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How did the lab activities help you answer the lesson question, "How do atmospheric conditions influence weather patterns?" What did you learn from conducting this lab?

Answer:

296.01 J

Explanation:

From the question,

Q = cm(t₂-t₁)....................... Equation 1

Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature

Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k

Substitute these values into equation 1

Q = 897×0.01×(55-22)

Q = 897×0.01×33

Q = 296.01 J

Hence 296.01 Joules of heat is required.

Answer:

acceleration due to gravity: -9.8 m/s^2

Fg=mass of object*(-9.8)

Explanation:

This is a pretty vague question, but I'll answer as best I can.

All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as

Force of gravity=(Gravitational constant*mass of object 1*mass of object  2)/distance between objects squared

Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)

Answer:

Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.

Explanation:

Definition of work in physics

Answer:

i dont know

Explanation:

hello

Answer:

F' = 64 F

Explanation:

The electric force between charges is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Where

q₁ and q₂ are charges

r is the distance between charges

When  each charge is doubled and the distance between them is 1/4 its original magnitude such that,

q₁' = 2q₁, q₂' = 2q₂ and r' = (r/4)

New force,

[tex]F'=\dfrac{kq_1'q_2'}{r'^2}[/tex]

Apply new values,

[tex]F'=\dfrac{k\times 2q_1\times 2q_2}{(\dfrac{r}{4})^2}\\\\=\dfrac{k\times 4q_1q_2}{\dfrac{r^2}{16}}\\\\=64\times \dfrac{kq_1q_2}{r^2}\\\\=64F[/tex]

So, the new force becomes 64 times the initial force.

Answer:

given Power= 5.6×1000=5600watt

t=20min=20×60=1200sec. work done=?

P=w/t

w=pt=5600×1200=672×10^4Joule

The amount of work done by the motor is equal to 6.72 Megajoules.

Given the following data:

Conversion:

To determine the amount of work done by the motor:

Mathematically, the work done by an object with respect to power and time is given by the formula:

[tex]Work\;done = power \times time[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 5600 \times 1200[/tex]

Work done = 6,720,000 Joules

Note: 1,000,000 Joules = 1 Megajoules.

Work done = 6.72 Megajoules.

Read more on work done here: https://brainly.com/question/13818347

Answer:

when waterways are polluted it affects all forms of life in the area - including us

expression:

for example when Lakes streams and ponds are polluted it can kill or harsh fish and other Wildlife that lives there!

hope that helps !

Work = (force) x (distance)

Work = (20 N) x (10 m)

Work = 200 Joules

Answer:

1. Mechanical energy = 298.4 Joules.

2. Mechanical energy = 2140 Joules.

3. Mechanical energy = 0.2838 Joules.

Explanation:

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

[tex] P.E = mgh[/tex]

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Given the following data;

1. Kinetic energy = 182.2 J

Potential energy = 116.2 J

To find the mechanical energy;

Mechanical energy = kinetic energy + potential energy

Mechanical energy = 182.2 + 116.2

Mechanical energy = 298.4 Joules.

2. Mass = 40kg

Velocity = 3m/s

Height = 5m

We know that acceleration due to gravity is equal to 9.8m/s²

To find the mechanical energy;

We would determine the kinetic and potential energy respectively.

K.E = ½mv²

K.E = ½*40*3²

K.E = 20*9

K.E = 180 Joules.

P.E = mgh

P.E = 40*9.8*5

P.E = = 1960 Joules

Mechanical energy = K.E + P.E

Mechanical energy = 180 + 1960

Mechanical energy = 2140 Joules.

3. Mass = 0.002kg

Height = 3m

Velocity = 15m/s

To find the mechanical energy;

K.E = ½mv²

K.E = ½*0.002*15²

K.E = 0.001*225

K.E = 0.225 Joules.

P.E = mgh

P.E = 0.002*9.8*3

P.E = = 0.0588 Joules

Mechanical energy = K.E + P.E

Mechanical energy = 0.225 + 0.0588

Mechanical energy = 0.2838 Joules.

Answer:

The balls in Pair 2 have a greater mass than the balls in pair 1.

Explanation:

I took the test.

Answer:

C

Explanation:

pls mark brainlest ty

have a good day

The gas has the same temperature throughout. (C)

Answer:

326 kg

Explanation:

m=f/a

3000/9.2=326 kg