Answer:
(B)
Explanation:
Because what ever angle the surface is, the light will reflect of of it perpendicular.
Two straight, parallel wires a and b carry currents in opposite directions, and are separated by a distance d. The magnitude of the force exerted by each wire on a segment of length L of the other wire is F. The vector sum of these forces is
Answer:
Zero
Explanation:
The magnetic field due to the first wire on the second wire with current i₁ in the first wire at a distance d from the second wire is B₁ = μ₀i₁/2πd.
The magnetic force due to this field on the second wire of length segment, L and current i₂ is F₁ = Bi₂L = (μ₀i₁/2πd)i₂L = μ₀i₁i₂L/2πd = F
The magnetic field due to the second wire on the first wire with current i₂ in the first wire at a distance d from the second wire is B₂ = μ₀i₂/2πd.
The magnetic force due to this field on the first wire of length segment, L and current i₁ is F₂ = Bi₁L = (μ₀i₂/2πd)i₁L = μ₀i₁i₂L/2πd = F
Since their magnetic fields are in opposite directions, according to the right hand rule, their forces would also be in opposite directions.
So F₁ = F and F₂ = -F
So their vector sum F₁ + F₂ = F +(-F) = F - F = 0
Newton’s third law of motion says that for every action there is a(n) and opposite reaction.
Answer:
for every action thete is an equal and opposite reaction
Answer:
Newton’s third law of motion says that for every action there is a(n)
equal and opposite reaction.
Explanation:
just got it right edg 1928
What is the overall charge of the wall?
Answer:
The overall charge on the wall is zero.
Explanation:
Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.
as a motorcycle takes a sharp turn the type of motion that occurs is called ——— motion
Answer:
circular motion
Explanation:
hope this helps you :)
Answer:
Centripetal motion
Explanation:
As a motorcycle takes a sharp turn the type of motion that occurs is called centripetal motion
Q- A body is acted upon by two forces 30N due east and 40N due North. Calculate
resultant and its direction.
Answer:
the following image will make you understand
Explanation:
*SS2 E_CAT 2020*
*DATE:* FRIDAY, 3RD JULY 2020
*Time allowed:* 40 minutes
*Instruction*: Attempt all questions. Send screenshots of solutions to my number *privately*.
*Take:* specific heat capacity of water = 4200 J/kgK
1. The lower and upper fixed points of a mercury-in-glass thermometer are marked X and 180mm respectively. On a particular day, the mercury meniscus in the thermometer rises to 60mm. If the corresponding reading on a Celsius scale is 20°C, what is the value of X?
2. A resistance thermometer has a resistance of 20 ohm at 0°C and 85 ohm at 100°C. If its resistance is 52 ohm in a medium, calculate the corresponding temperature.
3. A tap supplies water at 26°C while another supplies water at 82°C. If a man wishes to bath with water at 40°C, what is the ratio of the mass of hot water to that of cold water.
4. A metal of mass 1.55kg was heated from 300K to 320K in 6 minutes by a boiling ring of 85 W rating, calculate the specific heat capacity of the metal. {Neglect heat losses to the surrounding.}
5. (i) What is meant by the statement, _the specific heat capacity of copper is 400 J/KgK? (ii) Distinguish between specific heat capacity and thermal capacity deriving the mathematical relationship between.
thank you
Explanation:
2. Heat gained by tap1 = mass1 × SHC × change in temperature
= mass1 × 4200 × (40 - 26)
= mass1 × 58800
Heat lost by tap 2 = mass2 × SHC × change in temperature
= mass2 × 4200 × (82 - 40)
= mass2 × 176400
Heat gained = heat lost
mass1 × 58800 = mass2 × 176400
Ratio of mass 1 to mass 2 = 58800mass1 : 176400mass2
= 1 : 3
A car of mass 800 kg is moving at a uniform velocity of 72 km/hr. Find its
momentum.
[Ans: 16000 kgm/s)
A body of mass 5 kg has momentum of 125 kg m/s. Find the velocity of the body
in motion.
[Ans: 25 mls)
Answer:
hope its helpful to uh...
I NEED HELP PLEASE, THANKS! :)
Generate an explanation for the following formula: P = I²R . Explain.
Answer:
P = VI = (IR)I = I2R
Explanation:
What the equation means is that if you double the current you end up with 4 times the power loss. It's like the area of carpet you need for a room - if you make the room twice as long and twice as wide you need 4x as much carpet. The physical explanation is that the voltage difference along a wire depends on the current - more current flowing with a resistance means more voltage (pressure of electricity if you like) is built up.
This extra voltage means more power. So if you double the current your would double the power, but you also double the voltage which doubles the power again = 4x as much power. P = VI = (IR)I = I2R
I hope this helps you out, if I'm wrong, just tell me.
