3. Water near the poles receives much less solar energy than the tropical regions and often has water temperatures around 0 degrees Celsius. Why is the water in the polar
regions not completely frozen?
A color
C salinity B density
D phytoplankton

Answers

Answer 1

Answer:

Yes

Explanation:

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Answer 2
I think c I’m not sure though :))

Related Questions

A 34kg crate resting on a horizontal surface is pushed as shown. If the coefficient of static friction s between the surfaces is 0.25, what is the minimum force (Fs) required to start the motion?

1


a.
1332.80N

b.
83.30N

c.
8.50N

d.
136.00N
Heeelppp plzz​

Answers

Answer:

D (not so sure, look in the explanation and judge yourself)

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards

Minimum force required = 0.25 x 34 x 9.81

= 83.385 N

So technically the force need to be greater than 83.385 so the answer should be d, not really sure if it should be b though really depends on the acceleration due to gravity.

Why do we use copper wiring?

Answers

Explanation:

The lower the level of resistivity the more electrical conductivity a metal has. Copper has low resistivity, and therefore is an excellent conductor. Copper is also less oxidative than other metals

A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 11.5 pC. The inner cylinder has a radius of 0.550 mm, the outer one has a radius of 7.20 mm, and the length of each cylinder is 13.0 cm.
(a) What is the capacitance?
(b) What applied potential difference is necessary to produce these charges on the cylinders?

Answers

Answer:

A)2.811 × 10^-12 F

B)4.09V

Explanation:

(a) What is the capacitance?

Capacitance of coaxial cylinder can be determined using below expresion

C= (2π ε0 L)/ Ln[ rb/ra]

Where

ε0= permittivity of free space= 8.85×10^−12 Fm^-1

L= length of each cylinder =13.0 cm= 13×10^-2m

rb= radius of outer cylinder= 7.20 mm= 7.20×10^-3m

ra=radius of inner cylinder=0.550 mm= 0.550×10^-3 m

If we substitute the values we have,

C= (2π ε0 L)/ Ln[ rb/ra]

C= ( 2 × π × 8.85×10^−12 ×13×10^-2) / Ln[

7.20×10^-3/0.550×10^-3]

C=( 7.2288×10^-12 )/2.5729

C=2.811 × 10^-12 F

B) (b) What applied potential difference is necessary to produce these charges on the cylinders?

Vba= Q/C

Where Vba=potential difference

Q= charge on each = 11.5 pC. = 11.5×10^-12

C= capacitance= 2.811 × 10^-12 F

If we substitute the values we have

Vba=(11.5×10^-12)/2.811 × 10^-12

= 4.09V

As Carlos and Manual both push a 4 kg box to the right across a rough floor, the box speeds up at a rate of 2.0 m/s2.(Hint, this is the acceleration.) If you assume that Manual pushes with a force strength of 8.0 N and the friction force of the floor on the box is 5.0 N, then what is the strength of the force that Carlos pushes on the box

Answers

Answer: 5 N

Explanation:

Given

Mass of box [tex]m=4\ kg[/tex]

acceleration of box [tex]a=2\ m/s^2[/tex]

Force applied by Manual [tex]F_m=8\ N[/tex]

Friction force [tex]f=5\ N[/tex]

The net force on the block is [tex]F_{net}=m\times a=4\times 2=8 \N[/tex]

Suppose [tex]F_c[/tex] is the force applied by Carlos

[tex]\Rightarrow F_m+F_c-f=F_{net}\\\Rightarrow F_c=F_{net}-F_m+f\\\Rightarrow F_c=8-8+5=5\ N[/tex]

The strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

What is force?

The force is defined as the external effort applied on any object to move it or to restrict it.

Here following information is given in the question:

Mass of the box m=4 kg

The acceleration of the box [tex]a=2\ \frac{m}{s^2}[/tex]

The force applied by the Manual [tex]F_m=8\ N[/tex]

The frictional force is [tex]F_f=5\ N[/tex]

The net force on the body will be calculated by

[tex]F_{net}=m\times a=4\times 2=8\ N[/tex]

The force that Carlos pushes on the box will be calculated by the equilibrium of the forces:

[tex]F_m+F_c-F_f=F_{net}[/tex]

[tex]8+F_c-5=8[/tex]

[tex]F_c=5\ N[/tex]

Thus the strength of the force that Carlos pushes on the box will be [tex]F_c=5\ N[/tex]

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PLEASE HELP ME WITH THIS ONE QUESTION
How many joules are needed to vaporize 125 g of liquid water at 100°C? The latent heat of vaporization is 2258 J/g.

