The augmented matrix for the linear system corresponding to the matrix equation Ax = b is |1 2 4 0| |-2 2 9| |0 1 4 1| |2 -1| |-2 -4 -3 -1| |9 -1|. Solving the system yields the solution vector (x, y, z) = (5, -1, 4).
The augmented matrix for the linear system Ax = b is a way of combining the two matrices into one matrix. In this case, it is the combination of the coefficient matrix A and the constant matrix b. This new matrix contains all of the information needed to solve the linear system, as it contains both the coefficients of the variables and the solutions of the equations. We can solve the linear system by performing row operations to the augmented matrix, which is equivalent to solving the equations in the original matrix equation. After performing the row operations, we will be left with the solution vector (x, y, z) = (5, -1, 4). This solution vector represents the values of the variables that satisfy the original equation.
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Emma is buying a gift for her mother's birthday. She purchases flowers and a gift certificate that cost a total of $68, not including tax. If the cost of the gift certificate is $14 more than 2 times the cost of the flowers, what is the cost of the flowers? Set up a system of equations, then solve using a matrix.
The cost of the flowers she bought for her mum alone would be = $18
How to calculate the cost of flowers?The items purchased by Emma = flowers and a gift certificate.
The total cost of the flowers and a gift certificate = $68
But, cost of gift certificate= $14 +2x
cost of flower = X
That is 14 + 2x + X = 68
2x + X = 68 - 14
3X = 54
X = 54/3
X= $18
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#8 i need help with this problems.
ΔABD and ΔBCD are congruent by AAS congruence theorem.
The proof is given below.
What is a triangle?It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.
We have,
From the figure below,
ΔABD and ΔBCD are congruent.
∠BCD = ∠BAD [ 90 degrees ]
∠CDB = ∠ABD [ alternate angles ]
BD = BD [ Common ]
ΔABD ≈ ΔBCD [ AAS ]
Thus,
ΔABD and ΔBCD are congruent by AAS congruence theorem.
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The label on a car's antifreeze container claims to protect the car at temperatures greater than −40°C and less than 140°C. To convert Celsius temperature to Fahrenheit temperature, the formula is C equals five ninths times the quantity F minus thirty two.. Write a compound inequality to determine the Fahrenheit temperature range at which the antifreeze protects the car
Answer:
-40F to 284F
Step-by-step explanation:
C = 5/9F -32
so F = 32+9/5*C
so the range is
F= 32+9/5*(-40) = 32-72 = -40F
F= 32+9/5*(140) = 32+252 = 284F
Paul and $10 for mowing 2 lawns. What is the rate she earned per per lawn mowed  
Answer:
5$ Per Lawn
Step-by-step explanation:
10$/2=5$
2/2=1
MARK ME BRAINLISIST
Answer: the rate she is earning is 5$ per lawn mowed
Step-by-step explanation:
if she earns 10$ after mowing 2 lawns then if you divide 10 and 2 you get 5
Please make me brainllest
Read the following prompt and type your response in the space provided.
Explain how to model the division of –24 by –4 on a number line.
To model the division of -24 by -4 on a number line, we can start at -24 and move to the left by -4 units at a time, counting the number of times we move until we reach 0.
How to explain the number line?A number line is a diagram of a graduated straight line used to represent real numbers in elementary mathematics. It is assumed that each real number and each point on a number line correspond to one another.
Since -24 divided by -4 is 6, we would move to the left 6 times and end at 0 on the number line. The negative signs of the dividend and divisor indicate that the quotient will be a negative number.
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Select all of the following equation(s) that are quadratic in form. x4 – 6x2 – 27 = 0 3x4 = 2x 2(x + 5)4 + 2x2 + 5 = 0 6(2x + 4)2 = (2x + 4) + 2 6x4 = -x2 + 5 8x4 + 2x2 – 4x = 0
An equation 6(2x+4)²=(2x+4)+2 has degree 2, so it is quadratic equation. Therefore, option D is the correct answer.
