Answer:
It is Frequency.
Explanation:
It just is
Bob uses a wheelbarrow to move soil from his garden to a new flowerbed. He exerts an average force of 185 N while pushing the wheelbarrow, and he does 6.1 kJ of work while moving each load of soil. How far is he moving the soil?
A. 0.026 m
B. 0.039 m
C. 26 m
B. 39 m
Answer:
A. reduce the amount of soil by one-half and apply the same amount of force
Explanation:
A Ring, a solid Cylinder and a solid sphere all having the same mass and the Same radius are held at the top of an inclined plane if the objects are roll without slipping and the (see the picture)between each object and the plane is 0.3 if they are released from an incloed plane at the same time which wal bee reach the bottom first?
Answer:
Since they all have the same mass and radius they all experience the same amount of torque.
Torque = moment of inertia * angular acceleration
The one with the smallest moment of inertia will experience the greatest angular acceleration and thus reach the bottom first.
I = M r^2 ring
I = 1/2 M r^2 cylinder
I = 2/5 M r^2 sphere
The sphere will reach the bottom first.
Just a thought
If you had let’s say two pieces of glass one being much more rudder than the other, and you try to break the tougher glass with the other piece
Example: throwing a glass ball at a glass door
Question: is it possible to break a tougher piece of glass with a weaker piece of glass ?
Suspicion: I’m guessing at high speeds it’s possible but I’m not sure anyone care to put their input ?
Answer:
Explanation:
THE FOURTEEN WEEKS' COURSES
IN
NATURAL SCIENCE,
BY
J. DORMAN STEELE, A.M., PHI.D.
Fourteen Weeks iq Natural Philosophy,
Fourteen Weeks iq Ctlenqistry,
Fourteen Weeks iq Descriptive Astroqonqy,
Fourteel Weeks iq Popular Geology,
Fourteeq Weeks iQ2 Human P1ysiology,
Fourteen Weeks iq Zoology,
Fourteeq Weeks iq Botany,
A Key, containing Answers to the Questions
and Problems in Steele's I4 Weeks' Courses,
4 1ISTORIC4L SERIES,
ON THE PLAN OF STEELE'S 14 WEEKS IN THE SCIENCES.
A Brief History of the Urlited States,
A Brief History of France,
The same publishers also offer the following standard scientific
vworks, being more extended or difficult treatises than those of
Prof. Steele, though still of Academic grade.
Peck's Ganot's Natural Philosophy,
Porter's Principles of Chemistry,
Jarvis' Physiology and Laws of Healtl,
Wood's Botanist and Florist,
Clanlbers' Elenments of Zoology,
lcIqtyre's Astroqomy and tle Globes,
Page's. Elen~ents of Geology,
Entered according to Act of Congress, in the year 1869, by
A. S. BARNES & CO.,
In the Clerk's Office of the District Court of the United States
for the Southern District of New York.
sTERLE'S KEY.
Cora’s doctor suspects that she has acid reflux. He prescribes
for her.
Answer: antacids
Explanation: Excess acid secretion in the stomach often causes nausea, chest pain, and leaves a bitter taste in the mouth. Doctors perscribe antacids to neutralize the acid.
Answer: antacids
Explanation: Excess acid secretion in the stomach often causes nausea, chest pain, and leaves a bitter taste in the mouth. Doctors perscribe antacids to neutralize the acid.
ejemplos de fisica teorica
Answer:
Campo (física)
Computación cuántica.
Conservación de la energía.
Cosmología física.
Cromodinámica cuántica.
Dinámica.
Electrodinámica cuántica.
Electroquímica cuántica.
A 4.50-kg centrifuge takes 200 s to spin up from rest to its final angular speed with constant angular acceleration. A point P located 10.0 cm from the axis of rotation of the centrifuge moves with a speed of 150 m/s when the centrifuge is at full(final) speed. a) [4 points] What was its final angular speed
Answer:
Explanation:
ω = v / R
where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .
