How do i work out the probability of rolling two sixes

Answer:

[tex] P(X>8)[/tex]

And for this case we can use the cumulative distribution function given by:

[tex] F(x) = 1- e^{-\lambda x}[/tex]

And if we use this formula we got:

[tex] P(X>8)= 1- P(X \leq 8) = 1-F(8) = 1- (1- e^{-\frac{1}{8.9} *8})=e^{-\frac{1}{8.9} *8}= 0.4070[/tex]

Step-by-step explanation:

For this case we can define the random variable of interest as: "The life of an electric component " and we know the distribution for X given by:

[tex]X \sim exp (\lambda =\frac{1}{8.9}) [/tex]

And we want to find the following probability:

[tex] P(X>8)[/tex]

And for this case we can use the cumulative distribution function given by:

[tex] F(x) = 1- e^{-\lambda x}[/tex]

And if we use this formula we got:

[tex] P(X>8)= 1- P(X \leq 8) = 1-F(8) = 1- (1- e^{-\frac{1}{8.9} *8})=e^{-\frac{1}{8.9} *8}= 0.4070[/tex]

Answer:

Area = 108 cm^2

Perimeter = 44 cm

Step-by-step explanation:

Area, -->

24 + 30 + 24 + 30 -->

24(2) + 30(2)

48 + 60 = 108 cm^2

108 = area

10 + 12 + 10 + 12, -->

10(2) + 12(2) = 44 cm

44 = perim.

Hope this helps!

Answer:

Step-by-step explanation:

Draw the diagram.

This time put in the only one line for the height. That is only 1 height is 8 cm. That's it.

The base is 6 +  6 = 12 cm.

The slanted line is 10 cm

That's all your diagram should show. It is much clearer without all the clutter.

Now you are ready to do the calculations.

Area

The Area = the base * height.

base = 12

height = 8

Area = 12 * 8 = 96

Perimeter.

In a parallelagram the opposite sides are equal to one another.

One set of sides = 10 + 10 = 20

The other set = 12 + 12 = 24

Both sets = 20 + 24

Both sets = 44

Answer

Area = 96

Perimeter = 44

Answer:

3^4

Step-by-step explanation:

3^2*3^2

3*3*3*3

3^4

Answer:

18 pounds of cashews are needed.

Step-by-step explanation:

Given;

A manager bought 12 pounds of peanuts for $30.

Price of peanut per pound P = $30/12 = $2.5

Price of cashew per pound C = $5

Price of mixed nut per pound M = $4

Let x represent the proportion of peanut in the mixed nut.

The proportion of cashew will then be y = (1-x), so;

xP + (1-x)C = M

Substituting the values;

x(2.5) + (1-x)5 = 4

2.5x + 5 -5x = 4

2.5x - 5x = 4 -5

-2.5x = -1

x = 1/2.5 = 0.4

Proportion of cashew is;

y = 1-x = 1-0.4 = 0.6

For 12 pounds of peanut the corresponding pounds of cashew needed is;

A = 12/x × y

A = 12/0.4 × 0.6 = 18 pounds

18 pounds of cashews are needed.

Answer:

Step-by-step explanation:

Null hypothesis: u = 39.8

Alternative: u =/ 39.8

Using a one sample z test: the formula is

z = x-u / (sd/√n)

Where x = 33.1 u = 39.8, sd= 16.2 and n = 38

Thus we have:

z = 33.1-39.8 / (16.2/√38)

z = -6.7 / (16.2/6.1644)

z = -6.7/ 2.6280

z= -2.5495

To be able to arrive at a conclusion, we have to find the p value, the p value at a 0.1 significance level for a two tailed test is 0.0108. This is way less than 0.1 thus we will reject the null and conclude that there has been a change (either way) in the average number of e-mails received per day per employee. Yes, the new policy had an effect.

