Explanation:
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A molecule of water H2O and a molecule of methane CH4 have close to the same mass Which statement explains why water has much higher boiling point than methane?
A. There is hoydrogen bonding between water molecules?
B. There is ionic bonding between water molecules
C. There is hydrogen bonding between methane molecules
D. There is ionic bonding between methane molecules
Answer:
A. There is hydrogen bonding between water molecules
Explanation:
Boiling point is a physical property of matter. It is typically conditioned by the intermolecular forces present between the molecules of a compound.
The nature of the intermolecular forces between the molecules of water is very different from those of methane. Water molecules have hydrogen bonds within their molecules. These intermolecular bonds are very strong compared to the london dispersion forces in methane. Hydrogen bond forms when the hydrogen of one molecule binds with the oxygen of another molecule.Answer:
A)
Explanation:
There is hydrogen bonding between water molecules
Which of the following best describes the difference between type a and type b
Where would you find convergent and divergent plate boundaries relative to
convection currents in the mantle?
Answer:
When two tectonic plates meet, we get a “plate boundary.” There are three major types of plate boundaries, each associated with the formation of a variety of geologic features.
Explanation:
When the plates meet at the boundaries the convergent boundaries lie at the collision of two plates and the divergent lies near mid-oceanic ridges.
What are plate boundaries?The earth plate tectonics are divided into the three types of plates as convergent which is the destruction of crust and are found where the heavy and light plate comes and colloid with each other submerging the heavier plate into the mantel.
The divergent ones found near the mid-oceanic ridges are the formation of a new plate as the plates diverge away from the ridges.
Find out more information about the plate boundaries.
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A 45 kg swimmer starting from rest can develop a maximum speed of 12 m/s over a distance of 20 m How much net force must be applied to do this ?
MUST SHOW WORK!
I’ll mark u as brainlist if you get this right!
12. The diameter of a circle is 2.42m. Calculate its
area in proper significant figure
Answer:
A = 4.6 [m²]
Explanation:
The area of a circle can be calculated by means of the following equation.
[tex]A=\frac{\pi }{4} *D^{2}[/tex]
where:
A = area [m²]
D = diameter = 2.42 [m]
Now replacing:
[tex]A=\frac{\pi }{4} *(2.42)^{2} \\A = 4.6 [m^{2} ][/tex]
heres what
GIMBAP KIMCHI PORK BELLY look like
Answer:
OWOWOWOOWOWOWEO. PORK = PORK NOW GIOVE BRAINLIEST BC I SAID PORK = PORK
Explanation:
Melinda is taking a tour through a new city on the tour she walk there .40 miles south 0.65 miles east 0.78 miles north 1.24 miles west then 1.20 miles south at the end of the tour what is Melinda's displacement vector
Answer:
The displacement vector is [tex]-0.59 \hat i -0.82 \hat j[/tex]
Explanation:
Taking East as positive x-axis having a unit vector [tex]\hat i[/tex] and North as positive y-axis having a unit vector [tex]\hat j[/tex].
So, west and south are in negative x and negative y directions respectively.
As she walks 0.40 miles south, 0.65 miles east, 0.78 miles north, 1.24 miles west then 1.20 miles south.
Scaling 1 mile as 1 unit vector, so 1 mile east = 1 [tex]\hat i[/tex] and so on
Adding all the displacement vectors, we have
[tex]\vec {v} = -0.40 \hat j +0.65 \hat i + 0.78 \hat j -1.24 \hat i - 1.20 \hat j[/tex]
[tex]\vec {v} = -0.59 \hat i -0.82 \hat j[/tex]
Hence, the displacement vector is [tex]-0.59 \hat i -0.82 \hat j[/tex]
How are speed and velocity similar?
Answer:
Speed and velocity are related in much the same way that distance and displacement are related. Speed is a scalar and velocity is a vector.
A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the following forces does only negative work on the crate?
Answer: Fn
Explanation: Because Fn is applying force upward
If a 2kg ball rolls down a ramp that is 15 meters long in 25 seconds, what is the
average speed of the ball?
Will mark 5 stars!!!!!