Given v = 150 m/s ; R =.10 m
ω = 150 / .10
= 1500 radian /s .
Final angular speed is 1500 radian /s .
A truck with a mass of 1520 kg and moving with a speed of 16.0 m/s rear-ends a 663 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second. vcar
Answer:
Speed of truck after collision = 6.28 m/s
Speed of car after collision = 22.28 m/s
Explanation:
By law of conservation of momentum
momentum before collision = momentum after collision
[tex]m_1u_1+m_2u_2 = m_1v_1+m_2v_2\\plugging/values\\1520\times16+ 0= 1520\times v_1 + 663\times v_2\\24320= 1520v_1+663v_2[/tex]
Since, collision is elastic
[tex]16 = v_2-v_1///v_2 = v_1+16 ....(b)[/tex]
solving the above two equations we get
v_1 = 6.28 m/s and v_2 = 22.28 m/s
Speed of truck after collision = 6.28 m/s
Speed of car after collision = 22.28 m/s
If a team of workers comes to a consensus, what probably happened in the meeting?
A. They compromised with each other to reach an agreement.
B. They disagreed and were unable to come to a decision.
OC. They were forced by their manager to follow a new policy.
O D. They all turned in their letters of resignation.
Answer:
A
Explanation:
A consensus is when you come to an agreement
How do you make a mirages?
Answer: when the ground is very hot and the air is cool. The hot ground warms a layer of air just above the ground. When the light moves through the cold air and into the layer of hot air it is refracted (bent). A layer of very warm air near the ground refracts the light from the sky nearly into a U-shaped bend.
Explanation:
Draw Aufbua diagram of sodium ion
Answer:
Aufbau diagram of sodium ion:
2s²,2p⁶,3s¹
What is the electric field at a distance of 3 cm from 4 mC
of negative charge?
ucharee
Answer:
The magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.
Explanation:
Given;
magnitude of the charge, q = 4 mC = 4 x 10⁻³ C
distance of the charge, r = 3 cm = 0.03 m
The magnitude of the electric field is calculated as follows;
[tex]E = \frac{F}{q} = \frac{Kq}{r^2} \\\\[/tex]
where;
K is Coulomb's constant, = 9 x 10⁹ Nm²/C²
[tex]E = \frac{Kq}{r^2}\\\\E = \frac{(9\times 10^9)(4 \times 10^{-3})}{0.03^2} \\\\E = 4 \times 10^{10} \ N/C[/tex]
Therefore, the magnitude of the electric field experienced by the charge is 4 x 10¹⁰ N/C.
Which of the following choices is not an example of an occupation that is projected to lose jobs?
A. farm workers
B. sewing machine workers
C.private household childcare workers
D. computer support specialists
Answer:
D
Explanation:
D is the most likely answer because as we become more modernized as a whole we will progressively need to fill more positions in support specialty fields.
Describe the types of waves that are made by the music of an orchestra. For example, would the violins’ waves be fast or slow? Would the drums’ waves be large or small? 5 sentences MINIMUM!
Explanation:
Interference and Beats
Interference and Beats
The Doppler Effect and Shock Waves
Boundary Behavior
Reflection, Refraction, and Diffraction
Wave interference is the phenomenon that occurs when two waves meet while traveling along with the same medium. The interference of waves causes the medium to take on a shape that results from the net effect of the two individual waves upon the particles of the medium. As mentioned in a previous unit of The Physics Classroom Tutorial, if two upward displaced pulses having the same shape meet up with one another while traveling in opposite directions along with with a medium, the medium will take on the shape of an upward displaced pulse with twice the amplitude of the two interfering pulses. This type of interference is known as constructive interference. If an upward displaced pulse and a downward displaced pulse having the same shape meet up with one another while traveling in opposite directions along with a medium, the two pulses will cancel each other's effect upon the displacement of the medium and the medium will assume the equilibrium position. This type of interference is known as destructive interference. The diagrams below show two waves - one is blue and the other is red - interfering in such a way to produce a resultant shape in a medium; the result is shown in green. In two cases (on the left and in the middle), constructive interference occurs and in the third case (on the far right, destructive interference occurs.
