging x=1900 we get 1000√1900/2=21794.495 units/month increase in sales.