Answer:
dh/dt ≈ 0.55 ft/min
Step-by-step explanation:
The volume is given by the formula ...
V = (1/3)πr²h
We have r = h/2, so the volume as a function of height is ...
V = (1/3)π(h/2)²h = (π/12)h³
Then the rates of change are related by ...
dV/dt = (π/4)h²·dh/dt
dh/dt = (4·dV/dt)/(πh²) = 4(35 ft³/min)/(π(9 ft)²)
dh/dt ≈ 0.55 ft/min
Please answer this correctly
Answer:
33.3%
Step-by-step explanation:
The numbers greater than 6 from the spinner are 7 and 8.
2 numbers out of total 6 numbers.
2/6 = 1/3
= 0.333
= 33.3%
what polynomial has roots of -5, - 4 and 1
Answer:
[tex]\boxed{\sf \ \ \ x^3+8x^2+11x-20 \ \ \ }[/tex]
Step-by-step explanation:
hello,
(x+5)(x+4)(x-1) is one example of polynomial which has roots of -5,-4 and 1
[tex](x+5)(x+4)(x-1) = (x+5)(x^2-x+4x-4)=(x+5)(x^2+3x-4)\\= x^3+3x^2-4x+5x^2+15x-20=x^3+8x^2+11x-20[/tex]
hope this helps
Fraud detection has become an indispensable tool for banks and credit card companies to combat fraudulent credit card transactions. A fraud detection firm has detected some form of fraudulent activities in 2%, and serious fraudulent activities in 0.75% of transactions. Assume that fraudulent transactions remain stable.
a. What is the probability that fewer than 2 out of 110 transactions are fraudulent?
b. What is the probability that fewer than 2 out of 105 transactions are seriously fraudulent?
Answer:
a) 35.17% probability that fewer than 2 out of 110 transactions are fraudulent
b) 81.35% probability that fewer than 2 out of 105 transactions are seriously fraudulent
Step-by-step explanation:
For each transaction, there are only two possible outcomes. Either they are fradulent(or seriously fraudulent), or they are not. Transactions are independent. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
a. What is the probability that fewer than 2 out of 110 transactions are fraudulent?
2% are fraudulent, so [tex]p = 0.02[/tex]
110 transactions, so [tex]n = 110[/tex]
This is
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{110,0}.(0.02)^{0}.(0.98)^{110} = 0.1084[/tex]
[tex]P(X = 1) = C_{110,1}.(0.02)^{1}.(0.98)^{109} = 0.2433[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.1084 + 0.2433 = 0.3517[/tex]
35.17% probability that fewer than 2 out of 110 transactions are fraudulent.
b. What is the probability that fewer than 2 out of 105 transactions are seriously fraudulent?
0.75% are seriously fraudulent, so [tex]p = 0.0075[/tex]
105 transactions, so [tex]n = 105[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]
[tex]P(X = 0) = C_{105,0}.(0.0075)^{0}.(0.9925)^{105} = 0.4536[/tex]
[tex]P(X = 1) = C_{105,1}.(0.0075)^{1}.(0.9925)^{104} = 0.3599[/tex]
[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.4536 + 0.3599 = 0.8135[/tex]
81.35% probability that fewer than 2 out of 105 transactions are seriously fraudulent
Jamie is investing $47,000 in an account paying 9.26% interest compounded continuously. What will Jamie's account balance be in 17 years?
9514 1404 393
Answer:
$226,863.29
Step-by-step explanation:
The amount is given by ...
A = Pe^(rt)
where principal P is invested at annual rate r for t years.
A = $47,000×e^(0.0926×17) ≈ $226,863.29
Answer:
the answer is $226,863.29
Suppose we want to study the weekly rate of alcohol drinking among USF undergraduate students. Which of the following would be the LEAST preferred method of randomly selecting participants?
