Answer:
3.85
Explanation:
Calculate molar mass, starting with each element, then find grams per mole, then convert.
please answer all three of these questions
Answer:
I think it's 1.D
2.C
3.C
my apologies if it's incorrect
what does litmus do when it is put into sodium hydroxide?
PLEASE ANSWER ME FAST PLEASE
Answer:
The red litmus turns to blue
Explanation:
Hope it helps
BRAINISEST & 10 POINTS
Answer:
In order from left to right, 7 (gamma), 5 (ultraviolet, now continue pattern), 4, 6, 2, 3, 1.
Which organ produces the female hormone estrogen
Answer:
Ovary
Explanation:
ovaries produce the most estrogen in females.
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
Answer: There are [tex]16.14 \times 10^{23}[/tex] atoms of hydrogen are present in 40g of urea, [tex](NH_{2})_{2}CO[/tex].
Explanation:
Given: Mass of urea = 40 g
Number of moles is the mass of substance divided by its molar mass.
First, moles of urea (molar mass = 60 g/mol) are calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol[/tex]
According to the mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms.
So, the number of atoms present in 0.67 moles are as follows.
[tex]0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms[/tex]
In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.
[tex]4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms[/tex]
Thus, we can conclude that there are [tex]16.14 \times 10^{23}[/tex] atoms of hydrogen are present in 40g of urea, [tex](NH_{2})_{2}CO[/tex].
can u pls help me i need the answer ASAP
When a mixture of oxygen and hydrogen is ignited in a test tube, the
reaction shown occurs. What happens to the total mass of the contents of
the test tube?
Answer:
follow me and pm and I answer your question
A sample of aluminum absorbed 9.86 J of heat and its temperature increased from 23.2 and 30.5 degrees * C . What is the mass of the aluminum? Th specific heat of aluminum is 0.902 J/g^ C . Round your answer to 2 significant figures. Do not include units in your answer. *
Explanation:
H=mc×∆©
9.86=m×0.902×(30.5-23.2)
m=1.5
Explanation:
The specific heat of a substance is the amount of heat required to raise the temperature of 1 gram of the substance by 1 degree Celsius. The formula for calculating the heat absorbed or released by a substance is `q = mcΔT`, where `q` is the heat absorbed or released, `m` is the mass of the substance, `c` is the specific heat of the substance, and `ΔT` is the change in temperature.
In this case, we can use this formula to solve for the mass of the aluminum sample. We know that `q = 9.86 J`, `c = 0.902 J/g°C`, and `ΔT = 30.5°C - 23.2°C = 7.3°C`. Plugging these values into the formula, we get:
`9.86 J = m * 0.902 J/g°C * 7.3°C`
Solving for `m`, we find that the mass of the aluminum sample is approximately `1.5 g`, rounded to 2 significant figures.
PLEASE mark as Brainliest
Describe how to test your unknown salt mixture for the presence of
Na3PO4.12H2O.
Na3PO4*12H2O + BaCl2*2H2O = Ba3(PO4)2 + NaCl + H2O
add barium chloride to your Na3PO4.12H2O a white precipitate of Ba3(PO4)2 will be formed wrt salt(NaCl) and water(H20) if Na3PO4.12H2O. will be there.
What is the answers?
Is my answer right?
Answer:
I say the correct answers are primary and secondary and teriary.
Explanation:
I say you are right!!
does anyone know this??
Answer: C2H6O
Explanation: It is C2H6O with a molar mass of 46.07 g/mol.
The mass of 1.63×10^21 silicon atoms
Answer:
I think it is 7.60 X 1
but if it's not srry
Consider four different samples: aqueous LiBr, molten LiBr, aqueous LiF, and molten LiF. Current run through each sample produces one of the following products at the anode: liquid bromine, fluorine gas, or oxygen gas. Match each sample to its anodic product from aqueous LiBr, Molten LiBr, aqueous LiF, and molten LiFA. Liquid bromine,
B. Fluorine gas,
C. oxygen gas
Answer:
Following are the solution to the given question:
Explanation:
Please find the matching in attached file.
