how do you make coke for steel?

Answer:

wheel guard

Explanation:

to protect our hands and reduce spark

Answer:

B) write down all activities and commitments.

Explanation:

also i found the answer on quizlet hope this works:))

Answer:

write down all activities and commitments.

Explanation:

i had got the same question on my unit test and it was the answer it was right

Answer:Part washers

Explanation:

I did it..

The only option that uses cleaning solutions that become spent and must be disposed properly is;

Option C; Parts Washers

To answer this question, let us examine each option;

Option A; Sump Pits; These are basins at the lowest part of specific areas designed to allow all water collected in that basin area to drain into it. This has no business with cleaning solution.

Option B; Car washers; These are like machine dryers used to clean the exterior and interior parts of motor vehicles.

Option C; Part Washers; These are mechanical devices that are designed for cleaning to remove debris, grime, oil dirt, paint, and other substances that could potentially cause contamination from parts in order to get them ready for assembling, packaging, or even coating. They are basically used to clean parts to get them ready for functional use.

Option D; Tire cleaner is just used to clean tire but is not something that becomes spent and should be disposed properly as it is more like a liquid.

The only correct option is Option C.

Read more at; https://brainly.com/question/25024807

Answer:

Explanation:

For an electric motor, 1 hp = 746 W, so 1/2 hp = 373 W. Then the total wattage of the load is ...

  Pl = 373 +100 +100 +75 = 648 W

The equivalent resistance is ...

  R = V^2/P = (120 V)^2/(648 W) = 22 2/9 Ω

Adding the wiring resistance, we get a circuit resistance of ...

  22.2222 +0.22 +0.22 = 22.6622 Ω . . . . total circuit resistance

Then the circuit current is ...

  120 V/(22.6622 Ω) ≈ 5.29516 A

Circuit resistance is about 22.7 Ω; circuit current is about 5.3 A.

_____

Exact values are 5099/225 ohms and 27000/5099 amps. Of course, these assume the motor and lamps are purely resistive, which they are not.

PLEASE GIVE BRAINLIST

A parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.

HOPE THIS HELPED

Answer:

A

Explanation:

general information sign

safety is orange

caution is yellow

danger is red

Answer: the standard deviation STD of machine B is s (Lb) = 0.4557

Explanation:

from the given data, machine A and machine B produce half of the rods

Lt = 0.5La + 0.5Lb

so

s² (Lt) = 0.5²s²(La) + 0.5²s²(Lb) + 0.5²(2)Cov (La, Lb)

but Cov (La, Lb) = Corr(La, Lb) s(La) s(Lb) = 0.4s (La) s(Lb)

so we substitute

s²(Lt) = 0.25s² (La) + 0.25s² (Lb) + 0.4s (La) s(Lb)

0.4² = 0.25 (0.5²) + 0.25s² (Lb) + (0.5)0.4(0.5) s(Lb)

0.64 = 0.25 + s²(Lb) + 0.4s(Lb)

s²(Lb) + 0.4s(Lb) - 0.39 = 0

s(Lb) = { -0.4 ± √(0.16 + (4*0.39)) } / 2

s (Lb) = 0.4557

therefore the standard deviation STD of machine B is s (Lb) = 0.4557

Answer:skull and crossbones

Explanation:

The forklift overturning is a very common way of getting injured from a forklift. Overturning the forklift means it tips over onto it's side due to the operator turning it too fast.

Answer:

Place the jack under the part of the vehicle that it should contact when raised. If you're using jack stands, place them near the jack. If you place your jack incorrectly, you can injure your car. To find the proper place to position the jack for your particular vehicle, check your owner's manual.

Answer:

None of the above cause thats what i put

Answer: making sure that they are up to date

Explanation:

Answer:

While scientists study how nature works, engineers create new things, such as products, websites, environments, and experiences. Because engineers and scientists have different objectives, they follow different processes in their work.

Explanation:

Answer:

There are actually multiple types of processes a manufacturer uses, and those can be grouped into four main categories: casting and molding, machining, joining, and shearing and forming.

Explanation:

Answer:

The engineer will conduct a variety of tests, including chemical, mechanical, electrical, and physical examinations, to determine the potential of the new material.

Explanation:

They will need to test the material, this will also help to determine its malleability.

