PLEASE HELP ASAP‼️
A,12.5
B,11.75
C,18
D,13
FIRST ANSWER GETS BRAINLY
Answer:
Check pdf
Step-by-step explanation:
A triangle has sides of length 8 cm, 5 cm, and 5 cm. How many unique
triangles can be drawn that fit that description? Explain or show your
reasoning
1
Answer: I think it’s 2
Step-by-step explanation: because either of the sides are equal or the base and a side is not possible.
Aren’t you from CCA, Ryan Rivera, Maths 5th period.
Answer:
2
hope this helps
Pls help me calculate the inverse of y equals 2x over x-7
The recommended number of flowers to plant in a garden is probational to its area as shown in the table below. What is the recommended number of flowers for a garden of 24 square feet?
Answer:
The recommended number of flowers is 32
Step-by-step explanation:
Given
The attached graph
Required
The number of flowers when area = 15
First, calculate the slope (m)
Considering
[tex](x_1,y1) = (12,60)[/tex]
[tex](x_2,y_2) = (15,20)[/tex]
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]m = \frac{20-16}{15-12}[/tex]
[tex]m = \frac{4}{3}[/tex]
Considering:
[tex](x_1,y_1) = (15,20)[/tex]
[tex](x_2,y_2) = (24,y)[/tex]
The slope is:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]m = \frac{y - 20}{24 - 15}[/tex]
[tex]m = \frac{y - 20}{9}[/tex]
Recall that: [tex]m = \frac{4}{3}[/tex]
So:
[tex]\frac{4}{3} = \frac{y - 20}{9}[/tex]
Multiply through by 9
[tex]3*4 = y - 20[/tex]
[tex]y = 20 + 3 * 4[/tex]
[tex]y = 32[/tex]
Find the area of the figure.
Answer:
89
Step-by-step explanation:
So we need to find the area of the triangle. We already know that the individual two triangles height is 6 and so we need to find the width. The top is 13m and we know that 4m+4m is 8. 13-8 would be 5, and 5/2 (because there are two right triangles) is 2.5
After that, we can find 2.5 times 6 would be 15. We don't need to divide by two because we'll just have to multiply again because there are two triangles.
After that, we can find the area of the figure. 8 times 13 would be 104. 104-15 would be 89. That is the area of the figure, 89.
Miguel is a boxer. He had to decrease his weight by 4%
to 160 pounds in order to fight in this weight class.
What was his starting weight? Round his weight to the
nearest hundredth. Show your work.
Answer:
166.66 pounds
Step-by-step explanation:
160/0.96=166.66667
This is how I remember doing these questions
Determine which two values the following expression is between.
[tex]\sqrt[7]{37\\}[/tex]
Answer:
A. 42.57 and 42.58
42.579337.......
PLSSS hurry this is on my EXAM
A family installs and fills an aboveground pool. The swimming pool costs $850 to install, and it costs $75 per thousand gallons of water to fill.
Which function represents the total cost, C, of installing and filling a pool with 2 thousands of gallons of water?
Wouldnt that just be 75x2? bc if so then
The answer is:
75x2=150+ 850=1000
PLZZ HELP WILL GIVE BRAINLIEST
4 x 17355=
Answer:
69420
Step-by-step explanation:
What is the value of x?
Answer:
180 - 125
55
Hope this helps
A jet flies at a rate of 1.3 times 10 Superscript 6 feet per hour. Written in scientific notation, which is the best estimate of how many feet the jet will travel in 2.8 times 10 Superscript 3 hours?
Answer:
18 feet
Step-by-step explanation:
Answer:
3 x 10 ^18
Step-by-step explanation:
:P
HELP PLS Find the length of BC to the nearest tenth:
B
350
A
12
с
20.9
14.6
17.1
118
Answer:
14.6
Step-by-step explanation:
using the trigonometry ratio
cosine
cos35= 12/BC
BC= 12/cos35
BC = 14.64
I will give extra points pleasseeeee helpppp
Answer:
Step-by-step explanation:
7
At Brighton Middle School, Mr. Yule asked 50 randomly selected students from each grade level about their favorite subject, and 12 chose science. He used this data to draw the inference that about 25% of middle school students will indicate science is their favorite subject. If there are 200 students all together, did he make a reasonable inference?
