help plz- these were given to me and i was told i could only get help on two-

Answer:

x<20

Step-by-step explanation:

Building linear functions for each situation, the inequality is:

[tex]18x + 100 < 15x + 160[/tex]

------------------

Choice A:

Thus, the cost of inviting x guests is given by:

[tex]C_a(x) = 18x + 100[/tex]

Choice B:

Thus, the cost of inviting x guests is given by:

[tex]C_b(x) = 15x + 160[/tex]

A cost less than B, thus, the inequality is:

[tex]C_a(x) < C_b(x)[/tex]

[tex]18x + 100 < 15x + 160[/tex]

A similar problem is given at https://brainly.com/question/13270950

Answer:

He said " How much wrapping paper will Solomon need to cover all 7 boxes" so its probably 7-10 i think

Step-by-step explanation:

haha 900 is too much :) good try

Answer:

a31 = -334

Step-by-step explanation:

Given:

a1 = 26

a22 = -226

Find:

a31

Computation:

a22 = a + 21d

-226 = 26 + 21d

d = -12

a31 = a + 30d

a31 = 26 + 30(-12)

a31 = 26 - 360

a31 = -334

a1 = 26 and a22 = −226.

Answer:

A)  −334

Answer:

D)  Undefined slope

Step-by-step explanation:

Note that the x-coordinate (3) of both given points is 3.  This means that the two points lie on a vertical line.  The slope of a vertical line is undefined.

The correct answer is D)  Undefined slope

9514 1404 393

Answer:

  (x +3)(x +1)(x -2)

Step-by-step explanation:

A graphing calculator is a good tool for finding factors fast. Each zero (p) gives rise to a factor (x -p).

The graph shows zeros at -3, -1, and 2, so your factorization is ...

  (x +3)(x +1)(x -2)

Answer:

30 feet

Step-by-step explanation:

There a 3 ft in a yard

If there's 10 yards

then multiply 10 x 3 to get 30 feet

Use pythagoras theorem

x² = 48² + 14²

x² = 2500

x = √2500

x = 50

Answer:

you will time 2 by 2 then 4 by 4 you get 4 and 16 the multipl

those So you get 64 inches is your anser

Answer:x = -1 / 12

Step-by-step explanation: am i right??

8x + 8y = 2 -------(1)

8x + 5y = 1 -------(2)

subtract equation (2) from equation (1)

The 8x will be eliminated, leaving us with;

3y = 1

Divide bothside of the equation by 3

y = 1/3

substituting y = 1/3 in equation (1)

8x + 8y = 2

8x + 8(1/3) = 2

8x + 8/3 = 2

subtract 8/3 from both-side

8x + 8/3 -8/3 = 2 -8/3

8x = 2 - 8/3

8x = 6 - 8 / 3

8x = - 2/3

Divide both-side of the equation by 8

8x / 8 = -2/3 ÷ 8

x = -2/3 × 1/8

x = -1 / 12

Answer: A.

Step-by-step explanation: Its seems the only one on topic

Answer:

8,200= A)

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

edge 2020-2021

(xoxo proud of you <3)

Answer:

y=−9x and y=−4

Step-by-step explanation:

Answer:

66

Step-by-step explanation:

Answer:

x = 11.1

Its a right angle triangle with the values of its adjacent and hypotenuse given so cos is used.

Answer:

mhuaaa

Step-by-step explanation:

papapapapapapapapa

Answer:

The answer is 22.

Step-by-step explanation:

dklecmmkek

Answer:

Select All

Step-by-step explanation:

they all are correct

Answer:

75

Step-by-step explanation:

65 + 10 = 75

Answer:

GCF = x 2

x2 (x + 3)

Answer:

No solution

Step-by-step explanation:

Distribute

5x+45 = 3x+24+ 2x

Combine terms

45=5x-5x

45=0

This statement is not true so it is no solution

Answer:

Put the equation into the form ax 2 + bx = – c.

Make sure that a = 1 (if a ≠ 1, multiply through the equation by. before proceeding).

Using the value of b from this new equation, add. ...

Find the square root of both sides of the equation.

Solve the resulting equation.

Answer:

The answer is d.

Step-by-step explanation:

x is "a number." When a variable and a number are next to each other, they are being multiplied. So it's 7 times a number. Then you take the product of that and add 2.

So, d is the correct answer. :D

Answer: The walking path around it.

Step-by-step explanation:

Remember the Pythagorean's theorem, for a triangle rectangle with catheti A and B, and with hypotenuse H, we have:

A^2 + B^2 = H^2

or

H = √(A^2 + B^2)

Here, A + B is the total distance for the path, while the hypotenuse is the distance for the bridge

Here we can see that:

A = 1170 ft

B = 520 ft

Then:

H = √( (520 ft)^2 + (1170 ft)^2) = 1280.4 ft

Now, let's compute the costs.

For the bridge, we know that each foot costs $11, then for 1280.4 ft the cost is:

Cost of the bridge = (1280.4)*$11 = $14,084.4

And for the walking path, the cost is $6 per foot, then the total cost of the path is:

Cost of the path = (520 ft + 1170 ft)*$6 = $10,140

We know that the bridge is preferred if it is within the range of $1500 for the path's cost.

This range is:

($10,140 - $1,500, $10,140 + $1,500) = ($8,640, $11,640)

Here we can see that the cost of the bridge does not belong to this range, (is higher) so the option we should recommend is the walking path around.

Answer:

9p^2-12p+4

Step-by-step explanation:

Apply perfect square formula;

a=3p , b=2

Apply perfect square formula;

(3p)^2-2*3p*2+2^2

Simplify:

=9p^2-12p+4

Answer:

125

Step-by-step explanation:

131.25   105

of      100

Cross multiply process

131.25x100=108x?

131.25x100=13125

13125=108?

13125/108=?

125=?

:)

Answer:

Step-by-step explanation:

sin(D) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

         = [tex]\frac{7}{14}[/tex]

         = [tex]\frac{1}{2}[/tex]

         = 0.5

cos(D) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

          = [tex]\frac{12.124}{14}[/tex]

          = 0.866

tanD = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

        = [tex]\frac{7}{12.124}[/tex]

        = 0.577

Since, sinE = cosD

Therefore, sinE = 0.866

Since, cosE = sinD

Therefore, cosE = 0.5

Since, tanE = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

                   = [tex]\frac{12.124}{7}[/tex]

                   = 1.732

Answer:

3<-3 FALSE

0>-333 True

-13>-10 false

-10>-13 true

Answer:

-10 > -13

Step-by-step explanation:

On a number line (I wanna see if this works lol)

|___|___|___|___|___|___|

-15  -14   -13   -12   -11   -10   -9

Answer: [tex]2\sqrt{34[/tex]

Step-by-step explanation: The answer simplified is 2 radical 34