Answer:
Method of controlling the population of crabs.
Explanation:
The method of controlling the crabs by parasitic barnacle species I suggest should be learn before its introduction because this method provides valuable knowledge about the method the parasitic barnacle species control the crabs population. This barnacle species is a parasite that feeds on the crabs, it controls the population of crab by not killing the crabs but attack on the reproductive part of the crabs that leads to infertility and as a result the population of the crabs are decreases and controlled.
In a flower, the anther is attached to filament. What advantage does the filament provide to the anther?
A. The filament elevates the anther to allow for easier transport of pollen by wind or insects.
B. The filament provides the anther with nutrients to produce pollen grains.
C. The filament protects the anther from harsh sunlight and insects.
D. The filament produces a sticky surface to allow the anther to capture pollen.
The correct answer is A. The filament elevates the anther to allow for easier transport of pollen by wind or insects.
Explanation
The filament of a flower is the sterile part of the stamen (male organ of the flower) that is located just below the anther. Its function is structural to hold the sling so that it is accessible to insects. The filament is usually cylindrical and fine. Therefore, the correct answer is A. The filament elevates the anther to allow for easier transport of pollen by wind or insects.
Environmental scientists calculating pollutant half-lives often define a transport rate constant that is analogous to a reaction rate constant and describes how a pollutant moves out of an ecosystem. In a study of the gasoline additive MTBE in Donner Lake, California, scientists from the University of California, Davis, found that in the summer the half-life of MTBE in the lake was 26.01 days. Assume that the transport process is first order. What was the transport rate constant of MTBE out of Donner Lake during the study
Answer:
k ≈ [tex]2.7 *10^{-2} d^{-1}[/tex]
Explanation:
For a first order reaction
Half life ( [tex]t_{1/2}[/tex] ) = 0.693 / k
k = rate constant
[tex]t_{1/2}[/tex] = 26.01
hence k = 0.693 / ( 26.01)
k ≈ 2.7 * 10^-2 d^-1
This is a detailed simple solution as required
Drag the tiles to the correct boxes to complete the pairs.
Identify the types of inheritance based on the expression of alleles in the organism.
Answer:
Presence of many alleles for the trait to be expressed --> Multiple
Presence of two alleles for the trait to be expressed --> recessive
Presence of a single allele for the trait to be expressed --> dominant
Answer:
Presence of two alleles for the trait to be expressed: recessive
Presence of many alleles for the trait to be expressed: multiple
Presence of a single allele for the trait to be expressed: dominant
Explanation:
Edmentum
Which argument is BEST supported by the
information given?
A. The earthworm and lizard evolved at the same
time because of the absence of legs and hair.
B. The lizard and humans share a common
ancestor because of the presence of a
backbone and legs.
C. The trout and humans share a common
ancestor because of the presence of a
backbone.
D. Earthworms were the most recent to evolve
because of the absence of the derived
characteristics.
Answer:
B
Explanation:
It tells us a lot about why the argument is correct.
Evergreen broadleaf trees, along with abundant rain, warm temperatures, and consistent day length, characterize the _ biome.
Answer:
Rainforest biome (tropical rainforest)
Explanation:
The characteristics of the tropical rainforest biome are:
Located in humid and warm regions of equatorial climate.Medium temperature among 18 and 30 ºCAnnual precipitation is around 1000 and 8000 millimeters. Precipitation levels are never inferior to 1500 mm. There is no dry season, or if there is, it is too short. There is no hydric deficit. Fanerophic species dominate in this biome. Evergreen tall trees might reach up to 50 meters in height. They develop dense foliation and branches, becoming a refuge and source of food for many species. Vegetation does not need to develop strategies for surviving the dry season. Instead, they need to develop strategies for competing for light and nutrients. We can find different species of plants such as epiphytes, lianas, stranglers, aerial-rooted pants, tabular-rooted plants, among other vegetation forms. Tropical and subtropical rainforests might differentiate from each other in latitude and seasonality. Tropical rainforests might be found in latitudes of the Capricorn and Cancer tropics. From cero to ten degrees latitude. They are in America, Africa, and Asia continents. It is the biome with the greatest biodiversity on the planet. Rainforests have an extraordinary richness of animals and plants.