Now if two sound waves interfere at a given location in such a way that the compression of one wave meets up with the rarefaction of a second wave, destructive interference results. The net effect of compression (which pushes particles together) and a rarefaction (which pulls particles apart) upon the particles in a given region of the medium are to not even cause a displacement of the particles. The tendency of the compression to push particles together is canceled by the tendency of the rarefactions to pull particles apart; the particles would remain at their rest position as though there wasn't even a disturbance passing through them. This is a form of destructive interference. Now if a particular location along with the medium repeatedly experiences the interference of compression and rarefaction followed up by the interference of rarefaction and impression, then the two sound waves will continually cancel each other and no sound is heard. The absence of sound is the result of the particles remaining at rest and behaving as though there was no disturbance passing through it. Amazingly, in a situation such as this, two sound waves would combine to produce no sound. As mentioned in a previous unit, locations along with the medium where destructive interference continually occurs are known as nodes.
1. A 2,000-turn solenoid is 65 cm long and has cross-sectional area 30 cm2. What rate of change of current will produce a 600 Volts emf in this solenoid.
Answer:
[tex]\frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]
Explanation:
First, we will calculate the inductance of the solenoid by using the following formula:
[tex]L = \frac{\mu_o AN^2}{l}[/tex]
where,
L = self-inductance of solenoid = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
A = Cross-sectional area = 30 cm² = 3 x 10⁻³ m²
N = No. of turns = 2000
l = length = 65 cm = 0.65 m
Therefore,
[tex]L = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(3\ x\ 10^{-3}\ m^2)(2000)^2}{0.65\ m}\\\\L = 0.0232\ H[/tex]
Now, we will use Faraday's law to calculate the rate of change of current:
[tex]emf = L\frac{dI}{dt}\\\\ \frac{dI}{dt} =\frac{emf}{L} \\\\ \frac{dI}{dt} =\frac{600\ V}{0.0232\ H}\\\\ \frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]
g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a distant screen that has been set up behind the slit. The first dark fringe in the diffraction pattern is 4.0 cm from the center point of the pattern. If you replace the orange laser with an unknown laser and observe that the second dark fringe of the diffraction pattern appear at 4.0 cm from the center point, what is the wavelength of the unknown laser
Answer:
λ = 3 10⁻⁷ m, UV laser
Explanation:
The diffraction phenomenon is described by the expression
a sin θ = m λ
let's use trigonometry
tan θ = y / L
as in this phenomenon the angles are small
tan θ = [tex]\frac{sin \ \theta}{cos \ \theta}[/tex] = sin θ
sin θ = y / L
we substitute
a y / L = m λ
let's apply this equation to the initial data
a 0.04 / L = 1 600 10⁻⁹
a / L = 1.5 10⁻⁵
now they tell us that we change the laser and we have y = 0.04 m for m = 2
a 0.04 / L = 2 λ
a / L = 50 λ
we solve the two expression is
1.5 10⁻⁵ = 50 λ
λ = 1.5 10⁻⁵ / 50
λ = 3 10⁻⁷ m
UV laser
The nonreflective coating on a camera lens with an index of refraction of 1.23 is designed to minimize the reflection of 631-nm light. If the lens glass has an index of refraction of 1.52, what is the minimum thickness of the coating that will accomplish this task
Answer:
the minimum thickness of the coating is 128.25 nm
Explanation:
The computation of the minimum thickness of the coating is shown below:
In the case of non-reflective coatings, for determining the minimum film thickness needed we need to apply the following formula
Thickness = t = Wavelength ÷ 4n
where
n represent index of refraction of the coating material.
t = 631 ÷ (4 × 1.23)
= 128.25 nm
Hence, the minimum thickness of the coating is 128.25 nm
What type of boundary creates earthquakes? What type of boundaries create volcanoes? Compare and contrast these two types of plate movements, and explain how these geologic events occur.