What is a quadratic function in standard form?The standard form of a quadratic equation is given as:
ax² + bx + c = 0 where a, b, c are real numbers and a ≠ 0.
Quadratics are the polynomial equation which has highest degree of 2.
A) x⁴-6x²-27=0
Here, the highest degree is 4 so, it is biquadratic equation.
B) 3x⁴=2x
3x³=2
Here, the highest degree is 3 so, it is cubic equation.
C) 2(x + 5)⁴+2x²+5=0
Here, the highest degree is 4 so, it is biquadratic equation.
D) 6(2x+4)²=(2x+4)+2
6(4x²+16x+16)=(2x+4)+2
24x²+96x+96=2x+4+2
24x²+94x+90=0
Here, the highest degree is 2 so, it is quadratic equation.
E) 6x⁴= -x²+5
6x⁴+x²+5=0
Here, the highest degree is 4 so, it is biquadratic equation.
F) 8x⁴+2x²-4x=0
Here, the highest degree is 4 so, it is biquadratic equation.
Therefore, option D is the correct answer.
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"Your question is incomplete, probably the complete question/missing part is:"
Select all of the following equation(s) that are quadratic in form.
a) x⁴-6x²-27=0
b) 3x⁴=2x
c) 2(x + 5)⁴+2x²+5=0
d) 6(2x+4)²=(2x+4)+2
e) 6x⁴= -x²+5
f) 8x⁴+2x²-4x=0
Which of the values make 4x<45 true?
A 12
B. 11
C. 13.5
D. 16
Answer: B - 11
Step-by-step explanation: Hello! How you can do this is by substituting A, B, C, and D for x.
D:
4(16)<45
64<45
64 is not less than 45, so this is false. D is not the answer.
C:
4(13.5)<45
54<45
54 is not less than 45, so this is false. C is not the answer.
A:
4(12)<45
48<45
48 is not less than 45, so this is false. A is not the answer.
B:
4(11)<45
44<45
44 is less than 45 so this is true.
The answer is B - 11.
In the pattern below, the cat moves clockwise through the four squares, and the mouse moves counterclockwise through the eight exterior segments of the four squares.
If the pattern is continued, where would the cat and mouse be after the 247th move?
Only setup A places the mouse on the bottom right square and the cat there.
The pattern is continued, so we have to define where the cat and mouse would be after the 247th move.
Divide the issue into two parts: the location of the mouse and the location of the cat after the 247th move.
Every cycle, which consists of four different positions for the cat, is repeated once every four movements. When 247 is divided by 4, the remainder is 3. This matches the bottom right corner, where the cat is located after the third move.
Similar to the mouse, which repeats every eight moves, the mouse has eight possible places in a single cycle. When 247 is divided by 8, the remainder is 7. This matches the rat's bottom left corner position after the seventh motion.
The only configuration with the cat in the bottom right square and the mouse in that position is A.
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The complete question is given below:
13.) 5x − 2 – (8x − 1) =
14.) 1-(2-x) =
15.) 2x + 1 + (x + 3) =
16.) -1(3 + 2x) =
An equation is said to be linear if each term has a maximum of one degree.The system of linear equations is solved by (2,6).
What is a linear equation?An equation is said to be linear if each term has a maximum of one degree.
It is possible to formulate linear equations in the form y=mx+c.
A straight line results from a linear equation with two variables when its axes are plotted on the cartesian plane.
When the second equation for x is solved,
x + 5y = 32
x = 32 - 5y
Add the value of x to the first equation now,
2(32 - 5y) + 5y = 34
64 - 10y + 5y = 34
-5y = -30
y = 6
the value of y should be replaced in any one of the equations,
x + 5y = 32
x + 5(6) = 32
x = 2
Consequently, the system of linear equations' solution is (2,6).
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Graph the line y=−54x−3.
Use the line tool and select two points on the line.
The two points on the line y = − 54x − 3 will be (1, −57) and (−1, 51).
