Answer:
325/78 = 4 13/78 miles per hour
Step-by-step explanation:
Total distance for Gilda to travel = 650 miles
Speed used for the journey= 50 miles per hour
Time taken = distance/speed
Time taken = 650/50
Time taken = 13 hours
Then how many miles per hour in essence what will be her speed in other for the journey to last less than one hour of her journey , that is 13 -1 = 12 hours
Speed = distance/time
Speed= 650/12
Speed= 54.1667 miles per hour
She would have gone
=650/12 -650/13
=(8450-7800)/156
=650/156
= 325/78
= 4 13/78
Eye Color Each of two parents has the genotype brown>blue, which consists of the pair of alleles that determine eye color, and each parent contributes one of those alleles to a child. Assume that if the child has at least one brown allele, that color will dominate and the eyes will be brown. (The actual determination of eye color is more complicated than that.) a. List the different possible outcomes. Assume that these outcomes are equally likely. b. What is the probability that a child of these parents will have the blue>blue genotype? c. What is the probability that the child will have brown eyes?
Answer:
A) Brown-Brown ,Brown-Blue, Blue-Brown, Blue-Blue B) 1/4 =0,25 C)3/4=0,75
Step-by-step explanation:
Lets mother's "BROWN" is "BROWN-M",
mother's "BLUE" is " BLUE-M"
Lets father's "BROWN" is "BROWN-F" and
father's "BLUE " is "BLUE-F"
The kid can have the genotype as follows (list of possible outcomes) :
1. BROWN-M>BROWN-F ( received BROWN as from mother as from father)
2. BROWN-M>BLUE-F ( Received BROWN from mother and BLUE from father)
3. BLUE-M>BROWN-F ( Received BLUE from mother and Brown from father)
4. BLUE-M>BLUE-F ( Received BLUE as from mother as from father)
b) As we can see in a) only 1 outcome from 4 is BLUE-BLUE. So the probability of BLUE-BLUE genotype is
P(BLUE>BLUE)=1/4=0.25
c) As we know that if the child has at least one brown allele, that color will dominate and the eyes will be brown.
It means that outcomes BROWN-BROWN, BROWN-BLUE and BLUE-BROWN determine brown color of eye. So the number of these outcomes is 3. Total amount of outcomes is 4.
So probability that eyes are brown is P(Brown eyes)=3/4 =0.75
HELP PLEASE ITS FOR PLATO
Answer:
i think it might be A. 0.2
Step-by-step explanation:
I NEED HELP PLEASE, THANKS! :)
Answer:
Step-by-step explanation:
Step1 : Verify Sn is valid for n = 1
The state of Wisconsin would like to understand the fraction of its adult residents that consumed alcohol in the last year, specifically if the rate is different from the national rate of 70%. To help them answer this question, they conduct a random sample of 852 residents and ask them about their alcohol consumption.
Answer:
The answer is below
Step-by-step explanation:
What we should do is the following:
First, from the random sample of 852 researchers, it is necessary to obtain the number of adult residents who consumed alcohol in the past year.
After the above, we must calculate the proportion of adult residents who consumed alcohol in the last year by dividing the number of adult residents who consumed alcohol in the last year by 852.
After this, we must compare if the proportion is exactly 70% or different from it.
We have the following hypotheses:
Null Hypothesis: The proportion of adult residents who consumed alcohol in the last year in the state of Wisconsin is exactly 70%
Alternative hypothesis: The proportion of adult residents who consumed alcohol in the last year in the state of Wisconsin is not equal to 70%
Suppose that E(θˆ1) = E(θˆ2) = θ, V(θˆ 1) = σ2 1 , and V(θˆ2) = σ2 2 . Consider the estimator θˆ 3 = aθˆ 1 + (1 − a)θˆ 2. a Show that θˆ 3 is an unbiased estimator for θ. b If θˆ1 and θˆ2 are independent, how should the constant a be chosen in order to minimize the variance of θˆ3?
