Answers
Answer:
That is the Atomic mass
Explanation:
The element symbol is S, Element name is sulfur, and
Atomic number is 16
Related Questions
Is energy absorbed or released during cellular respiration?
Absorbed
Released
Answers
Answer:
Released
Explanation:
they convert into a form of energy that can be used by cells
Which food dyes in the diagram on the right only contain one colour?
( Science, Chromatography )
Answers
To a flask, 15.0 mL of 1.25 M hydrofluoric acid is added. Then, 3.05 M NaOH is used to titrate the acid sample. Write the balanced net ionic equation for the acid-base reaction.
HF(aq) + OH^- → H2O(I) + F^-
Answers
Answer:
H^+(aq) + OH^-(aq) --------> H2O(l)
Explanation:
We must first obtain the molecular equation, the net ionic equation before we obtain the net ionic equation.
The molecular reaction equation is;
HF(aq) + NaOH(aq) -------> H2O(l) + NaF(aq)
The complete ionic equation is;
H^+(aq) + F^-(aq) + Na^+(aq) + OH^-(aq) --------> H2O(l) + Na^+(aq) + F^-(aq)
The net ionic equation is;
H^+(aq) + OH^-(aq) --------> H2O(l)
When drawing a Bohr model for Sulfur, how many energy levels will you
draw?
5
4
3
2.
Answers
Answer:
3
Explanation:
2,8,6
how many grams of na2co3 would be needed to produce 1000g of nahco3
Answers
Answer:
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
Explanation:
The balanced reaction is:
Na₂CO₃ + CO₂+ H₂O → 2 NaHCO₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
Na₂CO₃: 1 moles CO₂: 1 moleH₂O: 1 mole NaHCO₃: 2 molesBeing the molar mass:
Na₂CO₃: 106 g/moleCO₂: 44 g/moleH₂O: 18 g/moleNaHCO₃: 84 g/moleThen by stoichiometry the following quantities of mass participate in the reaction:
Na₂CO₃: 1 mole* 106 g/mole= 106 gCO₂: 1 mole* 44 g/mole= 44 gH₂O: 1 mole* 18 g/mole= 18 gNaHCO₃: 2 moles* 84 g/mole= 168 gYou can apply the following rule of three: if 106 grams of Na₂CO₃ are needed to produce 168 grams of NaHCO₃, how much mass of Na₂CO₃ is necessary to produce 1000 grams of NaHCO₃?
[tex]mass of Na_{2} CO_{3}=\frac{1000grams ofNaHCO_{3} *106gramsofNa_{2} CO_{3} }{168grams ofNaHCO_{3}}[/tex]
mass of Na₂CO₃= 630.95 grams
630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃
The average adult heart pumps about 84./mLs of blood at 72 beats per minute. Suppose you need to calculate how long it would take the average heart to circulate 1700.mL of blood. Set the math up.
Answers
Answer:
1700 mL / 84 mLs
Explanation:
Given that:
Volume of blood pumped per minute = 84 /mLs
Time it takes to circulate 1700 mL of blood :
Time taken = Volume of blood circulate / Rate
Hence, to circulate 1700 mL of blood :
Time taken = 1700 mL / 84 mLs