Answer:

5-c)  6-c)

Step-by-step explanation:

5 c)= (a^4)^(1/3)= a^(4*1/3)=a^(4/3)

6. At the beginning of 1st year the total value on the bank account=500 USD

At the end of 1-st year the total value is 500 USD +3% from 500 USD=

500+500*0.03= 500*1.03

At the end of 2-nd year the total amount is 500*1.03+3% from 500*1.03=

500*1.03^2

Similarly at the end of the 3-rd year the total amount is 500*1.03^3

Finally at the end of fourth year the total amount is 500*1.03^4

Answer:

[tex]x\approx 50^\circ[/tex]

Step-by-step explanation:

[tex]c^2 = a^2 + b^2 - 2ab(cos(C))[/tex]

See the figure below to get the values as:

[tex]7^2=7^2+9^2-2\left(7\right)\left(9\right)cos\left(x\right)\\\\cos(x)=\frac{7^2+9^2-7^2}{2\cdot \:7\cdot \:9}\\\\x\approx 50^\circ[/tex]

There are multiple concepts to solve this problem. This is one of the concept used in high school. Other concept to solve this problem is to use the concept of isosceles triangle. An isosceles triangle is a triangle with (at least) two equal sides. The angles shared by the two equal sides are also equal. So that the sum of all the three angles will add up to 180.

[tex]x+x+80=180\\\\2x=100\\\\x=50^{\circ}[/tex]

Best Regards!

Answer:

Brainleist!

Step-by-step explanation:

12/3.5

3.42857142857

round down so its 3!

Answer:

The answer is -4.

Step-by-step explanation:

You should get this answer if you do 3 - 7.

Answer:

Step-by-step explanation:

[tex](\sqrt{b^{2}})^{3}=b^{3}\\\\[/tex]

or If it is

[tex]\sqrt[3]{b^{2}} =(b^{2})^{\frac{1}{3}}=b^{2*\frac{1}{3}}=b^{\frac{2}{3}}[/tex]

Answer:

Option (D)

Step-by-step explanation:

Formula for the area of a triangle is,

Area of a triangle = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]

For the given triangle ABC,

Area of ΔABC = [tex]\frac{1}{2}(\text{AB})(\text{CD})[/tex]

Length of AB = [tex](y_2-y_1)[/tex]

Length of CD = [tex](x_3-x_1)[/tex]

Now area of the triangle ABC = [tex]\frac{1}{2}(y_2-y_1)(x_3-x_1)[/tex]

Therefore, Option (D) will be the answer.

Answer: 4,582,656

Step-by-step explanation:

A coin is tossed 4 times,

2^4 outcomes: 16

and then a standard six-sided die is rolled 3 times, 6^3

216 outcomes:

and finally, a group of two cards is drawn from a standard deck of 52 cards without replacements

It says a “group”, so, I guess the order doesn’t matter… So it is “52 choose 2”

52*51/ (2*1) = 26*51

how many different outcomes are possible?

16*216*26*51 = 4,582,656

Answer:  cos²(θ) + sin(θ)sin(e)

Step-by-step explanation:

sin (90° - θ)cos(Ф) - sin(180° + θ) sin(e)

Note the following identities:

sin (90° - θ) = cos(x)

sin (180° + θ) = -sin(x)

Substitute those identities into the expression:

   cos(x)cos(x)  -  -sin(x)sin(e)

=  cos²(x) + sin(x)sin(e)

Answer:

Approximately 0% probability that the average price for 15 gas stations is over $4.99.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 4.74, \sigma = 0.16, n = 16, s = \frac{0.16}{\sqrt{16}} = 0.04[/tex]

What is the approximate probability that the average price for 15 gas stations is over $4.99?

This is 1 subtracted by the pvalue of Z when X = 4.99. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{4.99 - 4.74}{0.04}[/tex]

[tex]Z = 6.25[/tex]

[tex]Z = 6.25[/tex] has a pvalue very close to 1.

1 - 1 = 0

Approximately 0% probability that the average price for 15 gas stations is over $4.99.

Answer: -13

Step-by-step explanation:

c-2y

= -5-2(4)

= -5 - 8

= -13

Answer:

-13

Step-by-step explanation:

[tex]c=-5\\y=4\\c-2y=\\-5-(4*2)=\\-5-8=\\-13[/tex]

The expression is equal to -13 when [tex]c=-5[/tex] and [tex]y=4[/tex].

Answer:

The probability that one red chip was selected is 0.0053.

Step-by-step explanation:

Let the random variable X be defined as the number of red chips selected.

It is provided that the selections of the n = 5 chips are done with replacement.

This implies that the probability of selecting a red chip remains same for each trial, i.e. p = 6/9 = 2/3.

The color of the chip selected at nth draw is independent of the other selections.

The random variable X thus follows a binomial distribution with parameters n = 5 and p = 2/3.

