49 3/2 simplify with rational exponents.

Answers

Answer 1

Answer:

There. You didn't ask for and explanation!

Step-by-step explanation:

49 3/2 Simplify With Rational Exponents.
Answer 2

The solution of expression is,

⇒ 343

We have to given that;

The expression is,

⇒ [tex]49^{\frac{3}{2} }[/tex]

Now, We can simplify with rational exponents as,

⇒ [tex]49^{\frac{3}{2} }[/tex]

⇒ [tex](7^2 )^{\frac{3}{2} }[/tex]

Apply rule of exponent as,

⇒ [tex]7^2^* ^{\frac{3}{2} }[/tex]

⇒ 7³

⇒ 7 × 7 × 7

⇒ 343

Thus, The solution of expression is,

⇒ 343

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Related Questions

If the statement shown is rewritten as a conditional statement in if-then form, which best describes the conclusion?

When a number is divisible by 9, the number is divisible by 3.

then the number is divisible by 3

then the number is divisible by 9

O if a number is divisible by 3

O if a number is divisible by 9

Answers

Answer:

Correct statement: "the number is divisible by 3".

Step-by-step explanation:

The statement provided is:

When a number is divisible by 9, the number is divisible by 3.

The general form of a conditional statement in if-then form is:

[tex]p\rightarrow q[/tex]

This implies that if p, then q.

The part after the "if" is known as the hypothesis and the part after the "then" is known as the conclusion.

The if-then form of the provided statement is:

If a number is divisible by 9, then the number is divisible by 3.

So, the conclusion is:

"the number is divisible by 3"

Answer:

a

Step-by-step explanation:

How can you use an equilateral triangle to find the lengths of the sides in a 30-60-90 triangle?

Answers

Answer:

Step-by-step explanation:

1) divide equilateral tri from the middle you will get two 30-60-90 triangles

2) by using pythagorean law & trigimintory, you will get two unknowns (height and side length) and two functions

List the complete list of numbers that make up pi.

Answers

Answer:

Sry, i dont know all of the numbers. Hope this helps!

Here are the first:

Step-by-step explanation:

3.141592653589793238462643383279502884197169399375105820974944592307816406286208998628034825342117067982148086513282306647093844609550582231725359408128481117450284102701938521105559644622948954930381964428810975665933446128475648233786783165271201909145648566923460348610454326648213393607260249141273724587006606315588174881520920962829254091715364367892590360011330530548820466521384146951941511609433057270365759591953092186117381932611793105118548074462379962749567351885752724891227938183011949129833673362440656643086021394946395224737190702179860943702770539217176293176752384674818467669405132000568127145263560827785771342757789609173637178721468440901224953430146549585371050792279689258923542019956112129021960864034418159813629774771309960518707211349999998372978049951059731732816096318595024459455346908302642522308253344685035261931188171010003137838752886587533208381420617177669147303598253490428755468731159562863882353787593751957781857780532171226806613001927876611195909216420198938095257201065485863278865936153381827968230301952035301852968995773622599413891249721775283479131515574857242454150695950829533116861727855889075098381754637464939319255060400927701671139009848824012858361603563707660104710181942955596198946767837449448255379774726847104047534646208046684259069491293313677028989152104752162056966024058038150193511253382430035587640247496473263914199272604269922796782354781636009341721641219924586315030286182974555706749838505494588586926995690927210797509302955321165344987202755960236480665499119881834797753566369807426542527862551818417574672890977772793800081647060016145249192173217214772350141441973568548161361157352552133475741849468438523323907394143334547762416862518983569485562099219222184272550254256887671790494601653466804988627232791786085784383827967976681454100953883786360950680064225125205117392984896084128488626945604241965285022210661186306744278622039194945047123713786960956364371917287467764657573962413890865832645995813390478027590099465764078951269468398352595709825822620522489407726719478268482601476990902640136394437455305068203496252451749399651431429809190659250937221696461515709858387410597885959772975498930161753928468138268683868942774155991855925245953959431049972524680845987273644695848653836736222626099124608051243884390451244136549762780797715691435997700129616089441694868555848406353422072225828488648158456028506016842739452267467678895252138522549954666727823986456596116354886230577456498035593634568174324112515076069479451096596094025228879710893145669136867228748940560101503308617928680920874760917824938589009714909675985261365549781893129784821682998948722658804857564014270477555132379641451523746234364542858444795265867821051141354735739523113427166102135969536231442952484937187110145765403590279934403742007310578539062198387447808478489683321445713868751943506430218453191048481005370614680674919278191197939952061419663428754440643745123718192179998391015919561814675142691239748940907186494231961567945208095146550225231603881930142093762137855956638937787083039069792077346722182562599661501421503068038447734549202605414665925201497442850732518666002132434088190710486331734649651453905796268561005508106658796998163574736384052571459102897064140110971206280439039759515677157700420337869936007230558763176359421873125147120532928191826186125867321579198414848829164470609575270695722091756711672291098169091528017350671274858322287183520935396572512108357915136988209144421006751033467110314126711136990865851639831501970165151168517143765761835155650884909989859982387345528331635507647918535893226185489632132933089857064204675259070915481416549859461637180270981994309924488957571282890592323326097299712084433573265489382

