Answers
Answer:
The answer is option B.
using formula; rate %of total sale + monthly salary = total income per month.
hope it helps...
Related Questions
A square with side lengths of 3 cm is reflected vertically over a horizontal line of reflection that is 2 cm below the bottom edge of the square. What is the distance between the points C and C’? cm What is the perpendicular distance between the point B and the line of reflection? cm What is the distance between the points A and A’? cm
Answers
Answer:
a) 4 cm
b) 5 cm
c) 10 cm
Step-by-step explanation:
The side lengths of the reflected square are equal to the original, and the distance from the axis(2) also remains the same. From there, it is just addition.
Hope it helps <3
Answer:
A) 4
B) 5
C) 10
Step-by-step explanation:
edge2020
Bread recipe calls for 2 1/2 cups of whole wheat flour 2/3 cup of rice flour 2 1/4 cups of white flour how many total cups of flour are needed write your answer as a simplified mixed number
Answers
Answer:
5 5/12
Step-by-step explanation:
u first find the common denominator which is 12
2 6/12
8/12
2 3/12
now u add them all
hope this helps
A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data: (25.53, 37.87) and (23.59, 39.81). One of these intervals is a 99% CI and the other is a 95% CI. Please match them.
Answers
Answer:
(25.53, 37.87): 95% CI
(23.59, 39.81): 99% CI
Step-by-step explanation:
The margin of error of a confidence interval is given by:
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
z is related to the confidence level. The higher the confidence level, the higher the values of z, and thus, we wider the confidence interval is.
In this question:
The narrower C.I. is the 95%, and the wider is the 99%. So
(25.53, 37.87): 95% CI
(23.59, 39.81): 99% CI
What is the distance between (−11, −20) and (−11, 5)?
−25 units
−15 units
15 units
25 units
Answers
Because -11 and -20 has a difference if -9 and -11 and 5 has a difference of 6 but it’s asking for difference so it’s -6 and when those are combined it’s -15.
Answer:
IT'S NOT -15 FOR SUREEE
Step-by-step explanation:
I Believe it's 15
the bus fare in a city is $2.00. people who use the bus have the option of purchashing a monthly coupoun book is $20.00. with the copoun bok, the fare is reduced to $1.00 Determine the number of times in a month the bus be used so that the total monthly cost without the coupon book is the same as the total monthly cost with the coupon book
Answers
Answer:
but I can do it if you want but I don't you too too y u your help and you have time can you
Step-by-step explanation:
guy who was it that you are not going to be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house
A consultant wants to ask workers at a factory about the workers' job satisfaction. Which of the following best describes a cluster sample of workers?
a. The consultant takes a list of the workers and selects every 6" worker until 60 workers are selected.
b. The consultant forms 5 groups of workers based on the workers' shifts. Then, he selects 12 workers at random from each group.
c. The consultant forms groups of 12 workers based on the lengths of time the workers have worked at the factory. Then, he randomly chooses 5 groups and selects all of the workers in these groups
Answers
Answer:
i think option c must be correct because it has formed the grops on the basis of length of time and made the group by random selection.
Find A x B, where A=(5i+j) , B=（i-5j)
Answers
Answer:
5i² - 25ij +ji-5j²
Step-by-step explanation:
Use distributive property
Answer:
The answer is 5i² - 24ij - 5j²Step-by-step explanation:
A = (5i+j)
B = (i-5j)
A × B is
( 5i + j) ( i - 5j)
Expand
We have
5i² - 25ij + ij - 5j²
The final answer is
5i² - 24ij - 5j²
Hope this helps you.
Write the following equation into logarithmic form. 5=3x
Answers
Answer:
[tex]log_35=x[/tex]
Step-by-step explanation:
I am going to assume you meant [tex]5=3^x[/tex]
When converting exponential equations into logarithmic form, remember this: [tex]y = log_bx[/tex] is equivalent to [tex]x = b^y[/tex]
An object of mass 2kg is attached to a spring. A force of 5nt is applied to move the object 0.5m from its equilibrium position. The damping force of the object sliding on the table is int when the velocity is 0.25m/second. The object is pulled to the left until the spring is stretched lm and then released with the initial velocity of 2m/second to the right.