What is the solution to the equation?The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
y = − 56x − 4
Let x = 1, the value of y will be
y = − 54 (1) − 3
y = − 54 − 3
y = − 57
Let x = − 1, the value of y will be
y = − 54(−1) − 3
y = 54 − 3
y = 51
The two points on the line y = − 56x − 4 will be (1, −57) and (−1, 51). Then the diagram of the line is given below.
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billy makes $20 a week in allowance plus $5 for each lawn that he mows. this week billy wants to make over $50. select the inequality for the number of lawns he needs to mow.
The inequality for the number of lawns he needs to mow is: $50 < $20 + $5n
The correct answer is an option (b)
Let n represents the number of lawns he needs to mow.
Here, Billy needs to make more than $50 between his allowance and the lawns that he mows. This means that an inequality should include 50 <
As Billy will make $5 for each lawn that he mows, for 'n' number of lawns the cost would be = 5n
Based on the mentioned conditions we formulate an inequality,
50 < 20 + 5n
20 + 5n > 50
20 + 5n - 20 > 50 - 20 ...........(subtract 20 from each side)
5n/5 > 30/5 .............(divide each side by 5)
n > 6
This means, he needs to mow more that 6 lawns.
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The complete question is:
Billy makes $20 a week in allowance plus $5 for each lawn that he mows. this week billy wants to make over $50. select the inequality for the number of lawns he needs to mow.
a) $50 < $20+$5
b) $50 > $20+$5n
c) $50 < $20n+$5
d) $50 > $20n+$5
e) $50 < $20+$5n
Quinn deposit $3000 into a savings account her freshman year of college. She will earn simple interest on the account at 2.56%. If she makes no contributions or withdrawals, what will the accrued value of the account be when she graduates four years later 
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3000\\ r=rate\to 2.56\%\to \frac{2.56}{100}\dotfill &0.0256\\ t=years\dotfill &4 \end{cases} \\\\\\ A = 3000[1+(0.0256)(4)] \implies A=3000(1.1024)\implies A = 3307.2[/tex]
How do u solve: 4x-(9-3x)=8x-1
Answer:
x=-8
Brief explanation:
Well I simplify first
4x-(9-3x)=8x-1
4x-9+3x=8x-1
then you do this operation called collecting similar terms
4x+3x-9=8x-1
7x-9=8x-1
7x-8x=-1+9
7x-8x=8
-x=8
x=-8 should be ur solution--
Answer:
[tex] \sf \: x = - 8[/tex]
Step-by-step explanation:
Given equation,
→ 4x - (9 - 3x) = 8x - 1
Now the value of x will be,
→ 4x - (9 - 3x) = 8x - 1
→ 4x - 9 + 3x = 8x - 1
→ (4x + 3x) - 9 = 8x - 1
→ 7x - 9 = 8x - 1
→ 7x - 8x = -1 + 9
→ -x = 8
→ [ x = -8 ]
Hence, the value of x is -8.
The floor of a rectangular room is to be covered with tiles 1-foot sides. The floor of the room is 18 feet long and 12 feet wide. How much would it cost at $4 a tile?
The cost for the flooring of the rectangular room is $864.
What is Multiplication?Multiplication of two numbers is defined as the addition of one of the number repeatedly until the times of the other number.
a × b means that a is added to itself b times or b is added to itself a times.
Given that,
Dimension of each time = 1 foot
Length of the room = 18 feet
Width of the room = 12 feet
Number of tiles needed for the room = 18 × 12 = 216
Cost of one tile = $4
Total cost for the tile = 216 × $4 = $864
Hence the total cost for the tiles is $864.
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If each of these runners travels the indicated number of spaces in the same amount of time, at which numbered spot will all of the runners be next to one another?
The numbered spot at which all the runners will be next to one another is spot 19.
What is the LCM?Least Common Multiple is the meaning of the acronym LCM. The lowest number that may be divided by both numbers is known as the least common multiple (LCM) of two numbers. It may also be computed using two or more real numbers.