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The figure shows a square floor plan with a smaller square area that will accommodate a combination fountain and pool.The floor with the fountain pool area removed has an area of 33 Square meters and a perimeter of 36 meters. Find the dimensions of the floor and the dimensions of the square that will accommodate the fountain and pool.

Answers

Answer:

  (x, y) = (7, 4) meters

Step-by-step explanation:

The area of the floor without the removal is x^2, so with the smaller square removed, it is x^2 -y^2.

The perimeter of the floor is the sum of all side lengths, so is 4x +2y.

The given dimensions tell us ...

  x^2 -y^2 = 33

  4x +2y = 36

From the latter equation, we can write an expression for y:

  y = 18 -2x

Substituting this into the first equation gives ...

  x^2 -(18 -2x)^2 = 33

  x^2 -(324 -72x +4x^2) = 33

  3x^2 -72x + 357 = 0 . . . . write in standard form

  3(x -7)(x -17) = 0 . . . . . factor

Solutions to this equation are x=7 and x=17. However, for y > 0, we must have x < 9.

  y = 18 -2(7) = 4

The floor dimension x is 7 meters; the inset dimension y is 4 meters.

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems. The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013. Is this an unusually high number of faulty modems

Answers

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, [tex]H_0[/tex] : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, [tex]H_A[/tex] : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

                             T.S. =  [tex]\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }[/tex]  ~  N(0,1)

where, [tex]\hat p[/tex] = sample proportion faulty modems= [tex]\frac{10}{367}[/tex] = 0.027

           n = sample of modems = 367

So, the test statistics  =  [tex]\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }[/tex]

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

Solve the system of equations. \begin{aligned} & -5y-10x = 45 \\\\ &-3y+10x=-5 \end{aligned} ​ −5y−10x=45 −3y+10x=−5 ​

Answers

Answer:

x = -2

y = -5

Step-by-step explanation:

We can solve this algebraically (substitution or elimination) or graphically. I will be using elimination:

Step 1: Add the 2 equations together

-8y = 40

y = -5

Step 2: Plug y into an original equation to find x

-3(-5) + 10x = -5

15 + 10x = -5

10x = -20

x = -2

And we have our final answers!

Answer:

[tex]\boxed{\sf \ \ \ x=-2 \ \ \ and \ \ \ y=-5 \ \ \ }[/tex]

Step-by-step explanation:

let s solve the following system

(1) -5y-10x=45

(2) -3y+10x=-5

let s do (1) + (2) it comes

-5y-10x-3y+10x=45-5=40

<=>

-8y=40

<=>

y = -40/8=-20/4=-5

so y = -5

let s replace y in (1)

25-10x=45

<=>

10x=25-45=-20

<=>

x = -20/10=-2

so x = -2

Tamar is measuring the sides and angles of Triangle T U V to determine whether it is congruent to the triangle below. For triangle K L M, side K M is 27 millimeters, side L M is 20 millimeters, and side K L is 12 millimeters. Angle K is 45 degrees, angle M is 25 degrees, angle L is 110 degrees. Which pair of measurements would eliminate the possibility that the triangles are congruent? Measure of angle T = 25 degrees and Measure of angle U = 45 degrees Measure of angle T = 110 degrees and Measure of angle V = 25 degrees Measure of angle T = 25 degrees and TU = 12 Measure of angle T = 110 degrees and UV = 27

Answers

Answer:  Measure of angle T = 25 degrees and Measure of angle U = 45 degrees

Step-by-step explanation:

Measure of angle T = 25 degrees and TU = 12 is the pair of measurements would eliminate the possibility that the triangles are congruent.