No, Mr. Yule’s sample is biased and too small to be representative of the population.
Yes, Mr. Yule’s sample is small and biased, so it is representative of the population.
No, Mr. Yule’s percentage is too large. He should have used 6%.
Yes, Mr. Yule’s sample is random and representative of the population.
Answer:
D.) "Yes, Mr. Yule’s sample is random and representative of the population."
Step-by-step explanation:
Find the sum, if it exists, of the infinite geometric series related to the infinite geometric sequence described by An= 18(2)^n-1
Answer:
Step-by-step explanation:
Since r=2 and |r|>1 the sum does not converge to any value. The sum does not exist for this infinite geometric series.
The sum to infinity of the sequence is -18
Sum to infinity of a geometric sequenceThe formula for calculating the sum to infinity of a geometric sequence is expressed as:
Sinfty = a/1-r
where
a is the first term
r is the common ratio
From the nth term
a = 18
r = 2
Substitute
Sinfty = 18/1-2
Sinfty = -18
Hence the sum to infinity of the sequence is -18
Learn more on sum to infinity of a GP here: https://brainly.com/question/14570161
#SPJ5
Factor: -5a - 16 =
Answer?
Answer:
Do you need the answer or the factor??
Step-by-step explanation:
Answer: -(5a+16)
Step-by-step explanation:
Hey guys how do you find the perimeter of this shape in inches (explain)
Please helpppp
What is the distance between (1,7) and (9, 1)?
Answer: 10
Step-by-step explanation:
Hope this helps!
HELP PLEASE DUE IN 3 MINUTES
Answer:
Fossils: number one
Continental Shapes: number three
Seafloor Spreading: number two
A cheerleading team practices each week for 375 minutes. The team practiced for 26 weeks during the year. How many minutes did the team practice during the year?
Answer:
9750 min or 162.5 hours
Step-by-step explanation:
375 times 26 = 9750
Answer:
C) 24 cheerleaders
Step-by-step explanation:
20 last year
subtract 3 for those who decided not to join
20 -3 = 17
add 7 for those who joined
17 + 7 = 24
there are 24 cheer leaders
hope it help
Marc buys 4 candy bars and a pack of gum for $2.75. Dan buys 2 candy
bars and 3 packs of gum for $2.25. Part A. Write a system of equations for
this situation. Part B. What is the cost of each item?
how do i solve 21.772 divided by 4
Answer:
I don't know, but the answer is 5.443
Step-by-step explanation:
I need help on the bottom part of it
Answer:9800
Step-by-step explanation:
490 5
_____=______
x 100
490(100)=x(5)
49000=5x
__________
5 5
x=9800
Find the measure of angle ABC
Aanika performed a hypothesis test, and her p-value cutoff was 10%. What's the chance that her test will incorrectly reject the null hypothesis? In other words, what is the error probability?
A.) 90%
B.) 5%
C.) 10%
D.) Not enough information
Subtract the fractions. Write each difference in simplest form.
11/12 - 7/12 =
Answer:
1/3
Step-by-step explanation:
11 - 7 = 4
4/12 -> 1/3
really easy 5th grade math giving brainliest plz answer look a photo.
Answer:
I think it is 60
Step-by-step explanation:
because if you multiply 12 and 5 you get 60
Answer:
A.60
Step-by-step explanation:
12 multiplied by 5 will give you 60. since there are 12 in each layer and 5 layers in total this looks like you would multiply.
Please answer quick
Answer:
its the first option
Step-by-step explanation:
Assume that the car lot contains 20 percent Lincolns, 45 percent Porches, and 35 percent BMWs. Of the Lincol?
