Help on number 4
4.2 HW Straight Line Motion-Connecting Position, Velocity & Acceleration HW
Answers
Answer:
t=2s v(2)=-48feet/s
Explanation:
-16t^2+16t+32=0
(t-2)(t+1)=0
t=2
v(t)=s'(t)=-32t+16
v(2)=s'(2)=-32*2+16=-48
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