What are congruent triangles?

" Triangles are said to be congruent if the corresponding sides and angles of the one triangle are equals to the other triangles."

According to the question,

In triangle KLM,

KM =27millimeters

LM = 20millimeters

KL = 12 millimeters

∠K= 45degrees

∠M= 25 degrees

∠L = 110degrees

From the given measurements of the triangle we have,

side with measure 27millimeters is opposite to angle 110° .

side with measure 12millimeters is opposite to angle 25° .

side with measure 20millimeters is opposite to angle 45°.

From the conditions in triangle TUV to be congruent to triangle KLM ,

Measure of angle T = 25 degrees and TU = 12  is against the given condition of congruent triangle.

As angle T and side TU are adjacent to each other, which is against the correspondence of the given triangle.

Hence, measure of angle T = 25 degrees and TU = 12 is the pair of measurements would eliminate the possibility that the triangles are congruent.

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PLEASE answer pic provided

Answers

Answer:

50 to 60 seconds is the answer

polygon P'Q'R'S'T' shown on the grid below is an image of polygon PQRST after dilation with a scale factor of 3, keeping the origin as the center of dilation: ​

Answers

Answer:  d) SR and S'R' have the ratio 1:3

Step-by-step explanation:

In order for the polygons to be similar, they must have congruent angles and proportional side lengths.

a) ∠Q and ∠Q' have the ratio 1:3          

  FALSE - The angles must be congruent (not proportional)

b) TS and T'S' have equal lengths

 FALSE - We can see that there is a dilation so they cannot be congruent.

c) RT and R'T' have equal lengths

 FALSE - We can see that there is a dilation so they cannot be congruent.

d) SR and S'R' have a ratio of 1:3

 TRUE! - The sides are proportional so we can use this to prove similarity.

Answer:

D- The lengths of side SR and side S'R' are in the ratio 1:3.

Step-by-step explanation:

I took the test and it was right

Please answer this correctly

Answers

Answer:

25%

Step-by-step explanation:

less than 30 is from minimum to lower quartile. so, 25%

Which decimal is closest in value to the fraction below?
1/7
O A. 0.8
O B. .33333
O c. 0.143​

Answers

Answer:

0.143

Step-by-step explanation:

1/7 means 1 divided by 7. 1 divided by 7 is approximately 0.143.

Hope this helps!

LA=
Round your answer to the nearest hundredth.
A
5
B
3

Answers

Answer:

You didn't state it but you need to find Angle A.

From the Pythagorean Theorem, we calculate side ac

side ac^2 = 5^2 - 3^2  =25 -9 = 16 Side AC = 4

arc tangent angle A = 3 / 4 = .75

angle A =  36.87 Degrees

Step-by-step explanation:

A manufacturer knows that their items have a normally distributed length, with a mean of 18.1 inches, and standard deviation of 3.7 inches. If one item is chosen at random, what is the probability that it is less than 28.9 inches long

Answers

Answer:

Step-by-step explanation:

z = (X - μ) / σ, where X = date, μ = mean, σ = standard deviation

z = (28.9 - 18.1) / 3.7

z = 18.6

0.06681 is the area for this z.

6.681% shall be shorter than 18.6 inches.

Please answer this correctly I want genius expert or ace people to answer this correctly as soon as possible as my work is due today

Answers

Answer:

25%

Step-by-step explanation:

The last percentile always contains 25% of the observations.

what is the solution to the equation y=2/3x+3 X=-2

Answers

Answer: The solution  is [tex](-2,\frac{5}{3} )[/tex]

Step-by-step explanation:

it already gives you the solution for x so just plot it into the equation to solve for y.

y= [tex]\frac{2}{3} *\frac{-2}{1}+3[/tex]  

y= [tex]\frac{-4}{3}+\frac{3}{1}[/tex]

y= [tex]\frac{5}{3}[/tex]

   

Answer: -2 5/3

Step-by-step explanation:

y= 2/3*-2/1+3

y= -4+3/1

-2 5/3

Help please if your good at maths ?

