The reflected rays of light don't produce visible colored interference fringes in a window pane because the glass structure of a window pane prevents the interference patterns to be observed.
A window pane is the glass that acts as a window in a building. While usually a window pane is only composed of a single piece of glass, sometimes two or more glass sheets are used with some space between each.
When it strikes a window pane, some rays will be reflected back and forth between the glass surfaces. Theoretically, it should produce some visible colored interference fringes. However, the glass structures in window panes do not have the ability to produce these visible fringes. They do produce the effect, but they are negated by the effect of other sections of the glass.
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suppose that 20 j of work is needed to stretch a spring from a0 cm to 2a0 cm. 80 j of work is needed to stretch it from a1 cm to 2a1 cm. what is the natural length of the spring. note that a0 and a1 are some constants and the unit is cm instead of m
The needed length of spring or the natural length is ( 12a₀²- a₁²)( 8a₀- 2a₁).
Let L be the natural length,
Since 20J of work is demanded to stretch the spring from a₀ cm to 2a₀ cm,
We have,20 = k / 2(( 2a₀- L) ²-( a₀- L) ²)--------- eq 1
Again,80 J of work is demanded to stretch the spring from a₁ cm to 2a₁ cm,
80 = k / 2(( 2a₁- L) ²-( a₁- L) ²)---------- eq 2
Now, eq 2 / eq 1
k/ 2(( 2a₀- L) ²-( a₀- L) ²) k/ 2(( 2a₁- L) ²-( a₁- L) ²)
= (80/20)a₁( 3a₁- 2L)/ a₀( 3a₀- 2L)
= 43a₁ ²- 2La₁/ 3a₀ ²- 2La₀ = 43a₁ ²- 2La₁
= 12a₀ ²- 8La₀L( 8a₀- 2a₁)
= 12a₀ ²- 3a₁ ²L
= ( 12a₀ ²- 3a₁ ²)( 8a₀- 2a₁)
Therefore the needed length of spring or the natural length is ( 12a₀²- a₁²)( 8a₀- 2a₁).
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What is the formula for the compound that forms between magnesium and phosphorous?
Answer:
Magnesium phosphate | Mg3(PO4)2
Explanation:
The formula for the compound that forms between magnesium and phosphorous is Mg3(PO4)2
exhibit 6-5 the weight of items produced by a machine is normally distributed with a mean of 8 ounces and a standard deviation of 2 ounces. refer to exhibit 6-5. what percentage of items will weigh between 6.4 and 8.9 ounces? a. .2881 b. .1145 c. .4617 d. .1736
The percentage of items will weigh between 6.4 and 8.9 ounces 0.4617.
In science and engineering, the burden of an object is the force performing on the item because of gravity. a few well-known textbooks outline weight as a vector quantity, the gravitational force performed on the object. Others outline weight as a scalar quantity, the importance of the gravitational pressure.
Retaining your weight inside the ordinary range is an important part of healthful growing old. As in other tiers of existence, elevated body mass index (BMI) in older adults can growth the chance of developing fitness issues. those encompass heart ailments, excessive blood strain, stroke, and diabetes.
Bad sleep, sedentary activities, and consuming too many processed or sugary meals are simply some of the habits that could increase your hazard of weight advantage. yet, some simple steps — together with mindful ingesting, workout.
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for a parallel flow double pipe heat exchanger insulated from its surroundings, the mean outlet temperature of the initially cold fluid can exceed the mean outlet temperature of the initially hot fluid.
The final heat of your substance can be calculated by adding the temperature change to the starting point.Your water's final temperature would be 24 + 6, or 30 degrees Celsius, for instance,if the temperature was 24 degrees when it began.
What is the formula for the beginning temperature?Simple: Change in temperature divided by initial temperature.Grams are used to express the mass.T=TfTi, where Transfer function is the final temperature while Ti is the initial temperature, gives the change in temperature.
What distinguishes initial from final?In physics, an object's initial position is its starting point for motion, and its final position is where it comes to rest.
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What is the complete factorization of 8x2 − 8x + 2?
The complete factorization is 2 (2x-1)².