During the electrolysis of Molten LiBr : Li is reduced and Br are oxidized .
Lithium Metal is produced at the Cathod during the electrolysis of Molten LiBR .
In the aquous LiBr : In aquous LiBr potential of Li is greater than the of water then Li is reduced to produce solid Li ion. As well As aqueous LiF ( electrolysis)and Molten LiF electrolysis produce the gas.
aqueous LiF: Oxygen gas.
Molten LiF : Flourine gas.
Determine the molarity and mole fraction of a 1.09 m solution of acetone (CH3COCH3) dissolved in ethanol (C2H5OH). (Density of acetone
Answer:
Molarity = 0.809 M
mole fraction = 0.047
Explanation:
The complete question is
Calculate the molarity and mole fraction of acetone in a 1.09-molal solution of acetone (CH3COCH3) in ethanol (C2H5OH). (Density of acetone = 0.788 g/cm3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.
Solution -
Solution for molarity:
1.09-molal means 1.09 moles of acetone in 1.00 kilogram of ethanol.
1)
Mass of 1.09 mole of acetone
= 1.09 mol x 58.0794 g/mol = 63.306 g
Density of acetone = 0.788 g/cm3
Thus, volume of 1.09 moles of acetone = 63.306 g/0.788 g/cm3 = 80.34 cm3
For ethanol
1000 g divided by 0.789 g/cm3 = 1267.427 cm3
Total volume of the solution = Volume of acetone + Volume of ethanol = 80.34 cm3 + 1267.427 cm3 = 1347.765 cm3 = 1.347 L
a) Molarity:
1.09 mol / 1.347 L = 0.809 M
Mole Fraction
a) moles of ethanol:
1000 g / 46.0684 g/mol = 21.71 mol
b) moles of acetone:
1.09 / (1.09 + 21.71) = 0.047
Use the chart above to help you answer the following questions.
2Na + 2HCI →
2 NaCl
+ H
(s)
(aq)
(aq) 2(g)
? What are the reactants in the chemical reaction shown above?
Answer:
2Na and 2HCl
Explanation:
The equation for the above chemical reaction is as follows:
2Na + 2HCI → 2NaCl + H2
In a reaction, the reactants are said to be those that combine together to form products. In this case, sodium (Na) and hydrochloric acid (HCl) are the reactants of this reaction
how many moles of Carbon are in 3.06 g of Carbon
Answer:
[tex]\boxed {\boxed {\sf 0.255 \ mol \ C }}[/tex]
Explanation:
If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).
Look up the molar mass of carbon.
Carbon (C): 12.011 g/molSet up a ratio using the molar mass.
[tex]\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Since we are converting 3.06 grams to moles, we multiply by that value.
[tex]3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.
[tex]3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}[/tex]
[tex]3.06 * \frac{1 \ mol \ C}{12.011 }[/tex]
[tex]\frac {3.06}{12.011 } \ mol \ C[/tex]
[tex]0.25476646 \ mol \ C[/tex]
The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
0.25476646The 7 in the ten-thousandth place tells us to round the 4 up to a 5.
[tex]0.255 \ mol \ C[/tex]
3.06 grams of carbon is approximately 0.255 moles of carbon.
If a gas is at a pressure of 46 mm Hg and temperature of 640 K, what would be the temperature if the pressure was raised to 760 mm Hg?
Answer:
10573.9K
Explanation:
Using pressure law equation;
P1/T1 = P2/T2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
P1 = 46mmHg
P2 = 760mmHg
T1 = 640K
T2 = ?
Using P1/T1 = P2/T2
46/640 = 760/T2
Cross multiply
640 × 760 = 46 × T2
486400 = 46T2
T2 = 486400 ÷ 46
T2 = 10573.9K
Congratulations you have worked hard and now you are done with the year! I am so proud of you!
