gabriel created 270 grams of aluminum oxide from 145 grams of aluminum. what was his percent yield?

A. 99.1%
B. 98.6%
C. 97.2%
D.96.5%

( it’s not “D” because I got it wrong lol) pls help tho

Answer:

Err... Mate are we suppose to give you resources on this topic, or do we just err respond? if I will give you resources?

Explanation:

Answer:

The amount of N2O4 increases.

Explanation:

Based on LeCh's principle, a change in the state of an equilibrium produce an effect in the system that try to restore the initial equilibrium.

For example, in the problem, the change is the increasing in the pressure. The system will try to decrease the pressure of the system. To decrease the pressure the system needs to decrease the moles of gas. As 2 moles of NO2 produce 1 mole of N2O4, the system will:

Shift to the right increasing the amount of N2O4 and decreasing the amount of NO2. Right option is:

Answer:

B. two atoms share or transfer electrons

Explanation:

for a chemical bond to occur there must be association of atoms into molecules,ions , crystals or other species that make up familiar substances

Answer:

[tex]Y=63.1\%[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction:

[tex]4C_2H_3Cl + 7O_2 \rightarrow 8CO + 6H_2O + 2Cl_2[/tex]

It turns out possible for us to realize about the 7:8 mole ratio of O2 to CO, and therefore, the theoretical yield of the latter is calculated via stoichiometry:

[tex]m_{CO}=57.8gO_2*\frac{1molO_2}{32.0gO_2}*\frac{8molCO}{7molO_2} *\frac{28.01gCO}{1molCO} =57.82gCO[/tex]

Finally, the percent yield is calculated by dividing the actual yield, 36.5 g by the just computed theoretical one:

[tex]Y=\frac{36.5g}{57.8g} *100\%\\\\Y=63.1\%[/tex]

Regards!

Answer:

its answer is (Acetylene)

The first liquid (milk) that comes out of a woman's breast after delivery is called [tex]\sf\purple{colostrum}[/tex].

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]

Answer:

136 KJ

Explanation:

We'll begin by calculating the heat required to melt the ice. This can be obtained as follow:

Mass (M) = 250 g

Heat of fusion (Hբ) = 334 J/gºC

Heat (Q₁) required to melt the ice =?

Q₁ = MHբ

Q₁ = 250 × 334

Q₁ = 83500 J

Next, we shall determine the heat required to change the temperature. This can be obtained as follow:

Mass (M) = 250 g

Initial temperature (T₁) = 0 °C

Final temperature (T₂) = 50 °C

Specific heat capacity (C) = 4.184 J/gºC

Heat (Q₂) required to change the temperature =?

Q₂ = MC(T₂ – T₁)

Q₂ = 250 × 4.184 (50 – 0)

Q₂ = 1046 × 50

Q₂ = 52300 J

Next, we shall determine the total heat required.

Heat (Q₁) required to melt the ice = 83500 J

Heat (Q₂) required to change the temperature = 52300 J

Total heat (Qₜ) required =?

Qₜ = Q₁ + Q₂

Qₜ = 83500 + 52300

Qₜ = 135800 J

Finally, we shall convert 135800 J to KJ. This can be obtained as follow:

1000 J = 1 KJ

Therefore,

135800 J = 135800 J × 1 KJ / 1000 J

135800 J ≈ 136 KJ

Thus, the total heat required is 136 KJ.

The strongest acid as per dissociation constant is hydrochloric acid.

Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste. Compounds such as  HCl, H₂SO₄ and HNO₃ are acids as they yield H+ ions on dissociation.

According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic  acids  depending on the number of protons which are liberated on dissociation.

Acids are widely used in industries  for  production of fertilizers, detergents  batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.Acids are also used in titrations.

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The mass of iron required by one mole or 187.5 g of copper nitrate is 234 g. Then the mass of Fe required by 4 g of copper nitrate is 5 g.

Copper nitrate is an ionic compound formed by donating electrons from metallic copper to the nitrate group. Copper nitrate easily undergoes displacement reactions.

The reaction of copper nitrate with iron is written below:

[tex]\rm Cu(NO_{3})_{2} + 4 Fe \rightarrow 2Fe_{2}(NO_{3})_{2} + Cu[/tex]

As per this reaction, one mole of copper nitrate requires 4 moles of Fe.

molar mass of Fe = 58.5

mass of 4 moles = 234 g

molar mass of copper nitrate = 187.5 g.

187.5 g of copper nitrate need 234 g of Fe. Hence, 4 g of Cu needs:

234 × 4 /187.5 = 5 g

Therefore, the mass of Fe requires is 5 g.

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Answer:

Carbon dioxide.

Explanation:

Hope this will help

Answer:

It must be negative, for the reaction to be feasible.

explanation:

Answer: The given transition metal ions in order of decreasing number of unpaired electrons are as follows.

[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]

Explanation:

In atomic orbitals, the distribution of electrons of an atom is called electronic configuration.

The electronic configuration in terms of noble gases for the given elements are as follows.

