Chemistry College


Which general equation represents an endothermic reaction?
A. reactants - energy - products + energy
B. reactants
products + energy
C. reactants + products - energy
D. reactants + energy
products

Answers

Answer 1

Explanation:

The general equation for an endothermic reaction is: Reactants + Energy → Products.

Hope it helps :)❤

Answer 2

The equation represents an endothermic reaction is reactants + energy

products.

What is an endothermic reaction?

Endothermic reactions are chemical reactions in which the reactants soak up warm strength from the surroundings to form products.

net energy is not released.heat is not evolved with the product.heat is required to start the reaction.increase with the increase in temperature.decrease with a decrease in temperature.

Learn more about the endothermic reaction here:-https://brainly.com/question/6506846

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Related Questions

Of the three Intermolecular forces, the type with the largest dissociation energy is ________.
A. Dipole-dipole interactions
B. Dispersion forces
C. Hydrogen bonds​

Answers

Answer:

C. Hydrogen bonds​

Explanation:

Strongest intermolecular force

Hydrogen Bonding (H-Bonding)

Hydrogen bonds are caused by highly electronegative atoms. They only occur between hydrogen and oxygen, fluorine or nitrogen, and are the strongest intermolecular force.

Answer: C hydrogen bonds

Explanation:

How many grams of ( S ) - 1 - chloro - 4 - ethyl - 2 - methylhexane and triphenylphosphine would you need to create 4 . 1 5g of ( S ) - 1 - chloro - 4 - ethyl - 2 - methyl triphenylphosphonium assuming an 8 1 % yield for the reaction?

Answers

Answer:

Explanation:

The standard molar mass is:

For (S )-1-chloro-4-ethyl-2-methylhexane = 162.5 g/mol

For triphenylphosphine  = 262 g/mol

For  ( S )-1-chloro-4-ethyl-2-methyl triphenylphosphonium = 424.5 g/mol

The mass required for 81% yield = [tex]\dfrac{81}{100} \times Theoretical \ yield = 4.15 g[/tex]

Theoretical yield = [tex]\dfrac{4.15}{0.81}[/tex]

= 5.1235 g

thus, since 424.5 g yield produce from 162.5 g

∴

5.1235 g yield will produce = [tex]\dfrac{162.5}{424.5}\times 5.1235 \ g[/tex]

= 1.9613 g of alkyl halide (-chloro) required.

Also, since 424.5 g yield produce from 262 g phosphine

∴

5.1235 g yield will produce = [tex]\dfrac{262}{424.5}\times 5.1235 \ g[/tex]

= 3.1622 g of triphenylphosphine required.

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