Answer:
Step-by-step explanation:
Given that:
[tex]E( \hat \theta _1) = \theta \ \ \ \ E( \hat \theta _2) = \theta \ \ \ \ V( \hat \theta _1) = \sigma_1^2 \ \ \ \ V(\hat \theta_2) = \sigma_2^2[/tex]
If we are to consider the estimator [tex]\hat \theta _3 = a \hat \theta_1 + (1-a) \hat \theta_2[/tex]
a. Then, for [tex]\hat \theta_3[/tex] to be an unbiased estimator ; Then:
[tex]E ( \hat \theta_3) = E ( a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]
[tex]E ( \hat \theta_3) = aE ( \theta_1) + (1-a) E ( \hat \theta_2)[/tex]
[tex]E ( \hat \theta_3) = a \theta + (1-a) \theta = \theta[/tex]
b) If [tex]\hat \theta _1 \ \ and \ \ \hat \theta_2[/tex] are independent
[tex]V(\hat \theta _3) = V (a \hat \theta_1+ (1-a) \hat \theta_2)[/tex]
[tex]V(\hat \theta _3) = a ^2 V ( \hat \theta_1) + (1-a)^2 V ( \hat \theta_2)[/tex]
Thus; in order to minimize the variance of [tex]\hat \theta_3[/tex] ; then constant a can be determined as :
[tex]V( \hat \theta_3) = a^2 \sigma_1^2 + (1-a)^2 \sigma^2_2[/tex]
Using differentiation:
[tex]\dfrac{d}{da}(V \ \hat \theta_3) = 0 \implies 2a \ \sigma_1^2 + 2(1-a)(-1) \sigma_2^2 = 0[/tex]
⇒
[tex]a (\sigma_1^2 + \sigma_2^2) = \sigma^2_2[/tex]
[tex]\hat a = \dfrac{\sigma^2_2}{\sigma^2_1+\sigma^2_2}[/tex]
This implies that
[tex]\dfrac{d}{da}(V \ \hat \theta_3)|_{a = \hat a} = 2 \ \sigma_1^2 + 2 \ \sigma_2^2 > 0[/tex]
So, [tex]V( \hat \theta_3)[/tex] is minimum when [tex]\hat a = \dfrac{\sigma_2^2}{\sigma_1^2+\sigma_2^2}[/tex]
As such; [tex]a = \dfrac{1}{2}[/tex] if [tex]\sigma_1^2 \ \ = \ \ \sigma_2^2[/tex]
to prove triangleABC is isosceles, which of the following statements can be used in the proof?
&
given circleR, how is it known that QS = YT?
(idk the answers i guessed)
Answer:
Step-by-step explanation:
In an isosceles triangle, the base angles are equal. This also means that the length of two sides of the triangle are equal. Looking at triangle ABC, to prove that it is an isosceles triangle, then
Angle CAB = angle CBA
For the second question, to determine how it is known that QS is equivalent to YT, we would recall that the diameter of a circle passes through the center and from one side of the circle to the other side. Assuming R is the center of the circle, then QS and YT are the diameters of the circle and also the diagonals of the rectangle. Thus, the correct option is
The diameters act as diagonals
Unknown angle problems
Answer: x =40
Step-by-step explanation:
x +x +100 = 180 They form a straight line so they add to 180 degrees.
2x + 100 = 180 solve for x by combining like terms
-100 -100 subtract 100 from both sides
2x = 80 Divide both sides by 2
x =40
Answer:
x might be 40°.
Step-by-step explanation:
angle on a straight line =180°
x+100+x =180
2x =180-100
2x=80
2x/2=80/2
x=40°
Find the area of the surface correct to four decimal places by expressing the area in terms of a single integral and using your calculator to estimate the integral. The part of the surface that lies above the disk x2 + y2 ≤ 81
Answer:
A(s) = 255.8857
Step-by-step explanation:
Find the area of the surface correct to four decimal places by expressing the area in terms of a single integral and using your calculator to estimate the integral. The part of the surface z = e^-x^2-y^2 that lies above the disk x2 + y2 ≤ 81.
