Answer:
A = 18.5
Step-by-step explanation:
A = bh
A = 7.4(2.5)
A = 18.5
Answer:
18.
Step-by-step explanation:
Find the number of 4-digit numbers that contain at least three even digits.
Answer:
1234
Step-by-step explanation:
Answer:
2625
Step-by-step explanation:
First let's see all the possible combinations.
(Even=E, Odd= O)
1) EEEO
2) EEOE
3) EOEE
4) OEEE
5) EEEE
Now let's see what E and O possibly could be
E = 0, 2, 4, 5, 6 and 8 (5)
O = 1, 3, 5, 7, 9 (5)
Now we are just simply gonna multiply
1) EEEO = 4*5*5*5
2) EEOE = 4*5*5*5
3) EOEE = 4*5*5*5
4) OEEE = 5*5*5*5
5) EEEE = 4*5*5*5
The even contains a 0, so you can't put 0 in, so (5-1=4), there are only 4 digits for the even.
500 times 4 = 2000
5⁴ = 625
2000+625= 2625
find the height of a tree whose shadow is 42m long when the shadow of a man 1.8m tall is 2.4m long
Answer:
The ratio 1.8 : 2.4 can be rewritten as 3 : 4. We have to solve:
3 : 4 = x : 42
3 * 42 = 4x
x = 3 * 42 / 4 = 31.5
Help !!!! Match the written mathematical operation to the equivalent symbolic form
Answer:
The matched pairs are:
(A, 4), (B, 1), (C, 2) and (D, 3)
Step-by-step explanation:
The complete question is:
Match each description of an algebraic expression with the symbolic form of that expression :
A. 2 terms; variables = x and y
B. 3 terms; variables = x and y; constant = 3
C. 2 terms; variable = x; constant = 4.5
D. 3 terms; variables = x and y; constant = 2
1. x - 2y + 3
2. 4.5 - 2x
3. 4.5x + 2 - 3y
4. 4.5y - 2x
Solution:
A. 2 terms; variables = x and y ⇒ 4. 4.5y - 2x
B. 3 terms; variables = x and y; constant = 3 ⇒ 1. x - 2y + 3
C. 2 terms; variable = x; constant = 4.5 ⇒ 2. 4.5 - 2x
D. 3 terms; variables = x and y; constant = 2 ⇒ 3. 4.5x + 2 - 3y
What is the range of the function?
1
2
2
3
9
4
16
A. (2, 4, 9, 16)
B. {1, 2, 3, 4, 9, 16)
c. {1, 2, 3, 4)
D. {1,2}
Answer:
Im pretty sure its B
Step-by-step explanation:
Find the area in square centimeters of the composite shape shown below. Enter only a number as your answer.
Answer:
136 cm^2
Step-by-step explanation:
you can divide the shape into two shapes:
first : draw a line ⊥ to BC from point E to point F
rectangle : DCEF : Area = L*W=7*13=91 cm^2
the other shape AEBF is a trapezoid:
Area of AEBF= [(a+b)/2] h where a and b are the base and h is the height
height =18-13=5
a=7, b=11
A=[(7+11)/2]*5=45 cm^2
add the two areas : 45+91=136 cm^2
hope it works, many ways to find the area
Answer:
the answer is 49
Step-by-step explanation:
18+13+11+7=49
Drag each step and justification to the correct location on the table. Each step and justification can be used more than once, but not all steps and justifications will be used.
Order each step and justification that is needed to solve the equation below.
please help me
Answer/Step-by-step explanation:
Below are the steps to take in solving the given equation, as well as justification forf each step:
[tex] \frac{2}{3}y + 15 = 9 [/tex] => Given
[tex] \frac{2}{3}y + 15 - 15 = 9 - 15 [/tex] => subtraction property of equality
[tex] \frac{2}{3}y = - 6 [/tex] => simplification
[tex] \frac{2}{3}y * \frac{3}{2} = - 6 * \frac{3}{2} [/tex] => multiplication property of equality
[tex] y = - 9 [/tex] => simplification
PLEASE HELP Use the squared identities to simplify 2cos2x cos2x.