Answers

Answer:

Year 7 = 75 students

Year 9 = 25 students

Step-by-step explanation:

Year 7 has 3/8 of the total since the circle is divided into 8 sections and has 3 of the 8 sections

3/8 * 200 students = 75

Year 9 has 1/8 of the total since the circle is divided into 8 sections and has 1 of the 8 sections

1/8 * 200 =25

If the two angles are complementary, find the measure of each of angle. I am having trouble decoding this problem in it it says 7f and 2f what is the formula for this problem

Answers

Answer:

f=10

Step-by-step explanation:

I don't know a formula for this but I can see that <CRE is a 90° angle so 7f+2f=90 and if f=10 7f=70 and 2f=20 which fits

The measure of angle of each is 70° and 20°.

What are Angles?

Angles are the figure formed by the intersection of two lines or rays by sharing a common point. This point is called the vertex of the angle.

Angles are usually measured in degrees or radians.

The given angles are complementary.

That is, ∠CRE is complementary, which means the angle is 90 degrees.

∠CRT + ∠TRE = 90°

(7f)° + (2f)° = 90°

9f = 90°

f = 90 / 9

f = 10

Hence ∠CRT = (7f)° = 70°

∠TRE = (2f)° = 20°

Hence the measure of each of the angle is 70° and 20°.

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Please answer this correctly

Answers

Answer:

54

Step-by-step explanation:

The pink parts are 9 out of total 11 parts.

9/11

Multiply with 66.

9/11 × 66

= 54

Hey there! :)

Answer:

P(Pink) = 54.

Step-by-step explanation:

Begin by calculating the possibility of the spinner landing on pink:

[tex]P(pink) = \frac{pink}{total}[/tex]

Therefore:

[tex]P(Pink) = \frac{9}{11}[/tex]

In this question, the spinner was spun 66 times. Since we have solved for the probability, we can set up ratios to find the probability of the spinner landing on pink out of 66.

[tex]\frac{9}{11}= \frac{x}{66}[/tex]

Cross multiply:

594 = 11x

Divide both sides by 11:

x = 54.

P(Pink) = 54.

(06.02)A six-sided number cube labeled 1 through 6 is rolled 200 times. An even number is rolled 115 times. Compare the theoretical probability of rolling an even number with the relative frequency of rolling an even number and select one of the statements below that best describes the situation. The theoretical probability and relative frequency are the same. The theoretical probability is larger than the relative frequency. The theoretical probability is smaller than the relative frequency. There is not enough information to determine the relative frequency.

Answers

Answer:

The theoretical probability is smaller than the relative frequency

Step-by-step explanation:

6-sided cube rolled 200 times

Probability of an even number is 1/2= 0.5

200*1/2= 100- theoretical probability

Experimental frequency= 115

Relative frequency= 115/200= 0.575

0.575 > 0.5

The theoretical probability is smaller than the relative frequency

Answer:

The theoretical probability is smaller than the relative frequency.

Step-by-step explanation:

Given the following functions f(x) and g(x), solve f[g(6)]. f(x) = 6x + 12 g(x) = x − 8

Answers

Answer:

Answer:

Option 2nd is correct.

=0.

Step-by-step explanation:

Given the function:

Solve:

First calculate:

f[g(x)]

Substitute the function g(x)

Replace x with x-8 in the function f(x) we get;

The distributive property says that:

Using distributive property:

Put x = 6 we get;

Therefore, the value of   is 0.

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

f(x) = 6x + 12

g(x) = x − 8

f(g(6))=?

g(6)=6-8= -2

f(-2)= -2*6+12= -12+12=0

f(g(6))= f(-2)=0

Find an explicit formula for the following sequence, an which starts with a1=−1. −1,1/2,−1/3,1/4,−1/5,…

Answers

Answer:

The sequence can be represented by the formula of its nth term:

[tex]a_n=\frac{(-1)^n}{n}[/tex]

Step-by-step explanation:

Notice that we are in the presence of an alternate sequence (the values alternate from negative to positive. Therefore we need to take into account that there should be a factor "-1" raised to the "n" value for the sequence. Also, given that the sequence looks in absolute value like the harmonic sequence, we conclude upon the following general form for the "nth" term of the sequence:

[tex]a_n=\frac{(-1)^n}{n}[/tex]

20 points answer thisssss

Answers

area =πr²

6.5²xπ=132.73

2.3²xπ=16.62

132.73-16.62= 116.11

116cm^2

i think its this anyway

Answer:

116 cm^2 to 3 s f's.

