help with math please:)))))

Help With Math Please:)))))

Answers

Answer 1

Answer:

63 un²

Step-by-step explanation

Formula for Triangle = 1/2(b*h)

------------------------------------------------------------

Lets input our numbers

b(base) = 21

h(height) = 6

------------------------------------------------------------

Lets multiply

1/2(6 x 21) =

1/2(126) = 63

Now add the units

63 un²


Related Questions

Please help me solve this step by step please :(

Answers

Answer:

B) 60.21 ft²

Step-by-step explanation:

Area of a triangle = 1/2bh

You can‘t used mixed measurements (feet and inches), so you have to convert each length to inches

8’6”=102’

14’2”=170’

Now find the area

1/2 x 102 x 170 = 8670 in²

This is one of the answers, but the quetion asks how many quart feet you need.

So, convert it back to feet.

8670 x 0.06944444444 = 60.2083333

(You could also have converted the two lengths to feet. 8’6” = 8.5 ft.  14’2” = 14.16666666.  This way would probably have been faster.

1/2 x 8.5 x 14.166666 = 60.20833333)

Simplify this fraction: 36/168 show work pls

Answers

Answer:

0.214285714

Step-by-step explanation:

when you divide the numbers, you get 0.214285714.

36/168 = 0.214285714

Answer:

3/14

Step-by-step explanation:

first starting from 36/168, you can divide both by 3, which would be 12/56. then you can divide both numbers by 4, which would become 3/14, which is the in the most simplified form.

Need help with this, the answer is 61 but I need the work for it.

Answers

Answer:

61

Step-by-step explanation:

Arc AC = 180

Arc DC = 58

Arc AC = Arc AD + Arc DC

180 = Arc AD + 58

122 = Arc DC

Tangent Chord Angle = 1/2Intercepted Arc

Angle DBA = 1/2 Arc DC

Angle DBA = 1/2 (122)

Angle DBA = 61

Following are weights, in pounds, of two-month-old baby girls. It is reasonable to assume that the population is approximately normal.

12.32 11.87 12.34 11.48 12.66
8.51 14.13 12.95 9.34 8.63

Required:
a. Construct a interval for the mean weight of two-month-old baby girls.
b. According to the National Health Statistics Reports, the mean weight of two—month-old baby boys is 13.9 pounds. Based on the confidence interval, is it reasonable to believe that the mean weight of two-month—old baby girls may be the same as that of two-month-old baby boys? Explain.

Answers

Answer:

10.224 < μ < 12.622 ;

Since the mean weight of 2-montj old baby boys (13.9) falls outside the confidence interval, we can conclude that it is not reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys.

Step-by-step explanation:

The confidence interval is given as :

Mean ± Margin of Error

margin of error = Zcritical * standard deviation /sqrt(n)

n = sample size

From the data:

12.32, 11.87, 12.34, 11.48, 12.66, 8.51, 14.13, 12.95, 9.34, 8.63

From the data:

Using calculator :

Mean, = 11.423

Standard deviation, s = 1.934

Zcritical at 95% confidence interval = 1.96

Sample size, n = 10

Margin of Error = 1.96* 1.934/sqrt(10) = 1.199

Lower boundary = 11.423 - 1.199 = 10.224

Upper boundary = 11.423 + 1.199 = 12.622

10.224 < μ < 12.622

Since the mean weight of 2-montj old baby boys (13.9) falls outside the confidence interval, we can conclude that it is not reasonable to believe that the mean weight of two-month-old baby girls may be the same as that of two-month-old baby boys.

Enter an algebraic expression for the word expression.
The quotient of -5 and y
The expression is

Answers

9514 1404 393

Answer:

  -5/y

Step-by-step explanation:

The wording "the quotient of A and B" is used to signify A/B.

Here, we want the quotient of -5 and y:

  -5/y

Find the area of the shaded polygons



Answers

Explanation is in a file

Answer:

4 sq un

Step-by-step explanation:

Plssss helppppppl:((((

Answers

Answer:

I think it's 1.5 I'm not sure ._.

