graph the inequality
-x+4y>-16

Answer:

39.06 m

Step-by-step explanation:

Given that,

Height of the building, h = 50 m

The angle of elevation at top of building is 52° when seen from a point on level ground.

We need to find the distance between point and foot of the building. Let the distance be d. Using trigonometry to find it. So,

[tex]\tan\theta=\dfrac{P}{B}[/tex]

Where

P is perpendicular

B is base.

So,

[tex]\tan\theta=\dfrac{h}{d}\\\\d=\dfrac{h}{\tan\theta}\\\\d=\dfrac{50}{\tan(52)}\\\\d=39.06\ m[/tex]

So, the distance between point and foot of the building is 39.06 m

Applying the trigonometry ratio, TOA, the distance between the point and the foot of the building is: 39.1 m.

Recall:

The information of the building has been sketched in the diagram shown in the image attached below. It shows a right triangle.

Apply the trigonometry ratio, TOA:

tan ∅ = opposite/adjacent

tan 52 = 50/x

x = 50/tan 52

x = 39.1 m

Therefore, applying the trigonometry ratio, TOA, the distance between the point and the foot of the building is: 39.1 m.

Learn more about trigonometry ratios on:

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Answer:

A. 25.12 meters

..........

Answer:

the first one is y=x-1/2 and the second one is y=-3x+1

Step-by-step explanation:

Answer:

x=1

Step-by-step explanation:

x+y=4

replace y with 3x

x+3x=4

then add the x which is 1x plus 3x

4x=4

then divide 4 on both sides

4x/4=4/4

and your answer is 1

Answer:

a) 50yd2

b) 7ft2

Step-by-step explanation:

a) 1/2 x b x b

1/2 x 4 x 25 = 50

b) 1/2 x b x h

1/2 x 4 x 3.5 = 7

Answer:

B

Step-by-step explanation:

when x=1 y=3.9 when x=2 y=7.8 and so on

Answer:

No, he got extra (no need to be a Karen there)

Step-by-step explanation:

680 times 200=136000grams=136kilograms

136>129.2

Answer:

I am pretty sure it's A, 85% sure

Step-by-step explanation:

Sorry wasn't a ton of help, ignore if there is a better answer but you seem like in a rush

Answer:

D.70

Step-by-step explanation:

I think its D or B

8 1/4 pounds converted to ounces is 132 ounces. 1 pound is 16 ounces, so all you have to do is multiply the number of pounds by 16.

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sorry if this doesn't help

Answer:

132

Step-by-step explanation:

Answer:

x=27

Step-by-step explanation:

Answer:

Please take a photograph of the graph.

Answer:

0.75 seconds

Step-by-step explanation:

Answer:

Step-by-step explanation:

i feel like it would be (4)(4)(4)(4)(4)(4)(4)(4) = 65536

The number of different four digit passwords that are possible if we use letters and digits only, and can't include repeating characters is 13,388,280 ways.

We can use combinations for this case,

Total number of distinguishable things is m.

Out of those m things, k things are to be chosen such that their order doesn't matter.

This can be done in total of  [tex]^mC_k = \dfrac{m!}{k! \times (m-k)!}[/tex] ways.

If the order matters, then each of those choice of k distinct items would be permuted k! times.

So, total number of choices in that case would be:

[tex]^mP_k = k! \times ^mC_k = k! \times \dfrac{m!}{k! \times (m-k)!} = \dfrac{m!}{ (m-k)!}\\\\^mP_k = \dfrac{m!}{ (m-k)!}[/tex]

This is called permutation of k items chosen out of m items (all distinct).

For this case, we assume that:

"Letters" are denoting uppercase and lowercase english alphabets (26 uppercase, and 26 lowercase, so total 52 such letters).

And digits are denoting (0,1,2,3,4,5,6,7,8,9) so total 10 such digits.

Thus, total 52+10 = 62 different choices to choose from.

Of these 62 options, we can use one letter only one time in a password.

Choosing any 4 characters out of those 62 characters is done in:

[tex]^{62}C_4 = \dfrac{62 \times 61 \times 60 \times 59 \times 58!}{4 \times 3 \times 2 \times 1 \times 58!} = 557845[/tex] ways.

Each of those 4 selections have distinct characters, and in a password, their arrangement matters, so each of  those 557845 choices can be permuted in 4! ways.

Thus, total number of distinct 4 digit password out of 52 english letters and 10 digits is [tex]4! \times 557845 = 24 \times 557845= 13388280[/tex] ways. (or we could've directly evaluated [tex]^{62}P_4[/tex]

Thus, the number of different four digit passwords that are possible if we use letters and digits only, and can't include repeating characters is 13,388,280 ways.

Learn more about combinations and permutations here:

https://brainly.com/question/13387529

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Answer:

c

Step-by-step explanation:

tye both have the same amount on each side

Answer:

c

Step-by-step explanation:

Answer:

Area: 1920 ft²

Perimeter: 176 ft

Step-by-step explanation:

Formula of Area of a Rectangle => A = width × length

Area = 40 × 48

= 1920 ft²

Formula of Perimeter of a Rectangle => P = 2 (width + length)

Perimeter = 2 ( 40 + 48)

= 2 (88)

= 176 ft

15*19=285

base times height is the formula

Answer:

the lions speed would be 24 mph

Answer:

200%

Step-by-step explanation:

Answer:

the best way to to do this would be to use a protractor, if you don't have one you would have to guess on the 15 degrees, but it would be a very small angle

Answer:

110.50 dollar

Step-by-step explanation:

As each game has 5 dollar discount, he bought 2 games, so 2*5 = 10 dollar discount, so the original one is 100.50 + 10 = 110.50 dollar.

If you find it is helpful plz give Brainliest

Answer:

150

Step-by-step explanation:

Answer:

Your answer is -5n=1.75

Answer:

9x2 - 8x2

Step-by-step explanation:

(7x^2 - 4x^2) + (2x^2 - 4x^2)

9x^2 - 8x^2

x^2

If y = -x + 2, then substituting this into the first equation lets you solve for x :

x + 4y = 5

x + 4 (-x + 2) = 5

x - 4x + 8 = 5

-3x = -3

x = 1

Now solve for y :

y = -x + 2 = -1 + 2 = 1

So the solution is indeed (x, y ) = (1, 1).

Answer:

[tex]Probability = \frac{1}{2}[/tex]

Step-by-step explanation:

Given

Cards: E, L, O, R, U, and W

Required

The theoretical probability of selecting a vowel

The total number of cards are: 6

The vowels are:

Vowels: E, O and U

The total vowels are: 3

The theoretical probability is:

[tex]Probability = \frac{Vowels}{Total}[/tex]

[tex]Probability = \frac{3}{6}[/tex]

[tex]Probability = \frac{1}{2}[/tex]

The theoretical probability for drawing a card that has a vowel on it is 1/2 or 50%.

Given that a teacher placed the letter cards E, L, O, R, U, and W in a bag, and a card is drawn at random, to determine the theoretical probability for drawing a card that has a vowel on it the following calculation has to be done:

Therefore, the theoretical probability for drawing a card that has a vowel on it is 1/2 or 50%.

Learn more about probability in https://brainly.com/question/21852517

Answer:

Step-by-step explanation:

Take 8.

None of the equations work for 8.

Next, take 1.

None of the equations work for 1 either.

Third, take 15.

None of the equations work for 15 either.

Lastly, take 46.

The equations fit perfectly.

Hope that helps!