What is factorization?Factorization is a way of dividing mathematical algebraic statements into their components. The components will produce the original phrase if we multiply them once more.
Factorization is a way of dividing mathematical algebraic statements into their components. If we multiply the components again, we get the original equation.
Factorising is the opposite of extending brackets. Fully factorizing an expression implies putting it in brackets and removing the greatest common factors. Finding the largest common factor between each item in the phrase is the simplest method of factorization.
Given,
= 8x² - 8x +2
= 8x² - (4+4)x +2
= 8x² - 4x + 4x +2
= 4x (2x -1) -2 (2x-1)
= (4x-2) (2x-1)
= 2 (2x-1) (2x-1)
= 2 (2x-1)²
Thus, complete factorization is 2 (2x-1)².
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determine the moment of inertia of a 8.20 kg sphere of radius 0.793 m when the axis of rotation is through its center
The moment of inertia of the sphere when the axis of rotation is through its center be 2.063 kg-m².
What is moment of inertia?The sum of the products generated by multiplying each particle's mass by the square of its distance from the axis results in the moment of inertia (I), which is always expressed with respect to that axis.
Given parameters:
Mass of the sphere: m = 8.20 kg.
Radius of the sphere: r = 0.793 m.
Hence, the moment of inertia of the sphere when the axis of rotation is through its center be = 2/5 mr²
= 2/5 × 8.20 × 0.793 × 0.793 kg-m².
= 2.063 kg-m².
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6. conical surface of constant density find the moment of iner?tia about the z-axis of a thin shell of constant densthe cone 4x 2 4y 2 - z 2
We need to find the rotational inertia of the shell about the axis of rotation.
What is rotational inertia?Inertia of rest the inability of a body to change by itself its state of rest is called inertia of rest. Inertia of direction. The inability of a body to change by itself its direction of motion. Inertia of motion: The inability of the body to change by itself its state of motion is called inertia of motionYou tend to move forward when a sudden break is applied.You feel a backward force when the bus moves quickly from rest.Dusting bed with a broom removes dust due to inertia of rest.when you shake a branch the leaves get detached.According to Newton's first law of motion, an object with a given velocity maintains that velocity unless acted on by an external force. Inertia is the property of matter that makes this law hold true.Any item that can be turned has rotational inertia as a quality. It's a scalar value that indicates how complex it is to adjust an object's rotational velocity around a certain axis.Then the moment of inertia about the y-axis of the thin semicircular region of constant density will be.When a car makes a sharp turn at a high speed, the driver tends to get thrown to another side due to inertia of direction.The spark coming out of a grinding stone is tangential to the rotating stone due to directional inertia.The mud from the wheels of a moving vehicle flies off tangentially.[tex]I_{y} = (\frac{1}{8}) \pi r^{4}[/tex]
x = r cos θ
y = r sin θ
dA = r dr dθ
Then the moment of inertia about the x-axis will be
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write an expression for the gravitational potential energy of the falling mass in terms of the angular displacement
The potential energy of a falling mass is [tex]PE=-m g R \theta[/tex] and [tex]g=9.8 \mathrm{~m} / \mathrm{s}^2.[/tex]
As we know,
The expression that relates linear displacement and angular displacement is given below:
[tex]s=r \theta[/tex]
Now we will replace s with h and r with R in the above expression.
[tex]h=R\theta[/tex]
Here, the height is h and the radius is R.
The initial potential energy is as follows:
[tex]P E_{\mathrm{i}}=m g h[/tex]
Now, replace h with R[tex]\theta[/tex].
We will get it as: [tex]P E_{\mathrm{i}}=m g R \theta[/tex]
Now, substituting [tex]$0^{\circ}$[/tex] for [tex]\theta[/tex]
[tex]P E_{\mathrm{i}} & =m g R\left(0^{\circ}\right) \\=0 \mathrm{~J}[/tex]
The expression for the final potential energy will become:
[tex]P E_{\mathrm{f}}=m g R \theta[/tex]
The potential energy of the falling mass will become:
[tex]P E=P E_{\mathrm{i}}-P E_{\mathrm{f}}[/tex]
From Expressions (1) and (2), the following expression can be obtained:
[tex]P E =0 \mathrm{~J}-m g R \theta \\=-m g R \theta[/tex]
The value of g is as follows: g=9.8 [tex]\mathrm{~m} / \mathrm{s}^2[/tex]
The potential energy of a falling mass is [tex]PE=-m g R \theta[/tex] and [tex]g=9.8 \mathrm{~m} / \mathrm{s}^2.[/tex]
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What is the Goldilocks zone?
