HELP !!!! when will someone -

Answer:

Step-by-step explanation:

area = (3x³y)(2xy + x⁵)

= 3x³y·2xy + 3x³y·x⁵

= 6x⁴y² + 3x⁸y

Answer: 36.6

Step-by-step explanation: did on delta math

Answer:

yeaa what

Step-by-step explanation:

Answer:

This is the correct graph but can it fit on your graph?

Step-by-step explanation:

Answer:

is in the photo

Step-by-step explanation:

hope this helps

Answer:

I'm confused

Step-by-step explanation:

maybe more context?

Answer:

(-4,-6)

hope this helps !

Answer:

a) The standard score associated with a gestation period of 13.8 months is of [tex]Z = -1[/tex]

b) 34% of whale pregnancies will have a gestation period between 13.8 and 15 months.

c) Since when [tex]X = 21[/tex], [tex]Z = 5 \geq 2[/tex], it would be unusual for a whale to have a gestation period of 21 months.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If [tex]Z \geq 2[/tex] or [tex]Z \leq -2[/tex], the measure X is considered to be unusual.

According to a website, the mean gestation period for a whale is 15 months. Assume the distribution of gestation periods is Normal with a standard deviation of 1.2 months.

I corrected to 1.2 because it is what makes sense considering the questions.

This means that [tex]\mu = 15, \sigma = 1.2[/tex]

a. Find the standard score associated with a gestation period of 13.8 months

This is Z when X = 13.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{13.8 - 15}{1.2}[/tex]

[tex]Z = -1[/tex]

The standard score associated with a gestation period of 13.8 months is of [tex]Z = -1[/tex]

b. Using the Empirical Rule and your answer to part a, what percentage of whale pregnancies will have a gestation period between 13.8 and 15 months?

The standard score associated with a gestation period of 13.8 months is of [tex]Z = -1[/tex], which means that it is one standard deviation below the mean.

The normal distribution is symmetric, which means that of the approximately 68% of measures within one standard deviation of the mean, 68%/2 = 34% are within one standard deviation below the mean(in this case, 13.8) and the mean(in this case 15), and 34% are within the mean and one standard deviation above the mean.

So 34% of whale pregnancies will have a gestation period between 13.8 and 15 months.

c. Would it be unusual for a whale to have a gestation period of 21 months? Why or why not?

Let's find the z-score

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{21 - 15}{1.2}[/tex]

[tex]Z = 5[/tex]

Since when [tex]X = 21[/tex], [tex]Z = 5 \geq 2[/tex], it would be unusual for a whale to have a gestation period of 21 months.

Answer:

Square, Quadrilateral, Rhombus, Rectangle

Step-by-step explanation:

Answer:

5/6

Step-by-step explanation:

Answer:

this is the equation for the graph y=(x+3)(x-2)

Answer:

A) 35

Step-by-step explanation:

x + 50 + 95 = 180

x + 145 = 180

x = 180 - 145

x = 35

Answer:

3?

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

1.75

Step-by-step explanation:

nsjdjdjdjdjndnsjdjdjjddbjdjsjsj its 1.75

Answer:

7/4

Step-by-step explanation:

3/4 * 2 1/3 = 7/4

Hope this helps =]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

Answer:

A.) 12x+15x=120

B.) 5 sweatshirts

Step-by-step explanation:

A.)  Let x=T-shirts

     Let y= Sweatshirts

B.)  12x+15x=120

     12(5)+15x=120

      60 +  15x=120

    -60            -60

________________

            15x=104

           ___   ____

            15        15

___________________

               x=6.93333*

*Round it down to 5

Step-by-step explanation:

[tex] \sqrt{3} is \: between \: 1.73and1.74[/tex]

Answer:

I think this is the answer

Answer:

0,-2,-4

Step-by-step explanation:

1st Integer = x-2

2nd Integer = x

3rd Integer = x+2

(x-2) + x + (x+2) = -6

x+x+x=-6

3x=-6

x=-2

Hope this helps!

Answer:

Step-by-step explanation:

i think its 104

Answer:

B

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

because they are telling you that the 7th graders were randomly chosen out of everyone who rides in a car to school to be fractioned out.

Answer:

may it help you..MARK ME AS BRAINLISTS PLS

Answer:

I will post 4,5 and 6 separately.

Answer:   26

Step-by-step explanation:

5×6 - 8 ÷2​

= 30 - 8 ÷2​

= 30 - 4

= 26​

Answer:

26

Step-by-step explanation:

so we start off with 5x6 from PEMDAS so 5x6 = 30

then we have 8 divided by 2 = 4

30-4 = 26

Answer:

is this statistics? i will change my answer once u explain to me thank you.

Step-by-step explanation:

Answer:

Its infinite

Step-by-step explanation:

Answer:

[tex](21in,30in)=>210in^2[/tex]

[tex](15in,18in)=>90in^2[/tex]

[tex](15in,30in)=>150in^2[/tex]

Step-by-step explanation:

Required

Match the expressions on the left with the right

(a) 21 in by 15 in

Calculate area

[tex]Area = 21in * 15in[/tex]

[tex]Area = 315in^2[/tex]

Multiply by [tex]1/3[/tex]

[tex]1-third = 315in^2 * \frac{1}{3}[/tex]

[tex]1-third = 105in^2[/tex]

Hence:

[tex](21in,15in)=>105in^2[/tex]

(b) 21 in by 30 in

Calculate area

[tex]Area = 21in * 30in[/tex]

[tex]Area = 630in^2[/tex]

Multiply by [tex]1/3[/tex]

[tex]1-third = 630in^2 * \frac{1}{3}[/tex]

[tex]1-third = 210in^2[/tex]

Hence:

[tex](21in,30in)=>210in^2[/tex]

(c) 15 in by 18 in

Calculate area

[tex]Area = 15in * 18in[/tex]

[tex]Area = 270in^2[/tex]

Multiply by [tex]1/3[/tex]

[tex]1-third = 270in^2 * \frac{1}{3}[/tex]

[tex]1-third = 90in^2[/tex]

Hence:

[tex](15in,18in)=>90in^2[/tex]

(d) 15 in by 30 in

Calculate area

[tex]Area = 15in * 30in[/tex]

[tex]Area = 450in^2[/tex]

Multiply by [tex]1/3[/tex]

[tex]1-third = 450in^2 * \frac{1}{3}[/tex]

[tex]1-third = 150in^2[/tex]

Hence:

[tex](15in,30in)=>150in^2[/tex]

Answer:

Step-by-step explanation:

Answer: Linda's 1/2 .  Phil's $0.50

Step-by-step explanation: the rate is the slop which is rise/run if that makes sense

Answer:

A

Step-by-step explanation:

use the formula A=pi*r^2 to find the answer

Answer:

34.54 ft2

Step-by-step explanation:

You could figure it out by simply it