Answer:
lololol
Explanation:
Assume that your empty crucible weighs 15.98 g, and the crucible plus the sodium bicarbonate sample weighs 18.56 g. After the first heating, your crucible and contents weighs 17.51 g. After the second heating, your crucible and contents weighs 17.50 g.What is the theoretical yield of sodium carbonate
The question is incomplete, the complete question is;
Assume that your empty crucible weighs 15.98 g, and the crucible plus the sodium bicarbonate sample weighs 18.56 g. After the first heating, your crucible and contents weighs 17.51 g. After the second heating, your crucible and contents weighs 17.50 g.
What is the theoretical yield of sodium carbonate?
What is the experimental yield of sodium carbonate?
What is the percent yield for sodium carbonate?
Which errors could cause your percent yield to be falsely high, or even over 100%?
Answer:
See Explanation
Explanation:
We have to note that water is driven away after the second heating hence we are concerned with the weight of the pure dry product.
Hence;
From the reaction;
2 NaHCO3 → Na2CO3(s) + H2O(l) + CO2(g)
Number of moles of sodium bicarbonate = 18.56 - 15.98 = 2.58 g/87 g/mol
= 0.0297 moles
2 moles of sodium bicarbonate yields 1 mole of sodium carbonate
0.0297 moles of 0.015 moles sodium bicarbonate yields 0.0297 * 1/2 = 0.015 moles
Theoretical yield of sodium carbonate = 0.015 moles * 106 g/mol = 1.59 g
Experimental yield of sodium bicarbonate = 17.50 g - 15.98 g = 1.52 g
% yield = experimental yield/Theoretical yield * 100
% yield = 1.52/1.59 * 100
% yield = 96%
The percent yield may exceed 100% if the water and CO2 are not removed from the system by heating the solid product to a constant mass.
scenario Juan and Maria Lopez wish to invest in a no-risk savings account. They currently have 530,000 in an account bearing 5.25 % annual interest, compounded continuously. The following options are available to them.
Answer:
The amount after three year is 617934.1302
Explanation:
Complete question
A person places $530,000 in an investment account earning an annual rate of 5.25%, compounded continuously. Using the formula V = Pe^{rt}V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 3 years
Solution
The formula for calculating compound interest is
[tex]A = p (1 + \frac{r}{n})^{nt}[/tex]
Substituting the given values we get -
[tex]A = 530,000 (1 + \frac{5.25}{100})^3\\A = 530,000 * ( 1+ 0.0525)^3\\A = 530,000 * ( 1.0525)^3\\A = 617934.1302[/tex]
The amount after three year is 617934.1302
How many grams of glucose (CH20) can corn grown in central Illinois make using 5.0 L of carbon dioxide gas and 2.5 L of water at 32 °C and 750 mmHg?
ground to two decimal values)
Answer:
5.9 g
Explanation:
Step 1: Write the balanced reaction for the photosynthesis
6 CO₂ + 6 H₂O ⇒ C₆H₁₂O₆ + 6 O₂
Step 2: Calculate the moles of CO₂
We have 5.0 L of CO₂ at 32 °C (305 K) and 750 mmHg. We can calculate the moles of CO₂ using the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 750 mmHg × 5.0 L/(62.4 mmHg.L/mol.K) × 305 K = 0.20 mol
Step 3: Calculate the moles of C₆H₁₂O₆ produced from 0.20 moles of CO₂
The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1. The moles of C₆H₁₂O₆ produced are 1/6 × 0.20 mol = 0.033 mol
Step 4: Calculate the mass corresponding to 0.033 moles of C₆H₁₂O₆
The molar mass of C₆H₁₂O₆ is 180.16 g/mol.
0.033 mol × 180.16 g/mol = 5.9 g
Which change to an object would double its kinetic energy?
A. Increasing its velocity to twice its original value
B. Increasing its mass to four times its original value
C. Increasing its mass to twice its original value
Ο Ο
D. Increasing its velocity to four times its original value
Answer:
Increasing its mass to twice its original value
Explanation:
Pls mark me brainliest
Which waves are blocked by the atmosphere? A. gamma rays B. visible light C. radio waves D. infrared waves
Answer: look at the explanation and try to work it
Explanation: in contrast, our atmosphere blocks most ultraviolet light (UV) and all X-rays and gamma-rays from reaching the surface of Earth. Because of this, astronomers can only study these kinds of light using detectors mounted on weather balloons, in rockets, or in Earth-orbiting satellites.