Answer:
D
Step-by-step explanation:
The correct option is option D as 2cos²(x)cos²(x) simplifies as follows:
2cos²(x)cos²(x) = {3 + 4cos(2x) + cos(4x)} / 4
Simplification:The given expression is : 2cos²(x)cos²(x)
The square identity for cosine is given by:
2cos²(x) -1 = cos(2x)
Thus,
2cos²(x) = {cos(2x) +1}
simplifying again,
cos²(x) = {cos(2x) +1}/2
Simplifying the above using squared identities:
2cos²(x)cos²(x) = {cos(2x) +1}cos²x
= {cos(2x) +1} {{cos(2x) +1}/2}
[tex]= \frac{\{cos(2x) +1\}^2}{2}\\\\=\frac{cos^2(2x)+2cos(2x)+1}{2}\\\\=\frac{\frac{cos(4x)+1}{2}+2cos(2x)+1}{2}\\\\=\frac{3+4cos(2x)+cos(4x)}{4}[/tex]
so,
2cos²(x)cos²(x) = {3 + 4cos(2x) + cos(4x)} / 4
Hence option D is correct.
Learn more about squared identities:
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The same honey is sold in two different jars. Large jar (540g): £4.10 Small jar (360): £2.81 By considering the amount of honey per penny, workout which jar is the best value for money.
Answer:
I would go with the smaller jar because the bigger jar is only less than 200 grams away from 360 but is more expensive
Find the total surface area in square kilometers, of the 3-dimensional
figure shown below.
Enter only a number as your answer.
[tex]\displaystyle\bf\\\textbf{We have a prism with a rectangular triangle base.}\\\\Base~area\!:~~Ab=\frac{3\times4}{2}=\frac{12}{2}=6~km^2\\\\Lateral~area\!:~~Al=(3+4+5)\times9=12\times9=108~km^2\\Total~area\!:~~At=2\times Ab+Al=2\times 6+108=12+108=\boxed{\bf120~km^2}\\[/tex]
I WILL MARK BRAINLIEST IF ANSWER IN LESS THAN 5 MINUTES!!!!!!! tory is buying bananas. she has 15 dollars and bananas are 2.45 each. how many bananas can she buy?
Answer:
6 bananas
Step-by-step explanation:
Divide the dollars by the price for bananas
15/2.45
6.12244898
Round down because she cannot buy part of a banana
6 bananas
HELPPPP ME ASAP PLEASEEE DO STEP BY STEPPPP Distribute and simplify the following: x(3x + 2)(-2x + 1)
Answer:
-6x^3 - x^2 + 2x
Step-by-step explanation:
We can first start with distributing the x using the distributive property
(3x^2 + 2x)(-2x+1) Remember that when x is multiplied with 3x, it increases the exponent to 3x^2)
Now we use FOIL to distribute (First, Outside, Inside, Last)
-6x^3 + 3x^2 - 4x^2 + 2x
We can combine the like terms (3x^2 and - 4x^2) into -x^2
-6x^3 - x^2 + 2x
These are Helen’s top three financial goals: create an emergency fund, save for a new guitar, and invest in her company’s stock. Select one attribute that matches each goal. Goal Attribute Create an emergency fund by next fall. specific, timely Save $50 per month to purchase a new guitar. timely, measurable Invest $130 in company stock. specific, timely
Answer:
1. timely
2. measurable
3. specific
Step-by-step explanation:
Lincoln is measuring the angles of quadrilateral WXYZ to determine whether it is congruent to the quadrilateral below.
Quadrilateral R S T Q. Angle R is 140 degrees, angle S is 94 degrees, angle T is 79 degrees, and angle Q is 47 degrees.
Which pair of measurements are possible if they are congruent figures?
Measure of angle W = 47 degrees and Measure of angle X = 94 degrees
Measure of angle X = 94 degrees and Measure of angle Z = 79 degrees
Measure of angle W = 47 degrees and Measure of angle Y = 140 degrees
Measure of angle X = 140 degrees and Measure of angle = 94 degrees
Answer:
None of these
Step-by-step explanation:
The congruent occurs when the two diagrams are matched with each other in terms of the same sides and same angles
In other terms, we can say that if both quadrilaterals contain the same sides and same angles so we called as congruent
As we can see in the figure that there is only angles are given but not the sides that are totally different
Hence, none of these is the right answer
Answer:
D.) Measure of angle X = 140 degrees and Measure of angle = 94 degrees
Step-by-step explanation:
please answer
what is 2y^4 x 5y^3
it is the answer of your question
Step-by-step explanation:
STEP
1
:
Equation at the end of step 1
(2y4 • 5) • y3
STEP
2
:
Equation at the end of step 2
(2•5y4) • y3
STEP
3
:
Multiplying exponential expressions
3.1 y4 multiplied by y3 = y(4 + 3) = y7
Final result :
(2•5y7)
Which equation is true?