Given that:
[tex]Z = e^{-x^2-y^2}[/tex]
By applying rule; the partial derivatives with respect to x and y
[tex]\dfrac{\partial z }{\partial x}= -2xe^{-x^2-y^2}[/tex]
[tex]\dfrac{\partial z }{\partial y}= -2ye^{-x^2-y^2}[/tex]
The integral over the general region D with respect to x and y is :
[tex]A(s) = \int \int _D \sqrt{1+(\dfrac{\partial z}{\partial x} )^2 +(\dfrac{\partial z}{\partial y} )^2 }\ dA[/tex]
[tex]A(s) = \int \int _D \sqrt{1+(-2xe^{-x^2-y^2})^2 +(-2ye^{-x^2-y^2})^2 } \ dA[/tex]
[tex]A(s) = \int \int _D \sqrt{1+4x^2({e^{-x^2-y^2})^2 +4y^2({e^{-x^2-y^2}})^2 }} \ dA[/tex]
[tex]A(s) = \int \int _D \sqrt{1+(4x^2+4y^2)({e^{-x^2-y^2})^2 }} \ dA[/tex]
[tex]A(s) = \int \int _D \sqrt{1+(4x^2+4y^2)e^{-2}({{x^2+y^2}) }} \ dA[/tex]
By relating the equation to cylindrical coordinates
[tex]A(s) = \int \int_D \sqrt{1+4r^2 e^{-2r^2} }. rdA[/tex]
The bounds for integration for the circle within the cylinder [tex]x^2+y^2 =81[/tex] is r =9
[tex]A(s) = \int \limits ^{2 \pi}_{0} \int \limits^9_0 r \sqrt{1+4r^2 e^{-2r^2} }. dr d\theta[/tex]
[tex]A(s) = {2 \pi} \int \limits^9_0 r \sqrt{1+4r^2 e^{-2r^2} }\ dr[/tex]
Using integral calculator to estimate the integral,we have:
A(s) = 255.8857
John comes across a recent survey and wants to gauge the strength of the results.
Which of the following would best reflect upon the researcher.
O a margin of error of +/- 10%
O a margin of error of +/- 3%
O a margin of error of +/- 98%
O a margin of error of +/-8%
Answer:
A margin of error of +/- 3%
Step-by-step explanation:
Strenght of surveys:
The lesser the margin of error, the more precise, stronger, the confidence interval is.
The margin of error depends of the number of people surveyed. The more people are surveyed, lower the margin of error is, giving a stronger interval.
In this question:
We want the smaller margin of error, which is given by:
A margin of error of +/- 3%
Help me please thank you
Answer:
104 degrees
Step-by-step explanation:
The angle of the whole set of lines is 140 degrees. In addition, the partial angle of it is also given--which is 36 degrees. In order to solve for the remaining part, Subtract 36 degrees from 140 degrees to get 104 degrees.
10) BRAINLIEST & 10+ Points!
Answer:
20Solution,
Complement of 70°
=90°-70°
=20°
hope this helps...
Good luck on your assignment..
Answer:
20°
Step-by-step explanation:
Complement of 70° is 90°-70°= 20°
To determine the complement, subtract the given angle from 90.
The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any method. y = −x2 + 23x − 132, y = 0; about the y−axis
Answer:
V = 23π/6
Step-by-step explanation:
V = 2π ∫ [a to b] (r * h) dx
y = −x² + 23x − 132
y = −(x² − 23x + 132)
y = −(x − 11) (x − 12)
Parabola intersects x-axis (line y = 0) at x = 11 and x = 12 ----> a = 11, b = 12
r = x
h = −x² + 23x − 132
V = 2π ∫ [11 to 12] x (−x² + 23x − 132) dx
V = 23π/6
Please help I’m struggling:(
Jose's taxi charges $5 plus $0.30 per mile for fare in a city. Kathy's taxi charges $8
plus $0.20 per mile for fare in the city. At what distance would the charges for the
two taxis be the same?