Answer:

1/3

Step-by-step explanation:

Total students = 36

No of boys = 24

No of girls = 36 - 24 = 12

Probability of selecting a girl = 12/36 = 1/3

i will love you if u please answer this question PLSS

Answers

Answer:

On the dive boat deck

Step-by-step explanation:

This is above the water level and water level is considered to be 0

pls love me <3

(11+x)/2-(9x-3)/4 x=3

Answers

Answer:

(11+X)/2-(9x-3)/4 x=3

subsititute 3 into all x

(11+3)/2-(9*3)-3)/4

first solve the first diviision

2-(9 times 3)-3/4

=2-(27-3)/4

=2-(24)/4

since the "2-" is there, you have to subtract it from 24 before you dividewhich would then be

22/4=5.5(in decimal form)

DON'T forget you have another bracket waiting for you since you were given 3 brackets. bring the first bracket down

2-(9x-3)/4 was solved and we got 5.5, so basically we are "substituting 5.5 into that part of the question)

11+x/5.5

11+3/5.5

14/5.5

=2.54 which is your final answer

Sorry if I went overboard lol.

Step-by-step explanation:

yes, the answer is 2.54 I believe.

Solve the equation square root of the quantity x plus 3 plus 4 equals 5 for the variable. Show each step of your solution process

Answers

Answer: x:-2

The procedure is attached.

Answer:

x=-2

Step-by-step explanation:

[tex]\sqrt{x+3}+4=5[/tex]

subtract 4 from each side

[tex]\sqrt{x+3} +4-4=5-4[/tex]

square both sides

[tex]\sqrt{x+3}^2=1^2[/tex]

so we have

[tex]x+3=1[/tex]

subtract 3 from each side

[tex]x+3-3=1-3[/tex]

so our answer is [tex]x=-2[/tex]

Quadrilateral ABCD is a parallelogram with < BCA= 50 , < DCA=60, find value of

Answers

Answer:

[tex]ADC = 70[/tex]

Step-by-step explanation:

Given

[tex]BCA = 50[/tex]

[tex]DCA = 60[/tex]

See attachment for parallelogram and complete question

Required

Find ADC

From the attachment:

[tex]BCD = BCA + DCA[/tex]

[tex]BCD = 50+60[/tex]

[tex]BCD = 110[/tex]

Adjacent angles add up to 180.

So:

[tex]ADC + BCD = 180[/tex]

[tex]ADC = 180-BCD[/tex]

[tex]ADC = 180-110[/tex]

[tex]ADC = 70[/tex]

Can anyone help me on this please

Answers

it should be 12.57 i remember having that question a few months back and i got it right

A snack is 5 parts peanuts and 2 parts raisins. How many pounds of peanuts should be mixed with one-half pound raisins

Answers

One and one fourths pounds aka 1 1/4 or 1.25

What is the distance between point A and point B on the coordinate plane?
HELP PLSS​

Answers

Answer:

3

Step-by-step explanation:

If you count the units its three units away from each other.

Ellie worked 6 hours on Monday, 4.5 hours on Tuesday, 4 hours on Wednesday, 5.75 hours on Thursday, and 3 hours on Friday. If she is paid $10.18 per hour. Find her gross earnings for the week.

Answers

Answer:

⚠️DO NOT RELY ON ME⚠️ But, just by doing It in my head i think it's 236.685, but I don't really know just my thought process and mental math

A carpenter is putting a skylight in a roof. If the roof measures 10 + 8 by 8 + 6 and the skylight measures + 5 by 3 + 4, what is the area of the remaining roof after the skylight is built?
a. 77^2 + 115 + 68
b. 77^2 + 105 + 28
c. 83^2 + 115 + 68
d. 77^2 − 105 + 28

Answers

Yea what the other girl said

If 3 students eat 2 pizzas how many pizzas are needed for 54 students

Answers

Answer:

18 pizzas

Step-by-step explanation:

Here's a challenge.... solve for this ​

Answers

I'm very bad in geometry. Sorry mom I failed geometry .

Write two expressions that are equivalent to the expression below. (9 - c) + (9 - c) + (9 - c) + (9 - c)

Answers

Answer:

4(9 – c)

36 – 4c

Step-by-step explanation:

An example of two equivalent expressions includes the general expression and then the one that is factored.

In a class of 30 students 16 have a cat and 15 have a dog there are 11 students who have a cat and a dog what is the probability that a student has a dog given they do not have a cat?

Answers

so we know 11 have cats and dogs and 15 have dogs so do 15-11=4 and divide that by all the students which is 30 and get 13.3%

The probability that a student has a dog given they do not have a cat is 0.1333.

What is probability?

Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.

For the given situation,

Total number of students = 30

[tex]n(s)=30[/tex]

Number of students have cat = 16

Number of students have dog = 15

Number of students have a cat and a dog = 11

The event is the probability that a student has a dog given they do not have a cat,

[tex]n(e)=15-11[/tex]

⇒ [tex]4[/tex]

Thus the probability that a student has a dog given they do not have a cat is

⇒ [tex]P(e)=\frac{n(e)}{n(s)}[/tex]

⇒ [tex]P(e)=\frac{4}{30}[/tex]

⇒ [tex]P(e)=0.1333[/tex]

Hence we can conclude that the probability that a student has a dog given they do not have a cat is 0.1333.