The function f(x) is given by the set of ordered pairs.
{(1,0), (-10,2), (0,6), (3,17), (-2,-1)}
OH(- 10) = 1
f(2)= - 10
f(0) = 6
f(1) = - 10
Answer:
c f(0)=6
Step-by-step explanation:
they match
A large park in the shape of a rectangle is 8 km long and 6 km wide. How much shorter is your walk if you have to walk diagonally across the park than along the two sides of it?
Answer: The road is 4 miles shorter across the park
Step-by-step explanation: There are two right triangles
Answer:4 KM
Step-by-step explanation:
6km+4km=10km
Both sides 14 KM
[tex]\sqrt{6^{2} +4^{2}} =Diagonally[/tex]
Diagonally 10 KM
14KM-10KM=4KM
You cannot tessellate six-sided regular polygons by themselves.
A. True
B. False
Answer:
This statement is B. False
Step-by-step explanation:
You CAN tesselate six-sided regular polygons by themselves therefore, this statement is FALSE.
Hope this helped! :)
Answer:
Step-by-step explanation:
a man is four times as old as his son in five years time he will be three times as old as his son what is the present age of the son in years
I would start by setting up a chart like I did below.
Label one column age now and the other age in 5 years.
Since we don't know the son's age we use x.
We do know that the man's age is 4 times the son's age.
So the man's age will be 4x.
In the age in 5 year column, we add 5 to their current ages.
Now set up our equation.
Since it says "in five years" we use information in second column.
In 5 years time, he, "4x + 5", will be, equals,
3 times as old as his son, "3(x + 5)".
So we have 4x + 5 = 3(x + 5).
Solving from here, we find that x = 10.
So the son is 10 and the man is 4 times his age or 40.
Divide the following:
a) 25.2 divided by 0.6
b) 70.625 divided by 1.25
Answer:
25.2/0.6 = 4270.625/1.25 = 56.5you can do the normal operation
or use a calculator
Complete the table of values below:
x -3 -2 -1 0 1 2 3 How the graph relates to y=2x
y=2x Answer
Answer
Answer
Answer
Answer
Answer
Answer
Not applicable
y=-2x Answer
Answer
Answer
Answer
Answer
Answer
Answer
multiplied by Answer
y=(3)(2x)
Answer:
The values of x are:
x : -3, -2, -1, 0, 1, 2, 3
Let's solve each by putting each value of x into each equation:
a [tex]y = 2^x[/tex]
> x = -3
=> y = 2^(-3) = 1/8
> x = -2
=> y = 2^(-2) = 1/4
> x = -1
=> y = 2^(-1) = 1/2
> x = 0
=> y = 2^0 = 1
> x = 1
=> y = 2^1 = 2
> x = 2
=> y = 2^2 = 4
> x = 3
=> y = 2^3 = 8
b. [tex]y = -2^x[/tex]
> x = -3
=> y = -2^(-3) = -1/8
> x = -2
=> y = -2^(-2) = -1/4
> x = -1
=> y = -2^(-1) = -1/2
> x = 0
=> y = -2^0 = -1
> x = 1
=> y = -2^1 = -2
> x = 2
=> y = -2^2 = -4
> x = 3
=> y = -2^3 = -8
c. [tex]y = (3)(2^x)[/tex]
> x = -3
=> y = 3 * 2^(-3) = 3 * 1/8 = 3/8
> x = -2
=> y = 3 * 2^(-2) = 3 * 1/4 = 3/4
> x = -1
=> y = 3 * 2^(-1) = 3 * 1/2 = 3/2
> x = 0
=> y = 3 * 2^0 = 3 * 1 = 3
> x = 1
=> y = 3 * 2^1 = 3 * 2 = 6
> x = 2
=> y = 3 * 2^2 = 3 * 4 = 12
> x = 3
=> y = 3 * 2^3 = 3 * 8 = 24
Input these values into the table.
Answer:
x : -3, -2, -1, 0, 1, 2, 3
Let's solve each by putting each value of x into each equation:
a
> x = -3
=> y = 2^(-3) = 1/8
> x = -2
=> y = 2^(-2) = 1/4
> x = -1
=> y = 2^(-1) = 1/2
> x = 0
=> y = 2^0 = 1
> x = 1
=> y = 2^1 = 2
> x = 2
=> y = 2^2 = 4
> x = 3
=> y = 2^3 = 8
b.