Answers

Answer:

Q = 282,000 J

Explanation:

Given that,

The mass of liquid water, m = 125 g

Temperature, T = 100°C

The latent heat of vaporization, Hv = 2258 J/g.

We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :

[tex]Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J[/tex]

or

Q = 282,000 J

So, the required heat is 282,000 J .

a 1.5 kg ball is thrown vertically upward with an initial speed of 15 m/s. if the initial potential energy is taken as zero, find the ball's kinetic, potential, and mechanical energies (a) a its initial position, (b) at 5 m above the initial position, and (c) at its maximum height

Answers

Answer:

a) [tex] E_{p} = 0 [/tex]

[tex] E_{k} = 168.7 J [/tex]

[tex] E_{m} = 168.7 J [/tex]

b) [tex] E_{p} = 73.6 J [/tex]

[tex] E_{k} = 95.8 J [/tex]

[tex] E_{m} = 169.4 J [/tex]

c) [tex] E_{p} = 169.2 J [/tex]

[tex] E_{k} = 0 [/tex]

[tex] E_{m} = 169.2 J [/tex]

Explanation:

We have:

m: is the ball's mass = 1.5 kg

v₀: is the initial speed = 15 m/s

g: is the gravity acceleration = 9.81 m/s²

a) In the initial position we have:

h: is the height = 0

The potential energy is given by:

[tex] E_{p} = mgh = 0 [/tex]

The kinetic energy is:

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(15)^{2} = 168.7 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 0 + 168.7 J = 168.7 J [/tex]

b) At 5 m above the initial position we have:

h = 5 m

The potential energy is:

[tex] E_{p} = mgh = 1.5*9.81*5 = 73.6 J [/tex]

Now, to find the kinetic energy we need to calculate the speed at 5 m:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (15)^{2} - 2*9.81*5 = 126.9 [/tex]

[tex] v_{f} = \sqrt{126.9} = 11.3 m/s [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = \frac{1}{2}*1.5*(11.3)^{2} = 95.8 J [/tex]

And the mechanical energies:

[tex] E_{m} = E_{p} + E_{k} = 73.6 + 95.8 J = 169.4 J [/tex]

c) At its maximum height:

[tex] v_{f}[/tex]: is the final speed = 0

[tex] h = \frac{v_{0}^{2}}{2g} = \frac{(15)^{2}}{2*9.81} = 11.5 m [/tex]

Now, the potential, kinetic and mechanical energies are:

[tex] E_{p} = mgh = 1.5*9.81*11.5 = 169.2 J [/tex]

[tex] E_{k} = \frac{1}{2}mv^{2} = 0 [/tex]

[tex] E_{m} = 169.2 J + 0 = 169.2 J [/tex]

I hope it helps you!    

Need a little help here, ASAP please. The subject is simple science, not physics.

Answers

Shape, because a liquid can have mass, volume, and color, but it cannot have a definitive shape

4. If the cooling of magma takes place slowly beneath Earth's surface, the rock is that is formed
is called
a. extrusive igneous rock
b. intrusive igneous rock
c. sedimentary rock
d. metamorphic rock

Answers

I agree with the answer above listen to them :)

I need help with science please, ill give brianlist’s :

Question 1 :The size of a plant cell may change depending upon the amount of water it receives.

True
False
________________________________

Question 2: Chloroplasts are a category of organelles found in the cells of green plants.

True
False
_______________________________

Question 3: Photosynthesis in plants produces water and carbon dioxide.

True
False

Answers

Answer:

true , true, and I'm not sure about the last one!

Explanation:

The answer Is True!!! Good luck

A 1.6 kg ball is attached to the end of a 0.40 m string to form a pendulum. This pendulum is released from rest with the string horizontal. At the lowest point of its swing, when it is moving horizontally, the ball collides with a 0.80 kg block that is at rest on a horizontal frictionless surface. The speed of the block just after the collision is 3 m/s. What is the speed of the ball just after the collision

Answers

Answer:

the speed of the ball just after the collision is 1.5 m/s.