Answer:
30 miles
Step-by-step explanation:
Jose's charges are ...
j = 5 + 0.30m . . . . . for m miles
Kathy's charges are ...
k = 8 +0.20m . . . . . for m miles
The charges are the same when ...
j = k
5 +0.30m = 8 + 0.20m
0.30m = 3 + 0.20m . . . . subtract 5
0.10m = 3 . . . . . . . . . . . . subtract 0.20m
m = 30 . . . . . . . . . . . . . . . multiply by 10
The charges will be the same for a distance of 30 miles.
Find the length of AC in a triangle
Answer:
9.35
Step-by-step explanation:
AAS formula is easier if you add 12+90 then subtract it from 180, thats angle A.
then just write out the formula
sinA/a = sinB/b
The curvature of a plane parametric curve x = f(t), y = g(t) is $ \kappa = \dfrac{|\dot{x} \ddot{y} - \dot{y} \ddot{x}|}{[\dot{x}^2 + \dot{y}^2]^{3/2}}$ where the dots indicate derivatives with respect to t. Use the above formula to find the curvature. x = 6et cos(t), y = 6et sin(t)
Answer:
The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].
Step-by-step explanation:
The equation of the curvature is:
[tex]\kappa = \frac{|\dot {x}\cdot \ddot {y}-\dot{y}\cdot \ddot{x}|}{[\dot{x}^{2}+\dot{y}^{2}]^{\frac{3}{2} }}[/tex]
The parametric componentes of the curve are:
[tex]x = 6\cdot e^{t} \cdot \cos t[/tex] and [tex]y = 6\cdot e^{t}\cdot \sin t[/tex]
The first and second derivative associated to each component are determined by differentiation rules:
First derivative
[tex]\dot{x} = 6\cdot e^{t}\cdot \cos t - 6\cdot e^{t}\cdot \sin t[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot \sin t + 6\cdot e^{t} \cdot \cos t[/tex]
[tex]\dot x = 6\cdot e^{t} \cdot (\cos t - \sin t)[/tex] and [tex]\dot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t)[/tex]
Second derivative
[tex]\ddot{x} = 6\cdot e^{t}\cdot (\cos t-\sin t)+6\cdot e^{t} \cdot (-\sin t -\cos t)[/tex]
[tex]\ddot x = -12\cdot e^{t}\cdot \sin t[/tex]
[tex]\ddot {y} = 6\cdot e^{t}\cdot (\sin t + \cos t) + 6\cdot e^{t}\cdot (\cos t - \sin t)[/tex]
[tex]\ddot{y} = 12\cdot e^{t}\cdot \cos t[/tex]
Now, each term is replaced in the the curvature equation:
[tex]\kappa = \frac{|6\cdot e^{t}\cdot (\cos t - \sin t)\cdot 12\cdot e^{t}\cdot \cos t-6\cdot e^{t}\cdot (\sin t + \cos t)\cdot (-12\cdot e^{t}\cdot \sin t)|}{\left\{\left[6\cdot e^{t}\cdot (\cos t - \sin t)\right]^{2}+\right[6\cdot e^{t}\cdot (\sin t + \cos t)\left]^{2}\right\}^{\frac{3}{2}}} }[/tex]
And the resulting expression is simplified by algebraic and trigonometric means:
[tex]\kappa = \frac{72\cdot e^{2\cdot t}\cdot \cos^{2}t-72\cdot e^{2\cdot t}\cdot \sin t\cdot \cos t + 72\cdot e^{2\cdot t}\cdot \sin^{2}t+72\cdot e^{2\cdot t}\cdot \sin t \cdot \cos t}{[36\cdot e^{2\cdot t}\cdot (\cos^{2}t -2\cdot \cos t \cdot \sin t +\sin^{2}t)+36\cdot e^{2\cdot t}\cdot (\sin^{2}t+2\cdot \cos t \cdot \sin t +\cos^{2} t)]^{\frac{3}{2} }}[/tex]
[tex]\kappa = \frac{72\cdot e^{2\cdot t}}{[72\cdot e^{2\cdot t}]^{\frac{3}{2} } }[/tex]
[tex]\kappa = [72\cdot e^{2\cdot t}]^{-\frac{1}{2} }[/tex]
[tex]\kappa = 72^{-\frac{1}{2} }\cdot e^{-t}[/tex]
[tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex]
The curvature is modelled by [tex]\kappa = \frac{e^{-t}}{6\sqrt{2}}[/tex].
