Answer:
I'm not sure, I think it's near the northern hemisphere.
23. How does the microwave appliance work?
Answer: The microwaves are reflected within the metal interior of the oven where they are absorbed by food. Microwaves cause water molecules in food to vibrate, producing heat that cooks the food.
Explanation:
If each contour line represents 50 meters, what is a reasonable height of the mountain peak in the topographic map? Record your answer and fill in the bubbles on your answer document. Be sure to use the correct
Answer:
Explanation:
Answer: None of the above I got it right on my test
Can someone help me with this, please? I have the answer but I need help with why the answer is that :(
A block of mass m is placed against the inner wall of a hollow cylinder of radius R that rotates about a vertical axis with a constant angular velocity, ω, as shown above. In order for friction to prevent the mass from sliding down the wall, the coefficient of static friction, μ, between the mass and the wall must satisfy which of the following inequalities? (Ans: μ is greater than or equal to g/(w^2r)
Answer:
See explanation below
Explanation:
Recall that the force of static friction is the product of the coefficient of static friction between surface and object, times the force applied perpendicular to the surface.
In our case, that perpendicular force has magnitude equal to the centripetal acceleration times the mass m of the block. The centripetal acceleration is defined as the quotient between the square of the tangential velocity divided by the radius at which the rotating mass is located (in our case R).
In order to estimate the tangential velocity given the angular velocity ω, we simply multiply it by R:
[tex]v_t=\omega\,R[/tex]
and therefore the force acting on the surface of the cylinder is:
[tex]F=m\,*\,a_c=m\,*\,\frac{v_t^2}{R} =m\,*\, \frac{\omega^2\,R^2}{R} =m\,*\,\omega^2\,*R[/tex]
The force of friction between the block and the inner wall of the hollow cylinder will then be: [tex]f=\mu\, *\,m\,*\omega^2\,*\,R[/tex]
In order for this force of static friction to be able to prevent the mass to slide down due to gravity, we need that the friction force is at least equal to the gravitational force. That is:
[tex]f\geq F_g\\f\geq m\,*\,g\\\mu\,*\,m\,*\,\omega^2\,*\,R\geq m\,*\,g\\\mu\geq \frac{g}{\omega^2\,*\,R}[/tex]
The force of static friction to prevent the mass to slide down due to gravity, the friction force is must be equal or greater than to the gravitational force.
The force of static friction is the product of the coefficient of static friction between surface,and force applied perpendicular to the surface.
The tangential velocity,
[tex]\bold {V_t = \omega R}[/tex]
So, the force acting on the surface of the cylinder,
[tex]\bold {F= m\times a_c}\\\\\bold {F= m \times \dfrac {V_t^2 }{R}}\\\\\bold {F = m \times \dfrac {\omega ^2R2}{R}}}\\\\\bold {F = m \times \omega ^2 \times R}[/tex]
The force of friction between the block and the inner wall of the hollow cylinder,
[tex]\bold {F_f = \mu \times m \times \omega ^2 \times R}[/tex]
Therefore, the force of static friction to prevent the mass to slide down due to gravity, the friction force is must be equal or grater than to the gravitational force.
To know more about static friction,
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PLEASE HELP
IS THIS CORRECT?
Answer:
yes!
Explanation:
Answer:
yes!!
Explanation:
Which acids are found in acid precipitation?
understand friend
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Inside most ball-point pens is a small spring that compresses as the pen is pressed against the paper. If a force of 0.1 N compresses the pen's spring a distance of 0.005 m, what is the spring constant of the tiny spring?
Answer:
20 N/m
Explanation:
From the question,
The ball-point pen obays hook's law.
From hook's law,
F = ke............................ Equation 1
Where F = Force, k = spring constant, e = compression.
Make k the subject of the equation
k = F/e........................ Equation 2
Given: F = 0.1 N, e = 0.005 m.
Substitute these values into equation 2
k = 0.1/0.005
k = 20 N/m.
Hence the spring constant of the tiny spring is 20 N/m
What are the two parts of the SCM
A. Sternal head, Lateral Head
B. Bilateral Head, Long Head
C. Sternal Head, Clavicular Head
helpp me please
Answer:
C. Sternal Head, Clavicular Head
Observa a tu alrededor y escribe el nombre de diez objetos que se encuentren en movimiento, Luego escribe el de otros diez que pienses que se encuentran en reposo. ¿Qué criterio tuviste en cuenta para considerar que están en reposo?
Answer:
Objetos que se encuentran en movimiento:
1) Un automóvil pasando por la calle.
2) Una crustácea que se acerca a mi casa.
3) Un avión volando en el cielo.
4) Un repartidor de comida desplazándose en una bicicleta.
5) Las aspas del ventilador en rotación.
6) Una hojarasca afuera de la casa.
7) La puerta de mi habitación abrirse.
8) Un mosquito entrando por la ventana.
9) Un metrónomo en movimiento.
10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.
Objetos que se encuentran en reposo:
1) El semáforo de la esquina.
2) El automóvil de mi madre.