Explanation:

Given;

mass of the ball, m₁ = 1.6 kg

initial velocity of the ball, u₁ = 0

mass of the block, m₂ = 0.8 kg

initial velocity of the block, u₂ = 0

final velocity of the block, v₂ = 3 m/s

let the final velocity of the ball after collision = v₁

Apply the principle of conservation of linear momentum for elastic collision;

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

1.6 x 0   +    0.8 x 0       =   1.6 x v₁     +  0.8 x 3

0 = 1.6v₁  + 2.4

-1.6v₁ = 2.4

v₁  = -2.4 / 1.6

v₁ = - 1.5 m/s

v₁ = 1.5 m/s (in opposite direction of the block)

Therefore, the speed of the ball just after the collision is 1.5 m/s.

A baseball is thrown a distance of 20 m what is its speed if it takes 0.5 seconds to cover the distance

Answers

Answer:

40m/s

Explanation:

Which group is an international organization in which the United States is involved?

A. The Foreign Relations Committee
B. The Senate Armed Services Committee
C. The Department of Defense
D. The World Trade Organization

Ccorrect Answer Is D: The World Trade Organization​

Answers

Answer:

the answer is d the world  trade organization

Explanation:

Direction of Wave Travel
С
Which letter
correctly
identifies the
wavelength of
this wave?
А
B
A. A
B. B
C. C

Answers

Answer:

I THINK it's A but I'm not completely sure

A Is the answer! Good luck

NEED HELP What color is the container for R-134a refrigerant? A. Light blue B. Yellow C. Dark green D.White and yellow​

Answers

Answer:

It is A. Light blue

_____________

Hope this helps!

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┈┃┏┗┛┓┃╭┫o i n k    ┃

┈╰┓▋▋┏╯╯╰━━━━╯

╭━┻╮╲┗━━━━╮╭╮┈

┃▎▎┃╲╲╲╲╲╲┣━╯┈

╰━┳┻▅╯╲╲╲╲┃┈┈┈

┈┈╰━┳┓┏┳┓┏╯┈┈┈

┈┈┈┈┗┻┛┗┻┛┈┈┈┈

Explain why the sound waves always reach the observer after the light waves

Answers

Answer:

I think it's because the light waves travel faster than the sound waves.

The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.

What is the speed of light?

Light occurs in the electromagnetic spectrum. Recall that light can be transmitted through vaccuum unlike sound.

The speed of light is far greater than the speed of sound hence, sound waves always reach the observer after the light waves.

Learn more about speed of light:https://brainly.com/question/8832859

#SPJ2

please help me with the working too.​

Answers

Answer:

1 : b  2: d

Explanation:

Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (560 nm) on a double slit with a separation of 0.108 mm. The diffraction pattern shines on the classroom wall 3.0 m away. Calculate the fringe separation between the third order and central fringe.

Answers

Answer:

 y = 4.666 10⁻² m

Explanation:

The constructive interference experiment for the double slit

         d sin sin θ = m λ

Let's use trigonometry to find a sine relationship.

         Tan θ = y / L

          tan θ = sin θ/ cos θ

in these experiments the angles are very small

           tan θ = sin θ

           sin θ = y / L

            [tex]d \frac{y}{L}[/tex] = m λ

              y = [tex]\frac{ m \lambda \ L}{d}[/tex]

we replace the values

              y = 3  560 10⁻⁹ 3.0 / 0.108 10⁻³

              y = 4.666 10⁻² m

What does the power source in a circuit provide?

the means to break a circuit
a path along which electricity can flow
static electricity
a steady flow of electrons

plsssssssssssssssssss answer plss not in a meen way but plssss anwer correctly

Answers

Explanation:

The primary function of a power supply is to convert electric current from a source to the correct voltage, current, and frequency to power the load. As a result, power supplies are sometimes referred to as electric power converters. Some power supplies are separate standalone pieces of equipment, while others are built into the load appliances that they power. Examples of the latter include power supplies found in desktop computers and consumer electronics devices. Other functions that power supplies may perform include limiting the current drawn by the load to safe levels, shutting off the current in the event of an electrical fault, power conditioning to prevent electronic noise or voltage surges on the input from reaching the load, power-factor correction, and storing energy so it can continue to power the load in the event of a temporary interruption in the source power (uninterruptible power supply).