Starting with the runner on the outside track, the provided parameters are;
The runner covered n₁ = 5 places on the outside track, which is the number of spaces.
Next, the inner runner will traverse n₂ spaces, which equals one space.
The following inner runner will cover n₃ = 3 spaces.
The subsequent runner will traverse n₄ = 2 spaces.
The Lowest Common Multiple, or LCM, of all the runners' speeds or the total number of spaces they cover in the same amount of time, determines where all the runners will be placed next to one another.
LCM(5, 1, 3, 2) = 30 is the LCM of 5, 1, 3, and 2.
Time = 30/ = 6
Consequently, when the first runner has covered 30 places, we have;
Six time units have been expended.
The runner comes to a stop at position 30- (30 -19) = Position 19.
First runner's new destination is Spot 19.
The distance covered simultaneously by runner 2 is 6 x 1 = 6.
The distance covered by two runners running simultaneously equals six spaces.
Second runner's new position: 6 spaces plus spot 13 equals spot 19.
The combined distance covered by the three runners is 6 x 3 = 18.
The distance runner 3 covers 18 spaces simultaneously.
Third runner's new position: 18 spaces + Spot 1 = 19 spaces
Runner 4 covers a distance of 6 x 2 = 12 at the same time.
Distance runner 4 journeys equals 12 spaces
Runner 4's new position is now 12 spaces Plus Spot 7 = Spot 19.
Therefore, all the runners will be next to one another is spot 19.
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Given the midsegment below:
41°
14
Z
z=[?]
62⁰
y
Enter
Simplify. Need ASAP. show work
The solutions to the simplification of the following surds are:[tex]-12\sqrt[3]{3}+4\sqrt[3]{2}[/tex] and [tex]-5x^2 y^2\sqrt[3]{3x^2y^2}[/tex]
Simplification of surd forms:A number without a root is simply referred to as a surd. These surds illustration comprises fractions as powers if presented in exponential form. There are three main forms of surds, according to the definition of surds.
Pure surds, which are surds that include just one irrational number. Surd that comprises both rational and irrational numbers is called Mixed surds. Compound surds are two surds combined into one.The simplification of the given surds is carried out as follows:
[tex]-2\sqrt[3]{81} +2\sqrt[3]{16}-2\sqrt[3]{81}[/tex]
Factor 27 out of 81
[tex]-2\sqrt[3]{27*3} +2\sqrt[3]{16}-2\sqrt[3]{27*3}[/tex]
Rewrite it as 3³*3
[tex]-2\sqrt[3]{3^3*3} +2\sqrt[3]{16}-2\sqrt[3]{3^3*3}[/tex]
Rearrange and simplify
[tex]-2\sqrt[3]{3^3*3} -2\sqrt[3]{3^3*3}+2\sqrt[3]{16}[/tex]
Pull term out from the radical
[tex]-2*3\sqrt[3]{3} -2*3\sqrt[3]{3}+2\sqrt[3]{16}[/tex]
[tex]-6\sqrt[3]{3} -6\sqrt[3]{3}+2\sqrt[3]{16}[/tex]
Rewrite 16 as 2³*2
[tex]-6\sqrt[3]{3} -6\sqrt[3]{3}+2\sqrt[3]{2^3*2}[/tex]
Pull term out of the radical
[tex]-6\sqrt[3]{3} -6\sqrt[3]{3}+2*2\sqrt[3]{2}[/tex]
[tex]-6\sqrt[3]{3} -6\sqrt[3]{3}+4\sqrt[3]{2}[/tex]
Simplify altogether;
[tex]-12\sqrt[3]{3}+4\sqrt[3]{2}[/tex]
In [tex]\sqrt[3]{-375x^8y^8}[/tex]; simplify the radical by breaking the radicand up into a product of known factors, assuming real numbers.