A. It is the depth within the Earth’s crust where gold can be found.
B. It is a range of distance from a star where temperatures are right for liquid water to exist.
C. It is the distance from a star where pressures are right for an atmosphere to form.
D. It is the temperature range where porridge is just right.
The Goldilocks zone is a range of distance from a star where temperatures are right for liquid water to exist (option B).
What is the Goldilocks zone?The Goldilocks zone is a zone around a star where a planet could experience temperatures like those on Earth, allowing for the possible existence of liquid water and of life.
The Goldilocks Zone also called habitable zone refers to that range of distance with the right temperatures for water to remain liquid.
Only one planet so far is known to be habitable for life and that planet is Earth. On Earth, water is a critical ingredient for life.
If a planet’s orbit takes it too close to its parent star, then it will be too hot for liquid water to exist, and if it’s too far out it will be too cold. However, the actual distances involved, that define habitable or Goldilocks zone vary between stars.
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a mass m on a frictionless table is attached to a hanging mass m by a cord through a hole in the table. find the speed with which m must move for m to stay at rest.
The speed with which m must move from M to stay at rest is √Mgr/m m/sec .Centripetal Force is responsible for the speed of mass m.
We are given that final state of mass M is rest. It means its velocity is zero. If velocity is zero it means that force acts on the mass M is balanced. When forces are balanced ,body will remain at rest as component of force and gravity cancel each other.
So, if mass M is at rest we need to identify what force are acting on the mass M.
Since mass M is directly perpendicular to acceleration due to gravity, therefore gravity will act some force on it.
Since mass M is moving in circle, due to its movement mass M feels centripetal force.
Therefore, centripetal force due to mass m=Force due to gravity
=>m×(v²)/r=Mg
=>v² = (Mg×r)/m
=>v=√Mgr/m
Hence, speed of mass m is √Mgr/m,
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(Complete question) is:
a mass m on a frictionless table is attached to a hanging mass M by a cord through a hole in the table. find the speed with which m must move for M to stay at rest.
in a collision between a 50-ton bulldozer and a compact car, which vehicle will experience the greater impact force?
The vehicle that weighs less will be hit harder in a collision between two moving objects at the same speed; the more massive and heavy the vehicle, the more energy and momentum it will generate.
Which vehicle will experience the greater force of impact?When two objects come into contact, a force of impact is created. The impact or striking power of your vehicle increases with speed. According to the rules of physics, speed increases cause an increase in the force of impact. A car's force of impact will therefore increase four times if its speed is doubled. The impact increases ninefold when the speed is tripled. Consequently, hitting something at these speeds is equivalent to crashing off a one-, four-, or nine-story building, respectively.In a collision between two moving objects at the same speed, the lighter object will be hit harder since its energy and momentum are greater than those of the heavier one. The lighter, smaller vehicle will decelerate more quickly and might even be propelled in the opposite direction from where it was originally moving.To Learn more About vehicle that weighs less refer to:
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a small artery has a length of 1.6 ✕ 10−3 m and a radius of 2.4 ✕ 10−5 m. if the pressure drop across the artery is 1.8 kpa, what is the flow rate (in mm3/s) through the artery? (assume that the temperature is 37°c.)
The flow rate (in mm3/s) through the artery is [tex]7.031 * 10^-^1^1 m^3/s[/tex]
What is Poiseuille's Law?
Poiseuille's Law can be used to explain the fluid flow through an IV catheter. According to this, the viscosity (μ), pressure gradient (P), length (L), and diameter (r) of the tubing are all important variables that affect fluid flow (Q).