Answer:
The three types of plate boundaries are Convergent, Divergent and Transform.
The convergent plate boundary is when two plates move towards each other. In this case it has three possibilities:
An oceanic-continental convergent: In this case the the oceanic plate goes beneath the continental in a subduction zone. And due to this process, the continental crust crumples and forms mountains.
An oceanic-oceanic convergent: Here the denser plate goes beneath the other in a subduction zone.
A continental-continental convergent: And in this case the thickness of the crust doubles as the convergent makes mountains.
The divergent plate boundary is when two plates move away from each other. This type of plate boundaries happens between the same plate type, this way it has two possibilities:
An oceanic-oceanic divergent: In this case when two plates goes apart, the magma from the mantle goes up to fill the gap that the separation made.
A continental-continental divergent: And here it’s characterized by rift valleys.
The third and last type is the transform plate boundary. And this one happens when two plates slide along each other horizontally.
this is the correct answer
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8. (-/2 Points]
DETAILS
OBINPHYS8 3.Q.017.
A spring is stretched by an initial amount from its relaxed state. If the spring is then stretched by five times that amount from its relaxed state,
by what factor does the amount of mechanical energy stored in the spring change?
PE final
PE initial
The amount of mechanical energy stored in the spring changes by a factor of 25.
Energy stored in an elastic spring
The energy stored in an elastic spring is given as;
E = ¹/₂kx²
The energy stored in an elastic spring is directly proportional to the square of the extension of the spring.
when the spring is stretched by 5 times greater, the energy stored in the spring is calculated as;
E = ¹/₂k(5x)²
E = ¹/₂k(25x²)
E = 25(¹/₂kx²)
Thus, the amount of mechanical energy stored in the spring changes by a factor of 25.
Learn more about energy stored in a spring here: https://brainly.com/question/24920155
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A vehicle reaches a speed of 7.5 m/s over 15 seconds. What is its acceleration if it
starts from rest?
a. -0.5 m/s2
b. 0.5 m/s?
c. 2 m/s?
d. 22.5 m/s2
[tex]acceleration = \frac{velocity}{time} = \frac{7.5}{15} = 0.5ms^-^2[/tex]
So the answer is option b.
“Is it true or wrong to say that an automobile at rest can be accelerating very fast? Either yes or no explain it with mathematical background
Answer:
Yes.
a = dv/dt
but v might be zero in an instant.
Take the example of a pendulum.
Acceleration is defined as the rate of change of the velocity of the body. Yes, an automobile at rest can accelerate very fast.
What is acceleration?Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.
[tex]\rm a=\frac{dv}{dt}[/tex]
a is the acceleration of the body
dv is the change of velocity of the body
dt is the change in the time interval
The acceleration is defined as the change in velocity, and the slope of velocity is found as acceleration. It can be said that the body is at rest its velocity is zero.
The acceleration of the body can be increased when the body changes its direction. So the moment at which the body changes the direction the body is at rest after that the body can accelerate.
To learn more about acceleration refer to the link;
https://brainly.com/question/969842
8 A car accelerates at a rate of 10m/s
for a time of 4s and it reaches a speed of 52m/s . calculate the initial value
Answer:
From the First Law of Motion
Vf = Vi + at
"It reaches a speed of 52m/s" meaning the Final speed Vf=52
a(acceleration)=10m/s²
t=4s
Applying the formula
52=Vi + 10(4)
Vi = 52-40
Vi = 12m/s
how are force and motion related
. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. The first vehicle collides with a concrete barrier, and stops in a time of approximately 0.1 s. The second vehicle collides with a collapsible barrier, and comes to rest in about 1 second. Which object is subject to a larger force
Answer:
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
Explanation:
For this exercise let's use the relationship between momentum and momentum.