Step-by-step explanation:

The area of the shaded part = area of the outer circle - area of the inner circle

= π * 6.5^2 - π *  2.3^2

=  132.732 - 16.619

= 116.113  cm^2.

Pls Help!
Given the polynomial function below, find F(3).
F(x) = 2x3 - 7x + 1
A. 34
B. -8
C. 26
D. -2

Answers

Answer:

34

Step-by-step explanation:

F(x) = 2x^3 - 7x + 1

Let x= 3

F(3) = 2* 3^3 - 7*3 + 1

      = 2 * 27 -21+1

      = 54 -21 + 1

      = 34

Answer: 34

Step-by-step explanation:


Consider the diagram and the proof below.

Given: In △ABC, AD ⊥ BC
Prove: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

Triangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side C B forming a right angle. The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.

A 2-column table has 7 rows. The first column is labeled Statement with entries In triangle A B C line segment A D is perpendicular to line segment B C, In triangle A D B sine (uppercase B) = StartFraction h Over c EndFraction, c sine (uppercase B) = h, In triangle A C D, sine (uppercase C) = StartFraction h Over b EndFraction, b sine (uppercase C) = h, question mark, StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction. The second column is labeled Reason with entries given, definition of sine, multiplication property of equality, definition of sine, multiplication property of equality, substitution, and division property of equality.

What is the missing statement in Step 6?

b = c

StartFraction h Over b EndFraction = StartFraction h Over c EndFraction
csin(B) = bsin(C)

bsin(B) = csin(C)

Answers

Answer:

c- the right triangle altitude theorem

Step-by-step explanation:

i did it on edge! ; )

The missing statement in Step 6 is ,c- The right triangle altitude theorem.

We have given that,

In △ABC, AD ⊥ BC

Prove: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction.

Triangle A B C is shown.

What is the right triangle altitude theorem?

The right triangle altitude theorem or geometric mean theorem is a result in elementary geometry that describes a relation between the altitude on the hypotenuse in a right triangle and the two-line segments it creates on the hypotenuse

Therefore we have,

A perpendicular bisector is drawn from point A to point D on side C B forming a right angle.

The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.

So the missing statement in Step 6

b = c

c=The right triangle altitude theorem.

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The owner of a small machine shop has just lost one of his largest customers. The solution to his problem,he says, is to fire three machinists to balance his workforce with his current level of business. The owner says that it is a simple problem with a simple solution. The three machinists disagree. Why

Answers

Answer:

It may look simple to the owner because he is not the one losing a job. For the three machinists it represents a major event with major consequences

1) Use Newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given equation.
2 x − x2 + 1 = 0, x1 = 2
What is x3 =?
2) Use Newton's method to find all solutions of the equation correct to six decimal places.
x + 4 = x^2 - x
What is X =?
3) Use Newton's method to find all solutions of the equation correct to six decimal places.
5 cos(x) = x + 1
What is X =?
4) A graphing calculator is recommended.
Use Newton's method to find all solutions of the equation correct to eight decimal places. Start by drawing a graph to find initial approximations.
5A) Use Newton's method to find the critical numbers of the function
f(x) = x6 ? x4 + 3x3 ? 4x
What is X =?
B) Find the absolute minimum value of f correct to four decimal places.

Answers

Answer:

Check below, please

Step-by-step explanation:

Hello!

1) In the Newton Method, we'll stop our approximations till the value gets repeated. Like this

[tex]x_{1}=2\\x_{2}=2-\frac{f(2)}{f'(2)}=2.5\\x_{3}=2.5-\frac{f(2.5)}{f'(2.5)}\approx 2.4166\\x_{4}=2.4166-\frac{f(2.4166)}{f'(2.4166)}\approx 2.41421\\x_{5}=2.41421-\frac{f(2.41421)}{f'(2.41421)}\approx \mathbf{2.41421}[/tex]

2)  Looking at the graph, let's pick -1.2 and 3.2 as our approximations since it is a quadratic function. Passing through theses points -1.2 and 3.2 there are tangent lines that can be traced, which are the starting point to get to the roots.