[tex]\sqrt[3]{(-5) ^3(x^2)^3 (y^2)^3*3x^2y^2}[/tex]
[tex]\sqrt[3]{(-5x^2y^2) ^3*3(x^2y^2)}[/tex]
[tex]-5x^2 y^2\sqrt[3]{3x^2y^2}[/tex]
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Find the length of the midsegment of the trapezoid with the vertices S(-2,4) ,T(-2,-4) ,U(3,-2) ,V(13,10)
11.69 is the exact length needed for the mid-segment of the trapezoid with STUV vertices.
What is trapezoid?The Greek roots of the term trapezoid are trapeza, which means "table," and -oeides, which means "formed." A trapezoid is shaped like a table. It has two parallel sides, which are often referred to as the figure's bases. Take the average of the bases and multiply it by the height to determine the area of a trapezoid.
According to question:We have,
vertices S(-2,4) ,T(-2,-4) ,U(3,-2) ,V(13,10).
Half of the lengths of the two parallel sides, ST and UV, make up the length of the trapezoid's middle section.
The trapezoid's vertices are S(2, 4), T(2, 4), U(3, 2), and V. (13, 10).
The distance formula is then used to calculate the length of the ST and UV sides;
Length = [tex]\sqrt{x_{2}-x_{1}+y_{2}-y_{1}}[/tex]
Side ST's length is S(-2, 4), T(-2, -4).
ST = [tex]\sqrt{x_{2}-x_{1}+y_{2}-y_{1}}[/tex]
ST = [tex]\sqrt{(-2-(-2))^2+(-4-(4))^2[/tex]
ST = [tex]\sqrt{0 + 64}[/tex]
ST √64
ST = 8
Side UV's length is U(3, 2), V. (13, 10).
UV = [tex]\sqrt{(13-3)^2+(10-(-2))^2[/tex]
UV = [tex]\sqrt{(10)^2+(12)^2[/tex]
UV = √244
UV = 15.62
Therefore,
The mid-segment STUV's length is,
Length of mid-segment = (ST + UV)/2
Length of mid-segment = (8 + 15.62)/2
Length of mid-segment = (23.62)/2
Length of mid-segment = 11.81
Therefore, 11.69 is the exact length needed for the mid-segment of the trapezoid with STUV vertices.
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4. Juan cotiza un motor generador de ondas estacionarias para cuerdas en 50 almacenes
eléctricos. Obteniendo los siguientes datos:
300 mil pesos en un almacén y esta con el 10% de descuento; en el almacén dos, costaba 400
mil pesos con un 14% de descuento; en el almacén 3, tenía un costo de 500 mil pero le bajaban
el 20%, en el cuarto almacén, valía 700 mil pesos pero rebajan el 22%; en el almacén 5, costaba
750 mil pesos con un 12% de descuento; en el almacén 6, tenía un precio de 800 mil y le
bajaban el 10%; en el séptimo almacén, tiene un precio de 1000 y le hacen el descuento del 6%;
en almacén 8, cuesta 1200 y bajan el 4%; en el último almacén cobran 1500 y hacen el 2% de
rebaja.
De acuerdo con lo anterior, la respuesta correcta serían 270,000 es el precio más bajo que obtuvo para comprar un motor generador de ondas estacionarias para cuerdas en el primer almacén.
¿Cómo calcular cuál almacén le ofrece el precio más bajo a Juan?
Para calcular cuál es el almacén que le ofrece el precio más bajo a Juan debemos identificar a cuanto equivale el descuento y restarlo del precio total. Cuando sepamos el precio final comparamos para saber cuál de todos es el menor.
