Here are two similar solid toys.
A
B
The ratio surface area of toy A : surface area of toy B is 7:9
The volume of toy B is 20 cm
I
Work out the volume of toy A.
Give your answer correct to 3 significant figures.
Answers
Answer:
13.7
Step-by-step explanation:
7*k²=9
k²=9/7
k=√9/7
k=1.133893419
20/1.133893419³=13.7
The volume of toy A will be equal to 13.7 cubic centimetres.
What are ratios and proportions?An ordered pair of numbers a and b, represented as a / b, is a ratio if b is not equal to 0. A proportion is an equation that sets two ratios at the same value.
The numerical relationship between two values demonstrates how frequently one value contains or is contained within another.
Given that the ratio surface area of toy A: to the surface area of toy B is 7:9. The volume of toy B is 20 cm
The computation of the volume of toy A is shown below:
7 × k²=9
k²= 9 ÷ 7
k=√(9 ÷ 7)
k = 1.133893419
Now
The volume of toy A = 20 ÷ 1.133893419³
The volume of toy A = 13.7 cubic centimetres
Therefore, the volume of toy A will be equal to 13.7 cubic centimetres.
The missing figure is attached with the answer below.
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Answers
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Step-by-step explanation:
There is a 2 hour gap in between 8:30 and 10:30 and since they only made 600 jars throughout those 2 hrs you can divide 600 by 2 so you can fins out how many jars they make every hr.
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[tex] \frac{14}{12} = \frac{AB}{18} \\ [/tex]
[tex] \frac{7}{6} = \frac{AB}{18} \\ [/tex]
Multiply sides by 18
[tex]18 \times \frac{7}{6} =18 \times \frac{AB}{18} \\ [/tex]
[tex]3 \times 7 = AB[/tex]
[tex]AB = 21[/tex]
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Thus the correct answer is (( C )) .
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A person places $7420 in an investment account earning an annual rate of 5.9%, compounded continuously. Using the formula V = Pe^{rt}V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 20 years.
Answers
Answer:
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Step one:
given
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Step two:
Required
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= $24147.50
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