As I mentioned earlier, Ohm's law gives us the formula P = IV, where V is the voltage ( also known as the electrical potential difference ) and I is the current. It is confusing that P = I²R and P = IV are one in the same - so I want to go a bit deeper on that.
We have three formulas, P = IV, P = I²R, and P = V² / R. Each are considered the same. The two formulas P = I²R, and P = V² / R are derived from the statement that P = IV, under the condition V = IR. Substitute the value of V from this second condition V = IR into P = IV. You would get the following -
P = I( IR ),
P = I²R
That is how one can derive the formula P = I²R, and how P = IV and P = I²R are thought to be one in the same. If you would like, take a look at how to get the formula " P = V² / R, "
V = IR, P = IV
I = V / R, P = IV
P = ( V / R )V,
P = V² / R
Hope that helps!
Three 15.0-W resistors are connected in parallel across a 30.0-V battery. Please show all work.
a) Find the current through each branch of the circuit.
b) Find the equivalent resistance of the circuit.
c) Find the current through the battery.
Answer:
Part A)
Since all of the resistors have equal resistance, hence for finding even only 1 branch It will be fine because current will be the same for all branches.
=> [tex]I = \frac{V}{R_{1} }[/tex]
=> [tex]I = \frac{30}{15}[/tex]
=> I = 2 A
Part B)
Equivalent resistance for parallel circuits is the sum of reciprocals of each resistor.
=> [tex]\frac{1}{R} = \frac{1}{R_{1}}+\frac{1}{R_{2}} +\frac{1}{R_{3}}[/tex]
=> [tex]\frac{1}{R} = \frac{1}{15}+ \frac{1}{15}+\frac{1}{15}[/tex]
=> [tex]\frac{1}{R} = \frac{3}{15}[/tex]
=> R = 15/3
=> R = 5 ohms
Part C)
I = V/R
Where I is current, V is voltage and R is the equivalent resistance
=> I = 30/5
=> I = 6 A
A test car is driving toward a solid crash-test barrier with a speed of 46 mi/h. Two seconds prior to impact, the car begins to brake, but it is still moving when it hits the wall. After the collision with the wall, the car crumples somewhat and comes to a complete stop. In order to estimate the average force exerted by the wall on the car, what information would you need to collect?
Answer:
we have to measure distances and time, possibly with an automated system since the values are very small
Explanation:
For this exercise we can use the relationship between momentum and momentum
I = ∫ F dt = Δp
F t = m [tex]v_{f}[/tex] - mv₀
In the exercise they indicate that the final speed is zero
F t = - m v₀
F = -m v₀ / t
With this equation we can find what measurements should be carried out.
To find the speed with which the car collides with the wall, less measure the displacement and its time during the braking process before reaching the wall and from here find the speed with which it reaches the wall.
During the impact, we must find the time that the vehicle is in contact with the wall in the first approach is equal to the time that the car takes to reach the final speed of zero.
In summary we have to measure distances and time, possibly with an automated system since the values are very small
A box is dragged across a floor by pulling on a rope attached to the crate and inclined 25 o above the horizontal. If the coefficient of static friction is 0.64, it requires a force of 350 N to just start it moving. What is the mass of the box
Answer:
[tex]m=35.58 kg[/tex]
Explanation:
Using the first Newton's equation
[tex]\Sum F_{T}=F-mgsin(25)-\mu mgcos(25)=0[/tex]
We just need to solve it for m:
[tex]m=\frac{F}{g(sin(25)+\mu cos(25))}[/tex]
[tex]m=\frac{350}{9.81(sin(25)+0.64cos(25))}[/tex]
[tex]m=35.58 kg[/tex]
I hope it helps you!
Before beginning an experiment, Mrs. Wilson warns her science class not to drop the bar magnets on the floor. What is the most likely reason for Mrs. Wilson’s warning?
Answer:
we should not drop a magnet on the floor because the magnets tend to lose magnetism gradually and become weak over a period of time if they are not stored properly.
Answer:
Well depending on the floor like say if it was a wooden floor the magnet might lose it magnetism, if concrete floor the magnetic brake and still lose it magnetism, if a metal floor the magnet would stick not sure if it wood lose it magnetism or not but the possibilities still there, basically what I'm saying is the magnet would lose its magnetism if it were to interact with the floor maybe temporary or maybe permanently.
for those with with a learning disability it's a
Explanation:
With an initial velocity of 9.8 m / sg, an object is thrown upwards from the roof of a 100 m high building. Determine maximum height from the ground, time it takes to reach the ground, and the speed with which it reaches the ground.