hope my ans helps

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Stay safe

Which is NOT a way to stay safe from static electricity?

a lightning rod on a building
a metal spike in an airport runway
an anti-static chain on a large truck
a run through an open field during a lightning

plssssssssssss answer not in a meen way but corrrect answer only plsssssssssssss answer correct i will drop a thx and rate yo stars ans give you brainlyest

Answers

a metal spike in an airport runway

A metal spike in an airport runway  is NOT a way to stay safe from static electricity. Hence option C is correct.

What is electricity ?

Electricity is a collection of physical phenomena related with the presence and motion of matter having an electric charge. Both electricity and magnetism are connected to the phenomena of electromagnetic, as defined by Maxwell's equations. Lightning, static electricity, electric heating, electric discharges, and other frequent occurrences are all connected to electricity.

An electric field is created when either a positive or negative electric charge is present. The movement of electric charges results in an electric current and a magnetic field. In most applications, a force of magnitude determined by Coulomb's law operates on a charge. Volts are commonly used to measure electric potential.

Hence option C is correct.

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A police officer uses a radar gun that emits electromagnetic waves with a frequency of 10.525 GHz (1.0525 1010 Hz). Assume the police officer is at rest, and is aiming the radar gun at vehicles traveling either directly toward, or directly away from, the radar gun. Assume the speed limit is 110 km/h, as it is on many Canadian highways. The police officer observes reflected waves that have a frequency of 2460 Hz below the frequency of the emitted waves.

Required:
a. At what speed is the car moving?
b. Choose the two correct statements about this situation.

1. The car is moving toward the police officer.
2. The car is moving away from the police officer.
3. The police officer should not cite the driver for speeding.
4. The police officer should cite the driver for speeding.

Answers

Answer:

Explanation:

For Doppler effect in radar the formula is as follows

Δf = f₀ x 2v /c

Δf is change in frequency in reflected wave , f₀ is original frequency , v is velocity of source and c is velocity of right .

Δf  = 2460 Hz , f₀ = 1.0525 x 10¹⁰ Hz , v = ? c is velocity of light .

2460 =  1.0525 x 10¹⁰ x 2 v / 3 x 10⁸

2460 = 105.25 x 2 v / 3

v = 2460 x 3 / (105.25 x 2 )

v = 35 .06 m /s .

(b)

Since the observed frequency is less , the source is moving away from the observer .

option (2) is correct .

What is double stroking​

Answers

Answer: The double stroke roll works just like the single stroke roll - it's played in a sequence of alternating strokes (roll). But instead of having one stroke per hand you'll have two, as shown on the sheet music below. You can use full wrist turns to play each stroke of the double stroke at slower speeds.

Explanation: hope this helps!

Explanation:

it is played as a sequence of alternating strokes

A planet follows an elliptical orbit that brings it as close as 21 million km to a star and as far as 75 million km from the star. At both of these locations the velocity of the planet makes a right angle to the direction to the star. If the planet's speed is 38 km/s when it is farthest from the star, how fast is it moving when it is closest to the star

Answers

Answer:

Explanation:

In an elliptical orbit , the angular momentum of the planet remains constant because velocity of planet makes a right angle to the direction to the star .

mvr = constant .

mv₁r₁ = mv₂r₂

v₁r₁ = v₂r₂

v₁ x 21 = 38 x 75

v₁ = 135.71 km/s .

A young parent is dragging a 65 kg (640 N) sled (this includes the mass of two kids) across some snow on flat ground, by means of a rope attached to the sled. The rope is at an angle of 30 degrees with respect to the ground and the tension in the rope is 160 N. The sled is moving at a constant velocity of 1.5 m/s.
(a) Draw and label all forces acting on the kids + sled system. Indicate the relative size of each force by scaling the length of each force arrow appropriately
(b) Calculate the normal force acting on the system
(c) Calculate the force of friction acting on the system.
(d) Calculate the coefficient of friction between the sled and the snow.