Set up an I.V.P. to describe the motion of the object and solve it, then state the amplitude function of the motion.
Answers
Answer:
[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]
Step-by-step explanation:
Given that:
mass of the object = 2 kg
A force of 5nt is applied to move the object 0.5m from its equilibrium position.
i.e
Force = 5 newton
Stretchin (x) =0.5 m
Damping force = 1 newton
Velocity = 0.25 m/second
The object is pulled to the left until the spring is stretched lm and then released with the initial velocity of 2m/second to the right
SOLUTION:
If F = kx
Then :
5 N = k(0.5 m)
where ;
k = spring constant.
k = 5 N/0.5 m
k = 10 N/m
the damping force of the object sliding on the table is 1 newton when the velocity is 0.25m/second.
SO;
[tex]C \dfrac{dx}{dt}= F_d[/tex]
[tex]C* 0.25 = 1[/tex]
C = [tex]\dfrac{1 \ N }{0.25 \ m/s}[/tex]
C = 4 Ns/m
NOW;
[tex]m \dfrac{d^2x}{dt^2}+ C \dfrac{dx}{dt}+ kx = 0[/tex]
Divide through by m; we have;
[tex]\dfrac{m}{m}\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+ \dfrac{k}{m} x= 0[/tex]
[tex]\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+\dfrac{k}{m}x= 0[/tex]
[tex]\dfrac{d^2x}{dt^2}+ \dfrac{4}{2} \dfrac{dx}{dt}+\dfrac{10}{2}x= 0[/tex]
[tex]\dfrac{d^2x}{dt^2}+ 2 \dfrac{dx}{dt}+5x= 0[/tex]
we all know that:
[tex]x(t) = Ae^{(\alpha \ t)}[/tex] ------ (1)
SO;
[tex]\alpha ^2 + 2\alpha + 5 = 0[/tex]
[tex]\alpha = \dfrac{-2 \pm \sqrt{(4)-(4*5)}}{2}[/tex]
[tex]\alpha = -1 \pm 2i[/tex]
Thus ;
[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex] ------------ (1)
However;
[tex]\dfrac{dx}{dt} = e^{-t}[A \sin (2t)+ B cos (2t)]+ 2e ^{-t} [A \cos (2t)- B \ Sin (2t)][/tex] ------- (2)
From the question ; we are being told that;
The object is pulled to the left until the spring is stretched 1 m and then released with the initial velocity of 2m/second to the right.
So ;
[tex]x(0) = -1 \ m[/tex]
[tex]\dfrac{dx}{dt}|_{t=0} = 2 \ m/s[/tex]
x(0) ⇒ B = -1
[tex]\dfrac{dx}{dt}|_{t=0} =- B +2A[/tex]
[tex]=- 1 +2A[/tex]
1 = 2A
A = [tex]\dfrac{1}{2}[/tex]
From (1)
[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex]
[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)+ (-1) cos (2t)][/tex]
[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)-cos (2t)][/tex]
Assuming;
[tex]A cos \ \phi = \dfrac{1}{2}[/tex]
[tex]A sin \ \phi = 1[/tex]
Therefore:
[tex]A = \sqrt{\dfrac{1}{4}+1}[/tex]
[tex]A = \sqrt{\dfrac{1+4}{4}}[/tex]
[tex]A = \sqrt{\dfrac{5}{4}}[/tex]
[tex]A ={ \dfrac{ \sqrt5}{ \sqrt4}}[/tex]
[tex]A ={ \dfrac{ \sqrt5}{ 2}}[/tex]
where;
[tex]\phi = tan ^{-1} (2)[/tex]
Therefore;
[tex]x(t) = \dfrac{\sqrt 5}{2}e^{-t} \ sin (2 t - \phi)[/tex]
From above ; the amplitude is ;
[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]
A school is 16km due west of a school q.