Why is the 3-dimensional shape of a macromolecule (ex: protein) important to know from the perspective of understanding
the molecular basis of human disease? 2 pts
A/ Mutations in genes that cause a change in amino acid primary sequence can cause a change in the protein's function in a
cell. For example, it can cause the protein to mislocalize; the protein is now recruited to a specific site in the cell, like the
nucleus, where it can cause cellular dysfunction.
B/ If the protein is an enzyme, the 3-dimensional shape of the active site can be altered and decrease the rate of a reaction that
is catalyzed by that enzyme.
C/ If the protein is an enzyme, the 3-dimensional shape of the active site can be altered and increase the rate of a reaction that
is catalyzed by that enzyme.
D/ Only options A and B may be true.
F/Antions A, B and C may be true.
Answer:
A, B and C may be true
Explanation:
The three-dimensional structure (3D) of a protein, also known as tertiary structure, is critical to its function. In general, the 3D protein structure consists of alpha-helix and beta-sheets (secondary structures) associated through disordered coiled-coil regions. Genetic mutations may cause modifications in the 3D protein structure by modifying amino acids that are added to the growing polypeptide chain during the process of translation. In consequence, the relationships among amino acids (i.e., the intermolecular attractive forces that hold them together) may also be altered by these mutations. In general, mutations that generate amino acid changes at the active site of the enzyme will have a deleterious effect, thereby decreasing or inactivating protein function. However, there are situations where a mutation may be beneficial and can eventually increase the rate of reaction of a protein.
In fruit flies, curved wings (w) are recessive to the dominant straight wings (W), and ebony body (b) is recessive to the dominant gray body (B). A fly that has curved wings and ebony body is crossed with a fly that has straight wings and gray body. Of the offspring there were approximately equal numbers of straight gray, straight ebony, curved gray, curved ebony. What are the genotypes of the parents and offspring
Answer:
The correct answer =
parents : WwBb x wwbb
offspring :
WwBb, Wwbb, wwBb, and wwbb
Explanation:
It is given that the straight wings (W) is dominant over curved wings (w) and the ebony body (b) is recessive to the dominant gray body (B) and there is a cross between curved wings and ebony body and straight wings and gray body is made. The phenotypic ratio is: 1:1:1:1 for the four different phenotypes straight gray, straight ebony, curved gray, curved ebony.
It is not given the genotype of parents, however, for the curved and ebony fly, it is clear that both alleles are recessive as recessive alleles only appear in absence of the dominant allele of the trait.
For another parent, the possible genotypes can be WWBB or WwBb, however in the case of WWBB the phenotypic ratio would not be equal therefore,
crossing WwBb x wwbb
This can be represented in the form of a punnett square as below:
wb wb wb wb
WB WwBb WwBb WwBb WwBb Straight wing, Gray body
Wb Wwbb Wwbb Wwbb Wwbb Straight wing, Ebony body
wB wwBb wwBb wwBb wwBb Curved wing, Gray body
wb wwbb wwbb wwbb wwbb Curved wing, Ebony Body
The phenotypic ratio is: 1:1:1:1 for the four different phenotypes
what is a false scorpion
Answer:
huh im not prcicley undertsa
Answer:
A pseudoscorpion, also known as a false scorpion or book scorpion, is an arachnid belonging to the order Pseudoscorpiones, also known as Pseudoscorpionida or Chelonethida. Despite their appearance to true scorpions and ticks, they are NOT harmful to people. Physical removal is the only necessary control.
Explanation:
The light-independent reactions of photosynthesis, also known as the Calvin cycle, must repeat three times in order for a cell to have enough material to construct half a glucose molecule. A variety of molecules are used and produced during this process. Identify the molecules into three categories: molecules brought in and used in three turns of the Calvin cycle, molecules produced during three turns of the Calvin cycle that leave the cycle, and molecules used and regenerated within the Calvin cycle during three turns.
Answer:
- molecules brought in and used in three turns of the Calvin cycle = carbon dioxide (CO2)
- molecules produced during three turns of the Calvin cycle that leave the cycle = Glyceraldehyde-3-phosphate (G3P)
- molecules used and regenerated within the Calvin cycle during three turns = Ribulose bi phosphate (RUBP)
Explanation:
The second stage of photosynthesis, called CALVIN CYCLE, occurs in the stroma of the chloroplast. The processes that occur in this stage can be divided into three stages namely: carbon fixation, reduction and regeneration.