It is given by equation
Δp = 8μLQ / π[tex]R^4[/tex]
where,
Δp = pressure difference between the two ends
μ = dynamic viscosity
L = length of pipe
Q = volumetric flow rate
π = pi
R = pipe radius
Given,
Length of artery L = [tex]1.6 * 10^-^3m[/tex]
Radius R = [tex]2.4 * 10^-^5m[/tex]
Pressure Δp = 1.8 kPa = [tex]1.8 * 10^3 Pa[/tex]
Viscosity μ = [tex]2.084 * 10^-^3 Pa. s[/tex]
Subsituting the values in equation,
Δp = 8μLQ / π[tex]R^4[/tex]
Q = Δp × π[tex]R^4[/tex] / 8μL
Q = [tex]\frac{(1.8 * 10^3) (3.14)(2.4 * 10^-^5)^4}{8 * (2.084* 10^-^3)(1.6 * 10^-^3)}[/tex]
Q = [tex]7.031 * 10^-^1^1 m^3/s[/tex]
The flow rate (in mm3/s) through the artery is [tex]7.031 * 10^-^1^1 m^3/s[/tex]
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a planet with a radius of 6.00 x 107 m has a gravitational field of magnitude 30.0 m/s? at the surface. what is the escape speed from the planet?
The escape speed of the planet is 756.60 m/s
How to calculate escape speed from the planet ?The earth's surface escape speed is roughly 11.2 km/s. This means that an object must have a minimum beginning velocity of 11.2 km/s in order to escape the gravity of the earth and journey into limitless space.
The minimum speed required for a free, unpropelled object to be able to escape the gravitational pull of a primary body and travel an infinite distance from it is known as the escape velocity or escape speed in celestial mechanics. Typically, it is expressed as an ideal speed that disregards atmospheric friction.
Given ,
Gravitational magnitude = 30.00m/s
Escape speed from planet = √[2×30/6*107][
√[2×30.00] /6 ×107
= 756.60 m/s
Therefore Escape speed from planet is 42.4264
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what type of conduit, fittings, switches, lighting fixtures, and receptacles are to be used in the flammable storage area?
The combustible storage room must use cable, connectors, switches, lighting, and plugs of the explosion-proof E12 variety.
What purpose serves a switch?Numerous devices can be connected using switches. Switches prevent route between two devices connected to the same network from obstructing the use of other devices. Switches let you manage who will have access to different network areas. Switches let you keep an eye on utilization.
Explain what switches are.A switch is a device used in electrical engineering that has the ability to connect or detach a circuit's carrying line, halting the flow of electricity, or rerouting it to another conductor.
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the maximum speed of a child on a swing is 4.9 m/s. the child's height above the ground is 0.70 m at the lowest point in his motion. how high above the ground is he at his highest point
1.925 m high above the ground is he at his highest point.
As per the question,
V=4.9 m/s
h= 0.70 m (child's height above the ground at the lowest point in the motion)
Height of the child above the ground at his highest point=h’
H=h’-h
1/2mV²=mgH (g=9.8m/s²)
V²=2gH [V=2g(h’-h)]
V=√ 2×9.8×(h’-0.70)
(4.9)²=19.6(h’-0.70)
24.01=19.6h’-13.72
37.73=19.6h’
37.73/19.6=h’
1.925=h’
What is motion?In physics, motion is defined as a change in a body's position or orientation over time. Translation is the term for motion along a line or a curve. Rotation is another motion that modifies a body's orientation.
What is periodic motion?Periodic motion is defined as a motion that repeats at regular periods of time.
The motion of a youngster on a swing is periodic because the motion of a swing also repeats after short intervals.
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a ball of mass 1.50 kg is hung from a spring which stretches a distance of 0.6875 m. the spring constant of the spring (a scalar quantity) is n/m
The spring constant of the spring (a scalar quantity) is 21.38 N/m.
What is spring constant ?The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the larger the spring constant.
How do you calculate the spring constant?x represents the spring's displacement from its equilibrium position, and k is the spring constant in N/m.
The constant of proportionality k is called Coulomb's constant.
According to given information spring's displacement(x)= 0.6875 m and mass(m)=1.50kg
F=-K × x
K=f/x=mg/x=1.50×(9.8)/0.6875=21.38N/m
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photons in a beam of light with wavelength l have momentum p. if the wavelength is doubled, the momentum is:
When a beam of a photon with wavelength (λ) is doubled, momentum (p) will be halved.