300,000 / 100 = 3,000
3,000 * 10 = 30,000
300,000 - 30,000 = 270,000
400,000 / 100 = 4,000
4,000 * 14 = 56,000
400,000 - 56,000 = 344,000
500,000 / 100 = 5,000
5,000 * 20 = 100,000
500,000 - 100,000 = 400,000
700,000 / 100 = 7,000
7,000 * 22 = 154,000
700,000 - 154,000 = 546,000
750,000 / 100 = 7,500
7,500 * 12 = 90,000
750,000 - 90,000 = 660,000
800,000 / 100 = 8,000
8,000 * 10 = 80,000
800,000 - 80,000 = 720,000
1'000.0000 / 100 = 10,000
10,000 * 6 = 60,000
1'000.000 - 60,000 = 940,000
1'200.000 / 100 = 12,000
12,000 * 4 = 48,000
1'200,000 - 48,000 = 1'152.000
1'500.000 / 100 = 15,000
15,000 * 2 = 30,000
1'500,000 - 30,000 = 1'270,000
De acuerdo a lo anterior, el precio más bajo para comprar un motor generador de ondas estacionarias para cuerdas es 270,000 en el primer almacén.
Nota: Esta pregunta está incompleta y tiene errores en los valores. A continuación esta la información completa y correcta.
Pregunta
¿Cuál tienda le ofrece el precio más bajo a Juan?
Precios
Almacén 1: 300 mil pesos con el 10% de descuento.
Almacén 2: 400 mil pesos con el 14% de descuento.
Almacén 3: 500 mil pero con el 20% de descuento.
Almacén 4: 700 mil pesos con el 22% de descuento.
Almacén 5: 750 mil pesos con el 12% de descuento.
Almacén 6: 800 mil pesos con el 10% de descuento.
Almacén 7: 1'000.000 de pesos con el 6% de descuento.
Almacén 8: 1'200.000 de pesos con el 4% de descuento.
Almacén 9: 1'500.000 de pesos con el 2% de descuento.
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8. Stick A is 120 cm shorter than stick B. Stick C is 84 cm shorter than stick B. Sticks A, B, and C have a total length of 360 cm. What is the total length (in meters and centimeters) of sticks A and C?
The total length of A+C will be 172 cm(unit).
What is a unit?
Units are the tools to measure and compare different things. Comparison becomes easy when all the units for the measurement are the same. Different units can be classified depending on their use. A few of the units can be classified as:
The seven SI base units (The International System of Units (SI), commonly known as the metric system, is the international standard for measurement) which are comprised of:
Length - meter (m)
Time - second (s)
Amount of substance - mole (mole)
Electric current - ampere (A)
Temperature - kelvin (K)
Luminous intensity - candela (cd)
Mass - kilogram (kg)
Now,
Given B-A=120 -->1
B-C=84 -->2
A+B+C=360 -->3
Therefore, from equations 1,2 and 3
B-120+B+B-84=360
B=188
By putting B=188 in 1 and 2
A=68
C=104
A+C=172cm
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The store owner put 10 Tshirts on clearance. The Tshirts were originally priced at $22.00 each. The owner marked down the price of the Tshirts by 40%.
How much money did the store owner receive for selling all 10 Tshirts?
Answer:
$132
Step-by-step explanation:
Looks like $22.00 was the price at 100%
The owner marks the price down by 40%, making the total price 60% of $22 because 100%-40% is 60%
We can set up a ratio
60%. X
-------. =. ------
100%. $22
Cross multiplying makes it (100)(x) = (60)(22)
100x = 1,320
Dividing both by 100 to get X alone
x = 13.2
Each shirt is now $13.20
Last, but not least, we multiply by 10 because he sold 10 shirts
= $132
A file that is 237 megabytes is being downloaded. If the download is 17.6% complete, how many megabytes have been downloaded?
Answer:
Step-by-step explanation:
The answer is 42 MB.If it's round to nearest tenth than it's 40 MB
Help me ASAP math question.
The client should invest $8889 in AAA bonds, $4444 in A bonds, and $5667 in B bonds.
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
Example: 2x + 4 = 8 is an equation.