What is the bearing of q from p?
Answers
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
A respiratory therapist predicts that the proportion of U.S. college students who smoke hookah is greater than 30%. To test this prediction, she surveys 300 random U.S. college, and it is determined that 80 of them smoke hookah. The following is the setup for this hypothesis test: H0:p=0.30 H0:p>0.30 The p-value for this hypothesis test is 0.10. At the 5% significance level, should she reject or fail to reject the null hypothesis? Select the correct answer below: Reject the null hypothesis because 0.30>0.05. Fail to reject the null hypothesis because 0.30>0.05. Reject the null hypothesis because the p-value =0.10 is less than the significance level α=0.05. Fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
Answers
Answer:
Fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
Step-by-step explanation:
The significant level for this case study is 5% - 0.05. If the results gotten is less than the significance level, we reject the null hypothesis, but if greater, we fail to reject the null hypothesis.
In this case study, the p-value is 0.10 which is a lot higher than 0.05, thus we will fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.
A statistics tutor wants to assess whether her remedial tutoring has been effective for her five students. She decides to conduct a related samples t-test and records the following grades for students prior to and after receiving her tutoring.
Tutoring
Before After
2.4 3.1
2.5 2.8
3.0 3.6
2.9 3.2
2.7 3.5
Test whether or not her tutoring is effective at a 0.05 level of significance. State the value of the test statistic. (Round your answer to three decimal places.)
t =
Compute effect size using estimated Cohen's d. (Round your answer to two decimal places.)
d =
Answers
Answer:
The test statistic value is, t = -5.245.
The effect size using estimated Cohen's d is 2.35.
Step-by-step explanation:
A paired t-test would be used to determine whether the remedial tutoring has been effective for the statistics tutor's five students.
The hypothesis can be defined as follows:
H₀: The remedial tutoring has not been effective, i.e. d = 0.
Hₐ: The remedial tutoring has been effective, i.e. d > 0.
Use Excel to perform the Paired t test.
Go to Data → Data Analysis → t-test: Paired Two Sample Means
A dialog box will open.
Select the values of the variables accordingly.
The Excel output is attached below.
The test statistic value is, t = -5.245.
Compute the effect size using estimated Cohen's d as follows:
[tex]\text{Cohen's d}=\frac{Mean_{d}}{SD_{d}}[/tex]
[tex]=\frac{0.54}{0.23022}\\\\=2.34558\\\\\approx 2.35[/tex]
Thus, the effect size using estimated Cohen's d is 2.35.
Peter samples her class by selecting 5 girls and 7 boys. This type of sampling is called?
Answers
Answer:
Hello!
______________________
Peter samples her class by selecting 5 girls and 7 boys. This type of sampling is called?
This type of sampling is called Stratified.
Hope this helped you!
:D
A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places.
Answers
Answer:
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
Step-by-step explanation:
For this case we have the following dataset given:
[tex] n= 146[/tex] represent the sample size
[tex] \hat p =0.23[/tex] represent the estimated proportion of interest
[tex] Conf=0.95[/tex] represent the confidence level
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
An efficiency expert hired by a manufacturing firm has compiled these data relating workers output to their experience:
Experience t (months) 0 3
Output Q (units per hour) 200 190
Suppose output Q Is related to experience t by a function of the form Q (t) = 300 - A e^-kt. Find the function of this form that fits the data.
Answers
Answer:
Q(t) = 300 - 100e^0.0318tStep-by-step explanation:
Given the relationship between the output as related to the experience t to be Q (t) = 300 - A e^-kt.
From the table, at t = 0, Q(t) = 200, substituting this into he equation to get A we have:
200 = 300 - A e^-k(0).