What is Wavelength?
The distance in a wave between a given position and the same point in the following wave cycle. This can be from peak to peak, from trough to trough, from null to null, etc. The formula E = hν = hc/λ, where E is energy, h is Planck's constant, is frequency, c is the speed of light, and is the wavelength, relates wavelength to energy and frequency.
What is Momentum?
The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum because its mass is in motion. The amount of motion and the speed of the motion are the two factors that determine how much momentum an item possesses. The factors of mass and velocity affect momentum. According to an equation, an object's momentum is determined by multiplying its mass by its velocity.
Momentum = mass • velocity, (p = mv)
Hence, When a beam of a photon with wavelength (λ) is doubled, momentum (p) will be halved.
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the swirling gas that collects around a compact object, as its binary companion transfers material to it, is called
NOT an event horizon is its binary counterpart, which transports matter to it.
What is an object in a sentence?To refer to the item or person that is the target of an action, we typically use the word "object." Alternatively, the recipient. In a sentence, a verb's action is transferred to a noun or pronoun as a direct object. It typically responds to the what- or whom-questions regarding the verb.
What is a picture or an object?Icons, cursors, buttons, sprites, and other complicated artworks can be made from a collection of simple visual pieces called image objects. Without having to sketch a single pixel, Image Objects let you express creativity.
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I need a detailed answer
The mass of the beam, given that the beam is balanced is 400 g
How do I determine the mass of the beam?First, we shall re-conctruct the diagram given to better understand what we are looking for. Please see attached photo.
In the attached photo,
M is the mass of the beamNote: The mass of the beam act at the centre of the beam
Now, we shall determine the mass of the beam as follow:
Clock wise moment = M × 10Anti-clock wise moment = 200 × 20Mass of beam (M) =?Anti-clock wise moment = Clock wise moment
200 × 20 = M × 10
4000 = M × 10
Divide both sides by 10
M = 4000 / 10
M = 400 g
Thus, from the above calculation, we can conclude that the mass of the beam is 400 g
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g capacity, the ability of the material/structure to safely resist load without breaking or damage, depends on?
Ductility determines whether a material or structure can safely withstand a load without breaking or suffering damage.
Ductility: What is it?A material's ductility is a mechanical property that refers to how easily it can be drawn from. In the field of materials science, ductility refers to how much plastic deformation under tensile stress a material can withstand before breaking. Ductility is a top priority in both engineering and manufacturing.
It describes a material's suitability for specific manufacturing processes (like cold working) and its capacity to withstand mechanical overload. Among the metals that are frequently referred to as ductile are copper and gold. Not all metals, like cast iron, can fail brittlely; some can instead fail ductilely. Polymers can be thought of as ductile materials because they typically allow for plastic deformation.
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a 0.160-g puck strikes and embeds itself in a 6.4 kg block. the block moves off at 1.2 m/s. what was the puck's speed?
The puck's speed was 7.2 m/s.
What is speed?
Despite their similarities, speed and velocity have very different meanings, just as distance as well as displacement do. Speed, which is a scalar quantity, is the "speed at which an object is moving." The rate that an object travels a distance can be assumed of as its speed. A fast-moving object travels at a high speed and completes a significant distance in a brief period of time. This is in contrast to an object moving slowly, which travels a relatively short distance within the same amount of time. Zero speed refers to an object that is not moving at all.
The puck's speed can be determined by solving the equation for momentum conservation. Momentum is conserved when the total momentum before an interaction is equal to the total momentum after the interaction. In this case, the equation looks like this:
m_P * v_P + m_B * v_B = (m_P + m_B) * v_F
Where m_P is the mass of the puck, v_P is the initial velocity of the puck, m_B is the mass of the block, v_B is the initial velocity of the block, and v_F is the final velocity of the block.
Plugging in the given values, we get:
0.160 * v_P + 6.4 * 1.2 = (0.160 + 6.4) * 1.2
Solving for v_P, we get:
v_P = 7.2 m/s
Therefore, the puck's speed was 7.2 m/s.