Hope this helps!

Incomplete question. However, I provided information that could assist you in identifying the main problem or issue addressed in any case study.

Explanation:

First, note that a case study is simply a learning aid that allows one to learn from a real-life scenario.

To determine the main problems of a case study one needs to:

Thus, by taking these few steps you may be able to determine the main problem in that case study.

Answer:

a). α =  26.57  

b). Maximum load is 50 .kN

Explanation:

a).

The normal force is given by

N = σ A cosec β

where, σ is the normal stress

            A is the cross sectional area

Similarly, shear force is given by

S= τ A cosec β

where, τ is the shearing stress

Now from the figure,

tan β = S/N

        = τ/σ

Therefore, [tex]$\beta = \tan^{-1}(2)$[/tex]  = 63.43

α = 90 - β = 26.57

b).

The normal force is given by

[tex]$N=(100\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43$[/tex]

[tex]$N=44.78\times 10^3$[/tex] N

We have

[tex]$\Sigma F_y=0$[/tex]

∴ N - F sin β = 0

⇒ F = N / sin β

      = [tex]$\frac{44.72\times 10^3}{\sin(63.43)} = 50\times 10^3 N$[/tex]

Similarly,

The shear force is given by

S = τ A cosec β

  = [tex]$(50\times 10^6)(400\times 10^{-6}) \text{ cosec}\ 63.43 = 22.36\times 10^3 N$[/tex]

[tex]$\Sigma F_x=0$[/tex]

∴ S - F cos β = 0

⇒ F = S / cos β

[tex]$\frac{22.36\times 10^3}{\cos(63.43)} = 49.99\times 10^3 N$[/tex]

Therefore, force is 50 kN.

the answer to that would be a) true

Answer:

The percent elongation in the length of the specimen is 42%

Explanation:

Given that:

The gage length of the original test specimen  [tex]L_o[/tex] = 50 mm

The final gage length [tex]L_f[/tex] = 71 mm

The area = 206 mm²

maximum load  =  162,699 N

To determine the percent elongation in %, we use the formula:

[tex]\%EL = \dfrac{L_f-L_o}{L_o}\times 100[/tex]

[tex]\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100[/tex]

[tex]\%EL = \dfrac{21 mm}{50 \ mm}\times 100[/tex]

[tex]\%EL = 0.42 \times 100[/tex]

[tex]\mathbf{\%EL = 42 \%}[/tex]

The percent elongation in the length of the specimen is 42%

Answer:

The molecular weight of the gas mixture is 35.38 g/mol.

Explanation:

The molecular weight of the gas can be found using the following equation:

[tex] M = \frac{m}{n} [/tex]

Where:

m: is the mass = 230 g

n: is the number of moles

First, we need to find the number of moles using Ideal Gas Law:

[tex] PV = nRT [/tex]

Where:

P: is the pressure = 135 psi

V: is the volume = 15 L

R: is the gas constant = 0.082 L*atm/(K*mol)

T: is the temperature = 465 °R (K = R*5/9)

[tex]n = \frac{PV}{RT} = \frac{135 psi*\frac{1 atm}{14.6959 psi}*15 L}{0.082 L*atm/(K*mol)*465*(5/9) K} = 6.50 moles[/tex]                

Finally, the molecular weight of the gas is:

[tex] M = \frac{m}{n} = \frac{230 g}{6.50 moles} = 35.38 g/mol [/tex]

Therefore, the molecular weight of the gas mixture is 35.38 g/mol.

I hope it helps you!

Answer:

B. evaluation of a particular program

Explanation:

Before students enrol into any given discipline, they should first ensure that their program of choice is well accredited. In a specific program, specialized accreditation has the function of telling would be students if the program meets up with academic standards in the field

Accreditation is a way of assessing faculty and curriculum quality of schools to make sure that they are up to academic standards and are also preparing students to future success in the field.

Answer:

Material engineers study various materials to discover the reason and cause of its existence, the chemical properties, how long it has been there, and how it impacts human life.

Explanation:

Material engineer is an engineering discipline that focuses to improve human life by studying the environment and the various elements or materials it holds.

It uses the power of pure science to test and analysis its findings, documents its features and exposes them to the world. Materials like metals and other elemental forms were all tested by these engineers to determine its history and chemical and biological use.