The probability mass function of X is:

[tex]P(X=x)={5\choose x}\ (\frac{2}{3})^{x}\ (1-\frac{2}{3})^{5-x};\ x=0,1,2...[/tex]

Compute the probability that one red chip was selected as follows:

[tex]P(X=1)={5\choose 1}\ (\frac{2}{3})^{1}\ (1-\frac{2}{3})^{5-1}[/tex]

                [tex]=5\times\frac{2}{3}\times \frac{1}{625}\\\\=\farc{2}{375}\\\\=0.00533\\\\\approx 0.0053[/tex]

Thus, the probability that one red chip was selected is 0.0053.

Answer:

0.0412

Step-by-step explanation:

Total chips = 6 red + 3 black chips

Total chips=9

n=5

Probability of (Red chips ) can be determined by

=[tex]\frac{6}{9}[/tex]

=[tex]\frac{2}{3}[/tex]

=0.667

Now we used the binomial theorem

[tex]P(x) = C(n,x)*px*(1-p)(n-x).....Eq(1)\\ putting \ the \ given\ value \ in\ Eq(1)\ we \ get \\p(x=1) = C(5,1) * 0.667^1 * (1-0.667)^4[/tex]

This can give 0.0412

Answer:

y = x - 3

Step-by-step explanation:

Do rise/run to find the slope

8/8 = 1

y = x + b

Plug in a point to find the y-intercept

-5 = -2 + b

-3 = b

The equation will be y = x - 3

Answer:

Option 1.

Step-by-step explanation:

When triangles are similar, their angles cannot be proportional. The angles on both triangles have to be same.

Option 3 and 4 are wrong.

Angle T and angle U cannot be congruent on the same triangle.

Therefore, option 1 is correct.

The answer would be the third one because if they are simillar  that means they are not exactly the same but one is a dillation of one. This means they are proportinate. Mark Branliest!!!!

Answer:

a. The claim is that the amount of television watched per day last year by the average person differed from that in 2005.

b. The critical values are tc=-1.729 and tc=1.729.

The acceptance region is defined by -1.792<t<1.729. See the picture attached.

c. Test statistic t=0.18.

The null hypothesis failed to be rejected.

d. At a significance level of 10%, there is not enough evidence to support the claim that the amount of television watched per day last year by the average person differed from that in 2005.

e. The 95% confidence interval for the mean is (2.29, 7.23).

Step-by-step explanation:

We have a sample of size n=20, which has mean of 4.76 and standard deviation of 5.28.

[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{20}(1+4.6+5.4+. . .+6.2)\\\\\\M=\dfrac{95.2}{20}\\\\\\M=4.76\\\\\\s=\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2\\\\\\s=\dfrac{1}{19}((1-4.76)^2+(4.6-4.76)^2+(5.4-4.76)^2+. . . +(6.2-4.76)^2)\\\\\\s=\dfrac{100.29}{19}\\\\\\s=5.28\\\\\\[/tex]

a. This is a hypothesis test for the population mean.

The claim is that the amount of television watched per day last year by the average person differed from that in 2005.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=4.55\\\\H_a:\mu\neq 4.55[/tex]

The significance level is 0.1.

The sample has a size n=20.

The sample mean is M=4.76.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=5.28.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{5.28}{\sqrt{20}}=1.181[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{4.76-4.55}{1.181}=\dfrac{0.21}{1.181}=0.18[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=20-1=19[/tex]

The critical value for a level of significance is α=0.10, a two tailed test and 19 degrees of freedom is tc=1.729.

The decision rule is that if the test statistic is above tc=1.729 or below tc=-1.729, the null hypothesis is rejected.

As the test statistic t=0.18 is within the critical values and lies in the acceptance region, the null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of television watched per day last year by the average person differed from that in 2005.

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=4.76.

The sample size is N=20.

The standard error is s_M=1.181

The degrees of freedom for this sample size are df=19.

The t-value for a 95% confidence interval and 19 degrees of freedom is t=2.093.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=2.093 \cdot 1.181=2.47[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 4.76-2.47=2.29\\\\UL=M+t \cdot s_M = 4.76+2.47=7.23[/tex]

The 95% confidence interval for the mean is (2.29, 7.23).

Answer:

The 90% confidence interval for the mean production rate fro the new method is (75.9, 84.1).

Step-by-step explanation:

We have to calculate a 90% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=80.

The sample size is N=18.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{10}{\sqrt{18}}=\dfrac{10}{4.24}=2.36[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=18-1=17[/tex]

The t-value for a 90% confidence interval and 17 degrees of freedom is t=1.74.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.74 \cdot 2.36=4.1[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 80-4.1=75.9\\\\UL=M+t \cdot s_M = 80+4.1=84.1[/tex]

The 90% confidence interval for the mean production rate fro the new method is (75.9, 84.1).