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within the deep cold zone, average temperature and salinity . a. remain fairly constant with depth. b. increases and decreases, respectively. c. decrease with depth. d. increase with depth.
The average salinity in the deep cold zone increases with depth. The average temperature in the deep cold zone decreases with depth.
Salinity in the ocean is how much salt is in ocean water. Near the surface, the salinity could change.
Salinity will decrease after rainfall.Salinity will increase after evaporation on a sunny day.Sunlight can affect the temperature of the water. But only about 200 m from the surface. Below 200 m, the sunlight cannot get through.
According to hydrostatic pressure, as deeper as the ocean, the pressure increase. When the pressure increase, the temperature will decrease.
In the deep cold zone, there is a water current called thermohaline circulation which carries colder and saltier water to the deeper parts of the ocean. This circulation makes in the deep cold zone the temperature decrease and the salinity increase.
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A force of 570 N keeps a certain ideal spring stretched a distance of 0.900 m.
Part A:
What is the potential energy of the spring when it is stretched 0.900 mm?
Express your answer with the appropriate units.
Part B:
What is its potential energy when it is compressed 9.00 cm?
Express your answer with the appropriate units.
Hooke's law states that the elongation of a material is proportional to the applied stress within the elastic limits of the material.
Using Hooke's law
F = kx
570 = k * 0.9
k = 712.5 N/m
(a) energy at x = 0.8 m
U = 0.5 k x^2 = 0.5* 712.8* 0.8^2
U = 228 J
(b) U = 0.5 * 712.8* 0.09^2
U = 2.887 J
Elastic potential energy is the potential energy released as a result of the deformation of an elastic body. B. Spring extension is stored. This is equal to the work done to stretch the spring, which depends on the spring constant k and the stretched distance. The force exerted by the spring is the restoring force that helps return the spring to its equilibrium length.
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hree children are riding on the edge of a merry-go-round that is 115 kg, has a 1.7-m radius, and is spinning at 24 rpm. the children have masses of 32, 34, and 40 kg. (a) if the children with masses of 34 and 40 kg move to the center of the merry-go-round, what is the new angular velocity in rpm?
The new angular velocity in rpm is
27.7 rpm
M = 115 kg be the mass of the merry-go-round,
r = 1.7 m be its radius,
m1 = 32 kg,
m2 = 34 kg,
m3 = 40 kg be the masses of the three children,
ω = 22 rpm be the angular velocity with all children at the edge,
ω' (to be calculated) be the angular velocity after m2 is moved to the center.
The conservation of angular momentum can be used to resolve this.
The angular momentum before and after the move must be equal.
But there are two presumptions we must make.
1) The merry-go-round has a consistent disc shape. Although it is improbable, if the merry-go-round has a more widespread. The issue gets more complex due of its convoluted shape.
2) The kids are on the merry-go-outer round's edge. Regardless of where the kids are, the issue is easily fixable.
but, since I have no information, I'll guess it's on the edge.
In general, a mass m at the edge contributes mr²ω to the angular momentum.
The rotating uniform disk contributes Mr²ω/2 to the angular momentum.
Now we can equate the total angular momentum after the move to the total
angular momentum before the move.
Mr²ω'/2 + m1r²ω' + m3r²ω' = Mr²ω/2 + m1r²ω + m2r²ω + m3r²ω
From that express
ω' = ω(M/2 + m1 + m2 + m3)/(M/2 + m1 + m3)
Substituting actual numbers
ω' = 22×(115/2 + 32 + 34 + 40)/(115/2 + 32 + 40) = 27.7 rpm
Hence, new angular velocity in rpm is 27.7 rpm
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the light we see from the most distant known quasar was emitted around 10 gyrs ago. what was happening with our sun (and therefore earth) 10 gyrs ago? what was happening with the milky way galaxy at this time?
10 billion years ago, the sun was likely in its early stages of formation. At this time, the Milky Way was still in the process of collapsing and starting to form stars.
What is Milky Way?