We have,
Amount invested in AAA bond = 2x
Amount invested in A bond = y
Amount invested in B bond = x
Now,
Average yield:
AAA bond = 4%
A bond = 5%
B bond = 8%
Now,
Total amount = $19,000
Total yield = $990
Now,
Two equations can be made:
2x + y + x = 19000
3x + y = 19000 _____(1)
0.04 x (2x) + 0.05 x y + 0.08x = 990
0.08x + 0.05y + 0.08x = 990
0.16x + 0.05y = 990 ______(2)
From (1) and (2),
3x = 19000 - y
x = (19000 - y)/3
Substituting in (2)
0.16 x (19000 - y)/3 + 0.05y = 990
0.053 x 19000 - 0.053y + 0.05y = 990
1007 - 0.003y = 990
1007 - 990 = 0.003y
y = 17/0.003
y = 5666.6
y = 5667
Now,
x = (19000 - y)/3
x = (19000 - 5667)/3
x = 4444.333
x = 4444
Now,
x = $4444
y = $5667
2x = $8889
Thus,
Amount invested in AAA bond = $8889
Amount invested in A bond = $5667
Amount invested in B bond = $4444
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24(20) this is my question please answer
Answer:
480
Step-by-step explanation:
Lets break this down to make it even easier
(24x2)x10
=(48)x10
=480
Answer:
If you are looking for the simplest form of 24/20 it is basically 6/5.
because if you multiply 6/5 by 4/4 you could get the answer which is 24/20.
and the same thing if you divide
I hope that I helped
g components of force f with respect to x and y axes can be calculated as follow. please note that x and y axes are not perpendicular to each others. the angle between f and x is denote as (theta). the angle between f and y is denote as (gamma).
The force with respect to the x and y axes can be calculated as follows:
F_x = 100N cos(30) = 86.6N
F_y = 100N sin(60) = 50N
Let F be the magnitude of the force, (theta) be the angle between the force and the x-axis, and (gamma) be the angle between the force and the y-axis. The components of the force with respect to the x and y axes can be calculated using the following formulas:
F_x = F cos(theta)
F_y = F sin(gamma)
For example, if the magnitude of the force is 100N and (theta) = 30 degrees and (gamma) = 60 degrees, then the components of the force with respect to the x and y axes can be calculated as follows:
F_x = 100N cos(30) = 86.6N
F_y = 100N sin(60) = 50N
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the base company has assets other than investment securities, that cost $50,000. The current market value of the assets is $75 million. The assets will be recorded and reported as assets at
As the company asset other than investment securities cost $50,000 and market value of the assets is $75 million. The assets will be recorded and reported as at $75,050,000.
How are asset recorded and reported?An asset is a resource with monetary value that an individual, corporation, or country owns or controls with the expectation of future benefit. An asset is anything that can generate cash flow, reduce expenses, or increase sales in the future, whether it's manufacturing equipment or a patent.
A company's assets are reported on its balance sheet. They are divided into four categories: current, fixed, financial, and intangible. They are purchased or created in order to increase the value of a company or to benefit its operations.
The reported asset of the company will be:
= $50,000 + $75 million
= $75,050,000
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When using the multiplication method, it is important to multiply all the terms on both sides of the equation—not just the one term you are trying to eliminate
As per the elimination method, in order to solve a system of equations when multiplication is necessary to eliminate a variable.
The term equation is known as algebra is a statement of equality that contains one or more unknown quantities or variables.
Here we have given that When using the multiplication method, it is important to multiply all the terms on both sides of the equation, then here we do not just the one term you are trying to eliminate.
According to the rule of elimination method we all know while solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation.
So in order to multiplying to solve linear systems is to find a number to multiply to one or both of the equations so that the x or y terms in one of the equations will have opposite coefficients from the x or y in the other equation.
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NO LINKS!!!
Find the solution set for each inequality.