Answer:
104.9 m
5.63 s
45.3 m/s
Explanation:
Given:
y₀ = 100 m
v₀ = 9.8 m/s
a = -9.8 m/s²
Find: y when v = 0 m/s
v² = v₀² + 2a (y − y₀)
(0 m/s)² = (9.8 m/s)² + 2 (-9.8 m/s²) (y − 100 m)
y = 104.9 m
Find: t when y = 0 m
y = y₀ + v₀ t + ½ at²
0 m = 100 m + (9.8 m/s) t + ½ (-9.8 m/s²) t²
0 = 100 + 9.8t − 4.9t²
t = [ -9.8 ± √(9.8² − 4(-4.9)(100)) ] / 2(-4.9)
t = (-9.8 ± 45.3) / -9.8
t = 5.63 s
Find: v when y = 0 m
v² = v₀² + 2a (y − y₀)
v² = (9.8 m/s)² + 2 (-9.8 m/s²) (0 m − 100 m)
v = -45.3 m/s
|v| = 45.3 m/s
Swamp coolers are effective because _____.
A. the water is colder than the air.
B. the water pulls heat from the room to undergo a phase change.
C. the thermal energy of the water is decreasing.
D. the water's latent heat of vaporization is being pulled from the air.
Answer:
D. the water's latent heat of vaporization is being pulled from the air.
Explanation:
A swamp cooler also generally referred to as the evaporative cooler is an electronic device that uses moisture to cool air. This simply means that, the electronic device works on the principle of evaporation of water to cool the surrounding air.
In swamp coolers, water absorbs large amount of warm air via the evaporative wet cooler pad, so as to evaporate and consequently cooling the air effectively and efficiently.
Swamp coolers are effective because the water's latent heat of vaporization is being pulled from the air.
The latent heat of vaporization can be defined as the energy that is being absorbed by water during evaporation.
The swamp coolers are typically made up of the following essential components, these are;
1. Float.
2. Blower.
3. Pump.
4. Evaporative pad.
5. Water supply valve.
Hence, through the principle of evaporative cooling (latent heat of vaporization), swamp coolers reduces or lower the air temperature in its surroundings.
Answer:
B and D
Explanation:
a body starts from rest and gains the velocity of 5 metre per second into second is it of uniform velocity explain
Answer:
It is not a uniform velocity, because his velocity increases for 5 m every second (acceleration = 5m/s2), meaning his velocity always changes.
When he starts at rest, his velocity is 0 m/s. But in 1 second later, his velocity is already 5m/s. At 2 seconds, his velocity will be 10 m/s.
The speed of an electromagnetic wave is a constant, 3.0 × 108 m/s. The wavelength of a wave is 0.6 meters. What is the frequency?
Answer:
The answer to this should be: 5.0 x 10⁸ Hz
Explanation:
The speed, s, of a wave, equals the product of its frequency, ν, times its wavelength, λ:
s = νλ.
As the question states, the speed of an electromagnetic wave is a constant, c, equal to 3.0 × 10⁸ m/s.
Substituting this constant in the equation for the speed of the wave, you get:
c = νλ.
From that equation, you can solve for the frequency to show the inverse realation of frequency and wavelength:
ν = c / λ
Now, you just have to substitute values and compute, leaving you with:
5.0 x 10⁸ Hz
De acuerdo al calendario ecológico 2020, escriba cuanto CO2 produce el Ecuador y en un resumen máximo de 7 líneas, determine porque son importante los humedales en la biodiversidad.
Answer:
43,919.66 Kilotones de Co2 en 2016.
Explicación:
Ecuador produce 43,919.66 Kilotones de Co2 en 2016. Las tierras húmedas son muy importantes para la biodiversidad porque proporcionan hábitat a millones de animales. Alrededor del 35 por ciento de todas las especies amenazadas y en peligro vive en estas tierras húmedas. Estas tierras húmedas son altamente productivas y tienen la capacidad de mejorar la calidad del agua, prevenir la degradación del suelo y proporcionar alimentos a los animales que viven en estas tierras húmedas.
why is urbanization a contribution to pollution?
Answer:
people in urban areas strip the soil of nutrition and makes it difficult to grow crops. people of urban areas consume more energy,food,and water. people in urban areas remove minerals and metals from the ground so, urbanization is a contribution to pollution .
Explanation:
it may help you and give me brainliest
Answer:
pollution and loss of trees not to mention how much electricity we use which doesnt benefit the world.
Explanation: because when we urbanize things we get rid of natural resources around us
Find the electric field a distance z above a circular ring carrying a constant line charge. For extra credit you may derive the electric field a distance z above a disk carrying a constant surface charge density. 3 Find the force between an electron and a proton in a typical hvdrogen atom.