Options

Answer:

(C)Counting rule for combinations

Step-by-step explanation:

When selecting n objects from a set of N objects, we can determine the number of experimental outcomes using permutation or combination.

Therefore, The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N objects where order of selection is not important is called the counting rule for combinations.

A selection or listing of objects in which the order of the objects is not important

Answer:

His overall final​ score is 80.1.

His letter grade is a B.

Step-by-step explanation:

To find his grade, we multiply each grade by it's weight.

Grades and weights:

His midterm score is 64​. The midterm counts 20% = 0.2.

His project score is 80​. The project score counts 20% = 0.2.

His homework score is 94. The homework score counts 30%.

His final exam score is 77. It counts 30%.

What is his overall final​ score?

64*0.2 + 80*0.2 + 94*0.3 + 77*0.3 = 80.1

His overall final​ score is 80.1.

What letter grade did he earn​ (A, B,​ C, D, or​ F)?

At least 80 but less than 90 is a​ B. He scored 80.1, so his letter grade is a B.

Answer:

y = -0.4x - 3

Step-by-step explanation:

Using the slope formula, y2-y1/x2-x1 we need to find two points. Luckily, we already have two points, (5, -5) and (-5, -1). Plugging in, we have -4/10, or -0.4. Since now we know m = -0.4, we need to find the y-intercept. We have it as -3. Now we get y = -0.4x - 3 as our equation.

Answer:

The value of [tex]x_{1}[/tex] is given by [tex]\frac{10}{3}[/tex]. Hence, the answer is A.

Step-by-step explanation:

This exercise represents a case where the Newton-Raphson method is used, whose formula is used for differentiable function of the form [tex]f(x) = 0[/tex]. The expression is now described:

[tex]x_{n+1} = x_{n} - \frac{f(x_{n})}{f'(x_{n})}}[/tex]

Where:

[tex]x_{n}[/tex] - Current approximation.

[tex]x_{n+1}[/tex] - New approximation.

[tex]f(x_{n})[/tex] - Function evaluated in current approximation.

[tex]f'(x_{n})[/tex] - First derivative of the function evaluated in current approximation.

If [tex]f(x) = x^{2} - 4[/tex], then [tex]f'(x) = 2\cdot x[/tex]. Now, given that [tex]x_{0} = 6[/tex], the function and first derivative evaluated in [tex]x_{o}[/tex] are:

[tex]f(x_{o}) = 6^{2} - 4[/tex]

[tex]f(x_{o}) = 32[/tex]

[tex]f'(x_{o})= 2 \cdot 6[/tex]

[tex]f'(x_{o}) = 12[/tex]

[tex]x_{1} = x_{o} - \frac{f(x_{o})}{f'(x_{o})}[/tex]

[tex]x_{1} = 6 - \frac{32}{12}[/tex]

[tex]x_{1} = 6 - \frac{8}{3}[/tex]

[tex]x_{1} = \frac{18-8}{3}[/tex]

[tex]x_{1} = \frac{10}{3}[/tex]

The value of [tex]x_{1}[/tex] is given by [tex]\frac{10}{3}[/tex]. Hence, the answer is A.

162 inches is 13.5 feet or 13 feet 6 inches, so it would not fit underneath the bridge

Answer:

The truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.

Answer:

Step-by-step explanation:

The vertical asymptotes of the rational expression are the places where the denominator is zero:

  x^2 -16 = 0

  (x -4)(x +4) = 0 . . . . . true for x=4, x=-4

  x = 4, x = -4 are the equations of the vertical asymptotes

__

The zeros of a rational expression are the places where the numerator is zero:

  4x = 0

  x = 0 . . . . . . divide by 4

Answer:

a) 22.66% of customers receive the service for​ half-price.

b) The guaranteed time​ limit should be of 25.2 minutes.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 17, \sigma = 4[/tex]

​(a) The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take​ longer, the customer will receive the service for​ half-price. What percent of customers receive the service for​ half-price?

Longer than 20 minutes is 1 subtracted by the pvalue of Z when X = 20. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{20 - 17}{4}[/tex]

[tex]Z = 0.75[/tex]

[tex]Z = 0.75[/tex] has a pvalue of 0.7734

1 - 0.7734 = 0.2266

22.66% of customers receive the service for​ half-price.

