Helpppppp

The location of a vertical section through an object is shown by a(n)
_____ in the top view.

Answers

Answer 1

Answer:

Among us is the answer

Explanation:

If you play among is everyday then Among us is always the answer


Related Questions

Determine the tensile design strength for W16x89 and two connected 1/4"x12 in plates, with two lines of 7/8-in diameter bolts in each flange using A 572 Grade steel with Fy=50 ksi and Fu=65 ksi as shown in Figure. There are three bolts in each line 3-in on center. Check block shear for plate only.

Answers

Answer:

12

Explanation:

help asap 9) A poorly tied down blimp falls over in a field. If the blimp exerts a downward force of 4000 N over an area
of 250 m2, what pressure is put on the ground by the blimp?

Answers

Answer:

[tex]Pressure = 16\ pa[/tex]

Explanation:

Given

[tex]Force = 4000N[/tex]

[tex]Area = 250m^2[/tex]

Required

Determine the pressure

Pressure is calculated using:

[tex]Pressure = \frac{Force}{Area}[/tex]

Substitute values for Force and Area

[tex]Pressure = \frac{4000N}{250m^2}[/tex]

[tex]Pressure = 16N/m^2[/tex]

Change units

[tex]Pressure = 16\ pa[/tex]

could I please get help with this​

Answers

Answer:

1.[tex]I_{xc}[/tex] = 7.161458[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = 36.661458[tex]\overline 3[/tex] in.⁴

Iₓ = 28.6458[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = 138.6548[tex]\overline 3[/tex] in.⁴

2. [tex]I_{xc}[/tex] = 114.[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = 37.[tex]\overline 3[/tex] in.⁴

Iₓ = 457.[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = 149.[tex]\overline 3[/tex] in.⁴

3. The maximum deflection of the beam is 2.55552 inches

Explanation:

1. The height of the beam having a rectangular cross section is h = 2.5 in.

The breadth of the beam, is = 5.5 in.

The moment of inertia of a rectangular beam through its centroid is given as follows;

[tex]I_{xc}[/tex] = b·h³/12 = 5.5 × 2.5³/12 = 1375/192 = 7.161458[tex]\overline 3[/tex]

[tex]I_{xc}[/tex] = 7.161458[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = h·b³/12 = 2.5 × 5.5³/12 = 6655/192 = 36.661458[tex]\overline 3[/tex]

[tex]I_{yc}[/tex] = 36.661458[tex]\overline 3[/tex] in.⁴

The moment of inertia about the base is given as follows;

Iₓ = b·h³/3 = 5.5 × 2.5³/3 = 625/24 = 28.6458[tex]\overline 3[/tex]

Iₓ = 28.6458[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = h·b³/3 = 2.5 × 5.5³/3 = 6655/48= 138.6548[tex]\overline 3[/tex]

[tex]I_y[/tex] = 138.6548[tex]\overline 3[/tex] in.⁴

2. The height of the beam having a rectangular cross section is h = 7 in.

The breadth of the beam, b = 4 in.

The moment of inertia of a rectangular beam through its centroid is given as follows;

[tex]I_{xc}[/tex] = b·h³/12 = 4 × 7³/12 = 114.[tex]\overline 3[/tex]

[tex]I_{xc}[/tex] = 114.[tex]\overline 3[/tex] in.⁴

[tex]I_{yc}[/tex] = h·b³/12 = 7 × 4³/12 = 37.[tex]\overline 3[/tex]

[tex]I_{yc}[/tex] = 37.[tex]\overline 3[/tex] in.⁴

The moment of inertia about the base is given as follows;

Iₓ = b·h³/3 = 4 × 7³/3 = 457.[tex]\overline 3[/tex]

Iₓ = 457.[tex]\overline 3[/tex] in.⁴

[tex]I_y[/tex] = h·b³/3 = 2.5 × 5.5³/3 = 149.[tex]\overline 3[/tex]

[tex]I_y[/tex] = 149.[tex]\overline 3[/tex] in.⁴

3. The deflection, [tex]\delta _{max}[/tex], of a simply supported beam having a point load at the center is given as follows;

[tex]\delta_{max} = \dfrac{W \times L^3}{48 \times E \times I}[/tex]

The given parameters of the beam are;

The length of the beam, L = 22 ft. = 264 in.

The applied load at the center, W = 750 lbs

The modulus of elasticity for Cedar = 10,000,000 psi

The height of the wood, h = 3 in.

The breadth of the wood, b = 5 in.

The moment of inertia of the wood, [tex]I_{xc}[/tex] = b·h³/12 = 5 × 3³/12 = 11.25 in.⁴

By plugging in the given values, we have;

[tex]\delta_{max} = \dfrac{750 \times 264^3}{48 \times 10,000,000 \times 11.25} = 2.55552[/tex]

The maximum deflection of the beam, [tex]\delta _{max}[/tex] = 2.55552 inches

Which option identifies the next step in the following scenario?

After being chosen to reverse engineer the inside of an older refrigerator, an engineer determines all of the product’s components.

A: The engineer will create a detailed sketch that labels all of the visual components.
B: The engineer will create an enhanced version of the product.
C: The engineer will create an isometric computer analysis of all the components.
D: The engineer will create a prototype of the product.

Answers

Answer: The engineer will create a detailed sketch that labels all of the visual components.

Explanation:

It should be noted that the reverse engineering is required for the replacement and the modification of an existing product.

With regards to the question, the correct answer is option A "The engineer will create a detailed sketch that labels all of the visual components".

Answer:

visual engineer

Explanation:

took da class

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