200 = 300 - A e^-0
200 = 300 - A
A = 300-200
A = 100
Secondly we need to get the constant k by substituting the other condition into the equation. When t = 3, Q(t) = 190
190 = 300 - A e^-k(3)
190 = 300 - 100e^-3k
190-300 = -100e^-3k
-110 = -100e^-3k
e^-3k = -110/-100
e^-3k = 1.1
Taking the natural logarithm of both sides we have;
ln(e^-3k) = ln1.1
-3k = 0.09531
k = 0.09531/-3
k = -0.0318
The function of this form that fits the data can be gotten by substituting A = 100 and k = -0.0318 into the modeled equation given as shown:
Q(t) = 300 - A e^-kt
Q(t) = 300 - 100e^-(-0.0318)t
Q(t) = 300 - 100e^0.0318t
Ben bought the enormous box of juice shown below. He drinks 450 cubic centimeters of juice each day. How many days does it take Ben to drink the box of juice?
Answers
Answer:
Step-by-step explanation:
to find the answer you have to find the vulume and then divide by 450
Answer:
7 days
Step-by-step explanation:
vol = 20*15*10.5
vol = 3150
how many days to drink 3150 cu.cm if Ben drinks 450 cu.cm per day?
3150 cu.cm / 450 cu.cm per day = 7 days
Pls help me help me
Answers
Answer:
C.
Step-by-step explanation:
When two lines are parallel, their slopes are the same.
Since the slope of line l is 2/7, the slope of its parallel line m must also be 2/7.
The answer is C.
Answer:
C. 2/7
Step-by-step explanation:
Parallel lines are lines that have the same slopes.
We know that line l is parallel to line m.
Therefore, the slope of line l is equal to the slope of line m.
[tex]m_{l} =m_{m}[/tex]
We know that line l has a slope of 2/7.
[tex]\frac{2}{7} =m_{m}[/tex]
So, line m also has a slope of 2/7. The answer is C. 2/7
The given equation has been solved in the table.
Answers
The closest we get is the addition property, which was used in step 2. This is a fairly similar idea because subtraction is effectively adding on a negative number. Example: 5-7 = 5+(-7). Though because your teacher is making a distinction between addition property of equality and subtraction property of equality, it's safe to say that the subtraction property is not used.
If Brooklyn College students have an IQ of 100, on average, with a standard deviation of 16 points, and I collect 48 BC Psychology students to see how Psych majors compare to all of BC, find the following:_______.
1. mu =
2. sigma =
3. mu _x bar =
4. sigma _x bar =
Answers
Answer:
1 [tex]\mu = 100[/tex]
2 [tex]\sigma = 16[/tex]
3 [tex]\mu_x = 100[/tex]
4 [tex]\sigma _{\= x } = 2.309[/tex]
Step-by-step explanation:
From the question
The population mean is [tex]\mu = 100[/tex]
The standard deviation is [tex]\sigma = 16[/tex]
The sample mean is [tex]\mu_x = 100[/tex]
The sample size is [tex]n = 48[/tex]
The mean standard deviation is [tex]\sigma _{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]\sigma _{\= x } = \frac{16 }{\sqrt{48} }[/tex]
[tex]\sigma _{\= x } = 2.309[/tex]
Identify the slope and y-intercept of the line −2x+5y=−30.
Answers
Answer:
slope = 2/5 , y-intercept = -30
Step-by-step explanation:
-2x + 5y = -30
5y = 2x - 30
y = 2/5x - 6
we know that the general form is:
y = (slope)*x + (y- intercept)
so, from our equation, we can say that...
slope = 2/5
y- intercept = -30
How does changing the maximum value affect the range? A. The range is greatly affected by this change. B. The range of a data set depends on the number of data, not the specific values. Therefore, the range does not vary by changing the maximum value. C. The range becomes more accurate when the maximum value is an outlier. D. The change in the range is low and insignificant.
Answers
Answer:
The correct option is (A).
Step-by-step explanation:
The range of a data set is a measure of variability of that data set.
The range is the difference between the maximum and minimum value of the set.