> x = -3
=> y = -2^(-3) = -1/8
> x = -2
=> y = -2^(-2) = -1/4
> x = -1
=> y = -2^(-1) = -1/2
> x = 0
=> y = -2^0 = -1
> x = 1
=> y = -2^1 = -2
> x = 2
=> y = -2^2 = -4
> x = 3
=> y = -2^3 = -8
c.
> x = -3
=> y = 3 * 2^(-3) = 3 * 1/8 = 3/8
> x = -2
=> y = 3 * 2^(-2) = 3 * 1/4 = 3/4
> x = -1
=> y = 3 * 2^(-1) = 3 * 1/2 = 3/2
> x = 0
=> y = 3 * 2^0 = 3 * 1 = 3
> x = 1
=> y = 3 * 2^1 = 3 * 2 = 6
> x = 2
=> y = 3 * 2^2 = 3 * 4 = 12
> x = 3
=> y = 3 * 2^3 = 3 * 8 = 24
Input these values into the table.
please simplify this
Answer:
[tex]\frac{3\sqrt{2} }{2}[/tex]
Step-by-step explanation:
A bag contains 16 cards numbered 1 through 16. A card is randomly chosen from the bag. What is the probability that the card has a multiple of 3 on it?
Answer:
Step-by-step explanation:
Probability is expressed as
Number of favorable outcomes/total number of possible outcomes
From the information given,
Total number of outcomes = 16
Starting from 1, the multiples of 3 between 1 and 16 are 3, 6, 9, 12 and 15
This means that the number of favorable outcomes is 5
Therefore, the probability that the card has a multiple of 3 on it is
5/16 = 0.3125
At the beginning of an experiment, a scientist has 356 grams of radioactive goo. After 210 minutes, her sample has decayed to 44.5 grams. Find a formula for G ( t ) , the amount of goo remaining at time t . Keep at least 5 decimal places.
Answer: [tex]\bold{G(t)=356e^{-0.59413t}}[/tex]
Step-by-step explanation:
Use the decay formula: [tex]P=P_oe^{kt}[/tex] where
P is the remaining amount of the sampleP₀ is the original amount of the samplek is the decay ratet is the time (in hours)Given: P = 44.5, P₀ = 356, k = unknown, t = 210 minutes (3.5 hours)
[tex]44.5=356e^{k(3.5)}\\\\\\\dfrac{44.5}{356}=e^{3.5k}\\\\\\0.125=e^{3.5k}\\\\\\ln(0.125)=3.5k\\\\\\\dfrac{ln(0.125)}{3.5}=k\\\\\\-0.59413=k[/tex]
Input P₀ = 356 and k = -0.59413 into the decay formula
[tex]\large\boxed{P=356e^{-0.59413t}}[/tex]
Select the points that are solutions to the system of inequalities select all that apply
Answer:
B. (2, 4)
D. (10, -1)
Step-by-step explanation:
The solution sets must be in the shaded region of the systems of inequalities. It cannot be on either lines because both lines are dotted. In that case, only B and D work because they are inside the shaded regions while the other points are not.
Answer:
B. (2, 4)
D. (10, -1)
Step-by-step explanation:
To be a solution, a point must be in the shaded part of the graph.
Answer: (2, 4), (10, -1)
The pic is here , just the question wouldn’t show up right. Any help ?
Answer:
its 4√2i i think
Step-by-step explanation:
Answer:
Answer:B
Step-by-step explanation:
Given the transition matrix P and the? initial-state matrix Upper S 0S0 ?below, find Upper P Superscript 4P4 and use Upper P Superscript 4P4 to find Upper S 4S4. A B Upper PPequals= A B left bracket Start 2 By 2 Matrix 1st Row 1st Column 0.8 2nd Column 0.2 2nd Row 1st Column 0.3 2nd Column 0.7 EndMatrix right bracket 0.8 0.2 0.3 0.7 ?; Upper S 0S0equals= left bracket Start 1 By 2 Matrix 1st Row 1st Column 0.1 2nd Column 0.9 EndMatrix right bracket
Answer:
[tex]S^4=\left[\begin{array}{ccc}0.56875&0.43125\end{array}\right][/tex]
Step-by-step explanation:
[tex]\text{Initial-State Matrix}, S_0=\left[\begin{array}{ccc}0.1&0.9\end{array}\right][/tex]
[tex]\text{Transition Matrix}, P=\left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\end{array}\right][/tex]
First, we are to determine [tex]P^4[/tex].