Answer:
41. (-∞, -1] ∪ [2, 3)
42. (2, 5) ∪ (5, ∞)
Step-by-step explanation:
Question 41Given rational inequality:
[tex]\dfrac{x^2-x-2}{x-3} \leq 0[/tex]
Factor the numerator:
[tex]\dfrac{(x-2)(x+1)}{x-3} \leq 0[/tex]
Find the roots by solving f(x) = 0 (set the numerator to zero):
[tex]\implies (x-2)(x+1)=0[/tex]
[tex]\implies x-2=0 \implies x=2[/tex]
[tex]\implies x+1=0 \implies x=-1[/tex]
Find the restrictions by solving f(x) = undefined (set the denominator to zero):
[tex]\implies x-3=0 \implies x=3[/tex]
Create a sign chart, using closed dots for the roots and open dots for the restrictions (see attachment 1).
Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.
Test values: -2, 0, 2.5, 4For each test value, determine if the function is positive or negative:
[tex]f(-2)=\dfrac{(-2)^2-(-2)-2}{(-2)-3} =\dfrac{+}{-}=-[/tex]
[tex]f(0)=\dfrac{(0)^2-(0)-2}{(0)-3} =\dfrac{-}{-}=+[/tex]
[tex]f(2.5)=\dfrac{(2.5)^2-(2.5)-2}{(2.5)-3} =\dfrac{+}{-}=-[/tex]
[tex]f(4)=\dfrac{(4)^2-(4)-2}{(4)-3} =\dfrac{+}{+}=+[/tex]
Record the results on the sign chart for each region (see attachment 1).
As we need to find the values for which f(x) ≤ 0, shade the appropriate regions (zero or negative) on the sign chart (see attached).
Therefore, the solution set is:
x ≤ -1 or 2 ≤ x < 3As interval notation:
(-∞, -1] ∪ [2, 3)Question 42Given rational inequality:
[tex]\dfrac{\sqrt{x}}{(x-2)|x-5|} > 0[/tex]
Find the roots by solving f(x) = 0 (set the numerator to zero):
[tex]\implies \sqrt{x}=0 \implies x=0[/tex]
Find the restrictions by solving f(x) = undefined (set the denominator to zero):
[tex]\implies (x-2)|x-5|=0[/tex]
[tex]\implies x-2=0 \implies x=2[/tex]
[tex]\implies |x-5|=0 \implies x=5[/tex]
Create a sign chart, using closed dots for the roots and open dots for the restrictions (see attachment 1).
Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.
Test values: -1, 1, 3, 6For each test value, determine if the function is positive or negative:
[tex]f(-1)=\dfrac{\sqrt{-1}}{(-1-2)|-1-5|}=\dfrac{\sf unde\:\!fined}{-}=\sf unde\:\!fined[/tex]
[tex]f(1)=\dfrac{\sqrt{1}}{(1-2)|1-5|}=\dfrac{+}{-}=-[/tex]
[tex]f(3)=\dfrac{\sqrt{3}}{(3-2)|3-5|}=\dfrac{+}{+}=+[/tex]
[tex]f(6)=\dfrac{\sqrt{6}}{(6-2)|6-5|}=\dfrac{+}{+}=+[/tex]
Record the results on the sign chart for each region (see attachment 2).
As we need to find the values for which f(x) > 0, shade the appropriate regions (positive) on the sign chart (see attached).
Therefore, the solution set is:
2 < x < 5 or x > 5As interval notation:
(2, 5) ∪ (5, ∞)pls help me with this 4(x−2+y)
Answer: 4x + 4y - 8
Step-by-step explanation:
4(x−2+y)
4x -8 +4y
4x + 4y - 8
Complete the calculation in step 3 and drag the appropriate solute amounts to the ECF and ICF columns. Drag the appropriate labels to their respective targets.
The types of solutes and their distribution between the ICF and ECF are not the same for the appropriate solute amounts to the ECF and ICF columns.
Intracellular fluids are fluids found inside the cell's cytoplasm while extracellular fluid are fluids the flow outside the cells which consist of plasma, interstitial and trancellular fluid
The types of solutes and their distribution between the ICF and ECF are not the same because intracellular fluid of the cystosol is composed of water, dissolved ions, small molecules, and large, water-soluble molecules while extracellular fluid consist of plasma, interstitial fluid and cytosol have high potassium concentration and low sodium Concentration.
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