Write out the steps to finding the Empirical Formula.
The stream table shows the time needed for water to soak into the playfield soil.
Answer:
TRUE
Explanation:
plz brian list
Answer:
True
Explanation:
Consider the equation A(aq) 2B(aq) 3C(aq) 2D(aq). In one experiment, 45.0 mL of 0.050 M A is mixed with 25.0 mL 0.100 M B. At equilibrium the concentration of C is 0.0410 M. Calculate K. g
Answer:
K = 0.0396
Explanation:
Based on the reaction:
A + 2B ⇄ 3C + 2D
Where equilibrium constant, K, is:
K = [C]³[D]² / [A] [B]²
The initial concentrations of A and B are:
[A]₀ = 0.050M * (45.0mL / 70.0mL) = 0.0321M
[B]₀ = 0.100M * (25.0mL / 70.0mL) = 0.0357M
As [C] = 0.0410M, the molar concentration of D is:
0.0410M * (2mol D / 3mol C) = 0.0273M = [D]
And the concentration of A and B that reacted was:
0.0410M * (2mol B / 3mol C) = 0.0273M B
0.0410M * (1mol A / 3mol C) = 0.0137M A
Equilibrium concentration B and A:
0.0357M - 0.0273M = 0.0084M = [B]
0.0321M - 0.0137M = 0.0184M = [A]
And K is:
K = [0.0410M]³[0.0273M]² / [0.0184M] [0.0084M]²
K = 0.0396PLEASE HELP ME!!!!!!!
Answer:
The heat capacity of the metal underneath the gold is 0.431 J/g°C
Explanation:
Using the formula as outlined in the image:
Q = m × c × ∆T
Where;
Q = amount of heat energy (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to the information in this question;
Q = 503.9J
m = 23.02g
c = ?
∆T = 74°C - 23.2°C = 50.8°C
Using Q = m × c × ∆T
c = Q ÷ m∆T
c = 503.9 ÷ (23.02 × 50.8)
c = 503.9 ÷ 1169.42
c = 0.431 J/g°C
From the above heat capacity of the metal underneath the gold, it is obvious that the metal is not pure gold (c = 0.129J/g°C)
The solubility of an ionic compound can be expressed as the number of moles of the compound that will dissolve per liter of solution (molarity). The saturated solution has approximately____(a) sodium ions dissolved in it (give an estimate of the average value.) The solution (not the solid) contains approximately_____(b) moles of sodium ions.
Answer:
Number of moles of sodium dissolved = 6.0 *10^23
Explanation:
The image for the question is attached
Solution
a) Total 181 ions of Na are dissolved
b)
The number of moles of sodium dissolved = 181/6.023 *10^23
Number of moles of sodium dissolved = 5.987 * 10^23
Number of moles of sodium dissolved = 6.0 *10^23
If one neutron initiates a fission event that produces two neutrons in the products, how many new reactions can now be initiated? 9 If each of the neutrons produced in the first fission event then initiates a fission event that produces one neutron in the products, how many new reactions can now be initiated by each neutron? How many neutrons in total were produced by the two fission events described?
Answer:
See Explanation
Explanation:
A fission reaction is a chain reaction. The neutrons that are produced in one reaction leads to further chain reaction in the system.
If one neutron initiates fission that leads to the production of two other neutrons,two more new reactions are initiated.
If these reactions each produce one neutron, then another two new reactions are initiated. This makes a total of four new reactions from the two fission events described.
A total of four neutrons is produced from the two fission events.
Answer:
If one neutron initiates a fission event that produces two neutrons in the products, how many new reactions can now be initiated?
2
If each of the neutrons produced in the first fission event then initiates a fission event that produces one neutron in the products, how many new reactions can now be initiated by each neutron?
1
How many neutrons in total were produced by the two fission events described?
4
Explanation:
Got it correct on Edge.
HELP PLZ
Calculate the percent composition by mass of iron in Fe(NO3)3