Express $0.\overline{1}+0.\overline{01}+0.\overline{0001}$ as a common fraction.
Answer:
[tex]\dfrac{1213}{9999}[/tex]
Step-by-step explanation:
We are required to express [tex]0.\overline{1}+0.\overline{01}+0.\overline{0001}[/tex] as a common fraction.
The bar on top of the decimal part indicates the decimal number is a repeating decimal.
Therefore:
[tex]0.\overline{1}=\dfrac{1}{10-1}= \dfrac{1}{9}\\\\0.\overline{01}=\dfrac{1}{100-1}= \dfrac{1}{99}\\\\0.\overline{0001}=\dfrac{1}{10000-1}= \dfrac{1}{9999}\\\\\\$Therefore$:\\0.\overline{1}+0.\overline{01}+0.\overline{0001} \\=\dfrac{1}{9}+\dfrac{1}{99}+\dfrac{1}{9999}\\\\=\dfrac{1213}{9999}[/tex]
In the parallelogram below, solve for x and y. (Give your answer as a decimal, when necessary)
Answer: x = 15, y = 12.5
Step-by-step explanation:
The sum of the three angle measures of a triangle equals 180ᴼ
Since these triangles are vertical, the measures are congruent.
45 + 60 = 105
180 - 105 = 75
So now we know that 5x = 75ᴼ and 6y = 75ᴼ.
To find x, divide 75 by 5
75 / 5 = 15
x = 15
To find y, divide 75 by 6
75 / 6 = 12.5
y = 12.5
Find the amount in an account where $500 is invested at 2.5% compounded continuously for period of 10 years
Hi
500 *1.025^10 ≈ 640.04
Simplify: 1. (x−1)+(12−7.5x) 2. b−(4−2b)+(3b−1) 3. (2p+1.9)−(7−p)
Answer:
1. -6.5x+11
2. 6b-5
3. 3p-5.1
Step-by-step explanation:
[tex]1. \\(x-1)+(12-7.5x)=\\x-1+12-7.5x=\\x-7.5x-1+12=\\-6.5x-1+12=\\-6.5x+11\\\\2.\\b-(4-2b)+(3b-1)=\\b-4+2b+3b-1=\\b+2b+3b-4-1=\\3b+3b-4-1=\\6b-4-1=\\6b-5\\\\3.\\(2p+1.9)-(7-p)=\\2p+1.9-7+p=\\2p+p+1.9-7=\\3p+1.9-7=\\3p-5.1[/tex]
There are 12 teams, each representing a different country, in a women’s Olympic basketball tournament. In how many ways is it possible for the gold, silver, and bronze medals to be awarded? Use the formula for permutations to find your answer.
Answer:
1320 ways
Step-by-step explanation:
To solve we need to use permutations and factorials. If we wanted to find where they would all place 1-12, we would do 12!
12! is the same as 12x11x10x9x8... etc
But in this problem, we are only looking for the top 3.
We can set up a formula
[tex]\frac{n!}{(n-r)!}[/tex]
N is the number of options that are available and r represents the amount we are choosing
In this case, we have 12 teams so n=12
We are looking for the top 3 so r=3
[tex]\frac{12!}{(12-3)!}[/tex]
[tex]\frac{12!}{9!}[/tex]
We expand the equation and cancel out
[tex]\frac{12x11x10x9x8x7x6x5x4x3x2}{9x8x7x6x5x4x3x2}[/tex]
Notice how both sides can cancel out every number 9 and below
That leaves us with 12x11x10
1320 ways
The possible ways for the gold, silver, and bronze medals to be awarded is 1320
What is permutation?A permutation of a set is, loosely speaking, an arrangement of its members into a sequence or linear order, or if the set is already ordered, a rearrangement of its elements.