Answer:
1.968504 ft/s
A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How much energy was lost to air friction during this jump
Answer:
769,048.28Joules
Explanation:
A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How much energy was lost to air friction during this bump
The energy lost due to friction is expressed using the formula;
Energy lost = Potential Energy + Kinetic Energy
Energy lost = mgh + 1/2mv²
m is the mass
g is the acceleration due to gravity
h is the height
v is the speed
Substitute the given values into the formula;
Energy lost = 56(9.8)(1400) + 1/2(56)(5.10)²
Energy lost = 768,320 + 728.28
Energy lost = 769,048.28Joules
Hence the amount of energy that was lost to air friction during this jump is 769,048.28Joules
. What is the velocity of a free-
falling object after 5 seconds?
(Use 10 m/s2 for gravity.)
Answer:
vf = 50 m/s
Explanation:
The equation for this kinematic problem is:
vf = vi + at
We are given:
a = 10m/s^2
vi = 0m/s
t = 5 sec
vf = ?
Solve for final velocity:
vf = 0 + 10(5)
vf = 50 m/s
Describe how different types of motion are represented by distance-time graphs and velocity-time graphs.
Answer:
non-accelerated movement
velocity versus time a horizontal straight line.
distance versus time gives a horizontal straight line.
accelerated motion
graph of velocity versus time s an inclined line and the slope
graph of distance versus time is a parabola of the form
Explanation:
In kinematics there are two types of steely and non-accelerated movements
In a the velocity of the body is constant therefore a speed hook against time gives a horizontal straight line.
A graph of distance versus time is a straight line whose slope is the velocity of the body
x = v t
In an accelerated motion the velocity changes linearly with time, so a graph of velocity versus time is an inclined line and the slope is the value of the acceleration of the body
v = v₀ + a t
A graph of distance versus time is a parabola of the form
x =v₀ t + ½ a t²
In her lab, Mrs. Smith is pulling a 28 N block across a surface with a constant speed. If
she must pull with a force of 4.0 N, what is the coefficient of sliding friction between the
block and the lab table?
Answer:
0.14 is the friction coefficient.
Explanation:
The equation for the friction coefficient is friction coefficient = force/normal force. The force is 4N, and the normal force is 28N. 4/28=0.14.
What is the kinetic energy of a jogger with a mass of 70.8 kg traveling at a speed of 2.4 m/s?
90 points if you get it right :)
if wavelength and speed of a wave are 4 m and 332 m/s respectively, calculate its frequency
Explanation:
Given
wavelength = 4 m
speed = 332 m/s
frequency = ?
We know we have the formula
wavelength = speed / frequency
4 = 332 / frequency
frequency = 332/4
Therefore frequency is 83 Hertz .
Two balloons are charged with an identical quantity and type of charge: -0.0025 C. They are held apart at a separation distance of 8 m. Determine the magnitude of the electrical force of repulsion between them.
Answer:
F = 878.9 N
Explanation:
The electrostatic force of attraction or repulsion is given by Coulomb's Law as follows:
F = kq₁q₂/r²
where,
F = Force pf repulsion between balloons = ?
k = Coulomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = q₂ = magnitudes of 1st and 2nd charge = 0.0025 C
r = distance between balloons = 8 m
Therefore,
F = (9 x 10⁹ N.m²/C²)(0.0025 C)(0.0025 C)/(8 m)²
F = 878.9 N
The magnitude of the electrical force of repulsion between them is F = 878.9 N
Calculation of the magnitude of the electrical force:
Here we use Coulomb's Law
F = kq₁q₂/r²
Here,
F = Force of repulsion
k = Coulomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = q₂ = magnitudes of 1st and 2nd charge = 0.0025 C
r = distance between balloons = 8 m
So,
F = (9 x 10⁹ N.m²/C²)(0.0025 C)(0.0025 C)/(8 m)²
F = 878.9 N
Hence, The magnitude of the electrical force of repulsion between them is F = 878.9 N
Learn more about force here: https://brainly.com/question/24758639
Consider a 12.5 kg baby tiger in a tree has 490 J of gravitational potential energy. Determine the height of the tiger above the ground?