Learn more about probability here

https://brainly.com/question/16484393

#SPJ2

Please help! (I also put what a median is)

Answers

Answer:

Step-by-step explanation:

1. 2

2. 3

3. 6

4. 2

5. 4

Kai can wrap 42 gifts in 3 hours. Answer the following questions, assuming that Kai can continue wrapping gifts at that same rate. How many gifts can Kai wrap in 24 hours? _______________ How many hours would it take him to wrap 126 gifts? _______________ How many gifts does Kai wrap per hour? _______________

Answers

Answer:

1. 336

2. 9

3. 14

Step-by-step explanation:

He wraps 42 gifts/3hours

24 hours is 8 "3 hours"

42 hours per 3 gifts * 8 "3 hours" = 336 gifts

126 gifts is 3 "42 gifts"

3 hours per 42 gifts * 3 "42 gifts" = 9 hours

He wraps 42 gifts/3hours

divide these values by 3 and you get  14 gifts/one hour

14 gifts every one hour

MATH 20 POINTS HELP PLZ :)

Answers

Answer:

the answer is C.

Step-by-step explanation:

(40 POINTS!!!!) find FD

Answers

Answer:

FD = 25.94

Step-by-step explanation:

13x - 16 = 4x + 11 (Tangents drawn from an external point are equal)

13x - 4x = 11 + 16

9x = 27

x = 3

substituting x in 4x + 11,

4(3) + 11

12 + 11

23

ΔFED is a right triangle,

FD² = FE² + DE²

FD² = 12² + 23²

FD² = 144 + 529

FD² = 673

FD = 25.94

Answer:

FD= +-25.94

Step-by-step explanation:

EF=CF=r(radius)=12

we know,

FD^2=EF^2+ED^2 ......(1)

and

FD^2=CF^2+CD^2 ......(2)

We Know,

area of triangle, a= 1/2xbasexHeight

a=1/2xEFxED .......(3)

and

a=1/2xCFxCD .....(4)

from equation 3 and 4

1/2xEFxED=1/2xCFxCD

=> 1/2x12xED=1/2x12xCD

=>ED=CD

=>13x-16=4x+11

13x-4x=16+11

9x=27

x=3

so

FD^2=EF^2+(ED)^2

FD^2=(12)^2+(4x3+11)^2

=>FD^2=144+529

=>FD^2=673

FD=+-25.94

Solve the inequality:

8+4x≥12

Select one:

x≤1

x≥5

x≥1

x≤5

Answers

Answer:

x >_ 1

Step-by-step explanation:

Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!

(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)

8 + 4x >_ 12

-8             -8

4x >_ 4

/4       /4

x >_ 1

I don't understand how to solve Sequence dots? Can you show me step by step how to solve the first one A?

Answers

Answer how but just put it on brainly

Step-by-step explanation:

it tells you the answer

Please Help!!! I'll Give Best And Brainliest if it lets me!

Answers

Answer:

6

Step-by-step explanation:

this is the answer. have a great day.

6 is this answer, hope this help

does 7/10 x 80 represent 70% of 80

Answers

Answer:

yes

Step-by-step explanation:

I say yes I did the math for it

Please help me with number 6

Answers

x-4=y so when x is 40 then y will be 36
It’s gonna be 36 I think

(7^3)^3
Simplify.
Rewrite the expression in the form 7^n

Answers

Step-by-step explanation:

✧ [tex] \underline{ \underline{ \large{ \tt{R\: E \: M \: E \: M \: B \: E \: R}}} }: [/tex]

If [tex]( {x}^{a} )^{b} [/tex] is an algebraic term then [tex] {(x}^{a} )^{b} = {x}^{a \times b} [/tex] i.e When an algebraic term in the index form is raised to another index , the base is raised to the product of two indices.

⟶ [tex] \large{ \tt{( {7}^{3} ) ^{3} = {7}^{3 \times 3} = {7}^{9}}} [/tex]

☥ [tex] \boxed{ \boxed{ \large \tt{Our \: Final \: Answer : \underline{ \tt{ {7}^{9}}}}}} [/tex]

Hope I helped ! ♡

⋆ Have a wonderful day / night ! ♪

Let me know if you have any questions regarding my answer! ツ

[tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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