We can rewrite it as: [tex]x^2-2x-4=0[/tex]

[tex]x_{1}=-1.1\\x_{2}=-1.1-\frac{f(-1.1)}{f'(-1.1)}=-1.24047\\x_{3}=-1.24047-\frac{f(1.24047)}{f'(1.24047)}\approx -1.23607\\x_{4}=-1.23607-\frac{f(-1.23607)}{f'(-1.23607)}\approx -1.23606\\x_{5}=-1.23606-\frac{f(-1.23606)}{f'(-1.23606)}\approx \mathbf{-1.23606}[/tex]

As for

[tex]x_{1}=3.2\\x_{2}=3.2-\frac{f(3.2)}{f'(3.2)}=3.23636\\x_{3}=3.23636-\frac{f(3.23636)}{f'(3.23636)}\approx 3.23606\\x_{4}=3.23606-\frac{f(3.23606)}{f'(3.23606)}\approx \mathbf{3.23606}\\[/tex]

3) Rewriting and calculating its derivative. Remember to do it, in radians.

[tex]5\cos(x)-x-1=0 \:and f'(x)=-5\sin(x)-1[/tex]

[tex]x_{1}=1\\x_{2}=1-\frac{f(1)}{f'(1)}=1.13471\\x_{3}=1.13471-\frac{f(1.13471)}{f'(1.13471)}\approx 1.13060\\x_{4}=1.13060-\frac{f(1.13060)}{f'(1.13060)}\approx 1.13059\\x_{5}= 1.13059-\frac{f( 1.13059)}{f'( 1.13059)}\approx \mathbf{ 1.13059}[/tex]

For the second root, let's try -1.5

[tex]x_{1}=-1.5\\x_{2}=-1.5-\frac{f(-1.5)}{f'(-1.5)}=-1.71409\\x_{3}=-1.71409-\frac{f(-1.71409)}{f'(-1.71409)}\approx -1.71410\\x_{4}=-1.71410-\frac{f(-1.71410)}{f'(-1.71410)}\approx \mathbf{-1.71410}\\[/tex]

For x=-3.9, last root.

[tex]x_{1}=-3.9\\x_{2}=-3.9-\frac{f(-3.9)}{f'(-3.9)}=-4.06438\\x_{3}=-4.06438-\frac{f(-4.06438)}{f'(-4.06438)}\approx -4.05507\\x_{4}=-4.05507-\frac{f(-4.05507)}{f'(-4.05507)}\approx \mathbf{-4.05507}\\[/tex]

5) In this case, let's make a little adjustment on the Newton formula to find critical numbers. Remember their relation with 1st and 2nd derivatives.

[tex]x_{n+1}=x_{n}-\frac{f'(n)}{f''(n)}[/tex]

[tex]f(x)=x^6-x^4+3x^3-2x[/tex]

[tex]\mathbf{f'(x)=6x^5-4x^3+9x^2-2}[/tex]

[tex]\mathbf{f''(x)=30x^4-12x^2+18x}[/tex]

For -1.2

[tex]x_{1}=-1.2\\x_{2}=-1.2-\frac{f'(-1.2)}{f''(-1.2)}=-1.32611\\x_{3}=-1.32611-\frac{f'(-1.32611)}{f''(-1.32611)}\approx -1.29575\\x_{4}=-1.29575-\frac{f'(-1.29575)}{f''(-4.05507)}\approx -1.29325\\x_{5}= -1.29325-\frac{f'( -1.29325)}{f''( -1.29325)}\approx -1.29322\\x_{6}= -1.29322-\frac{f'( -1.29322)}{f''( -1.29322)}\approx \mathbf{-1.29322}\\[/tex]