3) Las sillas del comedor.
4) Un jarrón de porcelana.
5) La nevera de la cocina.
6) La mesa de noche de mi habitación.
7) El automóvil de policía en la calle.
8) La impresora de memes.
9) El estante de libros.
10) El cesto de galletas.
Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:
(i) Traslación.
(ii) Rotación.
(iii) Deformación.
Explanation:
Objetos que se encuentran en movimiento:
1) Un automóvil pasando por la calle.
2) Una crustácea que se acerca a mi casa.
3) Un avión volando en el cielo.
4) Un repartidor de comida desplazándose en una bicicleta.
5) Las aspas del ventilador en rotación.
6) Una hojarasca afuera de la casa.
7) La puerta de mi habitación abrirse.
8) Un mosquito entrando por la ventana.
9) Un metrónomo en movimiento.
10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.
Objetos que se encuentran en reposo:
1) El semáforo de la esquina.
2) El automóvil de mi madre.
3) Las sillas del comedor.
4) Un jarrón de porcelana.
5) La nevera de la cocina.
6) La mesa de noche de mi habitación.
7) El automóvil de policía en la calle.
8) La impresora de memes.
9) El estante de libros.
10) El cesto de galletas.
Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:
(i) Traslación.
(ii) Rotación.
(iii) Deformación.
How does the euglena differ from the paramecium? Question 20 options: Euglena are photosynthetic. Paramecia use flagella to move. Paramecia have an "eye spot" to detect light. Euglena have both a macronucleus and a micronucleus
Answer: Euglena are photosynthetic
Explanation: USA test prep
Which state helps produce light in fluorescent lightbulbs?
A.
Solid
B.
Plasma
C.
Gas
D.
Liquid
Hydrogeneous Sediment include_____.
A) granite
B) evaporative salts
C) igneous rocks
D) metamorphic rocks
What is the density of the material in g/cm³
Thus 1 cm–3 = 1/cm3 and the units for our densities could be written as gcm3, g/cm3, or g cm–3. In each case the units are read as grams per cubic centimeter, the per indicating division.) We often abbreviate "cm3" as "cc", and 1 cm3 = 1 mL exactly by definition.
...
1.9: Density.
If an object can make 10 revolutions in two minutes, what’s it’s period?
Answer:
the answer is 12 second easy
How would the moon appear to people on earth on this day
It would be half dark
It would be. Quarter dark
It would be complete light
It would be completely dark
Answer:
It would be. Quarter dark
Explanation:
Sun's lights going all the way to the moon but there will still a dark part of it
it's obviously won't be neither complete light nor completely dark
so the right answer is: Quarter dark
a rock stays in the same position without moving, which law is it ?
Answer:This is also known as the law of inertia. EXPLANATION: Inertia is the tendency of an object to remain at rest or remain in motion.
What’s the quotient in 80.64 ÷ 3.6
Answer:
30 30 30 yuhhhhhhhhhhhh
. Draw a Cartesian coordinate system on a sheet of paper. On this Cartesian coordinate system, draw each vector to scale, starting at the origin. (a) Dd > 5 8.0 cm [S 15° E] (b) Dd > 5 5.7 cm [N 35° W] (c) Dd > 5 4.2 cm [N 18° E]
Answer:
a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis
b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction
c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis
Explanation:
For this exercise we draw a Cartesian coordinate system in this system: East coincides with the positive part of the x-axis and North with the positive part of the y-axis.
a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis
b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction
c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis
In the attachment we can see the representation of the three vectors
write Newton's third low of motion and verify it with an experiment
Answer:
to something in action there is always a equal and opposite reaction. Like if you bounce a bounce ball on the ground, it will bounce back.
Explanation:
help me with physics
Answer:
z3
Explanation:
2. The frequency of the vibrating body decreases by increasing the periodic time.
Answer:
True
Explanation:
When the periodic time increases the frequency is lower.
If an object has a mass of 25 grams and a volume of 5 mL, then what is the density of the object?
Answer:
5
Explanation:
density = mass/volume
density = 25g /5 mL
density = 5
can someone help me please?
Answer:
is this math of science
Explanation:
The weight of an object is the effect of the gravitational pull on the object. Weight is calculated by multiplying mass of the object by the force of gravitational pull acting on it. A man weigh 120 N on earth. What will be his weight on the Moon, which has a gravity 1/6 of the gravity of Earth?
Answer:
20N
Explanation:
mass=weight/gravitational pull
mass=120/10
mass=12Kg
weight=mass×gravitational pull
=12× (⅙of 10)
=12×1.666666666667
=20N
find the kinetic energy of a 985 g bunny rabbit when running at 3.82 m/s. show work plz
Answer:
9.2m/s sir Thank me later
Answer:
Given
mass (m) =985 ☓ 0.001 , 0.985 kg
velocity (v) =3.82m/s
kinetic energy(k. e) =?