[tex]Fe^{3+} - [Ar] 3d^{5}[/tex]

So, there is only 1 unpaired electron present in [tex]Fe^{3+}[/tex].

[tex]Mn^{4+} - [Ar]3d^{3}[/tex]

So, there are only 3 unpaired electrons present in [tex]Mn^{4+}[/tex].

[tex]V^{3+} - [Ar] 3d^{2}[/tex]

So, there are only 2 unpaired electrons present in [tex]V^{3+}[/tex].

[tex]Ni^{2+} - [Ar] 3d^{8}[/tex]

So, there will be 2 unpaired electrons present in [tex]Ni^{2+}[/tex].

[tex]Cu^{+} - [Ar] 3d^{10}[/tex]

So, there is no unpaired electron present in [tex]Cu^{+}[/tex].

Therefore, given transition metal ions in order of decreasing number of unpaired electrons are as follows.

[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]

Thus, we can conclude that given transition metal ions in order of decreasing number of unpaired electrons are as follows.

[tex]Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}[/tex]

The balanced reaction equation is;  2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)

A chemical equation shows the conversion of reactants into products. Recall that in a chemical reactions, reactans interact with each other to yield products.

For the reaction we have in the question,the complete reaction equation is; 2KI(aq)+BaS(aq)→ K2S(aq) + BaI2(aq)

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Answer:

See explanation and image attached

Explanation:

Fischer esterification is a type of reaction used  to convert carboxylic acids to ester in the presence of excess alcohol and a strong acid which acts as a catalyst. Another final product formed in the reaction is water.

The mechanism for the fischer esterification of Benzoic acid and  C H 3 O H in the presence of HCl as the catalyst is shown in the image attached to this answer.

The final products of the reaction are methyl benzoate, water and H^+ as shown in the image attached.

The methyl ester, water, and the acid catalyst (HCl) are byproducts of the Fischer esterification process, which involves protonation, nucleophilic attack, elimination, and deprotonation processes.

Carbonyl oxygen protonation: The carbonyl oxygen of the carboxylic acid (benzoic acid) is protonated by the acid catalyst (HCl) in the first step. The protonation of the carbonyl carbon increases its electrophilicity and promotes the alcohol's nucleophilic assault. Attack by the alcohol's nucleophilic oxygen (methanol, CH3OH) on the protonated carboxylic acid's carbonyl carbon results in the formation of a tetrahedral intermediate. The acid catalyst also helps with this phase. Elimination of water: In the following step, the water molecule must be removed from the tetrahedral intermediate. The hydroxyl group (-OH) from the carboxylic acid and a hydrogen from the hydroxyl group of the alcohol are removed to create this water molecule. Deprotonation: A deprotonation occurs after the removal of water.

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Answer:

See explanation

Explanation:

We must remember that the energy required to move an electron from the 1s orbital to a higher energy level depends on the size of the nuclear charge.

The higher the nuclear charge, the more closely held the 1s electron of the atom is to the nucleus and the more difficult it is to excite this electron.

Hence, it requires more energy to excite the 1s electron of silver having a larger size of nuclear charge than it is to excite a 1s electron in lithium.

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of [tex]-6.4^oC[/tex] and a molal freezing point depression constant [tex]K_f=3.96^oC.kg/mol[/tex]. A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at [tex]-13.6^oC[/tex] . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

Answer: The mass of glycine that can be dissolved is [tex]1.3\times 10^2g[/tex]

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

[tex]\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m[/tex]

OR

[tex]\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}[/tex]           ......(1)

where,

Freezing point of pure solvent = [tex]-6.4^oC[/tex]

Freezing point of solution = [tex]-13.6^oC[/tex]

i = Vant Hoff factor = 1 (for non-electrolytes)

[tex]K_f[/tex] = freezing point depression constant = [tex]3.96^oC/m[/tex]

[tex]m_{solute}[/tex] = Given mass of solute (glycine) = ?

[tex]M_{solute}[/tex] = Molar mass of solute (glycine) = 75.07 g/mol

[tex]w_{solvent}[/tex] = Mass of solvent = 950. g

Putting values in equation 1, we get:

[tex]-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g[/tex]

Hence, the mass of glycine that can be dissolved is [tex]1.3\times 10^2g[/tex]

Answer:

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Explanation:

The activity series helps us to easily define whether or not a reaction will occur.

Elements at the top of the activity series are highly reactive and will always displace those at the bottom of the series in any reaction.

With the above information in mind, let us answer the questions given above.

Ag + NaNO₃ —> Na + AgNO₃

The above reaction will not occur because Na is higher than Ag in the activity series. Thus, Ag cannot displace Na from solution.

Pb + Mg(NO₃)₂ —> Pb(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Pb in the activity series. Thus, Pb cannot displace Mg from solution.

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

The above reaction will occur because Mg is higher than Fe in the activity series. Thus, Mg will displace Fe from solution.

Cu + Mg(NO₃)₂ —> Cu(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Cu in the activity series. Thus, Cu cannot displace Mg from solution.