The galaxy that contains our Solar System is known as the Milky Way, and its name refers to how it appears to us on Earth: a hazy band of light in the night sky made up of stars that are too close together to be seen individually. The Milky Way is a disk-shaped structure, but when viewed from Earth, it looks like a band. In 1610, Galileo Galilei used his telescope for the first time to separate the band of light in to the individual stars. Most astronomers believed that the Milky Way held all of the universe's stars until the early 1920s.
Gas and dust clouds were beginning to collect, and the first stars and proto-planetary disks were beginning to form. The Milky Way was also likely forming its spiral arms, as the young stars began to move around the center of the galaxy. As the stars aged, they began moving further away, creating the spiral arms that we see today.
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a disk of mass 7 kg and radius 0.6m hangs in the xy plane from a horizontal low friction axle. the axle is 0.06m from the center of the disk. what is the frequency of f of small - angle oscillations of the disk ?
The frequency of of small - angle oscillations of the disk is 1.99/sec. Frequency is converse of time period.
We know very well that,
T=2π√I/mgh
where T is the time period,
I is the moment of inertia of body
m is the mass of the body
g is the acceleration due to gravity
and h is the height of the point from center of body
Now, we know very well that moment of inertia of disk is given by=(1/2)mr² where m is the mass of the body and r is the radius of the body
So, putting the values of mass and radius of disk, we get
=>I=(1/2)×7×(0.6)²
=>I=3.5×0.36
=>I= 1.26kg-m²
Now, h is given as 0.06m,value of g is 9.8m/sec² and value of m is 7kg
So, mgh=7×9.8×0.06=4.116kgm²/sec²
Therefore, T=2π√1.26/4.116
=>T=2π√0.306
=>T=2π×0.55sec
=>T=6.28×0.55sec
=>T=3.454sec
=>Frequency(ω)=2π/T
=>Frequency(ω)=2π/3.454
=>ω=6.28/3.454
=>ω=1.99/sec
Hence, frequency is 1.99/sec.
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A carnival game consists of a two masses on a curved frictionless track, as pictured below. The player pushes the larger object so that it strikes the stationary smaller object which then slides follows the curved track so that it rises vertically to a maximum height, hmax. The masses are equipped with elastic bumpers so that the impact between them is an elastic collision. If the larger object has a mass, M = 7.76 kg and the smaller object has a mass of m = 1.86 kg, then with what velocity, v0, should the player release the larger object so that the smaller object just reaches the target maximum height of hmax = 3.0 m above the horizontal portion of the track?
Velocity 1.90 m / s , v0, should the player release the larger object so that the smaller object just reaches the target maximum height of hmax = 3.0 m above the horizontal portion of the track.
What is Velocity?
The directional speed of an item in motion, as measured by a specific unit of time and viewed from a certain point of reference, is what is referred to as velocity.
In this exercise we are given the maximum height data, with energy we can know how fast the body came out
Final mechanical energy, maximum height
EMF = U = m g h
Initial mechanical energy, in the lower part of the track
Em₀ = K = ½ m v²
Em= EMF
½ m v² = m g h
v = √ 2gh
Now we can use the moment to find the speed with which objects collide
The large object has a mass M = 5.41 kg a velocity starts v₁₀, the small object has a mass m = 1.68 kg an initial velocity of zero v₂₀ = 0 and final velocity v
Initial before the crash
p₀ = M v₁₀ + 0
Final after the crash
pf= = M v1f + m v
po=pf
M v₁₀ = M v1f + m v
As the shock is elastic the kinetic energy is conserved
[tex]$$\begin{aligned}& K_0=K_f \\& 1 / 2 M v_{10}{ }^2=1 / 2 M v_{1 f^2}+1 / 2 m v^2\end{aligned}$$[/tex]
Let's write the system of equations
[tex]$$\begin{aligned}& M v_{10}=M v_{1 f}+m v \\& M v_{10}{ }^2=M v_1 f^2+m v^2\end{aligned}$$[/tex]
We cleared vif in the first we replaced in the second
[tex]$$v_{1 f}=\left(\mathrm{M} \mathrm{v}_{10}-\mathrm{mv}\right) / \mathrm{M}$$[/tex]
M v₁₀² = M (M v₁₀ - mv)² / M² + m v²
M v₁₀² = 1 / M (M² v₁₀² - 2mM v v₁₀ + m² v²) +m v²
v₁₀² (M - M) + 2 m v v₁₀ - v² (m2 + m) / M = 0
2 m v₁₀ - v (m + 1) m/ M = 0
v₁₀ = v (m +1) / (2M)
Let's substitute the value of v
v1₁₀= √ (2gh) (m +1) / (2M)
Let's calculate
v₁₀ = √ (2 9.8 3) (1+ 1.68) / (2 5.41)
V₁₀ = 7.668 (2.68) / 10.82
v₁₀ = 1.90 m / s
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combining the two values calculated above tells us the total momentum before the collision. the total momentum of cart 1 and cart 2 before the collision is 0.01 . if you were to do the same calculations to determine the momenta of each cart after the collision and then combine them, you would find that the total momentum of cart 1 and cart 2 after the collision is -0.022 . therefore, the change in momentum (change = final -initial) pf the whole sistem from before the coallision is -0.03. this is one trial. Which of the following statements is most true?