The word "permutation" also refers to the act or process of changing the linear order of an ordered set.
Given that, there are 12 teams, each representing a different country, in a women’s Olympic basketball tournament.
We need to find that, in how many ways is it possible for the gold, silver, and bronze medals to be awarded,
Using the concept of permutation, to find the number of ways
ⁿPₓ = n!/(n-x)!
= 12! / (12-3)!
= 12! / 9!
= 1320
Hence, the possible ways for the gold, silver, and bronze medals to be awarded is 1320
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The scores from a state standardized test have a mean of 80 and a standard deviation of 10. The distribution of the scores is roughly bell shaped. to find the percentage of scores that lie between 60 and 80.
Answer:
47.5%.
Step-by-step explanation:
60 is 2 standard deviations below the mean.
According to the emperical rule, there is approximately 90% of normally distributed data within 2 standard deviations of the mean. Your interval is half of that because it is the data between the mean and two standard deviations
below the mean. therefore, the answer is 47.5%.
The percentage of scores that lie between 60 and 80 is 47.75%
Z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
[tex]z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \sigma=standard\ deviation[/tex]
Given that:
μ = 80, σ = 10
[tex]For\ x=60:\\\\z=\frac{60-80}{10} =-2\\\\For\ x=80:\\\\z=\frac{80-80}{10} =0[/tex]
P(60 < x < 80) = P(-2 < z < 0) = P(z < 0) - P(z < -2) = 0.5 - 0.0228 = 47.75%
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The vector matrix[ 27 ]is dilated by a factor of 1.5 and then reflected across the X axis if the resulting matrix is a B then a equals an VE
Correct question:
The vector matrix [ [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex] is dilated by a factor of 1.5 and then reflected across the x axis. If the resulting matrix is [a/b] then a=??? and b=???
Answer:
a = 3
b = 10.5
Step-by-step explanation:
Given:
Vector matrix = [tex] \left[\begin{array}{ccc}2\\7\end{array}\right] [/tex]
Dilation factor = 1.5
Since the vector matrix is dilated by 1.5, we have:
[tex] \left[\begin{array}{ccc}1.5 * 2\\1.5 * 7\end{array}\right] [/tex]
= [tex] \left[\begin{array}{ccc}3\\10.5\end{array}\right] [/tex]
Here, we are told the vector is reflected on the x axis.
Therefore,
a = 3
b = 10.5
Answer:
a = 3
b = -10.5
Step-by-step explanation:
got a 100% on PLATO
Please help!!!!! I'm on a timerrrrrrrrrrrrrr!
Step-by-step explanation:
6
[tex]6 \sqrt{6} [/tex]
Answer:
6√6is the exact answer
A bus can carry a maximum of 60 passengers. Each row accommodates the same number of passengers. If two rows are added then each row would accommodate one passenger less for the bus to carry maximum number of passengers. Determine number of rows in the bus and no. Of passengers per row
Answer:
10 rows with 6 passengers per row
Step-by-step explanation:
Let x be the number of rows and y the number of passengers per row.
Then we can interpret the story as the following two equations:
xy=60
(x+2)(y-1)=60
Solving these two equations:
y=60/x
(x+2)(60/x-1)=60 (substitute y)
60 - x + 120/x - 2 = 60 (multiply by -x)
x² + 2x - 120 = 0 (factor)
(x-10)(x+12) = 0
x = 10
y = 60/10 = 6
and indeed 10 * 6 = 60 and also 12 * 5 = 60
The Ball Corporation's beverage can manufacturing plant in Fort Atkinson, Wisconsin, uses a metal supplier that provides metal with a known thickness standard deviation σ = .000586 mm. Assume a random sample of 59 sheets of metal resulted in an x¯ = .2905 mm. Calculate the 95 percent confidence interval for the true mean metal thickness.