From the above illustration, only

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Will occur.

Answer:

A

Explanation:

A P E X

Answer:

0.278 mol

Explanation:

Step 1: Given and required data

Mass of acetic acid (m): 16.7 g

Chemical formula of acetic acid: CH₃COOH (C₂H₄O₂)

Step 2: Calculate the molar mass (M) of acetic acid

We will use the following expression.

M(C₂H₄O₂) = 2 × M(C) + 4 × M(H) + 2 × M(O)

M(C₂H₄O₂) = 2 × 12.01 g/mol + 4 × 1.01 g/mol + 2 × 16.00 g/mol = 60.06 g/mol

Step 3: Calculate the number of moles (n) of acetic acid

We will use the following expression.

n = m/M

n = 16.7 g/(60.06 g/mol) = 0.278 mol

Answer: Hello, please, the question is not complete. Attached is the complete question.

Answer:

1. Their bond strength

2. Their acidic strength

3. the size of their central atom

Explanation:

CH4 and Si4 compounds belong to the same molecular geometry and group and they do have the same bond angle and they do not contain lone pair and they have no repulsion. we can conclude that they are from the carbon family.

NH3 and PH3 have the same molecular geometry  an bond angle which we can say they are 3 bond and 1 lone pair. they are from the nitrogen family and lone pair.

NOTE: Bond angle shows that first atomically is f second period and PH3 is from third period (This is the Drego rule)  

HF and HCL have the same molecular geometry and bond angle.

Answer:

1.64 g/mL

Explanation:

Step 1: Calculate the mass of the solid

m(solid+flask) = m(solid) + m(flask)

m(solid) = m(solid+flask) - m(flask)

m(solid) = 48.8565 g - 35.9325 g = 12.9240 g

Step 2: Calculate the mass of water

m(solid+flask+water) = m(solid+flask) + m(water)

m(water) = m(solid+flask+water) - m(solid+flask)

m(water) = 140.8321 g - 48.8565 g = 91.9756 g

Step 3: Calculate the volume occupied by 91.9756 g of water

The density of water is 0.998203 g/mL.

91.9756 g × 1 mL/0.998203 g = 92.1412 mL

Step 4: Calculate the volume occupied by the solid

The 100.00 mL are occupied by the solid and the water.

100.00 mL = V(solid) + V(water

V(solid) = 100.00 mL - V(water)

V(solid) = 100.00 mL - 92.1412 mL = 7.86 mL

Step 5: Calculate the density of the solid

12.9240 g of the solid occupy 7.86 mL.

ρ = 12.9240 g/7.86 mL = 1.64 g/mL

Answer:

El cocodrilo se arrastró durante 20.833 segundos.

Explanation:

El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: "Un cocodrilo se arrastró 25 metros hacia la derecha con una  rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"

Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:

[tex]t = \frac{x}{v}[/tex] (1)

Donde:

[tex]x[/tex] - Distancia recorrida, en metros.

[tex]v[/tex] - Rapidez del cocodrilo, en metros por segundo.

[tex]t[/tex] - Tiempo, en segundos.

Si [tex]x = 25\,m[/tex] y [tex]v = 1.2\,\frac{m}{s}[/tex], entonces el tiempo empleado por el cocodrilo es:

[tex]t = \frac{25\,m}{1.2\,\frac{m}{s} }[/tex]

[tex]t = 20.833\,s[/tex]

El cocodrilo se arrastró durante 20.833 segundos.

Answer:

0.324 mole of sodium

Explanation:

From the question given above, the following data were obtained:

Volume of sodium = 7.25 L

Number of mole of sodium =..?

The number of mole of sodium that occupies 7.25 L can be obtained as follow:

22.4 L = 1 mole

Therefore,

7.25 L = 7.25 L × 1 mole / 22.4 L

7.25 L = 0.324 mole

Therefore, 0.324 mole of sodium is present in the container.

Given the data from the question,

A. The number of mole of water needed for the reaction is 1 mole

Bi. The number of mole of C₂H₂ formed is 0.5 mole

Bii. The number of mole of Ca(OH)₂ formed is 0.5 mole

Mole = mass / molar mass

Mole of CaC₂ = 32 / 64

Mole of CaC₂ = 0.5 mole

Balanced equation

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ required 2 moles of H₂O

Therefore,

0.5 mole of CaC₂ will require = 0.5 × 2 = 1 mole of H₂O

Thus, 1 mole of H₂O is needed for the reaction.

Balanced equation

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ reacted to produce 1 mole of C₂H₂

Therefore,

0.5 mole of CaC₂ will also react to produce 0.5 mole of C₂H₂

Thus, 0.5 mole of C₂H₂ was obtained from the reaction

Balanced equation

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

From the balanced equation above,

1 mole of CaC₂ reacted to produce 1 mole of Ca(OH)₂

Therefore,

0.5 mole of CaC₂ will also react to produce 0.5 mole of Ca(OH)₂

Thus, 0.5 mole of Ca(OH)₂ was obtained from the reaction

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