Step-by-step explanation:
I cannot do this table nicely here, but it is totally simple : the first number in brackets is the input, the second number the corresponding output.
you can do this easily and faster than in here.
it is not a function, because e.g. the input values -2 and 4 have more than 1 output value assigned (in different offered pairs, sure, but the whole group of ordered pairs defines the relationship).
-2 has 6 and 8
4 has 6 and 15
to be a function, each input value can have only one associated output value.
I GIVE BRAINLEST !! PLS SLOLVE
Answer:
√6/2+1
Step-by-step explanation:
multiplying by √6/√6, we get √6(3+√6)/6=(3√6+6)/6=√6/2+1
What is the value of x + y when x is the additive identity and y = 5?
O 5
O There is not enough information to determine the value.
O - 5
O 0
Answer:
-5.
Step-by-step explanation:
5 + -5 = 0, so i's -5.
Please help ASAP
Solve for X.
Answer:
86
Step-by-step explanation:
So the angle your trying to find has another angle 4 the triangle is a right triangle so 90-4=86
Hopes This Helps :)
The perimeter of the shape is
feet.
Answer:
This doens't realy make sense dude
please help me with the question please ☹️
Answer:
the last one
Step-by-step explanation:
because those are oppiste poles
help me with this question plz
Answer:
2
Step-by-step explanation:
you tell me true ya false
If f(1) = 9 and f(n) = -4f(n-1) + 4 then find the value of f(3).
Answer:
132
Step-by-step explanation:
f(1) = 9
f(n) = -4f(n-1) + 4
Let n = 2
f(2) = -4f(2-1) + 4 = -4 f(1) +4 = -4(9) +4 = -36+4 = -32
Let n = 3
f(3) = -4f(2-1) + 4 =-4f(2)+4 = -4 (-32) +4 = 128+4=132
Find the missing side in the similar figures below
Answer:
e
Step-by-step explanation:
24*5/3=40
need this soon please
Answer: pretty sure -7
Step-by-step explanation:
Answer:
-7
Step-by-step explanation:
(-80) - (-10) is -79
-70 / (+10) = -7
Find the side of a rhombus if its diagonals are 14 and 48
(Use Pythagorean theorem)
Answer:
25
Step-by-step explanation:
Let,
Rhombus = ABCD
Diagonal = AC and BD
Mark its centre as O
Now,
AC = 2AO
AO = AC/2
AO = 48/2
AO = 24 cm
Also,
BD = 2BO
BO = BD/2
BO = 14/2
BO = 7 cm²
Now,
In ∆AOB
AB² = AO² + BO²
Here, AB is the side
AB² = (24)² + (7)²
AB² = 576 + 49
AB² = 625
AB = √(625)
AB = 25
WILL GIVE BRAINLIEST
Answer:
it is d
Step-by-step explanation:
Compare the investment below to an investment of the same principal at the same rate compounded annually.
principal: $1,000, annual interest: 6%, interest periods: 6, number of years: 14 more than the investment compounded annually.
After 14 years, the investment compounded periodically will be worth $ ____(Round to two decimal places as needed.)
After 14 years, the investment will be worth $ 2,306.72.
Given that an investment has a $ 1000 principal, 6% annual interest, 6 interest periods and 14 years of investment, to determine, after 14 years, how much the investment will be worth, the following calculation must be performed:
1000 x (1 + 0.06 / 6) ^ 14x6 = X 1000 x 1.01 ^ 84 = X 1000 x 2.3067 = X 2,306.72 = X
Therefore, after 14 years, the investment will be worth $ 2,306.72.
Learn more about maths in https://brainly.com/question/15603792
A train leaves a point A at 5 pm and reach another point B at 11 pm. Another train leaves point B at 7 pm and reach point A at 10 pm. At what point will the two trains meet?