A. Selecting a random sample of students from each residence hall
B. Selecting a random sample of students from the list of all undergraduate students from the university's registrar office
C. Selecting a random sample of students who have used the university health services in the past month
D. Selecting a random sample of students from each college
Answer:
Option D
Step-by-step explanation:
I think the least preferred method the researcher would like is to select a random sample of students from each college. This means the researcher would have to go to every college and randomly selects participants which is very exhausting. Thus, this would be the least prefer method over the others...
Write an equation for a polynomial function that has the given roots
-2. 3i , and 5
Answer:
x^4 - 3x^3 - x^2 - 27x - 90 = 0.
Step-by-step explanation:
If 3i is one root then another is -3i.
In factor form we have:
(x + 2)(x - 5)(x - 3i)(x + 3i) = 0
(x^2 - 3x - 10)(x^2 -9i^2) = 0
(x^2 - 3x - 10)(x^2 + 9) = 0
x^4 + 9x^2 - 3x^3 - 27x - 10x^2 - 90 = 0
x^4 - 3x^3 - x^2 - 27x - 90 = 0.
If f(x) = x^2 is reflected over the x-axis and the shifted 4 units down, what is the equation of the new function, g(x)?
Answer:
g(x) = -x² - 4
Step-by-step explanation:
In this case, we are only changing a (reflection and vertical shrink/stretch) and k (vertical movement)
k = -4 because we are moving 4 units down
a = -1 because we are just reflecting over the x-axis
Mr. Taylor filled out a bracket for the NCAA National Tournament. Based on his knowledge of college basketball, he has a 0.54 probability of guessing any one game correctly. (a) What is the probability Mr. Taylor will pick all 32 of the first round games correctly
Answer:
The probability is [tex]2.7327 \times 10^{-9}[/tex]
Step-by-step explanation:
The probability of guessing correctly, P = 0.54
Probability of not guessing correctly, q = 1 – P
q = 1 – 0.54 = 0.46
Number of trials, n = 32
Now calculate the probability that Mr. Taylor will pick 32 correctly in first round of the game.
Below is the calculation using binomial distribution.
[tex]Probability = \left ( _{k}^{n}\textrm{} \right )P^{k}(1-P)^{(n-k)} \\= \left ( _{32}^{32}\textrm{} \right )0.54^{32}(0.46)^{(32-32)} \\= 0.54^{32} \\= 2.7327 \times 10^{-9}[/tex]
Can advise on the solution?
Answer:
340
Step-by-step explanation:
If x is the amount of pages in the book we can write:
1/4x + 5 + 3/5(x - (1/4x + 5)) + 10 + 12 + 24 = x
1/4x + 51 + 3/5(3/4x - 5) = x
1/4x + 51 + 9/20x - 3 = x
7/10x + 48 = x
3/10x = 48
x = 160
Which would be appropriate compatible numbers to use to estimate ( 19 4 5 ) ( 4 6 ) ? Using this compatible number, what is the estimated product?
Answer: first box is 20 (1/2)
Second box is 10
Answer:
Answer: first box is 20 (1/2)
Second box is 10
Step-by-step explanation:
State whether the decay is linear or exponential, and answer the associated question. The value of a car is decreasing by 9% per year. If the car is worth $11 comma 000 today, what will it be worth in two years? g
Answer:
ExponentialA(2)=$9109.10Step-by-step explanation:
Since the value of the car decreases by a common factor each year, the decay is exponential.
An exponential decay function is of the form
[tex]A(t)=A_0(1-r)^t$ where:\\Initial Value, A_0=\$11,000\\$Decay Factor, r=9%=0.09[/tex]
Therefore, the function modeling the car's decay is:
[tex]A(t)=11000(1-0.09)^t[/tex]
We want to determine the car's value in two years.
When t=2
[tex]A(2)=11000(1-0.09)^2\\A(2)=\$9109.10[/tex]
The value of the car in 2 years will be A(t)=$9109.10
Final value of the car after 2 years will be $9109.10
Value of the car decay by 9%.
Since, 9% is a common factor by which the value of car is decreasing,
Therefore, decay will be exponential.