Answer:
F = 8.23 × 10⁻⁸N
Explanation:
F= kq²/r²
k= 9×10⁹Nm²/C²
q= 1.6×10⁻¹⁹C
r= 5.29×10⁻¹¹m
F= 9×10⁹× (1.6×10⁻¹⁹)²/ (5.29×10⁻¹¹)²
F = 8.23 × 10⁻⁸N
A vehicle traveling on wet or slick roads can begin to _________ as water forms a barrier between the road and the tires and traction is lost as the wheels start to ride on top of the water and not the road surface. a) skid b) hydroplane c) lose traction d) splash water on to the engine
Answer: B.) HYDROPLANE
Explanation: The term hydroplane can be used to refer to a condition which usually occur during a downpour or on surfaces covered by water. It occurs when water forms a barrier or comes in between the frictional grip which occurs between the road surface and the car tyres. The contact between the car tyres and the road surface is supposed to give adequate frictional support which prevents the car from skidding or skidding uncontrollably on the road surface. However, when water comes invetween the surface, traction is lost and skidding results due to very low Coefficient of friction between the road and Tyre which was supposed to provide a firm grip between the tyres and the road surface.
When a vehicle is traveling on wet or slick roads, hydroplaning can occur. The correct answer is b) hydroplane.
When a vehicle is traveling on wet or slick roads, hydroplaning can occur. Hydroplaning happens when a layer of water builds up between the tires of the vehicle and the road surface, leading to a loss of traction.
This loss of traction can cause the vehicle to skid or slide, making it difficult to control. The tires ride on top of the water rather than maintaining contact with the road, resulting in reduced traction and control of the vehicle.
Therefore, When a vehicle is traveling on wet or slick roads, hydroplaning can occur. The correct answer is b) hydroplane.
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Please!!! I need some help!!! I will give Brainliest To anyone who truly helps.
Determine the net force charge acting at q1 (+ 2.0 × 10-5C), caused by q2 (-4.0 × 10-5 C) and q3 (-4.0 × 10-5 C). Be sure to include a free body diagram representing the force acting at q1 in your solution. Determine the net electric field acting at q1.
Answer:
Please INCLUDE a picture.
Explanation:
You did not include a picture, so there is no way to tell how the charges will interact with each other.
Please INCLUDE a picture.
The net force acting on q1 is 3.2 N to the right.
The force on q₁ due to q₂ is:
F1 = k * q₁ * q₂ / r²
where:
k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C⁻²
q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C
q₂ is the charge of q₂, which is -4.0 × 10⁻⁵ C
r is the distance between q₁ and q₂, which is 0.1 m
Plugging in the values, we get:
F₁ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.1 m)²
= 6.4 N
The force on q₁ due to q₃ is:
F₂ = k * q₁ * q₃ / r²
where:
k is Coulomb's constant, which is 8.98755 × 10⁹ N m² C²
q₁ is the charge of q₁, which is +2.0 × 10⁻⁵ C
q₃ is the charge of q₃, which is -4.0 × 10⁻⁵ C
r is the distance between q₁ and q₃, which is 0.2 m
Plugging in the values, we get:
F₂ = 8.98755 × 10⁹ N m² C⁻² * 2.0 × 10⁻⁵ C * -4.0 × 10⁻⁵ C / (0.2 m)²
= 16 N
The net force on q₁ is the sum of F₁ and F₂:
Fnet = F₁ + F₂
= 6.4 N + 16 N
= 22 N
The net force on q1 is to the right because both F₁ and F₂ are to the right.
Net electric field
The net electric field acting on q1 is 3.2 N/C to the right.
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What is the magnitude of these two vectors: 101 m 60.0 degrees 85.0 m
Answer:
85.0 please I don't understand
At one point in the rescue operation, breakdown vehicle A is exerting a force of 4000 N and breakdown vehicle B is exerting a force of 2000 N.(i) Using a scale of 1 cm = 500 N, make a scale drawing to show the resultant force on the truck. (ii) Use your diagram to find the magnitude and direction of the resultant force on the truck.
Answer:
1.) Magnitude = 5596 N
2.) Direction = 60 degrees
Explanation: You are given that the breakdown vehicle A is exerting a force of 4000 N at angle 45 degree to the vertical and breakdown vehicle B is exerting a force of 2000 N
Let us resolve the two forces into X and Y component
Sum of the forces in the X - component will be 4000 × cos 45 = 2828.43 N
Sum of the forces in the Y - component will be 2000 + ( 4000 × sin 45 )
= 2000 + 2828.43
= 4828.43 N
The resultant force R will be
R = sqrt ( X^2 + Y^2 )
Substitutes the forces at X component and Y component into the formula
R = sqrt ( 2828.43^2 + 4828.43^2 )
R = sqrt ( 31313752.53 )
R = 5595.87 N
The direction will be
Tan Ø = Y/X
Substitute Y and X into the formula
Tan Ø = 4828.43 / 2828.43
Tan Ø = 1.707106
Ø = tan^-1( 1.707106 )
Ø = 59.64 degree
Therefore, approximately, the magnitude and direction of the resultant force on the truck are 5596 N and 60 degree respectively.