[tex]\text{Range}=\text{Maximum}-\text{Minimum}[/tex]
Since the maximum value is used in the computation of range, changing the maximum value affects the range greatly.
The correct option is (A).
Suppose that a certain brand of light bulb has a mean life of 450 hours and a standard deviation of 73 hours. Assuming the data are bell-shaped: (Show work to get full credit)
a. Would it be unusual for a light bulb to have a life span of 320 hours? 615 hours? Justify each response.
b. According to the Empirical Rule, 99.7% of the light bulbs have a lifetime between what two values?
c. Determine the percentage of light bulbs that will have a life between 304 and 596 hours.
Answers
Answer:
yes it is correct
Step-by-step explanation:
plz give brainliest.
Construct 3 linear equation starting with qiven solution z = 1/3
Answers
Answer:
(a)[tex]9z+2=5[/tex]
(b)[tex]21z-11=-4[/tex]
(c)[tex]4z=2-2z[/tex]
Step-by-step explanation:
We are required to construct 3 linear equations starting with the given solution z = 1/3.
Equation 1
[tex]z=\frac{1}{3}[/tex]
Multiply both sides by 9
[tex]9z=\frac{1}{3}\times 9\\9z=3[/tex]
Rewrite 3 as 5-2
9z=5-2
Add 2 to both sides
Our first equation is: [tex]9z+2=5[/tex]
Equation 2
[tex]z=\frac{1}{3}[/tex]
Multiply both sides by 21
[tex]21z=\frac{1}{3}\times 21\\21z=7[/tex]
Rewrite 7 as 11-4
21z=11-4
Subtract 11 from both sides
Our second equation is: [tex]21z-11=-4[/tex]
Equation 3
[tex]z=\frac{1}{3}[/tex]
Multiply both sides by 6
[tex]6z=\frac{1}{3}\times 6\\6z=2[/tex]
Rewrite 6z as 4z+2z
4z+2z=2
Subtract 2z from both sides
Our third equation is: [tex]4z=2-2z[/tex]
The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16 cost reports for each of the two departments shows cost variances of 2.5 and 5.5, respectively. Is this sample sufficient to conclude that the two production departments differ in terms of unit cost variance? Use = .10. State the null and alternative hypotheses.
Answers
Answer:
[tex]F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2[/tex]
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_2 -1 =16-1=15[/tex] and for the denominator we have [tex]n_1 -1 =16-1=15[/tex] and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:
[tex]p_v =2*P(F_{15,15}>2.2)=0.138[/tex]
For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different
Step-by-step explanation:
Information given
[tex]n_1 = 16 [/tex] represent the sampe size 1
[tex]n_2 =16[/tex] represent the sample 2
[tex]s^2_1 = 2.5[/tex] represent the sample deviation for 1
[tex]s^2_2 = 5.5[/tex] represent the sample variance for 2
[tex]\alpha=0.10[/tex] represent the significance level provided
The statistic is given by:
[tex]F=\frac{s^2_2}{s^2_1}[/tex]
Hypothesis to test
We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:
H0: [tex] \sigma^2_1 = \sigma^2_2[/tex]
H1: [tex] \sigma^2_1 \neq \sigma^2_2[/tex]
The statistic is given by:
[tex]F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2[/tex]
Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have [tex]n_2 -1 =16-1=15[/tex] and for the denominator we have [tex]n_1 -1 =16-1=15[/tex] and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:
[tex]p_v =2*P(F_{15,15}>2.2)=0.138[/tex]
For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different
A(2,9), B(4,k), and C(9, -12) are 3 collinear points.
Find the value of k.
Answers
==========================================================
Explanation:
We're going to be using the slope formula a bunch of times.
Find the slope of the line through points A and C
m = (y2 - y1)/(x2 - x1)
m = (-12-9)/(9-2)
m = -21/7
m = -3
The slope of line AC is -3. The slopes of line AB and line BC must also be the same for points A,B,C to be collinear. The term collinear means all three points fall on the same straight line.