Answer:

how materials perform and deteriorate

Explanation:

Answer:

1) The power developed by the engine is 14705.7739 kW

2) The thermal efficiency is approximately 61.5%

Explanation:

The given parameters are;

P₁ = 95 kPa

T₁ = 22°C

V₁ = 3.17 liters

The cutoff ratio = 2.5

Displacement volume = 3 liters

The number of times the cycle is executed per minute = 1000 times per minute

We have;

The displacement volume = V₁ - V₂ = 3 l

V₁ = 3.17 l

V₂ = 3 - 3.17 = 0.17 l

Compression ratio = V₁/V₂ = 3.17/0.17 ≈ 18.65

P₂/P₁ = P₂/(95 kPa) =  (V₁/V₂)^(k) = 18.65^1.4

P₂ = (95×18.65^(1.4)) ≈ 5710.5 kPa

T₂/T₁ = (V₁/V₂)^(k - 1)

T₂/(295 K)= (18.65)^(1.4 - 1)

T₂ = 295 * (18.65)^(1.4 - 1) = 950.81 K

The cutoff ratio = V₃/V₂ = 2.5

T₃ = T₂ × V₃/V₂  = 2.5 * 950.81 K = 2377.025 K

[tex]Q_{in}[/tex] = [tex]C_p[/tex]×(T₃ - T₂) = 1.006 × (2377.025 - 950.81) = 1,434.77 kJ/kg

T₄ = T₃ × (V₃/V₄)^(k-1) =

Therefore,

[tex]T_4 = T_3 \times \left (\dfrac{r_c}{r} \right )^{k - 1} = 2377.025 \times \left( \dfrac{2.5}{18.65} \right )^{1.4 - 1} \approx 1064 \ K[/tex]

T₄ ≈ 1064 K

[tex]Q_{out}[/tex] = [tex]-C_v \times (T_4 - T_1)[/tex]

[tex]C_v = C_p/k = 1.006/1.4 \approx 0.7186 \ kJ/kg[/tex]

∴ [tex]Q_{out}[/tex] = 0.7186×(1064 - 295) = 552.6034 kJ/kg

1) The net work = [tex]Q_{in}[/tex] - [tex]Q_{out}[/tex] = 1,434.77 kJ/kg - 552.6034 kJ/kg ≈ 882.17 kJ/kg

The number of cycle per minute = 1000 rpm

The number of cycle per minute = 1000 rpm/60 = 16.67 cycles per second

The power developed by the engine = The number of cycles per second × The net work of the engine

Therefore;

The power developed by the engine = 16.67 cycles/second  × 882.17 kJ/kg

The power developed by the engine = 14705.7739 kW

2) Efficiency, [tex]\eta _{th}[/tex], is given as follows;

[tex]\eta _{th} = \dfrac{Q_{in}-Q_{out}}{Q_{in}} \times 100 = 1 - \dfrac{Q_{out}}{Q_{in}} \times 100= 1 - \dfrac{552.6034}{1434.77}\times 100 \approx 61.5\%[/tex]

Therefore, the thermal efficiency ≈ 61.5%.

Answer:

A. voltage

Explanation:

The rate of heat transfer per unit area in a thermal circuit is equivalent to the voltage in an electrical circuit.

This is because, within an electrical circuit the voltage is supplied by a generator, which can be batteries, batteries, or others. The moment the electrical voltage acts within a circuit, it will consist of the gradient of electrical potential between two points, which will cause the electrons to move from the point with the highest concentration to the point with the lowest concentration (similar to the transfer of heat from the thermal circuit) generating the electric current.

Answer:

Period = 0.2857 nanoseconds

Explanation:

We are told that frequency = 3.5 GHz

This is simply 3.5 × 10^(9) Hz

Now, from wave equations, Period is given by the formula;

Period = 1/frequency

Thus;

Period = 1/(3.5 × 10^(9))

Period = 0.2857 × 10^(-9) seconds

From conversions, we can simplify the answer.

1 second = 10^(-9) nanoseconds

Thus, 0.2857 × 10^(-9) seconds = 0.2857 × 10^(-9) × 10^(-9) nanoseconds = 0.2857 nanoseconds