[tex]P^2=\left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\end{array}\right]\left[\begin{array}{ccc}0.8&0.2\\0.3&0.7\end{array}\right]=\left[\begin{array}{ccc}0.8*0.8+0.2*0.3&0.8*0.2+0.2*0.7\\0.3*0.8+0.7*0.3&0.3*0.2+0.7*0.7\end{array}\right]\\\\=\left[\begin{array}{ccc}0.7&0.3\\0.45&0.55\end{array}\right][/tex]
[tex]P^4=(P^2)^2=\left[\begin{array}{ccc}0.7&0.3\\0.45&0.55\end{array}\right]\left[\begin{array}{ccc}0.7&0.3\\0.45&0.55\end{array}\right]\\=\left[\begin{array}{ccc}0.7*0.7+0.3*0.45&0.7*0.3+0.3*0.55\\0.45*0.7+0.55*0.45&0.45*0.3+0.55*0.55\end{array}\right]\\\\=\left[\begin{array}{ccc}0.625&0.375\\0.5625&0.4375\end{array}\right][/tex]
Therefore:
[tex]S^4=S_0P^4[/tex]
[tex]=\left[\begin{array}{ccc}0.1&0.9\end{array}\right]\left[\begin{array}{ccc}0.625&0.375\\0.5625&0.4375\end{array}\right]\\=\left[\begin{array}{ccc}0.1*0.625+0.9*0.5625&0.1*0.375+0.9*0.4375\end{array}\right]\\\\S^4=\left[\begin{array}{ccc}0.56875&0.43125\end{array}\right][/tex]
Answer:
CaCl2, MgO, Na2O
Step-by-step explanation:
Got it right on edg. 2020
A bike store marks up the wholesale cost of all bikes they sell by 30%. Calvin wants to buy a bike that has a price tag of $125. What was the wholesale cost of this bike?
Answer:
96.15
Step-by-step explanation:
The mark the bikes up 30 %
wholesale + wholesale * 30 percent = selling price
wholesale ( 1+ 30%) = selling price
wholesale (1.30) = 125
Divide by 1.30
wholesale = 125/1.30
wholesale =96.15384615
Rounding to the nearest cent
96.15
Answer:
the wholesale cost of this bike is $96.15
Step-by-step explanation:
2. If the bike is discounted by 20%, how much will Calvin pay (before tax)?
$100
Help pls!!! Indirect proofs?? probably super easy I just don't understand how to do
Answer:
If a figure has exactly three sides, then it is not a triangle.
Step-by-step explanation:
Josie ran a lap in 45.23 seconds.
Erica ran a lap in 43.11 seconds. How
much longer did it take Josie to rut
the lap?
Answer: 2.12 seconds
Step-by-step explanation:
From the question, we are informed that Josie ran a lap in 45.23 seconds while Erica ran a lap in 43.11 seconds.
To calculate the extra amount of time it took Josie to complete the lap, we subtract Erica's time from Josie's time. This will be:
= 45.23 seconds - 43.11 seconds
= 2.12 seconds
the density of ethanol is 1.09g/cm^3 the density of propylene is 0.97g/cm^3 80 litres of ethanol are mixed with 148 litres of propylene to make 228 litres of antifreeze work out the density of the antifreeze in g/cm^3
Answer:
The density of the final mixture is 1.012 g/cm³.
Step-by-step explanation:
To calculate the density of the final mixture we need to know the mass of each solution used is. We will also need to convert the volumes from litres to cm³, to do that we can just multiply 1000.
For the ethanol:
[tex]mass = volume*density\\mass = (80*1000)*1.09 = 87,200 \text{ g}\\[/tex]
For the propylene:
[tex]mass = (148*1000)*0.97 = 143,560 \text{ g}[/tex]
So the mass in the final mix is the sum of both:
[tex]mass_{final} = 87200 + 143560 = 230,760 \text{ g}[/tex]
Therefore the density is:
[tex]density_{final} = \frac{230760}{228000} = 1.012 \text{ }\frac{g}{cm^3}[/tex]
The density of the antifreeze is 1.01 g/cm³
Equations are used to show the relationship between two or more numbers and variables.
Let x represent the density of the antifreeze in g/cm^3.
1 cm³ = 0.001 L
80 L = 80000 cm³; 148 L = 148000 cm³, 228 L = 228000 cm³
Hence:
(1.09 * 80000) + (0.97 * 148000) = x * 228000
228000x = 230760
x = 1.01 g/cm³
The density of the antifreeze is 1.01 g/cm³
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