Answer:
The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]
Now, find the margin of error M as such
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 1.96\frac{0.000586}{\sqrt{59}} = 0.0002[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 0.2905 - 0.0002 = 0.2903 mm
The upper end of the interval is the sample mean added to M. So it is 0.2905 + 0.0002 = 0.2907 mm
The 95 percent confidence interval for the true mean metal thickness is between 0.2903 mm and 0.2907 mm
Please help!!! I'm really confused.
The value of root 10 is between 3 and 3.5
Match each correlation coefficient, r, to its description.
r = −0.08
r = −0.83
r = 0.96
r = 0.06
1.) strong negative correlation
2.) weak positive correlation
3.) weak negative correlation
4.) strong positive correlation
The answers are in order
r = −0.08 --> weak negative correlation
r = −0.83 --> strong negative correlation
r = 0.96 --> strong positive correlation
r = 0.06 --> weak positive correlation
The match of each correlation is given by,
r = −0.08 implies a weak negative correlation
r = −0.83 implies a strong negative correlation
r = 0.96 implies strong positive correlation
r = 0.06 implies weak positive correlation.
We have given that,
The correlation coefficient, r, to its description.
A B
r = −0.08 strong negative correlation
r = −0.83 weak positive correlation
r = 0.96 weak negative correlation
r = 0.06 strong positive correlation
We have to match the given relation
What is the positive and negative correlation?If the correlation coefficient is greater than zero, it is a positive relationship. Conversely, if the value is less than zero, it is a negative relationship.
So the correct match is,
r = −0.08 implies a weak negative correlation
r = −0.83 implies strong negative correlation
r = 0.96 implies strong positive correlation.
r = 0.06 is implies weak positive correlation.
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Perform the indicated operation.
Answer:
√75 = 5√3 and √12 = 2√3 so √75 + √12 = 5√3 + 2√3 = 7√3.
Answer:
[tex] 7\sqrt{3} [/tex]
Step-by-step explanation:
[tex] \sqrt{12} \: can \: be \: simplified \: as \: 2 \sqrt{3} \: and \: \sqrt{75} \: canbe \: simplified \: as \: 5 \sqrt{3} \\ after \: simplifying \: we \: can \: add \: them \: up \\ 2 \sqrt{3} + 5 \sqrt{3} = 7 \sqrt{3} [/tex]
A company determined that the marginal cost, Upper C prime (x )of producing the xth unit of a product is given by Upper C prime (x )equalsx Superscript 4minus2x. Find the total cost function C, assuming that C(x) is in dollars and that fixed costs are $6000.
Answer:
C(x) = 0.2x^5 - x^2 + 6000
Step-by-step explanation:
Given in the question are restated as follows:
Marginal cos = C'(x) = x^4 - 2x ...................... (1)
Note that marginal cost (C'(x)) refers to the change in the total cost (C(x)) as a result of one more unit increase in the quantity produced. That is, MC refers to the additional cost incurred in order to produce one more unit of a good.
Therefore, TC can be obtained by integrating equation (1) as follows:
C(x) = ∫C'(x) = ∫[x^4 - 2x]dx
C(x) = 1/5x^5 - 2/2x^2 + F ................................ (2)
Where F is the fixed cost. Since the fixed cost is given as $6,000 in the question, we substitute it for F into equation (2) and solve as follows:
C(x) = 0.2x^5 - x^2 + 6000 ......................... (3)
Equation (3) is the total cost function C.
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Answer:
(2x+16) + (x) = 180
Step-by-step explanation:
The opposite angles of a quadrilateral inscribed inside a circle will be supplementary angles, meaning that A+C=180, and B+D=180. A+C is not given in the answers below, but B+D is, so that is the correct answer.
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Answer:
C
Step-by-step explanation:
Opposite angles of a quadrilateral are supplementary