I still can't solve the problem. I did it step by step thoroughly but still get the wrong answer. Can someone help? thanks!
Assume that the car lot contains 20 percent Lincolns,
45 percent Porches, and 35 percent BMWs. Of the Lincolns,
70 percent have two airbags, 60 percent of the Porches have
two airbags, and 90 percent of the BMWs have two airbags. Furthermore,
70 percent of the Lincolns, 40 percent of the Porches, and
30 percent of the BMWs are white. The property of being white is
independent from having two airbags. You are assigned a car at random.
If the car has two airbags and is white, what is the probability that it is a Lincoln?
Answer:
0.3261 = 32.61% probability that it is a Lincoln
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Has two airbags and is white.
Event B: It is a Lincoln.
Probability of a car having two airbags and being white.
This is:
70%*70% of 20%(Lincolns).
60%*40% of 45%(Porches).
90%*30% of 35%(BMWs). So
[tex]P(A) = 0.7*0.7*0.2 + 0.6*0.4*0.45 + 0.9*0.3*0.35 = 0.3005[/tex]
Probability of a car having two airbags and being white, and being a Lincoln:
70%*70% of 20%(Lincolns).
So
[tex]P(A \cap B) = 0.7*0.7*0.2 = 0.098[/tex]
If the car has two airbags and is white, what is the probability that it is a Lincoln?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.098}{0.3005} = 0.3261[/tex]
0.3261 = 32.61% probability that it is a Lincoln
Assume a jar has five red marbles and three black marbles. Draw out two marbles with and without replacement. Find the requested probabilities. (Enter the probabilities as fractions.) (a) P(two red marbles) with replacement without replacement (b) P(two black marbles) with replacement without replacement (c) P(one red and one black marble) with replacement without replacement (d) P(red on the first draw and black on the second draw) with replacement without replacement
Answer:
For probabilities with replacement
[tex]P(2\ Red) = \frac{25}{64}[/tex]
[tex]P(2\ Black) = \frac{9}{64}[/tex]
[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{32}[/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{64}[/tex]
For probabilities without replacement
[tex]P(2\ Red) = \frac{5}{14}[/tex]
[tex]P(2\ Black) = \frac{3}{28}[/tex]
[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{28}[/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{56}[/tex]
Step-by-step explanation:
Given
[tex]Marbles = 8[/tex]
[tex]Red = 5[/tex]
[tex]Black = 3[/tex]
For probabilities with replacement
(a) P(2 Red)
This is calculated as:
[tex]P(2\ Red) = P(Red)\ and\ P(Red)[/tex]
[tex]P(2\ Red) = P(Red)\ *\ P(Red)[/tex]
So, we have:
[tex]P(2\ Red) = \frac{n(Red)}{Total} \ *\ \frac{n(Red)}{Total}\\[/tex]
[tex]P(2\ Red) = \frac{5}{8} * \frac{5}{8}[/tex]
[tex]P(2\ Red) = \frac{25}{64}[/tex]
(b) P(2 Black)
This is calculated as:
[tex]P(2\ Black) = P(Black)\ and\ P(Black)[/tex]
[tex]P(2\ Black) = P(Black)\ *\ P(Black)[/tex]
So, we have:
[tex]P(2\ Black) = \frac{n(Black)}{Total}\ *\ \frac{n(Black)}{Total}[/tex]
[tex]P(2\ Black) = \frac{3}{8}\ *\ \frac{3}{8}[/tex]
[tex]P(2\ Black) = \frac{9}{64}[/tex]