Answers

Answer:

b) N = 560 N, c)  fr = 138.56 N, d)  μ = 0.247

Explanation:

a) In the attachment we can see the free body diagram of the system

b) Let's write Newton's second law on the y-axis

              N + T_y -W = 0

              N = W -T_y

let's use trigonometry for tension

             sin θ = T_y / T

             cos θ = Tₓ / T

             T_y = T sin θ

             Tₓ = T cos θ

we substitute

              N = W - T sin 30

we calculate

              N = 640 - 160 sin 30

              N = 560 N

c) as the system goes at constant speed the acceleration is zero

X axis

              Tₓ - fr = 0

               Tₓ = fr

we substitute and calculate

              fr = 160 cos 30

              fr = 138.56 N

d) the friction force has the formula

             fr = μ N

             μ = fr / N

we calculate

             μ = 138.56 / 560

             μ = 0.247

Will the 79 kg skier in the figure below slide down if f the coefficient of static friction is 0.25?

Answers

Answer:

Man will not slide down

Explanation:

Given:

Coefficient of static friction = 0.25

Angle = 13°

Computation:

Man will slide down if

tan13° > Coefficient of static friction

Tan 13 = 0.23

So,

0.23 < 0.25

So,

Man will not slide down


C
D
7
The sun is the original source of
energy for many of our energy
resources
Which energy resource does not
originate from the sun? *
(1 Point)
.
A. Geothermal
B. Hydroelectric
C. Waves
D. Win

Answers

Answer:

geothermal

Explanation:

geothermal energy is the heat energy obtained from within the Earth. Hence not derived from Sun's energy.

how could you increase the gravitational potential energy of an object without changing its mass and gravity​

Answers

One way you can change the gravitational potential energy is by increasing the height of the object off the ground.
Gravitational potential energy is known as Ug.
Ug = mass x gravity x height

If you can’t change the mass or the gravity change the height.

A frictionless piston-cylinder contains carbon dioxide gas (CO2) initially at 500oC and 2 MPa. The system is o3 cooled in an isobaric process until the final temperature becomes 350 C and the final volume is 1 m . For this process, determine: (a) The reduced pressure and the reduced temperature of the initial state. (b) The initial volume of the piston-cylinder (in m3). (c) The mass of CO2 in the piston-cylinder (in kg). (d) The total boundary work for the process (in kJ). (e) The amount of heat transfer during the cooling process (in kJ).

Answers

Answer:

(a) The reduced pressure is 0.2711 MPa

The reduced temperature is 2.54 K

(b) The initial volume of the piston is approximately 0.806 m³

(c) The mass of CO₂ is approximately 16.9884 kg

(d) The work done, W is approximately 388.023 kJ

(e) The heat transfer is approximately -2,650.1904 kJ

Explanation:

The initial temperature of the piston-cylinder, T₁ = 500°C = 773.15 K

The initial pressure of the gas, P₁ = 2 MPa

The final temperature of the gas, T₂ = 350°C

The final volume of the gas = 1 m³

(a) For an isobaric process, we have;

The reduced pressure,

[tex]P_r = \dfrac{P}{P_c}[/tex]

The critical pressure of carbon dioxide, [tex]P_c[/tex] = 7.3773 MPa

[tex]P_r = \dfrac{2 \, MPa}{7.3773 \, MPa} \approx 0.2711 \, MPa[/tex]

The reduced pressure, [tex]P_r[/tex] = 0.2711 MPa

The critical temperature, [tex]T_c[/tex] = 304.13 K

The reduced temperature, [tex]T_r[/tex], is given by the following formula;

[tex]T_r = \dfrac{T}{T_c}[/tex]

Therefore, [tex]T_r[/tex] = (773.15 K)/(304.13 K) = 2.54216947 K

The reduced temperature, [tex]T_r[/tex] ≈ 2.54 K

(b) The initial volume of the piston, V₁ = (V₂/T₂) × T₁

∴ V₁ = (1 m³/773.15) × 623.15 = 0.80598848865 m³  ≈ 0.806 m³

The initial volume of the piston, V₁ ≈ 0.806 m³

(c) The number of moles of CO₂ in the cylinder, 'n', is given according to the following formula;

n = P·V/(T·R)