Expression for the exponential decay is given by,
[tex]P=P_0(1-\frac{r}{100} )^t[/tex]
Here, [tex]P=[/tex] Final price
[tex]P_0=[/tex] Initial price
[tex]r=[/tex] Rate of decay
[tex]t=[/tex] time
If initial price of the car [tex]P_0=11000[/tex], rate of decay [tex]r=0.09[/tex] and [tex]t=[/tex] Number of years
By substituting the values in the expression,
P = [tex]11000(1-0.09)^2[/tex]
= 11000(0.91)²
= $9109.10
Therefore, final value of the car after 2 years will be $9109.10
Learn more,
https://brainly.com/question/24515212
Jack knows the surface area of a cylinder and its radius. He wants to find the cylinder's helght. He needs to rewrite the formula A = 2#r(+h)
to find the cylinder's height (h) In terms of the cylinder's surface area (A) and its radius (7). Which is the correct formula?
Answer:
h= pi(r)2/A or h= 3.14 times 7 times 2 divided by A
Step-by-step explanation:
u need to do the opposite of multiplication which is division to find the height
hope this helps
correct me if this is wrong
Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides. The area of EFGH is 35 square units. What is the value of x? 4 units 5 units 6 units 7 units
*see attachment for the figure described
Answer:
5 units
Step-by-step explanation:
==>Given the figure attached below, let where FH and EG intercepted be K.
Since FH are midpoints of parallel lines, KE = KG = x.
Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.
Area of kite = ½ × d1 × d2
Where d1 = KH = 7
d2 = EG = KE + KG = x + x = 2x
Area of kite EFGH = 35
THUS:
35 = ½ × 7 × 2x
35 = 1 × 7 × x
35 = 7x
Divide both sides by 7
35/7 = x
x = 5
Answer:
5 units
Step-by-step explanation:
Find the interquartile range (IQR) of the data in the dot plot below. luis lacrosse scoring each season pls helpppppppppppppppp
Answer:
3.5
Step-by-step Explanation:
To find the IQR of the given data in the dot plot shown in the attachment below, follow the steps below:
==>Step 1: write out each data point represented on the dot plot in an ordered manner. A dot represents each value of number of goals scored by Luis each season.
Thus, we would have:
43 (1 dot)
44, 44, 44 (3 dots)
45, 45(2 dots)
47 (1 dot)
48, 48 (2 dots)
Our data set from the least to the highest is: 43, 44, 44, 44, 45, 45, 47, 48, 48
==>Step 2: Find the median
Our median value is the middle value of our data set. Thus:
43, 44, 44, 44, | 45, | 45, 47, 48, 48
Our median would be 45.
==>Step 3: Find the upper and lower median (Q3 & Q1):
Our upper median (Q3) would be the middle value of the upper portion of our data set, while our lower median would be the middle value portion of our data set.
Upper portion of our data set are the values we have from our median point upwards towards our right, while the lower portion are values downwards to our left. Thus, our upper and lower median values are shown below which would be the mean of the 2 middle values shown in the brackets below:
43, (44, 44,) 44, | 45, | 45, (47, 48,) 48
Upper median (Q3) = (47+48) ÷ 2 = 47.5
Lower median (Q1) = (44+44) ÷ 2 = 44
==>Step 4: Subtract the lower median from the upper median to get the IQR.
IQR = Upper median (Q3) - Lower median (Q1)
IQR = 47.5 - 44
IQR = 3.5
Answer:
3.5
Step-by-step Explanation:
To find the IQR of the given data in the dot plot shown in the attachment below, follow the steps below:
==>Step 1: write out each data point represented on the dot plot in an ordered manner. A dot represents each value of number of goals scored by Luis each season.
Thus, we would have:
43 (1 dot)
44, 44, 44 (3 dots)
45, 45(2 dots)
47 (1 dot)
48, 48 (2 dots)
Our data set from the least to the highest is: 43, 44, 44, 44, 45, 45, 47, 48, 48
==>Step 2: Find the median
Our median value is the middle value of our data set. Thus:
43, 44, 44, 44, | 45, | 45, 47, 48, 48
Our median would be 45.