Answer:
[tex]\boxed {\boxed {\sf 4 \ meters}}[/tex]
Explanation:
Gravitational potential energy can be found using the following formula:
[tex]E_P=m*g*h[/tex]
where m is the mass, g is the gravitational acceleration, and h is the height.
The mass of the tiger is 12.5 kilograms. The gravitational acceleration on Earth is 9.8 m/s².
The potential energy is 490 Joules. Convert the units to simplify cancelling units later. 1 Joule is equal to 1 kilogram * meter² /second²Our answer of 490 J = 490 kg*m²/s²[tex]m= 12.5 \ kg \\g= 9.8 \ m/s^2\\E_p= 490 \ kg*m^2/s^2[/tex]
Substitute the values into the formula.
[tex]490 \ kg*m^2/s^2 = 12.5 \ kg * 9.8 \ m/s^2 *h[/tex]
Multiply 12.5 kg and 9.8 m/s²
12.5 kg* 9.8 m/s² = 122.5 kg*m/s²[tex]490 \ kg*m^2/s^2 = 122.5 \ kg *m/s^2 *h[/tex]
Since we are trying to solve for h, we must isolate it. Since h is being multiplied by 122.5, we must divide both sides by that number because the inverse of division is the inverse of multiplication.
[tex]\frac{490 \ kg*m^2/s^2} { 122.5 \ kg *m/s^2}= \frac{ 122.5 \ kg *m/s^2 *h }{ 122.5 \ kg *m/s^2}[/tex]
Note that when dividing, the kg*m/s² will cancel each other out, but a m (meter) will be left.
[tex]\frac{490 \ m }{122.5} =h[/tex]
[tex]4 \ m =h[/tex]
The tiger was 4 meters above the ground.
Ethics are deliberately learned from the family. Please select the best answer from the choices provided
Answer:
what are the choices provided?
Explanation:
Answer:
True
Explanation:
On Edg
what does a plant need to take in from environment to live?
nitrogen gas
argon
carbon dioxide
oxygen
Answer:
Carbon Dioxide.
Explanation:
Which way can heat never flow?
Answer:
Cold to hot.
Explanation:
Heat can never flow from cold to hot, heat transfers itself from hot to cold.
9. A student notices that wearing darker colors in sunlight makes him feel warmer, so he decides to conduct an experiment. He takes five pieces of different
colored cloth and wraps
each one around a water bottle. He then places all five bottles in direct sunlight and measures the temperature of the water in each bottle an hour later
What is the dependent variable in this experiment?
O the time he leaves it in the sunlight
O the amount of water in each bottle
O the color of the cloth
O the temperature of the water
Answer: 4
Explanation:
The dependent variable is the temperature of the water.
If clouds were made of cotton-candy what is rain
Answer:
If clouds were made of cotton candy, I think rain would be soda.
Or liquified sugar.
:)
Answer:
Liquid Sugar
Explanation:
For an example, let's look at normal clouds. They're made of water vapor, and when they rain it's because the water vapor condenses and forms a droplet heavy enough that it falls out of the sky. In both sides of the equation, they're still made out of water. So, logically, cotton candy is made almost 100% with sugar, right? All that's happened is the sugar is heated and liquified and pushed through very small holes until they cluster together and form the fluffy treat you know today. Back to the leading question, though: "If clouds were made of cotton-candy, what is rain?". Rain is the liquid form of clouds (gas), and cotton candy is the (solid) form of itself. So in order for it to rain, it needs to liquefy itself. When melted at 367°F, sugar becomes a liquid, so in that case THAT is what cotton candy would rain if it were a cloud.
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mass does not vary from place to place why?