The universal gas constant, n = (2 × 10⁶Pa × 1 m³)/(623.15 K × 8.3145 J/(mol·K)) ≈ 386.0124 moles

The mass of CO₂ ≈ 386.0124 moles × 44.01 g/mol = 16.9884 kg

(d) The work done, W = P·([tex]V_f - V_i[/tex])

W = 2 × 10⁶ × (1 - 0.80598848865) = 388023.0227

The work done, W ≈ 388.023 kJ

(e) The heat transfer dQ = m·[tex]c_p[/tex] ×(T₂ - T₁)

[tex]c_p[/tex] for CO₂ ≈ 1.04 kJ/(kg·K)

∴ dQ = 16.9884 × 1.04 × (350 - 500) = -2,650.1904 kJ

Therefore, the heat transfer = dQ = -2,650.1904 kJ

A resistor, an ideal capacitor, and an ideal inductor are connected in parallel to a source of an alternating voltage of 160 V at a frequency of 250 Hz. A current of 2 A flows through the resistor and a current of 0.8 A flows through the inductor. The total current through the circuit is 2.5 A. Assess the resistance of the resistor, the capacity of the ideal capacitor, and the inductance of the ideal inductor (presume that IC > IL).

Answers

Answer:

R = 46,25 (Ω)

L = 0,07363 (H)

C = 2,7 *10⁻⁶ (F)

Explanation:

Statement problem does not specify if  160 (V) is peak voltage or RMS value. If 160 (V) is the peak value then for a sinusoidal wave,  RMS value is  V(rms) = 160 /√3

V(rms) =  92,49 (V)

In each branch: we have

V = I*Z         V = voltage through the impedance in (V) , I current in (A)

and Z impedance in Ω

Resistor case    Z = R  then V = 92,49 = 2 * R

R = 92,49/2       R = 46,25 (Ω)

Inductor case   |Z| = wL    Then Z = 2*π*f*L   V = 0,8 * |wl|

Inductor L in (H)       |wL| * 0,8 = 92,49   |wL| = 92,5/0,8    w = 2*π*f   2*3,14*250= 1570

1570*L = 92,49/0,8

L = 0,07363 (H)

In the case of the capacitor

|Z|  = 1/wc    = 1/1570*c

The current is 2 + 0,8 = 2,8          2,8 - 2,5 = 0,3 (A)

Again  V = I*Z        92,49 = 0,3 /1570*C

C = 0,3 / 1570*92,49

C = 2,7 *10⁻⁶ (F)

Which of the following is an example of the transformation of gravitational potential energy into motion energy (kinetic energy)?

Answers

Answer:

c

Explanation:

because a drop of water is falling and that is gravitational potential energy into motion energy

What is Gravity?
PLEASE ANSWER ​

Answers

Answer:

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

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Have a great day, be safe and healthy

Thank u  

XD

Answer:

GRAVITY:

In physics, gravity is the force that attracts a body towards the centre of the earth, or towards any other physical body having mass.