As rightly stated in this question, the calvin cycle must repeat three times in order for a cell to have enough material to construct half a glucose molecule. Hence;
- In carbon fixation, molecules of carbon dioxide (CO2) are brought in and used in three turns of the Calvin cycle. The CO2 combines with a CO2 acceptor called RUBP (ribulosebiphosphate) to produce PGA (3-phosphoglycerate).
- In the reduction stage, PGA is reduced to Glyceraldehyde-3-phosphate (G3P). This G3P molecule is produced during three turns of the Calvin cycle and leaves the cycle to be used to form glucose.
- In the regeneration stage, remaining molecules of G3P are used to regenerate RUBP in order for the cycle to continue. Hence, RUBP molecules are used and regenerated within the Calvin cycle during three turns.
Where are diploid cells found ?
A. only in reproductive organs
B. only in twin siblings
C. through out the body
D. only in the lungs
Answer:
c
Explanation:
diploid cells are cell that have 2 genetic alleles, one from your mom and one from dad, so all your cells are diploid, except haploid cells in the rep system.
The combination of fibers and ground substance in fluid connective tissue is known as
A) ground substance
B) fat
C) cytosol
D) plasma
BIOLOGY CIRCULATORY SYSTEM!! WILL NAME BRAINLIEST IF YOU ANSWER CORRECTLY!!
Answer:
C, G, F, I, H, D, A, E, B
They are in order from top to bottom
A cleft chin in humans is coded by the dominant allele C. A chin without a cleft is coded by the recessive allele c. A man with a cc allele combination for the trait produces a zygote with a woman with a Cc allele combination for the trait. Which allele combinations could occur in the zygote?
Answer:
The allele combinations are: Cc, cc, Cc, cc
Phenotypically there is a 50% chance that the child will be born with or without the cleft
The allele combinations that could occur in the zygote is Cc or cc.
What is an allele combination?An identification of the specific alleles found at each of the relevant mouse loci on the two homologous chromosomes (i.e., all allele pairs of a genotype). One or more allele pairs can make up an allele combination.
Genetic linkage is the capacity of a chromosome to transmit alleles that are near to one another as a whole unit through meiosis. Inheritance of traits is also understood by this principle. It is useful in locating the genes that are in charge of characteristics and diseases.
The person is homozygous for the allele if the two alleles are the same. The person is heterozygous if the alleles are different.
Therefore, the zygote may include the allele combinations Cc or cc.
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Using this illustration as a guide, indicate the level one would need to drill to gain a sample containing the highest ratio of parent rock in comparison with organic material.
horizon C
horizon A
horizon B
horizon O
Answer:
horizon C
Explanation:
The horizon C has the highest ratio of parent rock as compared to organic matter. This horizon starts after horizon B and present above the bed rock. This horizon consists of weathered and partially decomposed rocks. It is the actual layer of soil of that place whereas the other horizon A and B comes with the passage of time when the wind bring the soil particles and these particles deposits on this layer of the soil making horizon A and B.
When two parents join to form a new individual-
Offspring will NOT be identical to one parent.
It will have traits from both parents
Both A and C
Offspring will be identical to one parent.
Help please!!
Answer:
"B"
Explanation:
It will have both traits from both parents.
Meet the Johnson family. Crystal and Andre are the parents. They have four children: Scarlet, Ben, Joel, and Clarissa.
Number your answers for each question in the essay box below.
Use this table to help you answer the questions:
Answer:
Answer:
1.
a)dd
b) dd
c) 0%
2.
a) 25%
b) 75%
c) 25%
3.
a) 03
b) 0
c) tt
4.
a) FF x ff OR FF x Ff OR FF x FF
b) Because all the children have freckles
5.
a) 4:0
b) 100%
6.
a) 50%
b) Bb
c) 3 out of 6 (including parents)
The skin cells of an organism are analyzed and cells identified in G1 and have an average of 12 picograms of DNA. In the same organism a cell from gonadal tissues is identified and that single cell contains 6 picograms of DNA. Given this information, which of the following is true about the single gonadal tissue cell with 6pg of DNA?
1. The cell is at the beginning of Prophase I.
2. The cell has already completed meiosis.
3. The cell is not dividing (is in interphase).
4. The cell contains unduplicated chromosomes.
Answer:
El Rasho Macuin
Explanation:
The statement which is true about the single gonadal tissue cell with 6 picograms of DNA is that the cell has already completed meiosis. So, the correct option is B.
