Here are two rectangles.
B
A
The length of rectangle B is 25% greater than the length of rectangle A.
3
The width of rectangle B is three fifths x the width of rectangle A.
Find the fraction of area of rectangle b over area of rectangle a
Give your answer in its simplest form.

Answer:

[tex] \frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{4}{3}[/tex]

Step-by-step explanation:

Let the length of rectangle A be x units.

So, length of rectangle B

= x + 25% of x

= x + 0.25x

= 1.25x

Let the width of rectangle A be y units

So, Width of rectangle B

[tex]= \frac{3}{5}\times x\\

=0.6x [/tex]

Area of rectangle A = xy

Area of rectangle B

= 1.25x * 0.6y

= 0.75xy

[tex] \frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{xy}{0.75xy}\\\\

\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{1}{0.75}\\\\

\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{100}{75}\\\\

\red{\bold{\frac{Area \:of\: rectangle\: A}{Area \:of\: rectangle\: B} =\frac{4}{3}}} \\\\[/tex]

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