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A disturbance that generates a wave may be a simple pulse or shockTrue or false Can someone round these to the nearest .1 1.602564102564103 2.380952380952381 What is the value of n?Your answer in the box n= 5m 15m n 2m If you help me u are the best ;) Balance the following equations. Al4C3 + H2O Al(OH)3 + CH4 NH3 + O2 NO + H2O I need help pzlz.... One of the differences between embryonic stem cells and adult stem cells is ? help i cant find this answer PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Write an equation for the line shown above:y = x + Find the circumference use 3.14 for the value of Can I get a good suggestion for a song that I can cry to? Identify 4 waysparticipate in democracy Sepsis Case Study Review Scenario: At 12:00 noon, Jose Guerrero, a 17 year old high school student on the soccer team, arrives at the Emergency Department (ED) a few days after cutting his foot at practice. The area on his foot around the wound has progressively gotten red, tender, hot to the touch, and has some drainage. Today it caused pain when walking and he was feeling weak and had a temperature. His only medical history is a mild case of asthma for which he occasionally uses an inhaler. The ED Technician takes Joses vital signs. Joses vital signs are: Heart Rate (HR) 98 Respiratory Rate (RR) 24 Temperature (T) 38.2 C Systolic Blood Pressure (SBP) 100 (normal for Jose = 125 135) Level of Consciousness Alert & oriented to time, place and person Weight 90 kg Using the Sepsis Algorithm, answer the following questions: Does Jose have 2 or more Systemic Inflammatory Response Syndrome (SIRS) criteria? If yes, what criteria? Is there an actual or potential infection? If so, what is the source? What should happen next? . Based on Joses condition and vital signs, here are the steps the ED staff take: They place Jose into a bed at 1230 pm. The nurse starts an intravenous (IV) line in case fluids or IV medications need to be given The doctor orders the following labs: Lactate, Blood Culture and Complete Blood Count (CBC) (the phlebotomist draws the labs at 1255 pm) The doctor orders 1 Liter (L) of intravenous fluid [normal saline (NS)] and the nurse gives the fluid starting at 1:20 pm, at the time she hangs the fluid bag the SBP = 88 and the HR = 102 In the meantime, Jose is starting to shiver. Some lab results come back from the lab at 1:40 pm. The lab results are: Lactate = 4.2 CBC: White Blood Cell (WBC) count = 15 thousand; Hematocrit (Hct) = 42 The blood culture is pending The ED technician takes Joses vital signs (VS) again at 1:45 pm after the liter of fluid has been given to him. Joses vital signs are now: SBP = 80 HR = 114 RR = 28 T = 39 C Jose looks very pale Answer the following questions: Is Johns condition improving? What do you think needs to happen now? Because Joses condition is not improving: The doctor orders another liter (L) of fluid (NS) and IV antibiotics and asks the nurse to get VS again as soon as the fluid is administered 1 L fluid is given at 2:10 pm The antibiotic is started at 2:20 pm and takes 30 min to give The doctor calls the nurse at 2:25 pm and tells her that he wants to start Early Goal Directed Therapy (EGDT) on Jose The start time for EGDT is 1:40 pm when the lactate result of 4.2 came back from the lab. All interventions related to his care that have time frames associated with them are based on this start time. The liter of fluid has been administered and at 2:30 the nurse checks Johns VS again as the doctor ordered. Joses vital signs are: SBP = 85 HR = 105 RR = 25 T = 38.7 C The sepsis catheter is inserted at 3:05 pm and the nurse starts monitoring the measurements from the catheter that give information that helps guide treatment for Jose. The doctor orders a chest X-ray to make sure the catheter is inserted correctly and makes arrangements to transfer Jose to the Intensive Care Unit (ICU) as soon as possible. Here are the values recorded from the sepsis catheter: Time CVP MAP ScvO2 3:15 pm 4 56 60 3:40 pm 5 57 4:10 pm 5 56 62 4:45 pm 6 59 5:10 pm 8 60 65 5:40 pm 8 59 6:00 pm 10 62 64 6:30 pm 9 64 6:55 pm 9 67 66 7:15 pm 8 68 7:40 pm 9 68 68 8:15 pm 8 70 8:45 pm 10 69 69 9:10 pm 9 68 9:45 pm 9 72 72 The ED staff takes another lactate draw at 7:05 pm. The results from that draw arrive at 7:57 pm and are 2.3. Based on this information, did the ED staff meet the EGDT goals outlined in the Sepsis Algorithm? Which of these were met? Antibiotics given at the right time? Sepsis catheter inserted at the right time? CVP, MAP, ScvO2 targets? Decreased repeat lactate? Jose slowly improves over the next 2 days while in the ICU. He remains on IV antibiotics and is transferred to the Medical Surgical unit until he is discharged home 2 days later. Can someone just help me with this simultaneous equations with substitution. Ive asked ten times and no one has helped. Please Men and women work in a warehouse full of large artillery shells.English women and men work in a storage shed for large shells in a munitions factory in 1918.Use the image to answer the question.Which of the following statements most accurately describes how the working relationship depicted in the image was affected by the conclusion of World War I? A. Women went back to traditional prewar roles. B. Men and women continued to work side by side. C. Men left the workplace at higher rates than women. D. Women moved up faster than men in leadership positions. Please help me, is for today pls pls plsThe Triple Entente also refers to the ___________________ powers Whats the benefit of having people believe in what you are selling? Someone plz help me plz . Describe ways the medical assistant can help overcome barriers to communication.