I = F t = Δp
in this case the final velocity is zero
F t = 0 -m v₀
F = m v₀ / t
in order to answer the question we must assume that the two vehicles have the same mass and speed
concrete barrier
F₁ = -p₀ / 0.1
F₁ = - 10 p₀
barrier collapses
F₂ = -p₀ / 1
let's look for the relationship of the forces
F₁ / F₂ = 10
therefore the first out is 10 times greater than the second barrier
You throw a tennis ball straight up. Air resistance can be neglected.
(a) The maximum height above your hand that the ball reaches is H. At what speed does the ball leave your hand?
(b) What is the speed of the ball when it is a height H/2 above your hand? Express your answer as a fraction of the speed at which it left your hand.
(c) At what height above your hand is the speed of the ball half as great as when it left your hand? Express your answer in terms of H.
Answer:
(a) [tex]\sqrt{2gH}[/tex]
(b) [tex]\sqrt{gH}[/tex]
(c) [tex]\frac{3u^{2}}{8g}[/tex]
Explanation:
The maximum height = H
(a) Let the speed of the ball as it leaves the hand is u.
Use third equation of motion
[tex]v^{2}=u^{2}+2as\\0 = u^{2}- 2 gH\\u=\sqrt{2 gH}[/tex]
(b) Let the speed of the ball at H/2 is v.
Use third equation of motion
[tex]v^{2}=u^{2}+2as\\v^{2} = u^{2}- 2 g\frac{H}{2}\\v^{2}=2 g H - gH = gH\\v =\sqrt{gH}[/tex]
(c) Let the height is h.
[tex]v^{2}=u^{2}+2as\\\frac{u^{2}}{4} = u^{2}- 2 gh \\\\2 g h = \frac{3u^{2}}{4}\\h =\frac{3u^{2}}{8g}[/tex]
There are strong winds on these trees. What makes the wind stronger? Why are they blowing from different directions?
what makes molecules move. A. covection. B. Radiation. C. Thermal or heat. D. conduction.
Answer:
the answer is C
Explanation:
1. A ford engine is provided with 80,000 W power by burning its fuel. The engine produces a kinetic energy of 96 kJ for 20 seconds before its cut out.
a. Calculate the output power by the engine in watts.
b. What is the efficiency of the engine?
c. Why is there a considerable difference in the power input and output?
Answer: a) 4800 W b) 6 % c) most of the energy of fuel is converted to heat in combustion engine
Explanation: a) Power P = W/t = 96 000 J / 20 s = 4800 W
b) efficiency η = P(putput) / P(intake) = 4800 W / 80000 W = 0,06
The take-up reel of a cassette tape has a radius of 2.5 cm. Find the length of the tape that passes around the reel in 7.1 s when the reel rotates at an average angular speed of 1.9 rad/s.
Answer:
s = 0.337 m
Explanation:
First, we will find the angular displacement of the reel:
[tex]\theta = \omega t[/tex]
where,
θ = angular displacement = ?
ω = angular speed = 1.9 rad/s
t = time taken = 7.1 s
Therefore,
θ = (1.9\ rad/s)(7.1 s)
θ = 13.5 rad
Now, we will find out the length of tape:
s = rθ
where,
s = length of tape = ?
r = radius of reel = 2.5 cm = 0.025 m
Therefore,
s = (0.025 m)(13.5 rad)
s = 0.337 m
if 36C ofcharge pass through a write in 4s current is it carrying?
Answer:
The current flowing through the wire is 9 A.
Explanation:
Given;
quantity of charge passing through the wire, Q = 36 C
duration of the charge flow, t = 4 s
The current flowing through the wire is calculated as;
Q = It
I = Q / t
where;
I is the current flowing in the wire
I = 36/4
I = 9 A
Therefore, the current flowing through the wire is 9 A.
सत्मार्ग र शान्तिले नै समाजलाई सभ्य बनाउँछ भन्ने विषयमा ५० शब्दसम्मको एउटा अनुच्छेद
लेख्नुहोस्।
Answer:
So you have a question
Explanation:
either way have a nice day