==>Step 3: Find the upper and lower median (Q3 & Q1):
Our upper median (Q3) would be the middle value of the upper portion of our data set, while our lower median would be the middle value portion of our data set.
Upper portion of our data set are the values we have from our median point upwards towards our right, while the lower portion are values downwards to our left. Thus, our upper and lower median values are shown below which would be the mean of the 2 middle values shown in the brackets below:
43, (44, 44,) 44, | 45, | 45, (47, 48,) 48
Upper median (Q3) = (47+48) ÷ 2 = 47.5
Lower median (Q1) = (44+44) ÷ 2 = 44
==>Step 4: Subtract the lower median from the upper median to get the IQR.
IQR = Upper median (Q3) - Lower median (Q1)
IQR = 47.5 - 44
IQR = 3.5
What is the product -3 1/3of -8 7/10 and ?
Answer:
Brainliest!!!
Step-by-step explanation:
See picture!!
Answer:
29
Step-by-step explanation:
Please answer this correctly
Answer:
# of plants # of gardens
10-14 2
15-19 2
20-24 5
25-29 3
30-34 3
35-39 5
40-44 4
Step-by-step explanation:
10-14: 10, 12 (2 numbers)
15-19: 18, 19 (2 numbers)
20-24: 20, 22, 23, 24, 24 (5 numbers)
25-29: 25, 27, 38 (3 numbers)
30-34: 31, 33, 33 (3 numbers)
35-39: 36, 36, 36, 37, 38 (5 numbers)
40-44: 40, 44, 44, 44 (4 numbers)
Answer:
10-14 ⇒ 2
15-19 ⇒ 2
20-24 ⇒ 5
25-29 ⇒ 3
30-34 ⇒ 3
35-39 ⇒ 5
40-44 ⇒ 4
Google I would like to purchase 10 bags of chicken wings the store is selling three bags for $51.00 what is the cost of 10 bags of chicken wings
a. 61.00
b. 71.00
c. 170.00
d. 130.00
Answer:
A 61.00
Step-by-step explanation:
51 Added to 10 Equals 61.00 which is the Cost of 10 Bags of chicken Wings. Your Welcome.
Please help mehhh please!!
Answer:
It says your picture failed to load
Step-by-step explanation:
did it only happen to me or other people
Answer:
fraction: 70/100
decimal: 0.7
percent: 70%
Step-by-step explanation:
hope dis helps u! mark as brainlest if possible!
The sum of the ages of ahsan and his mother is 61 years.The difference in their ages is 29 years.By forming a pair of simultaneous linear equations,find (i)ahsan's present age (ii)the age of ahsan's mother when ahsan is 21 years old
Answer:
a. 16 years
b. 50 years
Step-by-step explanation:
Let us assume the age of Ahsan be X
And, the age of his mother be Y
It is mentioned in the question that the sum of the both ages to be 61 years and their difference is 29 years
So now the equation is as follows
X + Y = 61 .............................. (1)
-X + Y = 29 .............................. (2)
Now solve this
We get
2Y = 90
Y = 45 = Ahsan mother age age
Now put the value of Y in any of the above equation
So X would be
X = 61 - 45
= 16 i.e ahsan age
The mother age is
= 45 years + 5 years
= 50 years
The 5 years come from
= 21 years - 16 years
= 5 years
Please answer this correctly
Answer:
First box is 4This is because 2 is the stem and the leaves are 1, 2, 4, and 5
so the numbers are 21, 22, 24, and, 25
Second box is 3This is because 2 is the stem for the leaves 6 and 7
3 is the stem for the leaf 0
So the numbers are 26, 27, and 30
Hope this helped
Answer:
As you know about the stem and leaf plot
1 |7 7 7 8 => 17, 17, 17, 18
2|1 2 4 5 6 7 => 21, 22, 24, 25, 26, 27
3|0 2 5 5 6 7 7 8 9 => 30, 32, 35, 35, 36, 37, 37, 38, 39
4|1 2 => 41, 42
Now we count to complete the table:
16-20 | 4 {17, 17, 17, 18}
21-25 | 4 {21, 22, 24, 25}
26-30 | 3 {26, 27, 30}
31-35 | 3 {32, 35, 35}
36-40 | 5 {36, 37, 37, 38, 39}
41-45 | 2 {41, 42}
Hope this helps!