-------
Let's find the expression for the slope of line AB in terms of k
m = (y2 - y1)/(x2 - x1)
m = (k-9)/(4-2)
m = (k-9)/2
Set this equal to the desired slope -3 and solve for k
(k-9)/2 = -3
k-9 = 2*(-3) ..... multiply both sides by 2
k-9 = -6
k = -6+9 .... add 9 to both sides
k = 3
If k = 3, then B(4,k) updates to B(4,3)
-------
Let's find the slope of the line through A(2,9) and B(4,3)
m = (y2 - y1)/(x2 - x1)
m = (3-9)/(4-2)
m = -6/2
m = -3 we get the proper slope value
Finally let's check to see if line BC also has slope -3
m = (y2 - y1)/(x2 - x1)
m = (-12-3)/(9-4)
m = -15/5
m = -3 we get the same value as well
Since we have found lines AB, BC and AC all have slope -3, we have proven that A,B,C fall on the same straight line. Therefore, this shows A,B,C are collinear.
P-value test and Ctitical Value test are identical. P-value and Critical value are two different names for the same steps. They can be used interchangeably.
a. true
b. false
Answers
Answer:
Option B - False
Step-by-step explanation:
Critical value is a point beyond which we normally reject the null hypothesis. Whereas, P-value is defined as the probability to the right of respective statistic which could either be Z, T or chi. Now, the benefit of using p-value is that it calculates a probability estimate which we will be able to test at any level of significance by comparing the probability directly with the significance level.
For example, let's assume that the Z-value for a particular experiment is 1.67, which will be greater than the critical value at 5% which will be 1.64. Thus, if we want to check for a different significance level of 1%, we will need to calculate a new critical value.
Whereas, if we calculate the p-value for say 1.67, it will give a value of about 0.047. This p-value can be used to reject the hypothesis at 5% significance level since 0.047 < 0.05. But with a significance level of 1%, the hypothesis can be accepted since 0.047 > 0.01.
Thus, it's clear critical values are different from P-values and they can't be used interchangeably.
Find the value of s(t(-2)):
s(x)= - 3x-2
t(x)=5x-4
Answers
Explanation: first let’s find figure out t(-2) first before we move on to the next one
t(x) = 5x-4
t(-2)= 5(-2)-4= -14
Now that we know t(-2) = -14
Then let’s find s(x) where x is -14
s(x)= -3x-2
s(-14)= -3(-14)-2= 42-2=40
And s(t(-2)) = 40
: Bobby's Burger Palace had its
grand opening on Tuesday,
They had 164 1/2 lb of ground
beef in stock. They had 18 1/4
Ib left at the end of the day.
Each burger requires 1/4 lb of
ground beef. How many
hamburgers did they sell?
Answers
Explanation:
164 1/2 = 329/2
18 1/4 = 73/4
Find the amount used:
329/2 - 73/4
= 658/4 - 73/4
= 585/4
Find the amount of burger made:
585/4 divide by 1/4
= 585/4 x 4/1
= 585
The surface area of an open-top box with length L, width W, and height H can be found using the
formula:
A = 2LH + 2WH + LW
Find the surface area of an open-top box with length 9 cm, width 6 cm, and height 4 cm.
Answers
Answer:
174 square cm
Step-by-step explanation:
2(9×4) + 2(6×4)+ 9×6
2(36) + 2(24) + 54
72 + 48 + 54
120 + 54
174
The dose of a drug is 0.05 mg for each kg of a patient’s weight.The Drug is available as an oral liquid containing 50 mcg/0.1 ml.Calculate the dose of the oral liquid in ml for a patient who weighs 132 lb
Answers
Answer:
6 mL
Step-by-step explanation:
It is a matter of units conversion.
volume = (mass) × (dose/mass) ÷ (dose/volume)
(132 lb)/(2.2 kg/lb) × (0.05 mg/kg) / (0.05 mg/0.1 mL) = 6 mL