Step-by-step explanation:
let's think this through.
train a goes from A to B in 6 hours. that means with a speed of 1/6 / hour.
train b goes from B to A in 3 hours, so it is twice as fast as train a = 2/6 / hour.
when train b leaves B (at 7pm), train a was already traveling for 2 hours (1/3 of the whole trip) leaving it with 4 hours to go (2/3 if the distance).
that means that at that point now both trains are moving against each other with a relative speed of 3 times the
speed of a (the original speed of a plus the double speed of b).
this is the same as one train standing, and the other going the whole distance with 3 times the speed of a.
the whole distance is 2/3 of AB.
the speed is 3/6 / hour = 1/2 / hour.
so, a single train with that speed would cover the total distance AB in 2 hours. or half of the distance in 1 hour.
the question now, how long for 2/3 of AB.
the distances relate by a factor :
1/2 × f = 2/3
f = 2/3 / 1/2 = 2/3 × 2/1 = 4/3
now we need to multiply also the time in the distance/time speed ratio by this factor.
therefore, 2/3 of the total distance is done in 1×4/3 = 4/3 of an hour.
that means both trains meet after 4/3 of an hour after 7pm.
that is 7pm plus 1 hour and 20 minutes giving us 8:20pm.
Help help help math math
Answer:
25%
Step-by-step explanation:
multiply it by 100 over 1 then divide the top by the bottom.
PLS HELP HELLLLLOPPPPPP PLEASSSS BRO IM LITERALLY GONNA CRY
Answer:
F The last option
{ n = 7 h - 2}
{ n = 4 h - 2}
Step-by-step explanation: I HOPE THIS HELPS
Answer:
it's
n=2h+4
n=2h+7
(and vice versa)
The given represent 7 necklace and 4 necklace,that means add it to the no.of necklace they can make every hour and that is 2. So the correct equation is in the above answers.
Step-by-step explanation:
I hope it helps you a lot dude lovelots
#LEARN WITH BRAINLY
Divide 7 divided by 3/5
Express your answer in simplest form.
Answer:
35/5
Step-by-step explanation:
7/1 divded by 3/5. flip 3/5 to its reciprocal so it becomes 5/3, then times 7/1 by 5/3
ChallengE
See attachment and answer :)
[tex]\displaystyle{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]
Answer :[tex]\displaystyle{\boxed{\red{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}\:=\:\dfrac{127\:\sqrt{3}}{6}}}}[/tex]
Step-by-step-explanation:
We have given an expression.
We have to simplify the expression.
The given expression is
[tex]\displaystyle{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]
[tex]\displaystyle{\implies\sf\:4\:\sqrt{16\:\times\:3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]
We know that,[tex]\displaystyle{\boxed{\pink{\sf\:\sqrt{a\:\times\:b}\:=\:\sqrt{a}\:\times\:\sqrt{b}\:}}\:\cdots\sf\:a\:,\:b\:\geq\:0}[/tex]
[tex]\displaystyle{\implies\sf\:4\:\sqrt{16}\:\times\:\sqrt{3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]
[tex]\displaystyle{\implies\sf\:4\:\times\:4\:\sqrt{3}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}}[/tex]
We know that,[tex]\displaystyle{\boxed{\blue{\sf\:\sqrt{\dfrac{a}{b}}\:=\:\dfrac{\sqrt{a}}{\sqrt{b}}\:}}\:\cdots\sf\:b\: > \:0}[/tex]
[tex]\displaystyle{\implies\sf\:16\:\sqrt{3}\:-\:\dfrac{5}{2}\:\times\:\dfrac{\sqrt{1}}{\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]
[tex]\displaystyle{\implies\sf\:16\:\sqrt{3}\:-\:\dfrac{5}{2}\:\times\:\dfrac{1}{\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]
[tex]\displaystyle{\implies\sf\:\dfrac{16\:\sqrt{3}\:\times\:2\:\sqrt{3}\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]
[tex]\displaystyle{\implies\sf\:\dfrac{16\:\times\:2\:\sqrt{3}\:\times\:\sqrt{3}\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}} \\ \\\displaystyle{\implies\sf\:\dfrac{32\:\times\:3\:-\:5}{2\:\sqrt{3}}\:+\:6\:\sqrt{3}}[/tex]