Form equation
[tex]k.e = \frac{1}{2} mv {}^{2} \\ = \frac{1}{2} \times 0.985 \times 3.82 {}^{2} \\ = 7.1868kj \\ kinetic \: enegy = 7.1868kj[/tex]
I hope this help
A 18 g ball is swung at a 1m long string.It revolves every 1 s,what is the magnitude of swing's tension?
Answer:
The magnitude of swing's tension is 0.71 N.
Explanation:
Given;
mass of the ball, m = 18 g = 0.018 kg
angular speed of the ball, ω = 1 rev/s
radius of the motion, r = 1 m
Angular speed in rad/s is calculated as follows;
[tex]\omega = \frac{2\pi \ rad}{rev} \times \frac{1 \ rev}{s} \\\\\omega = 2 \pi \ rad/s[/tex]
Linear speed of the ball, v;
v = ωr
v = 2π x 1
v = 2π m/s
The magnitude of swing's tension is calculated as the centripetal force keeping the ball in circular motion.
[tex]F_c =T = \frac{mv^2}{r} \\\\T= \frac{0.018 \ \times (2\pi )^2}{1} \\\\T = 0.71 \ N[/tex]
Therefore, the magnitude of swing's tension is 0.71 N.
A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s east. Find the velocity of the tennis racket after the collision.
A day-care center has a merry-go-round that consists of a uniform 240-kg circular wooden platform 4.00m in diameter. Four children run alongside the merry-go-round and push tangentially along the platform’s circumference until, starting from rest, the merry-go-round is spinning at a rate of 2.14 rev/minute. During the spin-up:
a) If each child exerts a sustained force of 26N, how far does each child run?
b) What is the angular acceleration of the merry-go-round?
SHOW ALL WORK AND STEPS PLEASE.
Answer:
a) The distance each child ran is approximately 0.232 m
b) The angular acceleration is 0.21[tex]\overline 6[/tex] rad/s²
Explanation:
The given parameters of the merry-go-round are;
The mass of the merry-go-round, m = 240-kg
The diameter of the merry-go-round, d = 4.00 m
The number of children pushing tangentially on the merry-go round = Four children
The spinning rate of the merry-go-round, n = 2.14 rev/minute
a) Given that the force exerted by each child = 26 N, we have;
The total force applied by the four children, F = 26 N × 4 = 104 N
The tangential acceleration, [tex]a_t[/tex] = F/m = 104 N/240-kg = 0.4[tex]\overline 3[/tex] m/s²
The angular acceleration, α = [tex]a_t[/tex]/r
Where, the radius of the merry-go-round, r = d/2
∴ r = 4.00 m/2 = 2.00 m
α = 0.4[tex]\overline 3[/tex] m/s²/(2.00 m) = 0.21[tex]\overline 6[/tex] rad/s²
We have;
ω² = ω₀² + 2·α·Δθ
The merry-go-round starts from rest, therefore; ω₀ = 0 rad/s
ω² = 2·α·Δθ
Δθ = ω²/(2·α)
n = 2.14 rev/minute
∴ ω = 2·π×2.14/60 rad/s ≈ 0.22410 rad/s
∴ Δθ = (0.22410 rad/s)²/(2 × 0.21[tex]\overline 6[/tex] rad/s²) ≈ 0.11589 rad
Therefore, the angle each child ran, θ = 0.11589 rad
The distance each child ran = r·θ
∴ The distance each child ran = 2.00 m × 0.11589 rad ≈ 0.232 m
b) From part 'a' above, the tangential acceleration, [tex]a_t[/tex] = 0.4[tex]\overline 3[/tex] m/s²
Angular acceleration, α = [tex]a_t[/tex]/r
∴ α = 0.4[tex]\overline 3[/tex] m/s²/(2.00 m) = 0.21[tex]\overline 6[/tex] rad/s²
The angular acceleration = 0.21[tex]\overline 6[/tex] rad/s²
Which has a higher frequency, a wave that makes 7 cycles per second or one that makes 12 cycles per second?
Answer:
A sound wave that has a higher frequency is a wave that makes 12 cycles per second.
Explanation:
The frequency of a wave is the same as the frequency of the vibrations that caused the wave. This takes more energy, so a higher-frequency wave has more energy than a lower-frequency wave with the same amplitude.
HELPPP TIMED The etiology of somatoform disorders may consist of all of the following except __________ factors.
A.
personality
B.
biological
C.
cognitive
D.
environmental
Answer:
b. biologucal
Explanation:
it is b. biologucal
The etiology of somatoform disorders may consist of all the following except biological. Option B is correct.
What are the somatoform disorders?Somatoform disorder,is a mental health illness in which a person experiences physical symptoms as a result of psychological discomfort.
Family with a negative or anxious personality are more likely to acquire somatoform illnesses.
The etiology of somatoform disorders may consist of all the following except biological.
Hence,option B is correct.
To learn more about the somatoform disorders refer:
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Heating and cooling can cause matter to change state. Which of the following occurs when heat is added to a system?
A gas becomes a liquid.
A liquid becomes a solid.
A gas becomes a solid.
A liquid becomes a gas.
Answer:
A liquid becomes a gas.
Explanation:
I hope this helps a bit.