Answer:
It is always constant unlike weight
A light, flexible rope is wrapped several times around a hollow cylinder with a weight of 40 N and a radius of 0.25m that rotates without friction about a fixed horizontal axis. The cylinder is attached to the axle by spokes of a negligible moment of inertia. The cylinder is initially at rest. The free end of the rope is pulled with a constant force P for a distance of 5 m, at which point the end of the rope is moving 6 m/s. If the rope does not slip on the cylinder, what is the value of P
Answer:
The value is [tex]P = 14.7 \ N[/tex]
Explanation:
From the question we are told that
The weight of the hollow cylinder is [tex]W = 40 \ N[/tex]
The radius of the hollow cylinder is [tex]r = 0.25 \ m[/tex]
The distance which it is pulled is [tex]d = 5 \ m[/tex]
The velocity of the end of the rope is [tex]v = 6 \ m/s[/tex]
Gnerally the mass of the hollow cylinder is
[tex]m = \frac{W}{g }[/tex]
=> [tex]m = \frac{ 40 }{ 9.8 }[/tex]
=> [tex]m = 4.081 \ kg[/tex]
Generally angular displacement for the distance covered is mathematically represented as
[tex]\theta = 2 \pi * \frac{ d } {2\pi r }[/tex]
=> [tex]\theta = 2 \pi * \frac{ 5 } {2\pi r }[/tex]
=> [tex]\theta = \frac{ 5 } { 0.25}[/tex]
=> [tex]\theta =20[/tex]
Generally the torque experienced by the hollow cylinder is mathematically represented as
[tex]P * r = I * \alpha[/tex]
Here I is the moment of inertia
=> [tex]P * r = m r^2 * \alpha[/tex]
=> [tex]\alpha = \frac{P }{ mr }[/tex]
Generally from kinematic equation
[tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
=> [tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
Generally the final angular velocity is mathematically
[tex]w_f = \frac{v}{r}[/tex]
=> [tex]w_f = \frac{ 6 }{ 0.25 }[/tex]
=> [tex]w_f = 24 \ m/s[/tex]
Generally the initial angular velocity is Zero given that the hollow cylinder was at rest before rolling
[tex]24^2 = 0^2 + 2* \frac{P}{4.081 *0.25 } * 20[/tex]
=> [tex]24^2 = 0^2 + 2* \frac{P}{mr} * 20[/tex]
=> [tex]P = 14.7 \ N[/tex]
A 75 kg ball carrier is running to the right at 6.5 m/s. An 80 kg defender is chasing the ball carrier running at 7.0 m/s. The defender catches the ball carrier in a completely inelastic collision. What was the kinetic energy of the ball carrier/defender system BEFORE the tackle?
Answer:
3,544.375Joules
Explanation:
Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;
Kinetic energy = 1/2mv²
m is the mass of the body
v is the velocity
For the ball carrier;
KE = 1/2(75)(6.5)²
KE = 3168.75/2
KE = 1584.375Joules
For the defender;
KE = 1/2(80)(7)²
KE = 3920/2
KE = 1960Joules
The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender
kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules
A psychologist wants to identify how the holiday season impacts the anxiety levels of Americans. She wants to get results on the feelings of anxiety from over one million Americans in the next month. What design should she use and why?
Answer: survey
Explanation:
A survey can be an interview or a questionnaire which is given to a particular group in order to know their characteristics or opinions, towards certain issues.
Since the psychologist wants to get results on the feelings of anxiety from over one million Americans in the next month, the survey should be used.
2. Molly thinks, should I wear the red dress or the black dress. This is an example of ___________________.
A. self-concept
B. self-talk
C. self-disclosure
D. self-perception
Answer:
self concept
Explanation:
i think its self concept because she thinks
Explanation:
It is A. self concept. Because if I choose self talk I am talking to my self for example I made a mistake, I did something wrong etc.
PLEASEEE HELPPP!!!!
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor
a distance of 8.1 m. The force of friction between the refrigerator and the floor is
230 N. How much work has been performed by the mover on the refrigerator?
Answer: The work is 1863 N*m
Explanation:
We can define work as:
W = F*d
Where F is the force that the mover needs to apply to the refrigerator, and d is the distance that the refrigerator is moved.
To move the refrigerator, the minimal force that the mover needs to do is exactly the friction force (In this case, the refrigerator will move with constant speed).
Then we will have:
F = 230 N
and the distance is 8.1 meters, then the work will be:
W = 230N*8.1 m = 1863 N*m