What do you mean by DNA?It is a complex molecule that contains all the information necessary to build and maintain an organism. It stands for Deoxyribonucleic acid. It is considered the genetic material in most organisms.
The skin cells in the G1 phase have an average of 12 picograms of DNA. As the amount of DNA in the G1 phase is 2C, hence 2C = 12 pg of DNA.
Now in the same organism, a cell from gonadal tissue is identified and that single cell contains 6 pg of DNA, which means, the amount of DNA is 6 pg that is C. Therefore, after the completion of meiosis, the cell contains half the amount of DNA as compared to the parent cell in G1.
So, Amount of DNA = C = 6 pg.
Therefore, the statement which is true about the single gonadal tissue cell with 6 picograms of DNA is that the cell has already completed meiosis.
To learn more about the Cell cycle, refer to the link:
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Which change is an environmental effect of farming?
a.temperature increase
b.soil erosion
c.habitat succession
d.natural disasters
Answer:
it is probably b.
Explanation:
hope this helps :)
what is a cell membrane and its functions
Answer:
The cell membrane is a strip of membrane around the cell and it keeps bad things from entering the cell
Explanation:
Which has the highest density?
A. water at 0°C
B. water at 4°C
C. water at 6°C
D. water at 8°C
Corona means____ and most human corona viruses cause ____ symptoms in humans. A. Circle, mild B. Crown, major C. Crown, mild
Answer: the answer is c for both
Explanation:
hy help me do this fast plzz
bonus points
If a lock and key fit perfectly together and then one day the key melts and then it is now more droopy and no longer can fit into the lock, then that key wont work for the lock anymore. It's the same as if an enzyme breaks down a bit and now the shape doesn't fit perfectly, the enzyme doesn't work anymore
Consider a breeder that mates two heterozygous black Staffordshire bull terriers over the course of three years. The dam eventually produces 16 puppies: 11 are black like the parents, 4 turn out white, and 1 turns out gray colored. As a genetics student, what do you think of this outcome
Answer:
Different colour occur due to heterozygous nature.
Explanation:
Most of the puppies just like parents because the black colour gene or allele is dominant over other colour allele whereas other colour puppies also formed due to presence of heterozygous type of alleles. Other colour occurs due to appearance of recessive allele in the physique of the offspring or formation of hybrids occurs which causes colour other than black and white in the offspring. In the F1 generation all the offspring resembles to the male parent but after this generation some offspring resembles to male, some are hybrids and other resembles to female.
what do you call a soft ,heated mass of crushed leaves and other substances that spread over the skin to treat swelling or pain ?
a.bandage
b.ointment
c.poultice
d.solution
what is the cause of down syndrome
Answer:
there is multiple causes is this an acual question??????
Explanation:
22) During durg adminsteration not necesary tell
to the patient
A) Prupase of durg
B) Side effect of durg
C) Route of mrdication
it helps the plant to pollinate the flowers
Answer:
Bees or similar inscets.
Which of the following conclusions can be made from this experiment?
A Only Salmonella can send genes to CJ bacteria. how did detectives nab the suspect based on the pod evidence
B Only E. Coli can send genes to CJ bacteria.
C Neither Salmonella nor E. Coli can send genes to CJ bacteria.
D Both Salmonella and E. Coli can send genes to CJ bacteria.
Answer:
C. Neither Salmonella nor E. Coli can send genes to CJ bacteria. :))
Explanation:
The conclusions of the experiment are that Neither Salmonella nor E. Coli can send genes to CJ bacteria.
How can you tell the difference between E. coli and Salmonella in a lab?
The main contrast between E. coli and salmonella is that E. coli is a type of commensal bacteria that commonly lives in the lower intestine of warm-blooded animals whereas Salmonella is a facultative, intracellular pathogen in both warm-blooded and cold-blooded animals.
Thus, Neither Salmonella nor E. coli can send genes to CJ bacteria.
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What is a prokaryote
Answer:
Prokaryote is a microscopic single-celled organism which has neither a distinct nucleus with a membrane nor other specialized organelles, including the bacteria and cyanobacteria.and also blue green algae.
If a nation has 120 million employed people and 15
million unemployed people, what is the unemployment rate?