f(x) = (x + 2)(x + 2)
[tex]\displaystyle f(x) = (x + 2)(x + 2)[/tex]
[tex]\displaystyle f(x) = (x + 2)^2[/tex]
Answer:
[tex]f(x) = {(x + 2)}^{2} [/tex]
Step-by-step explanation:
[tex]f(x) = (x + 2)(x + 2) \\ f(x) = {(x + 2)}^{2} [/tex]
hope this helps you.
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 442 gram setting. It is believed that the machine is underfilling the bags. A 44 bag sample had a mean of 438 grams. Assume the population variance is known to be 576. A level of significance of 0.1 will be used. Find the P-value of the test statistic. You may write the P-value as a range using interval notation, or as a decimal value rounded to four decimal places.
Answer:
p value is 0.1343
Step-by-step explanation:
Null: u>= 442
Alternative: u < 442
Using the formula for z score:
(x - u)/sd/√n
Where x is 438, u = 442 sd can be determined from the variance = √variance =√576 = 24 and n = 44
z score = 438-442 / (24/√44)
z score = -4/(24/6.6332)
z = -4/3.6182
z =-1.1055
Now let's find the p value at 0.1 significance level using a z score of -1.1055, using a p value calculator, p value is 0.1343 which greatest than 0.1 meaning the day is not sufficient enough to conclude that the machine is underfilling the bags.
Once a fire is reported to a fire insurance company, the company makes an initial estimate, X, of the amount it will pay to the claimant for the fire loss. When the claim is finally settled, the company pays an amount, Y, to the claimant. The comapny has determined that X and Y have the joint density functionf(x,y) = Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.
Answer:
The probability that the final settlement amount is between 1 and 3 given that the initial claim is 2 = (2/9) = 0.2222
Step-by-step explanation:
The complete question is presented in the attached image to this solution
The joint probability distribution is given as
f(x, y) = {2/[x²(x - 1)} × y^-[(2x-1)/(x-1)] for x>1 And y>1
Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.
That is, x = 2, and y ranges from 1 to 3
Inserting x = 2 into the expression, we obtain
f(y) = (1/2) × y⁻³ = (y⁻³/2)
The required probability would then be
P(1 < y ≤ 3) = ∫³₁ f(y) dy
= ∫³₁ (y⁻³/2) dy
= [y⁻²/-4]³₁
= [3⁻²/-4] - [1⁻²/-4]
= (-1/36) - (-1/4)
= (1/4) - (1/36)
= (8/36)
= (2/9) = 0.2222
Hope this Helps!!!
if the vertex of a parabola is negative for 6 and the other point of the curve is (-3,14) what is the coefficient of the squared expression in Parabola equation?