[tex]\displaystyle{\implies\sf\:\dfrac{8\:\times\:4\:\times\:3\:-\:5\:+\:(\:6\:\sqrt{3}\:\times\:2\:\sqrt{3}\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:(\:6\:\times\:2\:\times\:\sqrt{3}\:\times\:\sqrt{3}\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:(\:12\:\times\:3\:)}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:-\:5\:+\:12\:\times\:3}{2\:\sqrt{3}}} \\ \\ \\ \displaystyle{\implies\sf\:\dfrac{8\:\times\:12\:+\:12\:\times\:3\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{12\:(\:8\:+\:3\:)\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{12\:\times\:11\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{132\:-\:5}{2\:\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127}{2\:\sqrt{3}}} \\ \\ \\ \displaystyle{\implies\sf\:\dfrac{127}{2\:\sqrt{3}}\:\times\:\dfrac{\sqrt{3}}{\sqrt{3}}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127\:\sqrt{3}}{2\:\times\:3}} \\ \\ \\\displaystyle{\implies\sf\:\dfrac{127\:\sqrt{3}}{6}} \\ \\ \\ \displaystyle{\therefore\:\underline{\boxed{\red{\sf\:4\:\sqrt{48}\:-\:\dfrac{5}{2}\:\sqrt{\dfrac{1}{3}}\:+\:6\:\sqrt{3}\:=\:\dfrac{127\:\sqrt{3}}{6}}}}}[/tex]
what is the equation of the line that passes through the point (4,0) and has a slope of 5/4?
Answer:
y=5/4x-5
Step-by-step explanation:
y-y1=m(x-x1)
y-0=5/4(x-4)
y=5/4(x-4)
y=5/4x-20/4
y=5/4x-5
Suppose a 5-digit number is formed using the digits from 1 to 9 (without replacement). What is the probability that it will be an even number?
Answer:
First take 5 empty. Digits.The no of digits are 9 (1-9).The last no must be even so . The total no of even no’s . Are 4 (2,4,6,8)The probability of last digit is 4There are remaing 8 digits so. Place them where. U required. The probability are. 8, 7,6,5(no reputations)The final answer is 4*8*7*6*5=6720 waysAnswer:
0.444 (44.4%)
Step-by-step explanation:
All possible ending: 1,2,3,4,5,6,7,8,9 ... 9
ending with 2,4 6,8 to make even number: 4
___ ___ ___ ___ ___
even number : 8 * 7 * 6 * 5 * 4
All 5 digit without repeating: 8 * 7 * 6 * 5 * 9
possibility = (8*7*6*5*4) / (8*7*6*5*9)
= 4/9
= 0.444 (44.4%)
_______________________________________________
(4 * ₈P₄) / (9 * ₈P₄) = 4/9
Need help asap! I would appreciate it soo much if your answered.
Answer:
Step-by-step explanation:
The point of closest approach is on a line perpendicular to the zip line
perpendicular lines have negative reciprocal slopes, so the perpendicular line has slope (8/3)
y = (8/3)x + b
adding our known point (3, 16)
16 = (8/3)3 + b
b = 8
y = (8/3)x + 8
now find where the two lines intersect by solving two equations with two unknowns
y = (-3/8)x + 8
as the two lines have a common y intercept of 8, that is the common point
(0, 8)
The distance from (0, 8) to (3, 16) is
d = √((3 - 0)² + (16 - 8)²) = √73 = 8.5440037453...
d = 8.5 ft
A quadratic function and an exponential function are graphed below. How do the decay rates of the functions compare over the interval -2<= x <= 0?
The exponential function decays at one-half the rate of the quadratic function.
The exponential function decays at the same rate as the quadratic function.
The exponential function decays at two-thirds the rate of the quadratic function.
The exponential function decays at three-fourths the rate of the quadratic function.
Answer:
×e[-2,0}Why;-2<x<0
Write the compound inequality in interval rotationso the answer is;×e[-2,0}brainliest me thanks for later
Answer:
D) The exponential function decays at three-fourths the rate of the quadratic function.
Step-by-step explanation:
F r e e points for people that is low on points :)
Answer:
im not low on points but thank you <3.