For x=0.4

[tex]x_{1}=0.4\\x_{2}=0.4\frac{f'(0.4)}{f''(0.4)}=0.52476\\x_{3}=0.52476-\frac{f'(0.52476)}{f''(0.52476)}\approx 0.50823\\x_{4}=0.50823-\frac{f'(0.50823)}{f''(0.50823)}\approx 0.50785\\x_{5}= 0.50785-\frac{f'(0.50785)}{f''(0.50785)}\approx \mathbf{0.50785}\\[/tex]

and for x=-0.4

[tex]x_{1}=-0.4\\x_{2}=-0.4\frac{f'(-0.4)}{f''(-0.4)}=-0.44375\\x_{3}=-0.44375-\frac{f'(-0.44375)}{f''(-0.44375)}\approx -0.44173\\x_{4}=-0.44173-\frac{f'(-0.44173)}{f''(-0.44173)}\approx \mathbf{-0.44173}\\[/tex]

These roots (in bold) are the critical numbers

I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!

Answers

Answer:

(x-1)(x-4)

Step-by-step explanation:

I used long division with polynomials to help me find the other factor to this problem.  Divide x cubed -5x squared -6x+8 by x+2 to get x squared -5x+4.

Hope this helps!

Answer:  (x + 2) (x - 4) (x - 1)

Step-by-step explanation:

Use synthetic division. If the remainder (last digit) is zero, then it is a factor. The other digits represent the coefficients of the reduced polynomial.

x³ - 3x² - 6 + 8   ; x + 2 = 0  --> x = -2

-2  |  1   -3    -6    8

    |  ↓   -2   10   -8  

       1    -5    4    0    → remainder is 0

Reduced polynomial: x² -5x + 4

                                = (x - 4) (x - 1)

Factored form: (x + 2) (x - 4) (x - 1)

Consider the set of sequences of seven letters chosen from W and L. We may think of these sequences as representing the outcomes of a match of seven games, where W means the first team wins the game and L means the second team wins the game. The match is won by the first team to win four games (thus, some games may never get played, but we need to include their hypothetical outcomes in the points in order that we have a probability space of equally likely points).A. What is the probability that a team will win the match, given that it has won the first game?B. What is the probability that a team will win the match, given that it has won the first two games? C. What is the probability that a team will win the match, given that it has won two out of the first three games?

Answers

Answer:

a) Probability that a team will win the match given that it has won the first game = 0.66

b) Probability that a team will win the match given that it has won the first two games= 0.81

c) Probability that a team will win the match, given that it has won two out of the first three games = 0.69

Step-by-step explanation:

There are a total of seven games to be played. Therefore, W and L consists of 2⁷ equi-probable sample points

a) Since one game has already been won by the team, there are 2⁶ = 64 sample points left. If the team wins three or more matches, it has won.

Number of ways of winning the three or more matches left = [tex]6C3 + 6C4 + 6C5 + 6C6[/tex]

= 20 + 15 + 6 + 1 = 42

P( a team will win the match given that it has won the first game) = 42/64 = 0.66

b)  Since two games have already been won by the team, there are 2⁵ = 32 sample points left. If the team wins two or more matches, it has won.

Number of ways of winning the three or more matches left = [tex]5C2 + 5C3 + 5C4 + 5C5[/tex] = 10 + 10 + 5 +1 = 26

P( a team will win the match given that it has won the first two games) = 26/32 = 0.81

c) Probability that a team will win the match, given that it has won two out of the first three games

They have played 3 games out of 7, this means that there are 4 more games to play. The sample points remain 2⁴ = 16

They have won 2 games already, it means they have two or more games to win.

Number of ways of winning the three or more matches left = [tex]4C2 + 4C3 + 4C4[/tex] = 6 + 4 + 1 = 11

Probability that a team will win the match, given that it has won two out of the first three games = 11/16

Probability that a team will win the match, given that it has won two out of the first three games = 0.69

What is the product? (3x-b)(2x^2-7x+1) A. -12x^2+42x-6 B. -12x^2+21x+6 C. 6x^3-33x^2+45x-6 D. 6x^3-27x^2-39x+6

Answers

Answer:

C.6x³-33x² + 45x-6

Step-by-step explanation:

(3x-6)(2x^2-7x+1)

= 3x(2x² - 21x +1) -6(2x² - 7x+1)

= (6x³ - 21x² + 3x) - (12x² - 42x+6)

= 6x³ - 21x² + 3x -12x² + 42x -6

= 6x³-33x² + 45x-6

Please answer this correctly

Answers

Answer:

3/10

Step-by-step explanation:

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