(b) If the automotive center does not want to give the discount to more than 2​% of its​ customers, how long should it make the guaranteed time​ limit?

The time limit should be the 100 - 2 = 98th percentile, which is X when Z has a pvalue of 0.98. So X when Z = 2.054.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]2.054 = \frac{X - 17}{4}[/tex]

[tex]X - 17 = 4*2.054[/tex]

[tex]X = 25.2[/tex]

The guaranteed time​ limit should be of 25.2 minutes.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  confidence interval is  [tex]64.86<\mu<67[/tex]

Step-by-step explanation:

From the question we are given the following data

   The following heights are

66, 65, 67, 62, 62, 65, 61, 70, 66, 66, 71, 63, 69, 65, 71, 66, 66, 69, 68, 62, 65, 67, 65, 71, 65, 70, 62, 62, 63, 64, 67, 67      

 The  sample size is n  =32

  The confidence level is [tex]k = 95[/tex]% = 0.95

The mean is evaluated as

          [tex]\= x = 66+ 65+ 67+ 62+ 62+ 65+ 61+ 70+ 66+ 66+ 71+63+ 69+ 65+ 71+ 66+ 66+ 69+ 68+ 62+ 65+ 67,+\\65+ 71+ 65+ 70+ 62+ 62+ 63+ 64+ 67+ 67 / 32[/tex]

=>   [tex]\= x = \frac{2108}{32}[/tex]

=>     [tex]\= x = 65.875[/tex]

The standard deviation is evaluated as

           [tex]\sigma = \sqrt{ v}[/tex]

Now  

   [tex]v = ( 66-65.875 )^2+(65-65.875)^2+( 67-65.875)^2+ (62-65.875)^2+ (62-65.875)^2+ (65-65.875)^2+( 61-65.875)^2+ (70-65.875)^2+ (66-65.875)^2+ (66-65.875)^2+ (71+63-65.875)^2+ (69-65.875)^2+ (65-65.875)^2+ (71-65.875)^2+( 66-65.875)^2+ (66-65.875)^2+ (69-65.875)^2+ (68-65.875)^2+ (62-65.875)^2+ (65-65.875)^2+ (67-65.875)^2,+\\(65-65.875)^2+ (71-65.875)^2+ (65-65.875)^2+ (70-65.875)^2+( 62-65.875)^2+( 62-65.875)^2+ (63-65.875)^2+ (64-65.875)^2+ (67-65.875)^2+ (67-65.875)^2 / 32[/tex]

=>[tex]v= 8.567329[/tex]

=>   [tex]\sigma = \sqrt{8.567329}[/tex]

=>   [tex]\sigma = 2.927[/tex]

The level of significance is evaluated as

        [tex]\alpha = 1 - 0.95[/tex]

        [tex]\alpha = 0.05[/tex]

The degree of freedom is  evaluated as

    [tex]Df = n- 1 \equiv Df = 32 -1 = 31[/tex]

The critical values for the level of significance is obtained from the z -table as

      [tex]t_c = t_{\alpha/2 } , Df = t _{0.05/2}, 31 =\pm 1.96[/tex]

The confidence interval is evaluated as

       [tex]\mu = \= x \pm t_c * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

        [tex]\mu =65.875 \pm 1.96* \frac{2.927}{\sqrt{32} }[/tex]

       [tex]\mu =65.875 \pm 1.01415[/tex]

=>    [tex]64.86<\mu<67[/tex]

Answer:

6 years is the correct answer.

Step-by-step explanation:

Given that

Principal, P =  £8000

Rate of interest, R = 3% compounding annually

Amount, A >  £9500

To find: Time, T = ?

We know that formula for Amount when interest in compounding:

[tex]A = P \times (1+\dfrac{R}{100})^T[/tex]

Putting all the values:

[tex]A = 8000 \times (1+\dfrac{3}{100})^T[/tex]

As per question statement, A >  £9500

[tex]\Rightarrow 8000 \times (1+\dfrac{3}{100})^T > 9500\\\Rightarrow (1+0.03)^T > \dfrac{9500}{8000}\\\Rightarrow (1.03)^T > 1.19[/tex]

Putting values of T, we find that at T = 6

[tex]1.03^6 = 1.194 > 1.19[/tex]

[tex]\therefore[/tex] Correct answer is T = 6 years

In 6 years, the amount will be more than £9500.