A)There must be a calculation error, because momentum should be conserved in this collision.
B)This demonstrates that momentum is not conserved in this collision.
C)This demonstrates that the motion detector is not precise enough to conduct this
experiment.
E)More trials will not improve the sensitivity of the motion detectors, so there is no point in
collecting more data.
F)Averaging the change in momentum for multiple trials can tell us whether momentum is not
conserved here or the motion detector is imprecise.
Answer:
b
Explanation:
A 30-cm-diameter, 1.4 kg solid turntable rotates on a 1.4-cm-diameter, 450 g shaft at a constant 33 rpm. When you hit the stop switch, a brake pad presses against the shaft and brings the turntable to a halt in 12 seconds. Part A How much friction force does the brake pad apply to the shaft?
0.628N friction force is applied by the brake pad to the shaft when a 30-cm-diameter, 1.4 kg solid turntable rotates on a 1.4-cm-diameter, 450 g shaft at a constant 33 rpm and when you hit the stop switch, a brake pad presses against the shaft and brings the turntable to a halt in 12 seconds.
To determine the friction force applied by the brake pad to the shaft, first we need to calculate the moment of inertia of the solid turn table. Let's consider the moment of inertia of turn table as a disk then -
I = MR²/2
where M= mass of the turntable=1.4 kg
R= radius of the turntable
= diameter of the turntable/2
R= 30cm/2 = 15cm or 0.15m
substituting the value -
I = 1.4kg*(0.15)²/2
I = 0.0157kg-m²
When we hit the stop switch, a brake pad presses against the shaft and brings the turntable to a halt in 12 seconds so the acceleration (α) will be-
α = (ωf-ωi)/t
The initial angular speed (ωi) of the turntable = 33rpm or 3.45rad/s
The final angular speed (ωf) of the turntable = 0 rad/s
so,
α = (0 rad/s - 3.45 rad/s)/12s
α = -0.28rad/s²
Now, the frictional force applied by the brake pad is-
Torque = I x α
from dynamics of rotational motion
r x f = I x α
f = (I x α)/r
where r = radius of the distance from the pivot point so
1.4cm/2 or 0.007m
f = (0.0157kg-m²) * (0.28 rad/s²)/ 0.007m
f = 0.628N
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Nasa’s orion spacecraft, which left earth last week, flew within 81 miles of the surface of which celestial body on monday?.
Nasa’s Orion spacecraft, which left earth last week, flew within 81 miles of the surface of the moon on Monday as part of Artemis I mission.
What is the Artemis I mission?On Nov. 16, 2022, Artemis blasted off on a nearly month-long mission to orbit the moon and return to Earth. Although there are no humans on board, the mission is meant to prepare the way for crews to land on the moon in the future. On November 21, 2022, flying day six of the Artemis I mission, the Orion spacecraft captured this monochrome image of the moon with its optical navigation camera. NASA's mission controllers lost touch with Orion when it passed behind the moon, as expected. Due to complications with the fuelling process, bad weather, and other factors, earlier launch attempts had to be scrubbed.On Monday, NASA's Orion spacecraft sped past the far side of the moon, coming within 81 miles of the surface.To learn more about Artemis I mission , refer:
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