Step-by-step explanation:
Answer:
:) :) :) :) :) :) :) :) :) :)
According to the website www.olx.uz, monthly rent for a two-bedroom apartment has a mean of
$250 and a standard deviation of $100 in the city of Andijan. The distribution of the monthly rent does not
follow the normal distribution. In fact, it is positively skewed. What is the probability of selecting a sample
of 40 two-bedroom apartments and finding the mean to be at least $275 per month?
Using the normal distribution and the central limit theorem, it is found that there is a 0.0571 = 5.71% probability of selecting a sample of 40 two-bedroom apartments and finding the mean to be at least $275 per month.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.In this problem:
The mean is of $250, hence [tex]\mu = 250[/tex].The standard deviation is of $100, hence [tex]\sigma = 100[/tex].The sample is of 40 apartments, hence [tex]n = 40, s = \frac{100}{\sqrt{40}}[/tex].The probability of selecting a sample of 40 two-bedroom apartments and finding the mean to be at least $275 per month is the p-value of Z when X = 275, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{275 - 250}{\frac{100}{\sqrt{40}}}[/tex]
[tex]Z = 1.58[/tex]
[tex]Z = 1.58[/tex] has a p-value of 0.9429.
1 - 0.9429 = 0.0571
0.0571 = 5.71% probability of selecting a sample of 40 two-bedroom apartments and finding the mean to be at least $275 per month.
You can learn more about the normal distribution and the central limit theorem at https://brainly.com/question/24663213
The area of any rectangular shape is given by the product of its width and length. If the area of a particular
rectangular garden is given by A = 15x°-35x and its width is given by 5x, then find an expression for the
garden's length.
The expression that can be used to find the
garden's length is l = 5x(x - 7) / 5x where l = (x - 7)
Given:
Area of a rectangle = 15x² - 35x
Width of the rectangle = 5x
Length of the rectangle = l
Area of the rectangle = length × width
15x² - 35x = l * 5x
Factor out the left hand side
5x(x - 7) = l * 5x
Divide both sides by 5x
5x(x - 7) / 5x = l
x - 7 = l
Therefore, the expression that can be used to find the garden's length is l = 5x(x - 7) / 5x
Learn more about area of a rectangle:
https://brainly.com/question/14137384
been trying for an hour, need help
Answer:
[tex]\sqrt{\frac{5}{2} }[/tex]
Step-by-step explanation:
We know that this is a 45-45 triangle. Where there are two angles that are 45 degrees and the other angle is a right angle (90 degrees).
The sides are a, b (which equals a) and, c (which equals a*square root of 2).
In this triangle we are given c, and tasked at finding a. Since c= [tex]a*\sqrt{2}[/tex], then we know that, [tex]\sqrt{5}= a*\sqrt{2}[/tex]. Divide the equation by square root of 2 to find a. Which equals [tex]\sqrt{\frac{5}{2} }[/tex]
Type the correct answer in each box.
The slope of the line shown in the graph is ___, and the y-intercept of the line is ___.
Answer:
The slope (or gradient) is 0.6 and the y-intercept is 6.
The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This distribution has a mean of 47 and a standard deviation of 7. Using the empirical rule, what is the approximate percentage of 1-mile long roadways with potholes numbering between 40 and 68?
This value is approximate.
==========================================================
Explanation:
Let's compute the z score for x = 40
z = (x-mu)/sigma
z = (40-47)/7
z = -1
We're exactly one standard deviation below the mean.
Repeat these steps for x = 68
z = (x-mu)/sigma
z = (68-47)/7
z = 3
This score is exactly three standard deviations above the mean.
Now refer to the Empirical Rule chart below. We'll add up the percentages that are between z = -1 and z = 3. This consists of the two pink regions (each 34%), the right blue region (13.5%) and the right green region (2.35%). These percentages are approximate.
34+34+13.5+2.35 = 83.85
Roughly 83.85% of the one-mile roadways have between 40 and 68 potholes.
1985 x 99 I already know the answer: 196515
Answer:
196515
Step-by-step explanation:
Answer:
196515
Step-by-step explanation:
At the beginning of a basketball season, the Panthers won 20 games out of 80 games. At this rate, how many games will they win in a normal 100-game season?
games
The
is the distance across a circle, going through the center.
circumference
diameter
radius
area
The distance across a circle, going through the center is called Diameter.