A. 6
B. 4
C. 8
D. 2
Answer:
coefficient of the square is a.6
The valve was tested on 270 engines and the mean pressure was 6.6 lbs/square inch. Assume the variance is known to be 0.49. If the valve was designed to produce a mean pressure of 6.5 lbs/square inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications
Answer:
[tex]z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347[/tex]
The p value for this case would be given by"
[tex]p_v =2*P(z>2.347)=0.0189[/tex]
For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications
Step-by-step explanation:
Information given
[tex]\bar X=6.6[/tex] represent the sample mean
[tex]s=\sqrt{0.49}= 0.7[/tex] represent the population deviation
[tex]n=270[/tex] sample size
[tex]\mu_o =6.5[/tex] represent the value that we want to test
[tex]\alpha=0.1[/tex] represent the significance level
z would represent the statistic
[tex]p_v[/tex] represent the p value for the test
Hypothesis to verify
We want to verify if the true mean for this case is equal to 6.5 lbs/square inch or not , the system of hypothesis would be:
Null hypothesis:[tex]\mu= 6.5[/tex]
Alternative hypothesis:[tex]\mu \neq 6.5[/tex]
The statistic for this case is given by:
[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)
And replacing we got:
[tex]z=\frac{6.6-6.5}{\frac{0.7}{\sqrt{270}}}=2.347[/tex]
The p value for this case would be given by"
[tex]p_v =2*P(z>2.347)=0.0189[/tex]
For this case since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean is significantly different from 6.5 lbs/square inch at 10% of significance. So then there is not enough evidence to conclude that the valve does not perform to the specifications
What is simplified expression for the expression below
Answer:
9x +17
Step-by-step explanation:
distrubute the numbers outside of the parenthesis to the inside. You would then be left with 4x +32 + 5x -15 from there you would combine like terms leaving you with 9x + 17
A television network, Network A, is scheduling its fall lineup of shows. For the Tuesday night 8 p.m. slot, Network A has selected its top show. If its rival network, Network B, schedules its top show during the same time slot, Network A estimates that it will get 1.1 million viewers. However, if Network B schedules a different show during that time slot, Network A estimates that it will get 1.9 million viewers. Network A believes that the probability that Network B will air their top show is 0.7 and the probability that Network B will air another show is 0.3. Determine the expected number of viewers for Network A's top show.
Answer:
1,280,000 (1.28 million.)
Step-by-step explanation:
If Network B schedules its top show (with a probability of 0.7), Network A will get 1.1 million viewers.
If Network B schedules a different show during that time slot, (with a probability of 0.3), Network A will get 1.9 million viewers.
Therefore, the probability distribution table of number of viewers of Network A is:
[tex]\left|\begin{array}{c|c|c}$Number of Viewers, x&1.1$ million&$1.7 million\\P(x)&0.7&0.3\end{array}\right|[/tex]
Therefore, the expected number of viewers for Network A's top show
= (1100000 X 0.7) + (1700000 X 0.3)
=1,280,000
The expected number of viewers for Network A's top show is 1.28 million.
what is the value of y
Answer:
y=54 degrees
Step-by-step explanation:
2y+72=180
2y=108
y=54
Answer:
B
Step-by-step explanation:
72 + y + y = 180
72 + 2y = 180
2y = 108
2y/2 = 108/2
y = 54
Hope this helps ^-^
The mail arrival time to a department has a uniform distribution over 5 to 45 minutes. What is the probability that the mail arrival time is more than 25 minutes on a given day? Answer: (Round to 2 decimal places.)
Answer:
0.5
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X higher than x is given by the following formula.
[tex]P(X > x) = \frac{b - x}{b-a}[/tex]
The mail arrival time to a department has a uniform distribution over 5 to 45 minutes.
This means that [tex]a = 5, b = 45[/tex].
What is the probability that the mail arrival time is more than 25 minutes on a given day?
[tex]P(X > 25) = \frac{45 - 25}{45 - 5} = 0.5[/tex]
So the probability that the mail arrival time is more than 25 minutes on a given day is 0.5.
What is the sampling method used in the following scenario? The marketing manager for an electronics chain store wants information about the ages of its customers. Over the next two weeks, at each store location, 100 randomly selected customers are given questionnaires to fill out asking for information about age, as well as about other variables of interest.
Answer:
Step-by-step explanation:
The method applied in this scenario is called simple random sampling. A sample of 100 customers is chosen from a larger population of customers and each customer has the same chance of being selected for the survey at any given time. Also, the chance of selecting 100 customers from each store is the same during the sampling process. The order of sampling at each store does not follow a certain order, thus, It is different from systematic random sampling.