(c) P(1 Red and 1 Black)
This is calculated as:
[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ and\ P(Black)]\ or\ [P(Black)\ and\ P(Red)][/tex]
[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ *\ P(Black)]\ +\ [P(Black)\ *\ P(Red)][/tex]
[tex]P(1\ Red\ and\ 1\ Black) = 2[P(Red)\ *\ P(Black)][/tex]
So, we have:
[tex]P(1\ Red\ and\ 1\ Black) = 2*[\frac{5}{8} *\frac{3}{8}][/tex]
[tex]P(1\ Red\ and\ 1\ Black) = 2*\frac{15}{64}[/tex]
[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{32}[/tex]
(d) P(1st Red and 2nd Black)
This is calculated as:
[tex]P(1st\ Red\ and\ 2nd\ Black) = [P(Red)\ and\ P(Black)][/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = P(Red)\ *\ P(Black)[/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{n(Red)}{Total} *\ \frac{n(Black)}{Total}[/tex]
So, we have:
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{5}{8} *\frac{3}{8}[/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{64}[/tex]
For probabilities without replacement
(a) P(2 Red)
This is calculated as:
[tex]P(2\ Red) = P(Red)\ and\ P(Red)[/tex]
[tex]P(2\ Red) = P(Red)\ *\ P(Red)[/tex]
So, we have:
[tex]P(2\ Red) = \frac{n(Red)}{Total} \ *\ \frac{n(Red)-1}{Total-1}[/tex]
We subtracted 1 because the number of red balls (and the total) decreased by 1 after the first red ball is picked.
[tex]P(2\ Red) = \frac{5}{8} * \frac{4}{7}[/tex]
[tex]P(2\ Red) = \frac{5}{2} * \frac{1}{7}[/tex]
[tex]P(2\ Red) = \frac{5}{14}[/tex]
(b) P(2 Black)
This is calculated as:
[tex]P(2\ Black) = P(Black)\ and\ P(Black)[/tex]
[tex]P(2\ Black) = P(Black)\ *\ P(Black)[/tex]
So, we have:
[tex]P(2\ Black) = \frac{n(Black)}{Total}\ *\ \frac{n(Black)-1}{Total-1}[/tex]
We subtracted 1 because the number of black balls (and the total) decreased by 1 after the first black ball is picked.
[tex]P(2\ Black) = \frac{3}{8}\ *\ \frac{2}{7}[/tex]
[tex]P(2\ Black) = \frac{3}{4}\ *\ \frac{1}{7}[/tex]
[tex]P(2\ Black) = \frac{3}{28}[/tex]
(c) P(1 Red and 1 Black)
This is calculated as:
[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ and\ P(Black)]\ or\ [P(Black)\ and\ P(Red)][/tex]
[tex]P(1\ Red\ and\ 1\ Black) = [P(Red)\ *\ P(Black)]\ +\ [P(Black)\ *\ P(Red)][/tex]
[tex]P(1\ Red\ and\ 1\ Black) = [\frac{n(Red)}{Total}\ *\ \frac{n(Black)}{Total-1}]\ +\ [\frac{n(Black)}{Total}\ *\ \frac{n(Red)}{Total-1}][/tex]
So, we have:
[tex]P(1\ Red\ and\ 1\ Black) = [\frac{5}{8} *\frac{3}{7}] + [\frac{3}{8} *\frac{5}{7}][/tex]
[tex]P(1\ Red\ and\ 1\ Black) = [\frac{15}{56} ] + [\frac{15}{56}][/tex]
[tex]P(1\ Red\ and\ 1\ Black) = \frac{30}{56}[/tex]
[tex]P(1\ Red\ and\ 1\ Black) = \frac{15}{28}[/tex]
(d) P(1st Red and 2nd Black)
This is calculated as:
[tex]P(1st\ Red\ and\ 2nd\ Black) = [P(Red)\ and\ P(Black)][/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = P(Red)\ *\ P(Black)[/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{n(Red)}{Total} *\ \frac{n(Black)}{Total-1}[/tex]
So, we have:
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{5}{8} *\frac{3}{7}[/tex]
[tex]P(1st\ Red\ and\ 2nd\ Black) = \frac{15}{56}[/tex]